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Centrifugal force with Newton's third law?
Centrifugal force with Newton's third law?
Why do we feel a force in circular motion?Centrifugal ForceWhy is centrifugal 'force' perpendicular to line of inertiaDoes centrifugal force exist?Reference frame and centrifugal forceWho plays the role of centrifugal force in an inertial frame of reference?Centripetal and centrifugal forceWhy do we only feel the centrifugal force?Solidifying understanding of centrifugal force at the equator vs polesHow is centrifugal force derived?Centrifugal force in effective potential
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When an object moves in a circle, there's an acceleration towards the center of the circle, the centripetal acceleration, which also gives us the centrifugal force (since $F = ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force). But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0. So my question is, what is actually this reaction force that's created by the centripetal force, and where does the centrifugal force come from? I do know that the centrifugal force can be viewed as an inertial force in a certian reference frame, but is there any way to describe it in another way? I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.
newtonian-mechanics reference-frames centripetal-force centrifugal-force
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When an object moves in a circle, there's an acceleration towards the center of the circle, the centripetal acceleration, which also gives us the centrifugal force (since $F = ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force). But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0. So my question is, what is actually this reaction force that's created by the centripetal force, and where does the centrifugal force come from? I do know that the centrifugal force can be viewed as an inertial force in a certian reference frame, but is there any way to describe it in another way? I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.
newtonian-mechanics reference-frames centripetal-force centrifugal-force
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When an object moves in a circle, there's an acceleration towards the center of the circle, the centripetal acceleration, which also gives us the centrifugal force (since $F = ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force). But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0. So my question is, what is actually this reaction force that's created by the centripetal force, and where does the centrifugal force come from? I do know that the centrifugal force can be viewed as an inertial force in a certian reference frame, but is there any way to describe it in another way? I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.
newtonian-mechanics reference-frames centripetal-force centrifugal-force
$endgroup$
When an object moves in a circle, there's an acceleration towards the center of the circle, the centripetal acceleration, which also gives us the centrifugal force (since $F = ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force). But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0. So my question is, what is actually this reaction force that's created by the centripetal force, and where does the centrifugal force come from? I do know that the centrifugal force can be viewed as an inertial force in a certian reference frame, but is there any way to describe it in another way? I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.
newtonian-mechanics reference-frames centripetal-force centrifugal-force
newtonian-mechanics reference-frames centripetal-force centrifugal-force
asked 8 hours ago
MelvinMelvin
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Lets look at the Earth-moon system for an example. The centripetal force is Earth's gravity, keeping the Moon from flying away. But this works both ways, the Earth is pulled towards the Moon just as hard as the moon is pulled towards the Earth.
In your car example, the angle of the front tires means some percentage of the force of the car is spent on turning the car. The opposite force is spent trying to push the roadway in the opposite direction. It's the same as driving forwards really, except your force vector isn't parallel with your velocity vector.
Quick little aside: Newton's laws, the ones you learn in High-school anyways, only work in inertial reference frames. Centrifugal force does exist in a rotating reference frame.
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oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
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– Melvin
8 hours ago
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Still Newton's laws, just more than you learn in an average highschool physics class.
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– Ryan_L
8 hours ago
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ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
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– Melvin
8 hours ago
1
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A rotating reference frame is NOT inertial because it is accelerating.
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– Ryan_L
7 hours ago
1
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In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
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– Ryan_L
7 hours ago
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This is a common misinterpretation of Newton's third law, often stated as "to every action, there's an equal and opposite reaction." As you surmise, "action" and "reaction" refer to forces. However, they refer to forces acting on different things. Otherwise, nothing could accelerate, ever: if every force were always canceled out by an equal and opposite force, no force could ever do anything. Instead, forces occur between objects--say car and road, to take your example. The road exerts an inward force on the car, which, you're right, is the centripetal force. The equal and opposite force is exerted by the car, on the road. The two forces are acting on different things, so they do not cancel. This second force (the force exerted by the car on the road) is sometimes referred to as the "reactive centrifugal force," which is confusing, because it's different from the more common meaning of centrifugal force.
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which also gives us the centrifugal force (since $F=ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force).
