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If the pressure inside and outside a balloon balance, then why does air leave when it pops?
Get an intuition for pressure valuesThe relation between Internal Pressure and flow rate in a balloonHow can a small volume of gas balance the pressure exerted by the whole atmosphere?The Balloon Model for Human VentilationWhy a balloon explodes by itself?Boyle's Law-$ PV= nRT.$ What equation should be used to find pressure if n is not constant, like in an elastic system?Atmospheric pressure changes on plastic bottle containing a liquidCan a balloon be inflated with electrons?Which balloon has the higher pressure and why?About a balloon in a balloon in a balloon in a balloon in a balloon
$begingroup$
Sorry for the primitive question but when we blow a plastic balloon and tie it, its volume stretches itself until its inner pressure equals to the atmospheric pressure.
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
pressure atmospheric-science surface-tension
edited 10 mins ago
knzhou
50.5k12140246
asked yesterday
panic attackpanic attack
1411
New contributor
panic attack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Sorry for the primitive question but when we blow a plastic balloon and tie it, its volume stretches itself until its inner pressure equals to the atmospheric pressure.
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
pressure atmospheric-science surface-tension
edited 10 mins ago
knzhou
50.5k12140246
asked yesterday
panic attackpanic attack
1411
New contributor
panic attack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
yesterday
$begingroup$
Surely you mean a rubber balloon, not a plastic one?
$endgroup$
– David Conrad
9 hours ago
add a comment |
$begingroup$
Sorry for the primitive question but when we blow a plastic balloon and tie it, its volume stretches itself until its inner pressure equals to the atmospheric pressure.
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
pressure atmospheric-science surface-tension
edited 10 mins ago
knzhou
50.5k12140246
asked yesterday
panic attackpanic attack
1411
New contributor
panic attack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Sorry for the primitive question but when we blow a plastic balloon and tie it, its volume stretches itself until its inner pressure equals to the atmospheric pressure.
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
pressure atmospheric-science surface-tension
pressure atmospheric-science surface-tension
edited 10 mins ago
knzhou
50.5k12140246
asked yesterday
panic attackpanic attack
1411
New contributor
panic attack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 10 mins ago
knzhou
50.5k12140246
asked yesterday
panic attackpanic attack
1411
New contributor
panic attack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 10 mins ago
knzhou
50.5k12140246
edited 10 mins ago
knzhou
50.5k12140246
edited 10 mins ago
knzhou
50.5k12140246
50.5k12140246
asked yesterday
panic attackpanic attack
1411
New contributor
panic attack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
panic attackpanic attack
1411
asked yesterday
panic attackpanic attack
1411
1411
New contributor
panic attack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
panic attack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
yesterday
$begingroup$
Surely you mean a rubber balloon, not a plastic one?
$endgroup$
– David Conrad
9 hours ago
add a comment |
$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
yesterday
$begingroup$
Surely you mean a rubber balloon, not a plastic one?
$endgroup$
– David Conrad
9 hours ago
$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
yesterday
$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
yesterday
$begingroup$
Surely you mean a rubber balloon, not a plastic one?
$endgroup$
– David Conrad
9 hours ago
$begingroup$
Surely you mean a rubber balloon, not a plastic one?
$endgroup$
– David Conrad
9 hours ago
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
For an inflated and tied balloon, the inner and outer pressures aren't equal. The inner pressure is higher by an amount $2 gamma |H|$, where $gamma$ is the inflated balloon's surface tension and $H$ is its mean curvature (which is $-1/R$ for a sphere). This is called the Young-Laplace equation.
After the balloon is untied and deflates, the pressures equalize and the surface tension becomes negligible.
answered yesterday
tparkertparker
24.8k151134
$endgroup$
2
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
yesterday
3
$begingroup$
@SolarMike Weird - almost every balloon I've ever seen has been pretty close to spherical.
$endgroup$
– tparker
16 hours ago
$begingroup$
well, the balloons I've blown up and all the ones I see at parties tend to have a pointy end were they get tied...
