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Representing an indicator function: binary variables and “indicator constraints”


When to use indicator constraints versus big-M approaches in solving (mixed-)integer programsDoes dispersion really matter?How to formulate this scheduling problem efficiently?How to reformulate (linearize/convexify) a budgeted assignment problem?Soft constraints and hard constraintsDifference between Chance constraints and logical constraintsThe rationale to improve MTZ?Static stochastic knapsack problem: unbounded versionFormulating a MINLP for CPLEX in PYOMOIs there a way to proportionalize fixed costs in a MILP?













10












$begingroup$


I want to represent the indicator function:
$$ mathbb1_(y=j)$$



where $y$ is a non negative, integer variable.



My attempt is as follows: define a binary variable:
$$ z_j =begincases
1 qquadtextif $y=j$ \
0 qquadtextotherwise
endcases $$



the model of the indicator function would be:



$$
sum_j=0^n z_j = 1
$$

$$
sum_j=0^n j cdot z_j = y
$$



where $n$ is an upper bound for $y$.



Actually, this can be conveniently modeled in OPL Cplex (for example) using indicator constraints such as follows:



forall(j in 0..n)
(y == j) == (z[j] == 1);



QUESTIONS:



  1. is my binary-variables-based formulation attempt correct? Do you know better (performance wise) formulations?

  2. in a hypothetical academic journal paper, is the second formulation (based on indicator constraints) acceptable? If yes, how would you formally express it in the paper in a way that is implementation-independent (that is, in a way that does not depend upon how a specific solver models such a constraint)? Or it is better to provide the more general, binary-variables-based formulation?

Thanks a lot.










share|improve this question









$endgroup$













  • $begingroup$
    This is correct, assuming $y in 0,dots,n$. More generally, if $y$ takes (not necessarily integer) values in a finite set $V$, impose $sum_j in V z_j=1$ and $sum_j in V j z_j=y$.
    $endgroup$
    – Rob Pratt
    8 hours ago






  • 1




    $begingroup$
    Something else to consider is to do a binary expansion of $y$, i.e., add the constraint $sum_j=0^m 2^j z_j=y$, where $2^m$ is an upper bound on $y$. Depending on the application you have in mind you might not be able to use this representation, but if you can I would imagine it's more efficient.
    $endgroup$
    – Ryan Cory-Wright
    7 hours ago










  • $begingroup$
    Note that you will need to linearize a product of binary variables to recover the indicator function for a fixed $j$. This can be achieved via $y <= z_i, forall i, y>=sum_i z_i - (n-1)$.
    $endgroup$
    – Ryan Cory-Wright
    7 hours ago















10












$begingroup$


I want to represent the indicator function:
$$ mathbb1_(y=j)$$



where $y$ is a non negative, integer variable.



My attempt is as follows: define a binary variable:
$$ z_j =begincases
1 qquadtextif $y=j$ \
0 qquadtextotherwise
endcases $$



the model of the indicator function would be:



$$
sum_j=0^n z_j = 1
$$

$$
sum_j=0^n j cdot z_j = y
$$



where $n$ is an upper bound for $y$.



Actually, this can be conveniently modeled in OPL Cplex (for example) using indicator constraints such as follows:



forall(j in 0..n)
(y == j) == (z[j] == 1);



QUESTIONS:



  1. is my binary-variables-based formulation attempt correct? Do you know better (performance wise) formulations?

  2. in a hypothetical academic journal paper, is the second formulation (based on indicator constraints) acceptable? If yes, how would you formally express it in the paper in a way that is implementation-independent (that is, in a way that does not depend upon how a specific solver models such a constraint)? Or it is better to provide the more general, binary-variables-based formulation?

Thanks a lot.










share|improve this question









$endgroup$













  • $begingroup$
    This is correct, assuming $y in 0,dots,n$. More generally, if $y$ takes (not necessarily integer) values in a finite set $V$, impose $sum_j in V z_j=1$ and $sum_j in V j z_j=y$.
    $endgroup$
    – Rob Pratt
    8 hours ago






  • 1




    $begingroup$
    Something else to consider is to do a binary expansion of $y$, i.e., add the constraint $sum_j=0^m 2^j z_j=y$, where $2^m$ is an upper bound on $y$. Depending on the application you have in mind you might not be able to use this representation, but if you can I would imagine it's more efficient.
    $endgroup$
    – Ryan Cory-Wright
    7 hours ago










  • $begingroup$
    Note that you will need to linearize a product of binary variables to recover the indicator function for a fixed $j$. This can be achieved via $y <= z_i, forall i, y>=sum_i z_i - (n-1)$.
    $endgroup$
    – Ryan Cory-Wright
    7 hours ago













10












10








10





$begingroup$


I want to represent the indicator function:
$$ mathbb1_(y=j)$$



where $y$ is a non negative, integer variable.