You shouldn't call it "centrifugal force", but rather centripetal force. A centripetal force inwards causes the centripetal acceleration inwards. When people say "centrifugal force", they usually mean the feeling of being swung outwards, so this imaginary "centrifugal force" would be opposite to the actual centripetal force.
Note, though, that there is no such thing as a centrifugal force (it just feels like there is, but that's just an illusion); there is only a centripetal force.
But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0.
A very important note: The action/reaction forces in Newton's 3rd law do not act on the same object. Your object is pulled inwards and another object is simultaneously pulled outwards (the opposite way) with an equal force.
A circular motion happens because
- you swing something around in a string (the outwards force acts on your hand)
- you turn with your car (the outwards force acts on the ground/asphault/planet)
- a satellite is orbiting Earth (the outwards force acts on the Earth)
- etc.
There is always a source of the inwards force; there is always an interaction with something else, before a force can be present. That "something else", is what feels the reaction force via Newton's 3rd law.
I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.
You are basically answering the question here yourself. The only last thing to point out is, as mentioned above, that there is no such thing as a "centrifugal force". That is a bad term, because it is not a force. It is a feeling. You are swung outwards against the window when a car turns, not because some "centrifugal force" pushes you outwards, but because the car is pulled inwards by the centripetal force.
It is not you being pushed outwards, it is the car moving away from the straight path your body has and thus pulling you along. But from the perspective of the car it looks like you are the one moving and not the car - that is just an illusion, a trick by our brains. The same trick happens when a guy on roller skates is standing in a bus. When the bus accelerates, it looks like he rolls backwards - but it is not him rolling backwards, it is the bus rolling forwards away from underneath his feet.
In summary: It is not you moving outwards, it is the car moving into you. Nothing pushes you outwards, and there is no motion/acceleration outwards which would be caused by any force. Only the feeling/illusion of it.
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Imagine an object connected by a string moving in a circular motion.
what is actually this reaction force that's created by the centripetal force?
The force on a object, which causes the centripetal acceleration of an object, is due to another entity - the action, eg the force on the object due to the string.
The Newton third law pair is the force on another entity due to the object - the reaction, eg the force on the string due to the object.
where does the centrifugal force come from?
The centrifugal force is not a real force, rather it is introduced for the convenience of being able to use Newton’s second law in the rotational (non-inertial) frame of the object.
There is no Newton third law pair to the centrifugal force.
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But this is obviously not true since that would mean that the net
acceleration on the object moving in the circle would be 0.
That is not correct. An object is undergoing acceleration if either its speed changes, it changes direction, or both. According to Newtons first law, a body moving in a straight line at constant speed will continue to do so unless acted upon by a net external force. At any instant in time the velocity vector of a body undergoing circular motion is tangent to the circle. The inertia of the body resists a change in direction of that vector. The centrifugal force is a fictitious force that appears to be acting on the body in a non-inertial (accelerating) reference frame due to the inertia of the body. The centripetal force is the net force acting on the object forcing it to constantly change direction towards the center of the circular path.
Perhaps it is easiest to see this if you consider a car driving in a straight line at constant speed. An object is on the passenger seat. The driver (in this case on the left side of the car) makes a sharp left turn, which is the beginning of circular motion. The object on the seat slides towards the passenger side door. The driver experiences the sensation of being pushed towards the passenger side. But neither the driver nor the object is subjected to any contact force pushing them in that direction. They are experiencing a centrifugal (fictitious) force.
Now suppose instead that the object does not slide on the seat because of the static friction between the object and the seat. The static friction force is a centripetal force towards the center of the circular preventing the object from continuing in a straight line as viewed from an inertial reference frame (e.g., the road). This is the same thing that is happening in your example.
Bottom line: The centripetal force keeps changing the direction of the object towards the center of the circular path. A change in direction of the motion of an object results in an acceleration even if the speed of the object is unchanged.
Hope this helps.
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Lets look at the Earth-moon system for an example. The centripetal force is Earth's gravity, keeping the Moon from flying away. But this works both ways, the Earth is pulled towards the Moon just as hard as the moon is pulled towards the Earth.