$endgroup$
– Solar Mike
16 hours ago
16
$begingroup$
They are certainly more spherical than any cow I've ever seen!
$endgroup$
– Cort Ammon
15 hours ago
1
$begingroup$
For non-spherical balloons, the relationship between the mean curvature and the dimensions is different, but the main idea remains.
$endgroup$
– dmckee♦
12 hours ago
add a comment |
$begingroup$
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
You need to take into account that the elastic tension of the balloon skin pulls inwards. This makes the pressure in the balloon greater than its surroundings. Since there is a pressure difference the air blows out when you penetrate the skin defeating the elastic tension of the balloon skin.
Think about what happens when you blow up a balloon. The more it expands the harder it is to blow it up. Clearly the outside pressure has not changed. The elastic tension of the balloon material has increased, like what happens when you stretch a rubber band more and more.
Hope this helps.
answered yesterday
Bob DBob D
7,7443626
$endgroup$
2
$begingroup$
Actually, most balloons I know are much harder to blow up while they are small, especially at the point when we go from just unwrinkoiing the skin to actually expanding it - but this effect is due to material properties of the rubber and not relevant to the qualitative effect.
$endgroup$
– Hagen von Eitzen
15 hours ago
$begingroup$
@HagenvonEitzen Yeah, sometimes the material sticks together at the beginning.
$endgroup$
– Bob D
7 hours ago
add a comment |
$begingroup$
Blowing into a balloon is harder than just blowing into the air, because it takes higher air pressure to stretch the rubber. once the balloon is tied the stretched rubber continues to squeeze the air inside, so inner air pressure stays higher than outer air pressure. Untie the balloon and the stretched rubber will squeeze the air out until it shrinks to its normal un-stretched size. Sticking the inflated balloon with a needle will create a flaw in the stretched rubber causing it to split open and release the inner air pressure very fast, pop.
answered yesterday
Adrian HowardAdrian Howard
866
New contributor
Adrian Howard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
The one thing you have not included is the tension force from the balloon membrane, that is what forces the air out.
answered yesterday
Solar MikeSolar Mike
26316
$endgroup$
1
$begingroup$
to be more understandable to non physicists I used stretched rubber squeezing, instead of surface tension of membrane
$endgroup$
– Adrian Howard
21 hours ago
$begingroup$
@AdrianHoward I kept my answer succinct as I don't have any reason for using 17 words when one will do...
$endgroup$
– Solar Mike
21 hours ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
For an inflated and tied balloon, the inner and outer pressures aren't equal. The inner pressure is higher by an amount $2 gamma |H|$, where $gamma$ is the inflated balloon's surface tension and $H$ is its mean curvature (which is $-1/R$ for a sphere). This is called the Young-Laplace equation.
After the balloon is untied and deflates, the pressures equalize and the surface tension becomes negligible.
answered yesterday
tparkertparker
24.8k151134
$endgroup$
2
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
yesterday
3
$begingroup$
@SolarMike Weird - almost every balloon I've ever seen has been pretty close to spherical.
$endgroup$
– tparker
16 hours ago
$begingroup$
well, the balloons I've blown up and all the ones I see at parties tend to have a pointy end were they get tied...
$endgroup$
– Solar Mike
16 hours ago
16
$begingroup$
They are certainly more spherical than any cow I've ever seen!
$endgroup$
– Cort Ammon
15 hours ago
1
$begingroup$
For non-spherical balloons, the relationship between the mean curvature and the dimensions is different, but the main idea remains.
$endgroup$
– dmckee♦
12 hours ago
add a comment |
$begingroup$
For an inflated and tied balloon, the inner and outer pressures aren't equal. The inner pressure is higher by an amount $2 gamma |H|$, where $gamma$ is the inflated balloon's surface tension and $H$ is its mean curvature (which is $-1/R$ for a sphere). This is called the Young-Laplace equation.
