logarithmic rules with functionsLogarithmic expression with three termsQuestion regarding differentiating logarithmic functionsHow to bound this difference between two logarithmic expressionIs this manipulation with logs allowed?Multi-valued logarithmic functionRoot of Logarithmic EquationComparing functions that have logs in exponentsFinding the domain of logarithmic functionLinear functions versus Logarithmic and Exponential functionschange to logarithmic form. solve for P.
What is the color associated with lukewarm?
Should I worry about having my credit pulled multiple times while car shopping?
New Site Design!
For Saintsbury, which English novelists constituted the "great quartet of the mid-eighteenth century"?
How can Caller ID be faked?
How can religions without a hell discourage evil-doing?
Is there a term for someone whose preferred policies are a mix of Left and Right?
Idiom for 'person who gets violent when drunk"
How can the US president give an order to a civilian?
When is the phrase "j'ai bon" used?
Digital signature that is only verifiable by one specific person
Why does MAGMA claim that the automorphism group of an elliptic curve is order 24 when it is order 12?
The last tree in the Universe
How can I improve readability and length of a method with many if statements?
How could I create a situation in which a PC has to make a saving throw or be forced to pet a dog?
Creating polygon with exact measurements in QGIS 3
IIS LAN and WAN separate SSL certificates for the same server
What made the Ancient One do this in Endgame?
Monotonic operations and integrals
Why did the USA sell so many airplanes prior to WW2?
Threading data on TimeSeries
Sci fi/fantasy book, people stranded on a planet where tech doesn't work, magic mist
What does the output current rating from an H-Bridge's datasheet really mean?
Cant bend fingertip when finger is straight
logarithmic rules with functions
Logarithmic expression with three termsQuestion regarding differentiating logarithmic functionsHow to bound this difference between two logarithmic expressionIs this manipulation with logs allowed?Multi-valued logarithmic functionRoot of Logarithmic EquationComparing functions that have logs in exponentsFinding the domain of logarithmic functionLinear functions versus Logarithmic and Exponential functionschange to logarithmic form. solve for P.
$begingroup$
Do the logarithmic rules work when taking logs of functions as opposed to numbers?
i.e. suppose $f$ is a function and n is a number, is $log (f(x)^n) = n · log(f)$
logarithms
edited 8 hours ago
Bernard
127k743121
asked 8 hours ago
JessJess
135111
$endgroup$
add a comment |
$begingroup$
Do the logarithmic rules work when taking logs of functions as opposed to numbers?
i.e. suppose $f$ is a function and n is a number, is $log (f(x)^n) = n · log(f)$
logarithms
edited 8 hours ago
Bernard
127k743121
asked 8 hours ago
JessJess
135111
$endgroup$
3
$begingroup$
Of course, because the equality is true for any specific $x$.
$endgroup$
– Mark
8 hours ago
1
$begingroup$
@Mark : What you have said is meaningless. Can you elaborate?
$endgroup$
– MPW
8 hours ago
1
$begingroup$
Why is it meaningless? Put any constant $x$ and you will get an equality. Two functions are equal if they are equal at all points.
$endgroup$
– Mark
8 hours ago
2
$begingroup$
Okay, I guess I understand what you mean. Note that, unfortunately, OP has omitted any mention of $x$ on the RHS.
$endgroup$
– MPW
8 hours ago
add a comment |
$begingroup$
Do the logarithmic rules work when taking logs of functions as opposed to numbers?
i.e. suppose $f$ is a function and n is a number, is $log (f(x)^n) = n · log(f)$
logarithms
edited 8 hours ago
Bernard
127k743121
asked 8 hours ago
JessJess
135111
$endgroup$
Do the logarithmic rules work when taking logs of functions as opposed to numbers?
i.e. suppose $f$ is a function and n is a number, is $log (f(x)^n) = n · log(f)$
logarithms
logarithms
edited 8 hours ago
Bernard
127k743121
asked 8 hours ago
JessJess
135111
edited 8 hours ago
Bernard
127k743121
asked 8 hours ago
JessJess
135111
edited 8 hours ago
Bernard
127k743121
edited 8 hours ago
Bernard
127k743121
edited 8 hours ago
Bernard
127k743121
127k743121
asked 8 hours ago
JessJess
135111
asked 8 hours ago
JessJess
135111
asked 8 hours ago
JessJess
135111
135111
3
$begingroup$
Of course, because the equality is true for any specific $x$.
$endgroup$
– Mark
8 hours ago
1
$begingroup$
@Mark : What you have said is meaningless. Can you elaborate?
$endgroup$
– MPW
8 hours ago
1
$begingroup$
Why is it meaningless? Put any constant $x$ and you will get an equality. Two functions are equal if they are equal at all points.
$endgroup$
– Mark
8 hours ago
2
$begingroup$
Okay, I guess I understand what you mean. Note that, unfortunately, OP has omitted any mention of $x$ on the RHS.
$endgroup$
– MPW
8 hours ago
add a comment |
3
$begingroup$
Of course, because the equality is true for any specific $x$.
$endgroup$
– Mark
8 hours ago
1
$begingroup$
@Mark : What you have said is meaningless. Can you elaborate?
$endgroup$
– MPW
8 hours ago
1
$begingroup$
Why is it meaningless? Put any constant $x$ and you will get an equality. Two functions are equal if they are equal at all points.
$endgroup$
– Mark
8 hours ago
2
$begingroup$
Okay, I guess I understand what you mean. Note that, unfortunately, OP has omitted any mention of $x$ on the RHS.