In your car example, the angle of the front tires means some percentage of the force of the car is spent on turning the car. The opposite force is spent trying to push the roadway in the opposite direction. It's the same as driving forwards really, except your force vector isn't parallel with your velocity vector.
Quick little aside: Newton's laws, the ones you learn in High-school anyways, only work in inertial reference frames. Centrifugal force does exist in a rotating reference frame.
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oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
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– Melvin
8 hours ago
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Still Newton's laws, just more than you learn in an average highschool physics class.
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– Ryan_L
8 hours ago
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ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
$endgroup$
– Melvin
8 hours ago
1
$begingroup$
A rotating reference frame is NOT inertial because it is accelerating.
$endgroup$
– Ryan_L
7 hours ago
1
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In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
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– Ryan_L
7 hours ago
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show 7 more comments
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Lets look at the Earth-moon system for an example. The centripetal force is Earth's gravity, keeping the Moon from flying away. But this works both ways, the Earth is pulled towards the Moon just as hard as the moon is pulled towards the Earth.
In your car example, the angle of the front tires means some percentage of the force of the car is spent on turning the car. The opposite force is spent trying to push the roadway in the opposite direction. It's the same as driving forwards really, except your force vector isn't parallel with your velocity vector.
Quick little aside: Newton's laws, the ones you learn in High-school anyways, only work in inertial reference frames. Centrifugal force does exist in a rotating reference frame.
$endgroup$
$begingroup$
oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
$endgroup$
– Melvin
8 hours ago
$begingroup$
Still Newton's laws, just more than you learn in an average highschool physics class.
$endgroup$
– Ryan_L
8 hours ago
$begingroup$
ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
$endgroup$
– Melvin
8 hours ago
1
$begingroup$
A rotating reference frame is NOT inertial because it is accelerating.
$endgroup$
– Ryan_L
7 hours ago
1
$begingroup$
In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
$endgroup$
– Ryan_L
7 hours ago
|
show 7 more comments
$begingroup$
Lets look at the Earth-moon system for an example. The centripetal force is Earth's gravity, keeping the Moon from flying away. But this works both ways, the Earth is pulled towards the Moon just as hard as the moon is pulled towards the Earth.
In your car example, the angle of the front tires means some percentage of the force of the car is spent on turning the car. The opposite force is spent trying to push the roadway in the opposite direction. It's the same as driving forwards really, except your force vector isn't parallel with your velocity vector.
Quick little aside: Newton's laws, the ones you learn in High-school anyways, only work in inertial reference frames. Centrifugal force does exist in a rotating reference frame.
$endgroup$
Lets look at the Earth-moon system for an example. The centripetal force is Earth's gravity, keeping the Moon from flying away. But this works both ways, the Earth is pulled towards the Moon just as hard as the moon is pulled towards the Earth.
In your car example, the angle of the front tires means some percentage of the force of the car is spent on turning the car. The opposite force is spent trying to push the roadway in the opposite direction. It's the same as driving forwards really, except your force vector isn't parallel with your velocity vector.
Quick little aside: Newton's laws, the ones you learn in High-school anyways, only work in inertial reference frames. Centrifugal force does exist in a rotating reference frame.
answered 8 hours ago
Ryan_LRyan_L
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oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
$endgroup$
– Melvin
8 hours ago
$begingroup$
Still Newton's laws, just more than you learn in an average highschool physics class.
$endgroup$
– Ryan_L
8 hours ago
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ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
$endgroup$
– Melvin
8 hours ago
1
$begingroup$
A rotating reference frame is NOT inertial because it is accelerating.
$endgroup$
– Ryan_L
7 hours ago
1
$begingroup$
In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
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– Ryan_L
7 hours ago
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show 7 more comments
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oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
$endgroup$
– Melvin
8 hours ago
$begingroup$
Still Newton's laws, just more than you learn in an average highschool physics class.
$endgroup$
– Ryan_L
8 hours ago
$begingroup$
ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
$endgroup$
– Melvin
8 hours ago
1
$begingroup$
A rotating reference frame is NOT inertial because it is accelerating.
