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Implementation of a Singularly LinkedList


Inserting a node to a given position in a linked listImplementation of stackMerging sorted linked lists - C++Generic singly linked list using the C++11 standardLinked List design and implementation - C++Insert a Node at the Tail of a Linked ListHackerrank delete a nodeC++11 Singly Linked List with raw pointersLinked List using templates and smart pointersLeetcode #146. LRUCache solution in Java (Doubly Linked List + HashMap)






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1












$begingroup$


I'm new to C++ and trying to learn by implementing data structures in it.



Is the code below the most efficient way of implementing the data structure in C++? Does it conform to C++ standards, and how readable is it?



#include <iostream>

class Node

public:
int data;
Node *next;
Node(int data)

this->data = data;
this->next = nullptr;

;

class LinkedList

public:
Node *head;
Node *tail;
int length;
LinkedList()

this->head = nullptr;
this->tail = nullptr;
this->length = 0;


void add(int data);
void add(int data, int position);
void delete_node(int position);
int get_length();
void print();
int get_first();
;

void LinkedList::add(int data)

Node *node = new Node(data);

if (this->head == nullptr)

this->head = node;

else

this->tail->next = node;

this->tail = node;
this->length = this->length + 1;


void LinkedList::add(int data, int position)

Node *temp_head = this->head;
Node *node = new Node(data);
int i = 0;
while (i < this->length)

if (i == position - 1)

node->next = this->head->next;
this->head->next = node;

this->head = this->head->next;
i++;

this->head = temp_head;
this->length = this->length + 1;


void LinkedList::print()

Node *temp_head = this->head;
while (this->head != nullptr)

std::cout << this->head->data << 'n';
this->head = this->head->next;

this->head = temp_head;


int LinkedList::get_length()

return this->length;


int LinkedList::get_first()

return this->head->data;


int main()

LinkedList *llist = new LinkedList();
llist->add(0);
llist->add(1);
llist->add(3);
llist->add(4);
llist->add(2, 2);
llist->print();
std::cout << "Length: " << llist->get_length() << 'n';
std::cout << "First Element : " << llist->get_first() << 'n';










share|improve this question











$endgroup$









  • 1




    $begingroup$
    If you are new to a language, you should add the beginner tag to your question. Reviewers take this tag into account.
    $endgroup$
    – dfhwze
    8 hours ago

















1












$begingroup$


I'm new to C++ and trying to learn by implementing data structures in it.



Is the code below the most efficient way of implementing the data structure in C++? Does it conform to C++ standards, and how readable is it?



#include <iostream>

class Node

public:
int data;
Node *next;
Node(int data)

this->data = data;
this->next = nullptr;

;

class LinkedList

public:
Node *head;
Node *tail;
int length;
LinkedList()

this->head = nullptr;
this->tail = nullptr;
this->length = 0;


void add(int data);
void add(int data, int position);
void delete_node(int position);
int get_length();
void print();
int get_first();
;

void LinkedList::add(int data)

Node *node = new Node(data);

if (this->head == nullptr)

this->head = node;

else

this->tail->next = node;

this->tail = node;
this->length = this->length + 1;


void LinkedList::add(int data, int position)

Node *temp_head = this->head;
Node *node = new Node(data);
int i = 0;
while (i < this->length)

if (i == position - 1)

node->next = this->head->next;
this->head->next = node;

this->head = this->head->next;
i++;

this->head = temp_head;
this->length = this->length + 1;


void LinkedList::print()

Node *temp_head = this->head;
while (this->head != nullptr)

std::cout << this->head->data << 'n';
this->head = this->head->next;

this->head = temp_head;


int LinkedList::get_length()

return this->length;


int LinkedList::get_first()

return this->head->data;


int main()

LinkedList *llist = new LinkedList();
llist->add(0);
llist->add(1);
llist->add(3);
llist->add(4);
llist->add(2, 2);
llist->print();
std::cout << "Length: " << llist->get_length() << 'n';
std::cout << "First Element : " << llist->get_first() << 'n';










share|improve this question











$endgroup$









  • 1




    $begingroup$
    If you are new to a language, you should add the beginner tag to your question. Reviewers take this tag into account.
    $endgroup$
    – dfhwze
    8 hours ago













1












1








1





$begingroup$


I'm new to C++ and trying to learn by implementing data structures in it.