After the balloon is untied and deflates, the pressures equalize and the surface tension becomes negligible.
answered yesterday
tparkertparker
24.8k151134
$endgroup$
2
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
yesterday
3
$begingroup$
@SolarMike Weird - almost every balloon I've ever seen has been pretty close to spherical.
$endgroup$
– tparker
16 hours ago
$begingroup$
well, the balloons I've blown up and all the ones I see at parties tend to have a pointy end were they get tied...
$endgroup$
– Solar Mike
16 hours ago
16
$begingroup$
They are certainly more spherical than any cow I've ever seen!
$endgroup$
– Cort Ammon
15 hours ago
1
$begingroup$
For non-spherical balloons, the relationship between the mean curvature and the dimensions is different, but the main idea remains.
$endgroup$
– dmckee♦
12 hours ago
add a comment |
$begingroup$
For an inflated and tied balloon, the inner and outer pressures aren't equal. The inner pressure is higher by an amount $2 gamma |H|$, where $gamma$ is the inflated balloon's surface tension and $H$ is its mean curvature (which is $-1/R$ for a sphere). This is called the Young-Laplace equation.
After the balloon is untied and deflates, the pressures equalize and the surface tension becomes negligible.
answered yesterday
tparkertparker
24.8k151134
$endgroup$
For an inflated and tied balloon, the inner and outer pressures aren't equal. The inner pressure is higher by an amount $2 gamma |H|$, where $gamma$ is the inflated balloon's surface tension and $H$ is its mean curvature (which is $-1/R$ for a sphere). This is called the Young-Laplace equation.
After the balloon is untied and deflates, the pressures equalize and the surface tension becomes negligible.
answered yesterday
tparkertparker
24.8k151134
answered yesterday
tparkertparker
24.8k151134
answered yesterday
tparkertparker
24.8k151134
answered yesterday
tparkertparker
24.8k151134
24.8k151134
2
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
yesterday
3
$begingroup$
@SolarMike Weird - almost every balloon I've ever seen has been pretty close to spherical.
$endgroup$
– tparker
16 hours ago
$begingroup$
well, the balloons I've blown up and all the ones I see at parties tend to have a pointy end were they get tied...
$endgroup$
– Solar Mike
16 hours ago
16
$begingroup$
They are certainly more spherical than any cow I've ever seen!
$endgroup$
– Cort Ammon
15 hours ago
1
$begingroup$
For non-spherical balloons, the relationship between the mean curvature and the dimensions is different, but the main idea remains.
$endgroup$
– dmckee♦
12 hours ago
add a comment |
2
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
yesterday
3
$begingroup$
@SolarMike Weird - almost every balloon I've ever seen has been pretty close to spherical.
$endgroup$
– tparker
16 hours ago
$begingroup$
well, the balloons I've blown up and all the ones I see at parties tend to have a pointy end were they get tied...
$endgroup$
– Solar Mike
16 hours ago
16
$begingroup$
They are certainly more spherical than any cow I've ever seen!
$endgroup$
– Cort Ammon
15 hours ago
1
$begingroup$
For non-spherical balloons, the relationship between the mean curvature and the dimensions is different, but the main idea remains.
$endgroup$
– dmckee♦
12 hours ago
2
2
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
yesterday
$begingroup$
Not seen many balloons that are spherical...
$endgroup$
– Solar Mike
yesterday
3
3
$begingroup$
@SolarMike Weird - almost every balloon I've ever seen has been pretty close to spherical.
$endgroup$
– tparker
16 hours ago
$begingroup$
@SolarMike Weird - almost every balloon I've ever seen has been pretty close to spherical.
$endgroup$
– tparker
16 hours ago
$begingroup$
well, the balloons I've blown up and all the ones I see at parties tend to have a pointy end were they get tied...
$endgroup$
– Solar Mike
16 hours ago
$begingroup$
well, the balloons I've blown up and all the ones I see at parties tend to have a pointy end were they get tied...