$endgroup$
– Ryan_L
7 hours ago
1
$begingroup$
In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
$endgroup$
– Ryan_L
7 hours ago
$begingroup$
oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
$endgroup$
– Melvin
8 hours ago
$begingroup$
oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
$endgroup$
– Melvin
8 hours ago
$begingroup$
Still Newton's laws, just more than you learn in an average highschool physics class.
$endgroup$
– Ryan_L
8 hours ago
$begingroup$
Still Newton's laws, just more than you learn in an average highschool physics class.
$endgroup$
– Ryan_L
8 hours ago
$begingroup$
ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
$endgroup$
– Melvin
8 hours ago
$begingroup$
ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
$endgroup$
– Melvin
8 hours ago
1
1
$begingroup$
A rotating reference frame is NOT inertial because it is accelerating.
$endgroup$
– Ryan_L
7 hours ago
$begingroup$
A rotating reference frame is NOT inertial because it is accelerating.
$endgroup$
– Ryan_L
7 hours ago
1
1
$begingroup$
In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
$endgroup$
– Ryan_L
7 hours ago
$begingroup$
In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
$endgroup$
– Ryan_L
7 hours ago
|
show 7 more comments
$begingroup$
This is a common misinterpretation of Newton's third law, often stated as "to every action, there's an equal and opposite reaction." As you surmise, "action" and "reaction" refer to forces. However, they refer to forces acting on different things. Otherwise, nothing could accelerate, ever: if every force were always canceled out by an equal and opposite force, no force could ever do anything. Instead, forces occur between objects--say car and road, to take your example. The road exerts an inward force on the car, which, you're right, is the centripetal force. The equal and opposite force is exerted by the car, on the road. The two forces are acting on different things, so they do not cancel. This second force (the force exerted by the car on the road) is sometimes referred to as the "reactive centrifugal force," which is confusing, because it's different from the more common meaning of centrifugal force.
$endgroup$
add a comment
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This is a common misinterpretation of Newton's third law, often stated as "to every action, there's an equal and opposite reaction." As you surmise, "action" and "reaction" refer to forces. However, they refer to forces acting on different things. Otherwise, nothing could accelerate, ever: if every force were always canceled out by an equal and opposite force, no force could ever do anything. Instead, forces occur between objects--say car and road, to take your example. The road exerts an inward force on the car, which, you're right, is the centripetal force. The equal and opposite force is exerted by the car, on the road. The two forces are acting on different things, so they do not cancel. This second force (the force exerted by the car on the road) is sometimes referred to as the "reactive centrifugal force," which is confusing, because it's different from the more common meaning of centrifugal force.
$endgroup$
add a comment
|
$begingroup$
This is a common misinterpretation of Newton's third law, often stated as "to every action, there's an equal and opposite reaction." As you surmise, "action" and "reaction" refer to forces. However, they refer to forces acting on different things. Otherwise, nothing could accelerate, ever: if every force were always canceled out by an equal and opposite force, no force could ever do anything. Instead, forces occur between objects--say car and road, to take your example. The road exerts an inward force on the car, which, you're right, is the centripetal force. The equal and opposite force is exerted by the car, on the road. The two forces are acting on different things, so they do not cancel. This second force (the force exerted by the car on the road) is sometimes referred to as the "reactive centrifugal force," which is confusing, because it's different from the more common meaning of centrifugal force.
$endgroup$
This is a common misinterpretation of Newton's third law, often stated as "to every action, there's an equal and opposite reaction." As you surmise, "action" and "reaction" refer to forces. However, they refer to forces acting on different things. Otherwise, nothing could accelerate, ever: if every force were always canceled out by an equal and opposite force, no force could ever do anything. Instead, forces occur between objects--say car and road, to take your example. The road exerts an inward force on the car, which, you're right, is the centripetal force. The equal and opposite force is exerted by the car, on the road. The two forces are acting on different things, so they do not cancel. This second force (the force exerted by the car on the road) is sometimes referred to as the "reactive centrifugal force," which is confusing, because it's different from the more common meaning of centrifugal force.
answered 7 hours ago
Ben51Ben51
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which also gives us the centrifugal force (since $F=ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force).