$endgroup$
– MPW
8 hours ago
3
3
$begingroup$
Of course, because the equality is true for any specific $x$.
$endgroup$
– Mark
8 hours ago
$begingroup$
Of course, because the equality is true for any specific $x$.
$endgroup$
– Mark
8 hours ago
1
1
$begingroup$
@Mark : What you have said is meaningless. Can you elaborate?
$endgroup$
– MPW
8 hours ago
$begingroup$
@Mark : What you have said is meaningless. Can you elaborate?
$endgroup$
– MPW
8 hours ago
1
1
$begingroup$
Why is it meaningless? Put any constant $x$ and you will get an equality. Two functions are equal if they are equal at all points.
$endgroup$
– Mark
8 hours ago
$begingroup$
Why is it meaningless? Put any constant $x$ and you will get an equality. Two functions are equal if they are equal at all points.
$endgroup$
– Mark
8 hours ago
2
2
$begingroup$
Okay, I guess I understand what you mean. Note that, unfortunately, OP has omitted any mention of $x$ on the RHS.
$endgroup$
– MPW
8 hours ago
$begingroup$
Okay, I guess I understand what you mean. Note that, unfortunately, OP has omitted any mention of $x$ on the RHS.
$endgroup$
– MPW
8 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Yes it will work.
$$log(f(x)^n) = log(f(x)times f(x) ... times f(x)$$
$$= log(f(x)) +log(f(x)) + ... +log(f(x))$$
$$=n times log(f(x))$$
answered 8 hours ago
VizagVizag
2,7711518
$endgroup$
add a comment |
$begingroup$
Yes, of course.
Because $f(x)$ is still a number for any $x$.
It even works on expressions: for example $log((x^2+3)^9)=9log(x^2+3).$
answered 8 hours ago
Saketh MalyalaSaketh Malyala
10.2k1637
$endgroup$
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3261547%2flogarithmic-rules-with-functions%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Yes it will work.
$$log(f(x)^n) = log(f(x)times f(x) ... times f(x)$$
$$= log(f(x)) +log(f(x)) + ... +log(f(x))$$
$$=n times log(f(x))$$
answered 8 hours ago
VizagVizag
2,7711518
$endgroup$
add a comment |
$begingroup$
Yes it will work.
$$log(f(x)^n) = log(f(x)times f(x) ... times f(x)$$
$$= log(f(x)) +log(f(x)) + ... +log(f(x))$$
$$=n times log(f(x))$$
answered 8 hours ago
VizagVizag
2,7711518
$endgroup$
add a comment |
$begingroup$
Yes it will work.
$$log(f(x)^n) = log(f(x)times f(x) ... times f(x)$$
$$= log(f(x)) +log(f(x)) + ... +log(f(x))$$
$$=n times log(f(x))$$
answered 8 hours ago
VizagVizag
2,7711518
$endgroup$
Yes it will work.
$$log(f(x)^n) = log(f(x)times f(x) ... times f(x)$$
$$= log(f(x)) +log(f(x)) + ... +log(f(x))$$
$$=n times log(f(x))$$
answered 8 hours ago
VizagVizag
2,7711518
answered 8 hours ago
VizagVizag
2,7711518
answered 8 hours ago
VizagVizag
2,7711518
answered 8 hours ago
VizagVizag
2,7711518
2,7711518
add a comment |
add a comment |
$begingroup$
Yes, of course.
Because $f(x)$ is still a number for any $x$.
It even works on expressions: for example $log((x^2+3)^9)=9log(x^2+3).$
answered 8 hours ago
Saketh MalyalaSaketh Malyala
10.2k1637
$endgroup$
add a comment |
$begingroup$
Yes, of course.
Because $f(x)$ is still a number for any $x$.
It even works on expressions: for example $log((x^2+3)^9)=9log(x^2+3).$
answered 8 hours ago
Saketh MalyalaSaketh Malyala
10.2k1637
$endgroup$
add a comment |
$begingroup$
Yes, of course.
Because $f(x)$ is still a number for any $x$.
It even works on expressions: for example $log((x^2+3)^9)=9log(x^2+3).$
answered 8 hours ago
Saketh MalyalaSaketh Malyala
10.2k1637
$endgroup$
Yes, of course.
Because $f(x)$ is still a number for any $x$.
It even works on expressions: for example $log((x^2+3)^9)=9log(x^2+3).$
answered 8 hours ago
Saketh MalyalaSaketh Malyala
10.2k1637
answered 8 hours ago
Saketh MalyalaSaketh Malyala
10.2k1637
answered 8 hours ago
Saketh MalyalaSaketh Malyala
10.2k1637
answered 8 hours ago
Saketh MalyalaSaketh Malyala
10.2k1637
10.2k1637
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3261547%2flogarithmic-rules-with-functions%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
3
$begingroup$
Of course, because the equality is true for any specific $x$.
$endgroup$
– Mark
8 hours ago
1
$begingroup$
@Mark : What you have said is meaningless. Can you elaborate?
$endgroup$
– MPW
8 hours ago
1
$begingroup$
Why is it meaningless? Put any constant $x$ and you will get an equality. Two functions are equal if they are equal at all points.
$endgroup$
– Mark
8 hours ago
2
$begingroup$
Okay, I guess I understand what you mean. Note that, unfortunately, OP has omitted any mention of $x$ on the RHS.
$endgroup$
– MPW
8 hours ago