$endgroup$
– Solar Mike
16 hours ago
16
16
$begingroup$
They are certainly more spherical than any cow I've ever seen!
$endgroup$
– Cort Ammon
15 hours ago
$begingroup$
They are certainly more spherical than any cow I've ever seen!
$endgroup$
– Cort Ammon
15 hours ago
1
1
$begingroup$
For non-spherical balloons, the relationship between the mean curvature and the dimensions is different, but the main idea remains.
$endgroup$
– dmckee♦
12 hours ago
$begingroup$
For non-spherical balloons, the relationship between the mean curvature and the dimensions is different, but the main idea remains.
$endgroup$
– dmckee♦
12 hours ago
add a comment |
$begingroup$
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
You need to take into account that the elastic tension of the balloon skin pulls inwards. This makes the pressure in the balloon greater than its surroundings. Since there is a pressure difference the air blows out when you penetrate the skin defeating the elastic tension of the balloon skin.
Think about what happens when you blow up a balloon. The more it expands the harder it is to blow it up. Clearly the outside pressure has not changed. The elastic tension of the balloon material has increased, like what happens when you stretch a rubber band more and more.
Hope this helps.
answered yesterday
Bob DBob D
7,7443626
$endgroup$
2
$begingroup$
Actually, most balloons I know are much harder to blow up while they are small, especially at the point when we go from just unwrinkoiing the skin to actually expanding it - but this effect is due to material properties of the rubber and not relevant to the qualitative effect.
$endgroup$
– Hagen von Eitzen
15 hours ago
$begingroup$
@HagenvonEitzen Yeah, sometimes the material sticks together at the beginning.
$endgroup$
– Bob D
7 hours ago
add a comment |
$begingroup$
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
You need to take into account that the elastic tension of the balloon skin pulls inwards. This makes the pressure in the balloon greater than its surroundings. Since there is a pressure difference the air blows out when you penetrate the skin defeating the elastic tension of the balloon skin.
Think about what happens when you blow up a balloon. The more it expands the harder it is to blow it up. Clearly the outside pressure has not changed. The elastic tension of the balloon material has increased, like what happens when you stretch a rubber band more and more.
Hope this helps.
answered yesterday
Bob DBob D
7,7443626
$endgroup$
2
$begingroup$
Actually, most balloons I know are much harder to blow up while they are small, especially at the point when we go from just unwrinkoiing the skin to actually expanding it - but this effect is due to material properties of the rubber and not relevant to the qualitative effect.
$endgroup$
– Hagen von Eitzen
15 hours ago
$begingroup$
@HagenvonEitzen Yeah, sometimes the material sticks together at the beginning.
$endgroup$
– Bob D
7 hours ago
add a comment |
$begingroup$
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
You need to take into account that the elastic tension of the balloon skin pulls inwards. This makes the pressure in the balloon greater than its surroundings. Since there is a pressure difference the air blows out when you penetrate the skin defeating the elastic tension of the balloon skin.
Think about what happens when you blow up a balloon. The more it expands the harder it is to blow it up. Clearly the outside pressure has not changed. The elastic tension of the balloon material has increased, like what happens when you stretch a rubber band more and more.
Hope this helps.
answered yesterday
Bob DBob D
7,7443626
$endgroup$
But after that equality is obtained why does the air goes out when we penetrate the balloon? If there is pressure equality what causes the air flow?
You need to take into account that the elastic tension of the balloon skin pulls inwards. This makes the pressure in the balloon greater than its surroundings. Since there is a pressure difference the air blows out when you penetrate the skin defeating the elastic tension of the balloon skin.
Think about what happens when you blow up a balloon. The more it expands the harder it is to blow it up. Clearly the outside pressure has not changed. The elastic tension of the balloon material has increased, like what happens when you stretch a rubber band more and more.