You shouldn't call it "centrifugal force", but rather centripetal force. A centripetal force inwards causes the centripetal acceleration inwards. When people say "centrifugal force", they usually mean the feeling of being swung outwards, so this imaginary "centrifugal force" would be opposite to the actual centripetal force.
Note, though, that there is no such thing as a centrifugal force (it just feels like there is, but that's just an illusion); there is only a centripetal force.
But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0.
A very important note: The action/reaction forces in Newton's 3rd law do not act on the same object. Your object is pulled inwards and another object is simultaneously pulled outwards (the opposite way) with an equal force.
A circular motion happens because
- you swing something around in a string (the outwards force acts on your hand)
- you turn with your car (the outwards force acts on the ground/asphault/planet)
- a satellite is orbiting Earth (the outwards force acts on the Earth)
- etc.
There is always a source of the inwards force; there is always an interaction with something else, before a force can be present. That "something else", is what feels the reaction force via Newton's 3rd law.
I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.
You are basically answering the question here yourself. The only last thing to point out is, as mentioned above, that there is no such thing as a "centrifugal force". That is a bad term, because it is not a force. It is a feeling. You are swung outwards against the window when a car turns, not because some "centrifugal force" pushes you outwards, but because the car is pulled inwards by the centripetal force.
It is not you being pushed outwards, it is the car moving away from the straight path your body has and thus pulling you along. But from the perspective of the car it looks like you are the one moving and not the car - that is just an illusion, a trick by our brains. The same trick happens when a guy on roller skates is standing in a bus. When the bus accelerates, it looks like he rolls backwards - but it is not him rolling backwards, it is the bus rolling forwards away from underneath his feet.
In summary: It is not you moving outwards, it is the car moving into you. Nothing pushes you outwards, and there is no motion/acceleration outwards which would be caused by any force. Only the feeling/illusion of it.
$endgroup$
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$begingroup$
which also gives us the centrifugal force (since $F=ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force).
You shouldn't call it "centrifugal force", but rather centripetal force. A centripetal force inwards causes the centripetal acceleration inwards. When people say "centrifugal force", they usually mean the feeling of being swung outwards, so this imaginary "centrifugal force" would be opposite to the actual centripetal force.
Note, though, that there is no such thing as a centrifugal force (it just feels like there is, but that's just an illusion); there is only a centripetal force.
But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0.
A very important note: The action/reaction forces in Newton's 3rd law do not act on the same object. Your object is pulled inwards and another object is simultaneously pulled outwards (the opposite way) with an equal force.
A circular motion happens because
- you swing something around in a string (the outwards force acts on your hand)
- you turn with your car (the outwards force acts on the ground/asphault/planet)
- a satellite is orbiting Earth (the outwards force acts on the Earth)
- etc.
There is always a source of the inwards force; there is always an interaction with something else, before a force can be present. That "something else", is what feels the reaction force via Newton's 3rd law.
I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.
You are basically answering the question here yourself. The only last thing to point out is, as mentioned above, that there is no such thing as a "centrifugal force". That is a bad term, because it is not a force. It is a feeling. You are swung outwards against the window when a car turns, not because some "centrifugal force" pushes you outwards, but because the car is pulled inwards by the centripetal force.
It is not you being pushed outwards, it is the car moving away from the straight path your body has and thus pulling you along. But from the perspective of the car it looks like you are the one moving and not the car - that is just an illusion, a trick by our brains. The same trick happens when a guy on roller skates is standing in a bus. When the bus accelerates, it looks like he rolls backwards - but it is not him rolling backwards, it is the bus rolling forwards away from underneath his feet.
In summary: It is not you moving outwards, it is the car moving into you. Nothing pushes you outwards, and there is no motion/acceleration outwards which would be caused by any force. Only the feeling/illusion of it.
$endgroup$
add a comment
|
$begingroup$
which also gives us the centrifugal force (since $F=ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force).
You shouldn't call it "centrifugal force", but rather centripetal force. A centripetal force inwards causes the centripetal acceleration inwards. When people say "centrifugal force", they usually mean the feeling of being swung outwards, so this imaginary "centrifugal force" would be opposite to the actual centripetal force.