Is the code below the most efficient way of implementing the data structure in C++? Does it conform to C++ standards, and how readable is it?



#include <iostream>

class Node

public:
int data;
Node *next;
Node(int data)

this->data = data;
this->next = nullptr;

;

class LinkedList

public:
Node *head;
Node *tail;
int length;
LinkedList()

this->head = nullptr;
this->tail = nullptr;
this->length = 0;


void add(int data);
void add(int data, int position);
void delete_node(int position);
int get_length();
void print();
int get_first();
;

void LinkedList::add(int data)

Node *node = new Node(data);

if (this->head == nullptr)

this->head = node;

else

this->tail->next = node;

this->tail = node;
this->length = this->length + 1;


void LinkedList::add(int data, int position)

Node *temp_head = this->head;
Node *node = new Node(data);
int i = 0;
while (i < this->length)

if (i == position - 1)

node->next = this->head->next;
this->head->next = node;

this->head = this->head->next;
i++;

this->head = temp_head;
this->length = this->length + 1;


void LinkedList::print()

Node *temp_head = this->head;
while (this->head != nullptr)

std::cout << this->head->data << 'n';
this->head = this->head->next;

this->head = temp_head;


int LinkedList::get_length()

return this->length;


int LinkedList::get_first()

return this->head->data;


int main()

LinkedList *llist = new LinkedList();
llist->add(0);
llist->add(1);
llist->add(3);
llist->add(4);
llist->add(2, 2);
llist->print();
std::cout << "Length: " << llist->get_length() << 'n';
std::cout << "First Element : " << llist->get_first() << 'n';










share|improve this question











$endgroup$




I'm new to C++ and trying to learn by implementing data structures in it.



Is the code below the most efficient way of implementing the data structure in C++? Does it conform to C++ standards, and how readable is it?



#include <iostream>

class Node

public:
int data;
Node *next;
Node(int data)

this->data = data;
this->next = nullptr;

;

class LinkedList

public:
Node *head;
Node *tail;
int length;
LinkedList()

this->head = nullptr;
this->tail = nullptr;
this->length = 0;


void add(int data);
void add(int data, int position);
void delete_node(int position);
int get_length();
void print();
int get_first();
;

void LinkedList::add(int data)

Node *node = new Node(data);

if (this->head == nullptr)

this->head = node;

else

this->tail->next = node;

this->tail = node;
this->length = this->length + 1;


void LinkedList::add(int data, int position)

Node *temp_head = this->head;
Node *node = new Node(data);
int i = 0;
while (i < this->length)

if (i == position - 1)

node->next = this->head->next;
this->head->next = node;

this->head = this->head->next;
i++;

this->head = temp_head;
this->length = this->length + 1;


void LinkedList::print()

Node *temp_head = this->head;
while (this->head != nullptr)

std::cout << this->head->data << 'n';
this->head = this->head->next;

this->head = temp_head;


int LinkedList::get_length()

return this->length;


int LinkedList::get_first()

return this->head->data;


int main()

LinkedList *llist = new LinkedList();
llist->add(0);
llist->add(1);
llist->add(3);
llist->add(4);
llist->add(2, 2);
llist->print();
std::cout << "Length: " << llist->get_length() << 'n';
std::cout << "First Element : " << llist->get_first() << 'n';







c++ beginner linked-list






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 8 hours ago







Dan Savage

















asked 8 hours ago









Dan SavageDan Savage

623 bronze badges




623 bronze badges










  • 1




    $begingroup$
    If you are new to a language, you should add the beginner tag to your question. Reviewers take this tag into account.
    $endgroup$
    – dfhwze
    8 hours ago












  • 1




    $begingroup$
    If you are new to a language, you should add the beginner tag to your question. Reviewers take this tag into account.
    $endgroup$
    – dfhwze
    8 hours ago







1




1




$begingroup$
If you are new to a language, you should add the beginner tag to your question. Reviewers take this tag into account.
$endgroup$
– dfhwze
8 hours ago




$begingroup$
If you are new to a language, you should add the beginner tag to your question. Reviewers take this tag into account.
$endgroup$
– dfhwze
8 hours ago










1 Answer
1






active

oldest

votes


















2












$begingroup$

  • C++ is not Java. You may safely get rid of all this->.


  • The client doesn't need to know about Node. Make it an inner class of the LinkedList.


  • The ~LinkedList() destructor is missing. You should also consider (or prohibit) the copy constructor, operator=, and move constructor.


