Colliding particles and Activation energyHow much activation energy is required to combust propane?Activation Energy of a rotting appleIs activation energy temperature-independent?Is activation energy related to reactivity?Relation between activation energy and temperature sensitivityCalculate activation energy of intermolecular displacement on a nano particleIs the kinetic energy turning into activation energy when the reaction takes place?What's the actual or official definition of activation energy?Energy of activation vs Bond energyDoes activation energy depend on steric factors?
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Colliding particles and Activation energy
How much activation energy is required to combust propane?Activation Energy of a rotting appleIs activation energy temperature-independent?Is activation energy related to reactivity?Relation between activation energy and temperature sensitivityCalculate activation energy of intermolecular displacement on a nano particleIs the kinetic energy turning into activation energy when the reaction takes place?What's the actual or official definition of activation energy?Energy of activation vs Bond energyDoes activation energy depend on steric factors?
$begingroup$
If two particles collide and they are under activation energy, why do they JUST “bounce apart”? Isn’t the activation energy steadily decreasing if those particles continuously collide?
I always viewed the activation energy as a "barrier" that prevents collisions from producing a reaction, if sufficient energy is not met. I thought that if particles collide and they do not have enough energy to cause a reaction, the "barrier" gets weakened. Therefore, I found it surprising that this "barrier" doesn't get weakened, and the activation energy isn't reduced.
equilibrium energy
asked 2 hours ago
minori minusminori minus
111
New contributor
minori minus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
If two particles collide and they are under activation energy, why do they JUST “bounce apart”? Isn’t the activation energy steadily decreasing if those particles continuously collide?
I always viewed the activation energy as a "barrier" that prevents collisions from producing a reaction, if sufficient energy is not met. I thought that if particles collide and they do not have enough energy to cause a reaction, the "barrier" gets weakened. Therefore, I found it surprising that this "barrier" doesn't get weakened, and the activation energy isn't reduced.
equilibrium energy
asked 2 hours ago
minori minusminori minus
111
New contributor
minori minus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
2
$begingroup$
Atoms and molecules obviously don't wear out. Not in a minute, or a year, or a million years. If there's no reaction, they stay exactly the same.
$endgroup$
– Karl
55 mins ago
1
$begingroup$
Reactants have to jump over the barrier, not bulldoze through it. Think high jump rather than American football.
$endgroup$
– Karsten Theis
54 mins ago
add a comment |
$begingroup$
If two particles collide and they are under activation energy, why do they JUST “bounce apart”? Isn’t the activation energy steadily decreasing if those particles continuously collide?
I always viewed the activation energy as a "barrier" that prevents collisions from producing a reaction, if sufficient energy is not met. I thought that if particles collide and they do not have enough energy to cause a reaction, the "barrier" gets weakened. Therefore, I found it surprising that this "barrier" doesn't get weakened, and the activation energy isn't reduced.
equilibrium energy
asked 2 hours ago
minori minusminori minus
111
New contributor
minori minus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
If two particles collide and they are under activation energy, why do they JUST “bounce apart”? Isn’t the activation energy steadily decreasing if those particles continuously collide?
I always viewed the activation energy as a "barrier" that prevents collisions from producing a reaction, if sufficient energy is not met. I thought that if particles collide and they do not have enough energy to cause a reaction, the "barrier" gets weakened. Therefore, I found it surprising that this "barrier" doesn't get weakened, and the activation energy isn't reduced.
equilibrium energy
equilibrium energy
asked 2 hours ago
minori minusminori minus
111
New contributor
minori minus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
minori minusminori minus
111
New contributor
minori minus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
minori minusminori minus
111
New contributor
minori minus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
minori minusminori minus
111
asked 2 hours ago
minori minusminori minus
111
111
New contributor
minori minus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
minori minus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
minori minus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
$begingroup$
Atoms and molecules obviously don't wear out. Not in a minute, or a year, or a million years. If there's no reaction, they stay exactly the same.
$endgroup$
– Karl
55 mins ago
1
$begingroup$
Reactants have to jump over the barrier, not bulldoze through it. Think high jump rather than American football.
$endgroup$
– Karsten Theis
54 mins ago
add a comment |
2
$begingroup$
Atoms and molecules obviously don't wear out. Not in a minute, or a year, or a million years. If there's no reaction, they stay exactly the same.
$endgroup$
– Karl
55 mins ago
1
$begingroup$
Reactants have to jump over the barrier, not bulldoze through it. Think high jump rather than American football.
$endgroup$
– Karsten Theis
54 mins ago
2
2
$begingroup$
Atoms and molecules obviously don't wear out. Not in a minute, or a year, or a million years. If there's no reaction, they stay exactly the same.
$endgroup$
– Karl
55 mins ago
$begingroup$
Atoms and molecules obviously don't wear out. Not in a minute, or a year, or a million years. If there's no reaction, they stay exactly the same.
$endgroup$
– Karl
55 mins ago
1
1
$begingroup$
Reactants have to jump over the barrier, not bulldoze through it. Think high jump rather than American football.
$endgroup$
– Karsten Theis
54 mins ago
$begingroup$
Reactants have to jump over the barrier, not bulldoze through it. Think high jump rather than American football.
$endgroup$
– Karsten Theis
54 mins ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
This is the nature of the quantum world. An action, at some level, either takes place or does not... there is no half-way state. Another example is the photoelectric effect. Planck and Einstein explained the requirement for at least a minimum energy of a photon before it can raise an electron to a higher energy level. A million photons just under that energy will not* raise an electron to a higher level, but just a single photon of the required energy (or higher) can bump up the electron.