My attempt is as follows: define a binary variable:
$$ z_j =begincases
1 qquadtextif $y=j$ \
0 qquadtextotherwise
endcases $$



the model of the indicator function would be:



$$
sum_j=0^n z_j = 1
$$

$$
sum_j=0^n j cdot z_j = y
$$



where $n$ is an upper bound for $y$.



Actually, this can be conveniently modeled in OPL Cplex (for example) using indicator constraints such as follows:



forall(j in 0..n)
(y == j) == (z[j] == 1);



QUESTIONS:



  1. is my binary-variables-based formulation attempt correct? Do you know better (performance wise) formulations?

  2. in a hypothetical academic journal paper, is the second formulation (based on indicator constraints) acceptable? If yes, how would you formally express it in the paper in a way that is implementation-independent (that is, in a way that does not depend upon how a specific solver models such a constraint)? Or it is better to provide the more general, binary-variables-based formulation?

Thanks a lot.










share|improve this question









$endgroup$




I want to represent the indicator function:
$$ mathbb1_(y=j)$$



where $y$ is a non negative, integer variable.



My attempt is as follows: define a binary variable:
$$ z_j =begincases
1 qquadtextif $y=j$ \
0 qquadtextotherwise
endcases $$



the model of the indicator function would be:



$$
sum_j=0^n z_j = 1
$$

$$
sum_j=0^n j cdot z_j = y
$$



where $n$ is an upper bound for $y$.



Actually, this can be conveniently modeled in OPL Cplex (for example) using indicator constraints such as follows:



forall(j in 0..n)
(y == j) == (z[j] == 1);



QUESTIONS:



  1. is my binary-variables-based formulation attempt correct? Do you know better (performance wise) formulations?

  2. in a hypothetical academic journal paper, is the second formulation (based on indicator constraints) acceptable? If yes, how would you formally express it in the paper in a way that is implementation-independent (that is, in a way that does not depend upon how a specific solver models such a constraint)? Or it is better to provide the more general, binary-variables-based formulation?

Thanks a lot.







modeling cplex academic binary-variable indicator-constraints






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 9 hours ago









LibraLibra

3061 silver badge8 bronze badges




3061 silver badge8 bronze badges














  • $begingroup$
    This is correct, assuming $y in 0,dots,n$. More generally, if $y$ takes (not necessarily integer) values in a finite set $V$, impose $sum_j in V z_j=1$ and $sum_j in V j z_j=y$.
    $endgroup$
    – Rob Pratt
    8 hours ago






  • 1




    $begingroup$
    Something else to consider is to do a binary expansion of $y$, i.e., add the constraint $sum_j=0^m 2^j z_j=y$, where $2^m$ is an upper bound on $y$. Depending on the application you have in mind you might not be able to use this representation, but if you can I would imagine it's more efficient.
    $endgroup$
    – Ryan Cory-Wright
    7 hours ago










  • $begingroup$
    Note that you will need to linearize a product of binary variables to recover the indicator function for a fixed $j$. This can be achieved via $y <= z_i, forall i, y>=sum_i z_i - (n-1)$.
    $endgroup$
    – Ryan Cory-Wright
    7 hours ago
















  • $begingroup$
    This is correct, assuming $y in 0,dots,n$. More generally, if $y$ takes (not necessarily integer) values in a finite set $V$, impose $sum_j in V z_j=1$ and $sum_j in V j z_j=y$.
    $endgroup$
    – Rob Pratt
    8 hours ago






  • 1




    $begingroup$
    Something else to consider is to do a binary expansion of $y$, i.e., add the constraint $sum_j=0^m 2^j z_j=y$, where $2^m$ is an upper bound on $y$. Depending on the application you have in mind you might not be able to use this representation, but if you can I would imagine it's more efficient.
    $endgroup$
    – Ryan Cory-Wright
    7 hours ago










  • $begingroup$
    Note that you will need to linearize a product of binary variables to recover the indicator function for a fixed $j$. This can be achieved via $y <= z_i, forall i, y>=sum_i z_i - (n-1)$.
    $endgroup$
    – Ryan Cory-Wright
    7 hours ago















$begingroup$
This is correct, assuming $y in 0,dots,n$. More generally, if $y$ takes (not necessarily integer) values in a finite set $V$, impose $sum_j in V z_j=1$ and $sum_j in V j z_j=y$.
$endgroup$
– Rob Pratt
8 hours ago