  • add(int data, int position) may silently leak memory. If the position is too large, the created node is not linked into the list, and is lost. Also, there is no way to prepend a node.



  • I don't like the temp_head approach. Better leave the head alone, and iterate using a cursor variable, e.g.:



    void LinkedList::print() 
    Node * cursor = head;
    while (cursor)
    std::cout << cursor->data << 'n';
    cursor = cursor->next;




    At least, there is no need to restore head.



    Ditto for add.







share|improve this answer









$endgroup$

















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    1






    active

    oldest

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    active

    oldest

    votes






    active

    oldest

    votes









    2












    $begingroup$

    • C++ is not Java. You may safely get rid of all this->.


    • The client doesn't need to know about Node. Make it an inner class of the LinkedList.


    • The ~LinkedList() destructor is missing. You should also consider (or prohibit) the copy constructor, operator=, and move constructor.


    • add(int data, int position) may silently leak memory. If the position is too large, the created node is not linked into the list, and is lost. Also, there is no way to prepend a node.



    • I don't like the temp_head approach. Better leave the head alone, and iterate using a cursor variable, e.g.:



      void LinkedList::print() 
      Node * cursor = head;
      while (cursor)
      std::cout << cursor->data << 'n';
      cursor = cursor->next;




      At least, there is no need to restore head.



      Ditto for add.







    share|improve this answer









    $endgroup$



















      2












      $begingroup$

      • C++ is not Java. You may safely get rid of all this->.


      • The client doesn't need to know about Node. Make it an inner class of the LinkedList.


      • The ~LinkedList() destructor is missing. You should also consider (or prohibit) the copy constructor, operator=, and move constructor.


      • add(int data, int position) may silently leak memory. If the position is too large, the created node is not linked into the list, and is lost. Also, there is no way to prepend a node.



      • I don't like the temp_head approach. Better leave the head alone, and iterate using a cursor variable, e.g.:



        void LinkedList::print() 
        Node * cursor = head;
        while (cursor)
        std::cout << cursor->data << 'n';
        cursor = cursor->next;




        At least, there is no need to restore head.



        Ditto for add.







      share|improve this answer









      $endgroup$

















        2












        2








        2





        $begingroup$

        • C++ is not Java. You may safely get rid of all this->.


        • The client doesn't need to know about Node. Make it an inner class of the LinkedList.


        • The ~LinkedList() destructor is missing. You should also consider (or prohibit) the copy constructor, operator=, and move constructor.


        • add(int data, int position) may silently leak memory. If the position is too large, the created node is not linked into the list, and is lost. Also, there is no way to prepend a node.



        • I don't like the temp_head approach. Better leave the head alone, and iterate using a cursor variable, e.g.:



          void LinkedList::print() 
          Node * cursor = head;
          while (cursor)
          std::cout << cursor->data << 'n';
          cursor = cursor->next;




          At least, there is no need to restore head.



          Ditto for add.







        share|improve this answer









        $endgroup$



        • C++ is not Java. You may safely get rid of all this->.


        • The client doesn't need to know about Node. Make it an inner class of the LinkedList.


        • The ~LinkedList() destructor is missing. You should also consider (or prohibit) the copy constructor, operator=, and move constructor.


        • add(int data, int position) may silently leak memory. If the position is too large, the created node is not linked into the list, and is lost. Also, there is no way to prepend a node.



        • I don't like the temp_head approach. Better leave the head alone, and iterate using a cursor variable, e.g.:



          void LinkedList::print() 
          Node * cursor = head;
          while (cursor)
          std::cout << cursor->data << 'n';
          cursor = cursor->next;




          At least, there is no need to restore head.



          Ditto for add.








        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 7 hours ago









        vnpvnp

        42.6k2 gold badges35 silver badges109 bronze badges




        42.6k2 gold badges35 silver badges109 bronze badges






























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            Черчино Становништво Референце Спољашње везе Мени за навигацију46°09′29″ СГШ; 9°30′29″ ИГД / 46.15809° СГШ; 9.50814° ИГД / 46.15809; 9.5081446°09′29″ СГШ; 9°30′29″ ИГД / 46.15809° СГШ; 9.50814° ИГД / 46.15809; 9.508143179111„The GeoNames geographical database”„Istituto Nazionale di Statistica”Званични веб-сајтпроширитиуу