Note, though, that there is no such thing as a centrifugal force (it just feels like there is, but that's just an illusion); there is only a centripetal force.
But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0.
A very important note: The action/reaction forces in Newton's 3rd law do not act on the same object. Your object is pulled inwards and another object is simultaneously pulled outwards (the opposite way) with an equal force.
A circular motion happens because
- you swing something around in a string (the outwards force acts on your hand)
- you turn with your car (the outwards force acts on the ground/asphault/planet)
- a satellite is orbiting Earth (the outwards force acts on the Earth)
- etc.
There is always a source of the inwards force; there is always an interaction with something else, before a force can be present. That "something else", is what feels the reaction force via Newton's 3rd law.
I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.
You are basically answering the question here yourself. The only last thing to point out is, as mentioned above, that there is no such thing as a "centrifugal force". That is a bad term, because it is not a force. It is a feeling. You are swung outwards against the window when a car turns, not because some "centrifugal force" pushes you outwards, but because the car is pulled inwards by the centripetal force.
It is not you being pushed outwards, it is the car moving away from the straight path your body has and thus pulling you along. But from the perspective of the car it looks like you are the one moving and not the car - that is just an illusion, a trick by our brains. The same trick happens when a guy on roller skates is standing in a bus. When the bus accelerates, it looks like he rolls backwards - but it is not him rolling backwards, it is the bus rolling forwards away from underneath his feet.
In summary: It is not you moving outwards, it is the car moving into you. Nothing pushes you outwards, and there is no motion/acceleration outwards which would be caused by any force. Only the feeling/illusion of it.
$endgroup$
which also gives us the centrifugal force (since $F=ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force).
You shouldn't call it "centrifugal force", but rather centripetal force. A centripetal force inwards causes the centripetal acceleration inwards. When people say "centrifugal force", they usually mean the feeling of being swung outwards, so this imaginary "centrifugal force" would be opposite to the actual centripetal force.
Note, though, that there is no such thing as a centrifugal force (it just feels like there is, but that's just an illusion); there is only a centripetal force.
But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0.
A very important note: The action/reaction forces in Newton's 3rd law do not act on the same object. Your object is pulled inwards and another object is simultaneously pulled outwards (the opposite way) with an equal force.
A circular motion happens because
- you swing something around in a string (the outwards force acts on your hand)
- you turn with your car (the outwards force acts on the ground/asphault/planet)
- a satellite is orbiting Earth (the outwards force acts on the Earth)
- etc.
There is always a source of the inwards force; there is always an interaction with something else, before a force can be present. That "something else", is what feels the reaction force via Newton's 3rd law.
I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.
You are basically answering the question here yourself. The only last thing to point out is, as mentioned above, that there is no such thing as a "centrifugal force". That is a bad term, because it is not a force. It is a feeling. You are swung outwards against the window when a car turns, not because some "centrifugal force" pushes you outwards, but because the car is pulled inwards by the centripetal force.
It is not you being pushed outwards, it is the car moving away from the straight path your body has and thus pulling you along. But from the perspective of the car it looks like you are the one moving and not the car - that is just an illusion, a trick by our brains. The same trick happens when a guy on roller skates is standing in a bus. When the bus accelerates, it looks like he rolls backwards - but it is not him rolling backwards, it is the bus rolling forwards away from underneath his feet.
In summary: It is not you moving outwards, it is the car moving into you. Nothing pushes you outwards, and there is no motion/acceleration outwards which would be caused by any force. Only the feeling/illusion of it.
edited 6 hours ago
answered 6 hours ago
SteevenSteeven
29.9k8 gold badges72 silver badges121 bronze badges
29.9k8 gold badges72 silver badges121 bronze badges
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$begingroup$
Imagine an object connected by a string moving in a circular motion.
what is actually this reaction force that's created by the centripetal force?
The force on a object, which causes the centripetal acceleration of an object, is due to another entity - the action, eg the force on the object due to the string.
The Newton third law pair is the force on another entity due to the object - the reaction, eg the force on the string due to the object.
where does the centrifugal force come from?
The centrifugal force is not a real force, rather it is introduced for the convenience of being able to use Newton’s second law in the rotational (non-inertial) frame of the object.