$begingroup$
This is correct, assuming $y in 0,dots,n$. More generally, if $y$ takes (not necessarily integer) values in a finite set $V$, impose $sum_j in V z_j=1$ and $sum_j in V j z_j=y$.
$endgroup$
– Rob Pratt
8 hours ago




1




1




$begingroup$
Something else to consider is to do a binary expansion of $y$, i.e., add the constraint $sum_j=0^m 2^j z_j=y$, where $2^m$ is an upper bound on $y$. Depending on the application you have in mind you might not be able to use this representation, but if you can I would imagine it's more efficient.
$endgroup$
– Ryan Cory-Wright
7 hours ago




$begingroup$
Something else to consider is to do a binary expansion of $y$, i.e., add the constraint $sum_j=0^m 2^j z_j=y$, where $2^m$ is an upper bound on $y$. Depending on the application you have in mind you might not be able to use this representation, but if you can I would imagine it's more efficient.
$endgroup$
– Ryan Cory-Wright
7 hours ago












$begingroup$
Note that you will need to linearize a product of binary variables to recover the indicator function for a fixed $j$. This can be achieved via $y <= z_i, forall i, y>=sum_i z_i - (n-1)$.
$endgroup$
– Ryan Cory-Wright
7 hours ago




$begingroup$
Note that you will need to linearize a product of binary variables to recover the indicator function for a fixed $j$. This can be achieved via $y <= z_i, forall i, y>=sum_i z_i - (n-1)$.
$endgroup$
– Ryan Cory-Wright
7 hours ago










1 Answer
1






active

oldest

votes


















6












$begingroup$

First question: Yes, your algebraic formulation is correct.



Second question: I would lean toward using the algebraic formulation, for two reasons. First, it is not solver-specific. Second, a reader not familiar with indicator constraints will find interpreting the algebraic formulation a bit easier, while a reader familiar with indicators is not likely to find the algebraic formulation much harder. That said, it would not hurt to mention in the paper that the constraint can be implemented by indicators in a solver that supports them (or, if your computational results were produced using CPLEX and you used indicators, just say that in the section describing the experiments).






share|improve this answer









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    1 Answer
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    active

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    6












    $begingroup$

    First question: Yes, your algebraic formulation is correct.



    Second question: I would lean toward using the algebraic formulation, for two reasons. First, it is not solver-specific. Second, a reader not familiar with indicator constraints will find interpreting the algebraic formulation a bit easier, while a reader familiar with indicators is not likely to find the algebraic formulation much harder. That said, it would not hurt to mention in the paper that the constraint can be implemented by indicators in a solver that supports them (or, if your computational results were produced using CPLEX and you used indicators, just say that in the section describing the experiments).






    share|improve this answer









    $endgroup$



















      6












      $begingroup$

      First question: Yes, your algebraic formulation is correct.



      Second question: I would lean toward using the algebraic formulation, for two reasons. First, it is not solver-specific. Second, a reader not familiar with indicator constraints will find interpreting the algebraic formulation a bit easier, while a reader familiar with indicators is not likely to find the algebraic formulation much harder. That said, it would not hurt to mention in the paper that the constraint can be implemented by indicators in a solver that supports them (or, if your computational results were produced using CPLEX and you used indicators, just say that in the section describing the experiments).






      share|improve this answer









      $endgroup$

















        6












        6








        6





        $begingroup$

        First question: Yes, your algebraic formulation is correct.



        Second question: I would lean toward using the algebraic formulation, for two reasons. First, it is not solver-specific. Second, a reader not familiar with indicator constraints will find interpreting the algebraic formulation a bit easier, while a reader familiar with indicators is not likely to find the algebraic formulation much harder. That said, it would not hurt to mention in the paper that the constraint can be implemented by indicators in a solver that supports them (or, if your computational results were produced using CPLEX and you used indicators, just say that in the section describing the experiments).






        share|improve this answer









        $endgroup$



        First question: Yes, your algebraic formulation is correct.



        Second question: I would lean toward using the algebraic formulation, for two reasons. First, it is not solver-specific. Second, a reader not familiar with indicator constraints will find interpreting the algebraic formulation a bit easier, while a reader familiar with indicators is not likely to find the algebraic formulation much harder. That said, it would not hurt to mention in the paper that the constraint can be implemented by indicators in a solver that supports them (or, if your computational results were produced using CPLEX and you used indicators, just say that in the section describing the experiments).







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 8 hours ago









        prubinprubin

        3,2615 silver badges24 bronze badges




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