Hope this helps.
answered yesterday
Bob DBob D
7,7443626
edited 23 hours ago
answered yesterday
Bob DBob D
7,7443626
answered yesterday
Bob DBob D
7,7443626
answered yesterday
Bob DBob D
7,7443626
7,7443626
2
$begingroup$
Actually, most balloons I know are much harder to blow up while they are small, especially at the point when we go from just unwrinkoiing the skin to actually expanding it - but this effect is due to material properties of the rubber and not relevant to the qualitative effect.
$endgroup$
– Hagen von Eitzen
15 hours ago
$begingroup$
@HagenvonEitzen Yeah, sometimes the material sticks together at the beginning.
$endgroup$
– Bob D
7 hours ago
add a comment |
2
$begingroup$
Actually, most balloons I know are much harder to blow up while they are small, especially at the point when we go from just unwrinkoiing the skin to actually expanding it - but this effect is due to material properties of the rubber and not relevant to the qualitative effect.
$endgroup$
– Hagen von Eitzen
15 hours ago
$begingroup$
@HagenvonEitzen Yeah, sometimes the material sticks together at the beginning.
$endgroup$
– Bob D
7 hours ago
2
2
$begingroup$
Actually, most balloons I know are much harder to blow up while they are small, especially at the point when we go from just unwrinkoiing the skin to actually expanding it - but this effect is due to material properties of the rubber and not relevant to the qualitative effect.
$endgroup$
– Hagen von Eitzen
15 hours ago
$begingroup$
Actually, most balloons I know are much harder to blow up while they are small, especially at the point when we go from just unwrinkoiing the skin to actually expanding it - but this effect is due to material properties of the rubber and not relevant to the qualitative effect.
$endgroup$
– Hagen von Eitzen
15 hours ago
$begingroup$
@HagenvonEitzen Yeah, sometimes the material sticks together at the beginning.
$endgroup$
– Bob D
7 hours ago
$begingroup$
@HagenvonEitzen Yeah, sometimes the material sticks together at the beginning.
$endgroup$
– Bob D
7 hours ago
add a comment |
$begingroup$
Blowing into a balloon is harder than just blowing into the air, because it takes higher air pressure to stretch the rubber. once the balloon is tied the stretched rubber continues to squeeze the air inside, so inner air pressure stays higher than outer air pressure. Untie the balloon and the stretched rubber will squeeze the air out until it shrinks to its normal un-stretched size. Sticking the inflated balloon with a needle will create a flaw in the stretched rubber causing it to split open and release the inner air pressure very fast, pop.
answered yesterday
Adrian HowardAdrian Howard
866
New contributor
Adrian Howard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Blowing into a balloon is harder than just blowing into the air, because it takes higher air pressure to stretch the rubber. once the balloon is tied the stretched rubber continues to squeeze the air inside, so inner air pressure stays higher than outer air pressure. Untie the balloon and the stretched rubber will squeeze the air out until it shrinks to its normal un-stretched size. Sticking the inflated balloon with a needle will create a flaw in the stretched rubber causing it to split open and release the inner air pressure very fast, pop.
answered yesterday
Adrian HowardAdrian Howard
866
New contributor
Adrian Howard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Blowing into a balloon is harder than just blowing into the air, because it takes higher air pressure to stretch the rubber. once the balloon is tied the stretched rubber continues to squeeze the air inside, so inner air pressure stays higher than outer air pressure. Untie the balloon and the stretched rubber will squeeze the air out until it shrinks to its normal un-stretched size. Sticking the inflated balloon with a needle will create a flaw in the stretched rubber causing it to split open and release the inner air pressure very fast, pop.
answered yesterday
Adrian HowardAdrian Howard
866
New contributor
Adrian Howard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Blowing into a balloon is harder than just blowing into the air, because it takes higher air pressure to stretch the rubber. once the balloon is tied the stretched rubber continues to squeeze the air inside, so inner air pressure stays higher than outer air pressure. Untie the balloon and the stretched rubber will squeeze the air out until it shrinks to its normal un-stretched size. Sticking the inflated balloon with a needle will create a flaw in the stretched rubber causing it to split open and release the inner air pressure very fast, pop.