There is no Newton third law pair to the centrifugal force.
$endgroup$
add a comment
|
$begingroup$
Imagine an object connected by a string moving in a circular motion.
what is actually this reaction force that's created by the centripetal force?
The force on a object, which causes the centripetal acceleration of an object, is due to another entity - the action, eg the force on the object due to the string.
The Newton third law pair is the force on another entity due to the object - the reaction, eg the force on the string due to the object.
where does the centrifugal force come from?
The centrifugal force is not a real force, rather it is introduced for the convenience of being able to use Newton’s second law in the rotational (non-inertial) frame of the object.
There is no Newton third law pair to the centrifugal force.
$endgroup$
add a comment
|
$begingroup$
Imagine an object connected by a string moving in a circular motion.
what is actually this reaction force that's created by the centripetal force?
The force on a object, which causes the centripetal acceleration of an object, is due to another entity - the action, eg the force on the object due to the string.
The Newton third law pair is the force on another entity due to the object - the reaction, eg the force on the string due to the object.
where does the centrifugal force come from?
The centrifugal force is not a real force, rather it is introduced for the convenience of being able to use Newton’s second law in the rotational (non-inertial) frame of the object.
There is no Newton third law pair to the centrifugal force.
$endgroup$
Imagine an object connected by a string moving in a circular motion.
what is actually this reaction force that's created by the centripetal force?
The force on a object, which causes the centripetal acceleration of an object, is due to another entity - the action, eg the force on the object due to the string.
The Newton third law pair is the force on another entity due to the object - the reaction, eg the force on the string due to the object.
where does the centrifugal force come from?
The centrifugal force is not a real force, rather it is introduced for the convenience of being able to use Newton’s second law in the rotational (non-inertial) frame of the object.
There is no Newton third law pair to the centrifugal force.
answered 4 hours ago
FarcherFarcher
56.6k3 gold badges45 silver badges123 bronze badges
56.6k3 gold badges45 silver badges123 bronze badges
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$begingroup$
But this is obviously not true since that would mean that the net
acceleration on the object moving in the circle would be 0.
That is not correct. An object is undergoing acceleration if either its speed changes, it changes direction, or both. According to Newtons first law, a body moving in a straight line at constant speed will continue to do so unless acted upon by a net external force. At any instant in time the velocity vector of a body undergoing circular motion is tangent to the circle. The inertia of the body resists a change in direction of that vector. The centrifugal force is a fictitious force that appears to be acting on the body in a non-inertial (accelerating) reference frame due to the inertia of the body. The centripetal force is the net force acting on the object forcing it to constantly change direction towards the center of the circular path.
Perhaps it is easiest to see this if you consider a car driving in a straight line at constant speed. An object is on the passenger seat. The driver (in this case on the left side of the car) makes a sharp left turn, which is the beginning of circular motion. The object on the seat slides towards the passenger side door. The driver experiences the sensation of being pushed towards the passenger side. But neither the driver nor the object is subjected to any contact force pushing them in that direction. They are experiencing a centrifugal (fictitious) force.
Now suppose instead that the object does not slide on the seat because of the static friction between the object and the seat. The static friction force is a centripetal force towards the center of the circular preventing the object from continuing in a straight line as viewed from an inertial reference frame (e.g., the road). This is the same thing that is happening in your example.
Bottom line: The centripetal force keeps changing the direction of the object towards the center of the circular path. A change in direction of the motion of an object results in an acceleration even if the speed of the object is unchanged.
Hope this helps.
$endgroup$
add a comment
|
$begingroup$
But this is obviously not true since that would mean that the net
acceleration on the object moving in the circle would be 0.
That is not correct. An object is undergoing acceleration if either its speed changes, it changes direction, or both. According to Newtons first law, a body moving in a straight line at constant speed will continue to do so unless acted upon by a net external force. At any instant in time the velocity vector of a body undergoing circular motion is tangent to the circle. The inertia of the body resists a change in direction of that vector. The centrifugal force is a fictitious force that appears to be acting on the body in a non-inertial (accelerating) reference frame due to the inertia of the body. The centripetal force is the net force acting on the object forcing it to constantly change direction towards the center of the circular path.