Caveat: There is also the uncertainty principle, allowing electrons to tunnel to a higher level, or for multi-photon absorption to cause ionization, but they're not as common as single-photon absorption and ionization.
If you're bothered by this non-intuitive behavior, you're not alone. Bohr, Bose, Boltzmann, Einstein, and others were forced to this theory through experimental results and the horrors of the ultraviolet catastrophe. Those who fail to appreciate the ultraviolet catastrophe shall be made, energetically, to walk the Planck.
answered 1 hour ago
DrMoishe PippikDrMoishe Pippik
14.8k1231
$endgroup$
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1 Answer
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oldest
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1 Answer
1
active
oldest
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active
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active
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votes
$begingroup$
This is the nature of the quantum world. An action, at some level, either takes place or does not... there is no half-way state. Another example is the photoelectric effect. Planck and Einstein explained the requirement for at least a minimum energy of a photon before it can raise an electron to a higher energy level. A million photons just under that energy will not* raise an electron to a higher level, but just a single photon of the required energy (or higher) can bump up the electron.
Caveat: There is also the uncertainty principle, allowing electrons to tunnel to a higher level, or for multi-photon absorption to cause ionization, but they're not as common as single-photon absorption and ionization.
If you're bothered by this non-intuitive behavior, you're not alone. Bohr, Bose, Boltzmann, Einstein, and others were forced to this theory through experimental results and the horrors of the ultraviolet catastrophe. Those who fail to appreciate the ultraviolet catastrophe shall be made, energetically, to walk the Planck.
answered 1 hour ago
DrMoishe PippikDrMoishe Pippik
14.8k1231
$endgroup$
add a comment |
$begingroup$
This is the nature of the quantum world. An action, at some level, either takes place or does not... there is no half-way state. Another example is the photoelectric effect. Planck and Einstein explained the requirement for at least a minimum energy of a photon before it can raise an electron to a higher energy level. A million photons just under that energy will not* raise an electron to a higher level, but just a single photon of the required energy (or higher) can bump up the electron.
Caveat: There is also the uncertainty principle, allowing electrons to tunnel to a higher level, or for multi-photon absorption to cause ionization, but they're not as common as single-photon absorption and ionization.
If you're bothered by this non-intuitive behavior, you're not alone. Bohr, Bose, Boltzmann, Einstein, and others were forced to this theory through experimental results and the horrors of the ultraviolet catastrophe. Those who fail to appreciate the ultraviolet catastrophe shall be made, energetically, to walk the Planck.
answered 1 hour ago
DrMoishe PippikDrMoishe Pippik
14.8k1231
$endgroup$
add a comment |
$begingroup$
This is the nature of the quantum world. An action, at some level, either takes place or does not... there is no half-way state. Another example is the photoelectric effect. Planck and Einstein explained the requirement for at least a minimum energy of a photon before it can raise an electron to a higher energy level. A million photons just under that energy will not* raise an electron to a higher level, but just a single photon of the required energy (or higher) can bump up the electron.
Caveat: There is also the uncertainty principle, allowing electrons to tunnel to a higher level, or for multi-photon absorption to cause ionization, but they're not as common as single-photon absorption and ionization.
If you're bothered by this non-intuitive behavior, you're not alone. Bohr, Bose, Boltzmann, Einstein, and others were forced to this theory through experimental results and the horrors of the ultraviolet catastrophe. Those who fail to appreciate the ultraviolet catastrophe shall be made, energetically, to walk the Planck.
answered 1 hour ago
DrMoishe PippikDrMoishe Pippik
14.8k1231
$endgroup$
This is the nature of the quantum world. An action, at some level, either takes place or does not... there is no half-way state. Another example is the photoelectric effect. Planck and Einstein explained the requirement for at least a minimum energy of a photon before it can raise an electron to a higher energy level. A million photons just under that energy will not* raise an electron to a higher level, but just a single photon of the required energy (or higher) can bump up the electron.
Caveat: There is also the uncertainty principle, allowing electrons to tunnel to a higher level, or for multi-photon absorption to cause ionization, but they're not as common as single-photon absorption and ionization.
If you're bothered by this non-intuitive behavior, you're not alone. Bohr, Bose, Boltzmann, Einstein, and others were forced to this theory through experimental results and the horrors of the ultraviolet catastrophe. Those who fail to appreciate the ultraviolet catastrophe shall be made, energetically, to walk the Planck.
answered 1 hour ago
DrMoishe PippikDrMoishe Pippik
14.8k1231
answered 1 hour ago
DrMoishe PippikDrMoishe Pippik
14.8k1231
answered 1 hour ago
DrMoishe PippikDrMoishe Pippik
14.8k1231
answered 1 hour ago
DrMoishe PippikDrMoishe Pippik
14.8k1231
14.8k1231
add a comment |
add a comment |
minori minus is a new contributor. Be nice, and check out our Code of Conduct.
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2
$begingroup$
Atoms and molecules obviously don't wear out. Not in a minute, or a year, or a million years. If there's no reaction, they stay exactly the same.
$endgroup$
– Karl
55 mins ago
1
$begingroup$
Reactants have to jump over the barrier, not bulldoze through it. Think high jump rather than American football.
$endgroup$
– Karsten Theis
54 mins ago