answered yesterday
Adrian HowardAdrian Howard
866
New contributor
Adrian Howard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
Adrian HowardAdrian Howard
866
New contributor
Adrian Howard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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answered yesterday
Adrian HowardAdrian Howard
866
answered yesterday
Adrian HowardAdrian Howard
866
866
New contributor
Adrian Howard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Adrian Howard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
$begingroup$
The one thing you have not included is the tension force from the balloon membrane, that is what forces the air out.
answered yesterday
Solar MikeSolar Mike
26316
$endgroup$
1
$begingroup$
to be more understandable to non physicists I used stretched rubber squeezing, instead of surface tension of membrane
$endgroup$
– Adrian Howard
21 hours ago
$begingroup$
@AdrianHoward I kept my answer succinct as I don't have any reason for using 17 words when one will do...
$endgroup$
– Solar Mike
21 hours ago
add a comment |
$begingroup$
The one thing you have not included is the tension force from the balloon membrane, that is what forces the air out.
answered yesterday
Solar MikeSolar Mike
26316
$endgroup$
1
$begingroup$
to be more understandable to non physicists I used stretched rubber squeezing, instead of surface tension of membrane
$endgroup$
– Adrian Howard
21 hours ago
$begingroup$
@AdrianHoward I kept my answer succinct as I don't have any reason for using 17 words when one will do...
$endgroup$
– Solar Mike
21 hours ago
add a comment |
$begingroup$
The one thing you have not included is the tension force from the balloon membrane, that is what forces the air out.
answered yesterday
Solar MikeSolar Mike
26316
$endgroup$
The one thing you have not included is the tension force from the balloon membrane, that is what forces the air out.
answered yesterday
Solar MikeSolar Mike
26316
answered yesterday
Solar MikeSolar Mike
26316
answered yesterday
Solar MikeSolar Mike
26316
answered yesterday
Solar MikeSolar Mike
26316
26316
1
$begingroup$
to be more understandable to non physicists I used stretched rubber squeezing, instead of surface tension of membrane
$endgroup$
– Adrian Howard
21 hours ago
$begingroup$
@AdrianHoward I kept my answer succinct as I don't have any reason for using 17 words when one will do...
$endgroup$
– Solar Mike
21 hours ago
add a comment |
1
$begingroup$
to be more understandable to non physicists I used stretched rubber squeezing, instead of surface tension of membrane
$endgroup$
– Adrian Howard
21 hours ago
$begingroup$
@AdrianHoward I kept my answer succinct as I don't have any reason for using 17 words when one will do...
$endgroup$
– Solar Mike
21 hours ago
1
1
$begingroup$
to be more understandable to non physicists I used stretched rubber squeezing, instead of surface tension of membrane
$endgroup$
– Adrian Howard
21 hours ago
$begingroup$
to be more understandable to non physicists I used stretched rubber squeezing, instead of surface tension of membrane
$endgroup$
– Adrian Howard
21 hours ago
$begingroup$
@AdrianHoward I kept my answer succinct as I don't have any reason for using 17 words when one will do...
$endgroup$
– Solar Mike
21 hours ago
$begingroup$
@AdrianHoward I kept my answer succinct as I don't have any reason for using 17 words when one will do...
$endgroup$
– Solar Mike
21 hours ago
add a comment |
panic attack is a new contributor. Be nice, and check out our Code of Conduct.
panic attack is a new contributor. Be nice, and check out our Code of Conduct.
panic attack is a new contributor. Be nice, and check out our Code of Conduct.
panic attack is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
The inner pressure does not equal the outer pressure. Rather, they are close enough that the difference can be ignored for most purposes (such as computing the buoyancy of the balloon).
$endgroup$
– Hot Licks
yesterday
$begingroup$
Surely you mean a rubber balloon, not a plastic one?
$endgroup$
– David Conrad
9 hours ago