Perhaps it is easiest to see this if you consider a car driving in a straight line at constant speed. An object is on the passenger seat. The driver (in this case on the left side of the car) makes a sharp left turn, which is the beginning of circular motion. The object on the seat slides towards the passenger side door. The driver experiences the sensation of being pushed towards the passenger side. But neither the driver nor the object is subjected to any contact force pushing them in that direction. They are experiencing a centrifugal (fictitious) force.
Now suppose instead that the object does not slide on the seat because of the static friction between the object and the seat. The static friction force is a centripetal force towards the center of the circular preventing the object from continuing in a straight line as viewed from an inertial reference frame (e.g., the road). This is the same thing that is happening in your example.
Bottom line: The centripetal force keeps changing the direction of the object towards the center of the circular path. A change in direction of the motion of an object results in an acceleration even if the speed of the object is unchanged.
Hope this helps.
$endgroup$
add a comment
|
$begingroup$
But this is obviously not true since that would mean that the net
acceleration on the object moving in the circle would be 0.
That is not correct. An object is undergoing acceleration if either its speed changes, it changes direction, or both. According to Newtons first law, a body moving in a straight line at constant speed will continue to do so unless acted upon by a net external force. At any instant in time the velocity vector of a body undergoing circular motion is tangent to the circle. The inertia of the body resists a change in direction of that vector. The centrifugal force is a fictitious force that appears to be acting on the body in a non-inertial (accelerating) reference frame due to the inertia of the body. The centripetal force is the net force acting on the object forcing it to constantly change direction towards the center of the circular path.
Perhaps it is easiest to see this if you consider a car driving in a straight line at constant speed. An object is on the passenger seat. The driver (in this case on the left side of the car) makes a sharp left turn, which is the beginning of circular motion. The object on the seat slides towards the passenger side door. The driver experiences the sensation of being pushed towards the passenger side. But neither the driver nor the object is subjected to any contact force pushing them in that direction. They are experiencing a centrifugal (fictitious) force.
Now suppose instead that the object does not slide on the seat because of the static friction between the object and the seat. The static friction force is a centripetal force towards the center of the circular preventing the object from continuing in a straight line as viewed from an inertial reference frame (e.g., the road). This is the same thing that is happening in your example.
Bottom line: The centripetal force keeps changing the direction of the object towards the center of the circular path. A change in direction of the motion of an object results in an acceleration even if the speed of the object is unchanged.
Hope this helps.
$endgroup$
But this is obviously not true since that would mean that the net
acceleration on the object moving in the circle would be 0.
That is not correct. An object is undergoing acceleration if either its speed changes, it changes direction, or both. According to Newtons first law, a body moving in a straight line at constant speed will continue to do so unless acted upon by a net external force. At any instant in time the velocity vector of a body undergoing circular motion is tangent to the circle. The inertia of the body resists a change in direction of that vector. The centrifugal force is a fictitious force that appears to be acting on the body in a non-inertial (accelerating) reference frame due to the inertia of the body. The centripetal force is the net force acting on the object forcing it to constantly change direction towards the center of the circular path.
Perhaps it is easiest to see this if you consider a car driving in a straight line at constant speed. An object is on the passenger seat. The driver (in this case on the left side of the car) makes a sharp left turn, which is the beginning of circular motion. The object on the seat slides towards the passenger side door. The driver experiences the sensation of being pushed towards the passenger side. But neither the driver nor the object is subjected to any contact force pushing them in that direction. They are experiencing a centrifugal (fictitious) force.
Now suppose instead that the object does not slide on the seat because of the static friction between the object and the seat. The static friction force is a centripetal force towards the center of the circular preventing the object from continuing in a straight line as viewed from an inertial reference frame (e.g., the road). This is the same thing that is happening in your example.
Bottom line: The centripetal force keeps changing the direction of the object towards the center of the circular path. A change in direction of the motion of an object results in an acceleration even if the speed of the object is unchanged.
Hope this helps.
answered 6 hours ago
Bob DBob D
13.7k3 gold badges12 silver badges40 bronze badges
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