Alternatives to achieve certain output formatDynamically format labels/columns of a LaTeX table generated in R/knitr/xtableHow can I format this in lyx?Array stretch only for certain rowsUsing nearrow and searrow to separate an equation in two alternativesSwap two array elementsarray: set width for certain columnsPlacing the middle of a predefined picture at a certain node

Alternatives to achieve certain output format

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Alternatives to achieve certain output format


Dynamically format labels/columns of a LaTeX table generated in R/knitr/xtableHow can I format this in lyx?Array stretch only for certain rowsUsing nearrow and searrow to separate an equation in two alternativesSwap two array elementsarray: set width for certain columnsPlacing the middle of a predefined picture at a certain node













4















Consider the following MWE



documentclass[border=10 pt]standalone
usepackagemathtools,setspace

begindocument
$displaystyle
setstretch1.5
beginarrayccccccccccccccccccccccc
^12 mathrmC&+&^1 mathrmH &longrightarrow& ^13mathrmN&+&gamma\
&&&&^13 mathrmN& longrightarrow&^13 mathrmC&+&e^+&+&nu\
&&&&&&^13 mathrmC&+&^mathrml mathrmH& longrightarrow&^14 mathrmN&+&gamma\
&&&&&&&&&&^14 mathrmN&+&^mathrml mathrmH& longrightarrow&^15 mathrmO&+&gamma\
&&&&&&&&&&&&&&^15 mathrmO& longrightarrow&^15 mathrmN&+&e^+&+&nu\
&&&&&&&&&&&&&&&&^15 mathrmN&+&^1 mathrmH &longrightarrow&^12 mathrmC&+&^4 mathrmHe
endarray
$
enddocument


with the output
enter image description here
The output is pretty much what I'm looking for, but the way I get it seems rather clunky to me... Is there a better way to get the same output? The only relevant part here is that the same elements in each reaction need to be below each other... The spacing of the other parts doesn't have to be the same as in the picture..










share|improve this question


























    4















    Consider the following MWE



    documentclass[border=10 pt]standalone
    usepackagemathtools,setspace

    begindocument
    $displaystyle
    setstretch1.5
    beginarrayccccccccccccccccccccccc
    ^12 mathrmC&+&^1 mathrmH &longrightarrow& ^13mathrmN&+&gamma\
    &&&&^13 mathrmN& longrightarrow&^13 mathrmC&+&e^+&+&nu\
    &&&&&&^13 mathrmC&+&^mathrml mathrmH& longrightarrow&^14 mathrmN&+&gamma\
    &&&&&&&&&&^14 mathrmN&+&^mathrml mathrmH& longrightarrow&^15 mathrmO&+&gamma\
    &&&&&&&&&&&&&&^15 mathrmO& longrightarrow&^15 mathrmN&+&e^+&+&nu\
    &&&&&&&&&&&&&&&&^15 mathrmN&+&^1 mathrmH &longrightarrow&^12 mathrmC&+&^4 mathrmHe
    endarray
    $
    enddocument


    with the output
    enter image description here
    The output is pretty much what I'm looking for, but the way I get it seems rather clunky to me... Is there a better way to get the same output? The only relevant part here is that the same elements in each reaction need to be below each other... The spacing of the other parts doesn't have to be the same as in the picture..










    share|improve this question
























      4












      4








      4








      Consider the following MWE



      documentclass[border=10 pt]standalone
      usepackagemathtools,setspace

      begindocument
      $displaystyle
      setstretch1.5
      beginarrayccccccccccccccccccccccc
      ^12 mathrmC&+&^1 mathrmH &longrightarrow& ^13mathrmN&+&gamma\
      &&&&^13 mathrmN& longrightarrow&^13 mathrmC&+&e^+&+&nu\
      &&&&&&^13 mathrmC&+&^mathrml mathrmH& longrightarrow&^14 mathrmN&+&gamma\
      &&&&&&&&&&^14 mathrmN&+&^mathrml mathrmH& longrightarrow&^15 mathrmO&+&gamma\
      &&&&&&&&&&&&&&^15 mathrmO& longrightarrow&^15 mathrmN&+&e^+&+&nu\
      &&&&&&&&&&&&&&&&^15 mathrmN&+&^1 mathrmH &longrightarrow&^12 mathrmC&+&^4 mathrmHe
      endarray
      $
      enddocument


      with the output
      enter image description here
      The output is pretty much what I'm looking for, but the way I get it seems rather clunky to me... Is there a better way to get the same output? The only relevant part here is that the same elements in each reaction need to be below each other... The spacing of the other parts doesn't have to be the same as in the picture..










      share|improve this question














      Consider the following MWE



      documentclass[border=10 pt]standalone
      usepackagemathtools,setspace

      begindocument
      $displaystyle
      setstretch1.5
      beginarrayccccccccccccccccccccccc
      ^12 mathrmC&+&^1 mathrmH &longrightarrow& ^13mathrmN&+&gamma\
      &&&&^13 mathrmN& longrightarrow&^13 mathrmC&+&e^+&+&nu\
      &&&&&&^13 mathrmC&+&^mathrml mathrmH& longrightarrow&^14 mathrmN&+&gamma\
      &&&&&&&&&&^14 mathrmN&+&^mathrml mathrmH& longrightarrow&^15 mathrmO&+&gamma\
      &&&&&&&&&&&&&&^15 mathrmO& longrightarrow&^15 mathrmN&+&e^+&+&nu\
      &&&&&&&&&&&&&&&&^15 mathrmN&+&^1 mathrmH &longrightarrow&^12 mathrmC&+&^4 mathrmHe
      endarray
      $
      enddocument


      with the output
      enter image description here
      The output is pretty much what I'm looking for, but the way I get it seems rather clunky to me... Is there a better way to get the same output? The only relevant part here is that the same elements in each reaction need to be below each other... The spacing of the other parts doesn't have to be the same as in the picture..







      arrays chemistry






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 9 hours ago









      SitoSito

      3241212




      3241212




















          3 Answers
          3






          active

          oldest

          votes


















          3














          It's a matter of opinion whether this is less clunky...it eliminates all & tab characters, but requires multiple stackunders and some bracing.



          The appearance is a bit different, however "the same elements of each reaction are below each other", as requested by the OP. While there are no other alignments that apply one may observe that the spacing on any given line is "correct".



          documentclass[border=10 pt]standalone
          usepackagemathtools,setspace,stackengine
          begindocument
          renewcommandstackalignmentl
          renewcommandstacktypeL
          setstackgapL1.4baselineskip
          stackMath
          $displaystyle
          ^12mathrmC+^1mathrmHlongrightarrow stackunder^13mathrmN+gamma
          ^13mathrmNlongrightarrow stackunder^13mathrmC+e^++nu
          ^13mathrmC+^mathrmlmathrmHlongrightarrow stackunder^14mathrmN+gamma
          ^14mathrmN+^mathrmlmathrmHlongrightarrow stackunder^15mathrmO+gamma
          ^15mathrmOlongrightarrow stackunder^15mathrmN+e^++nu
          ^15mathrmN+^1mathrmHlongrightarrow ^12mathrmC+^4mathrmHe

          $
          enddocument


          enter image description here






          share|improve this answer






























            2














            I suggest to align your entries like the way I did (using Tab) to make it easier to read and modify if needed.
            I have used newcommand to create a way for you to enter the data of a row and every cell in the array is encapsulated by mathrm....
            Also, I changed the 23 cs you had in the array to *23c.



            Output



            documentclass[border=10 pt]standalone
            usepackagemathtools,setspace
            % Usage:
            % dataoperand-1operator-1operand-2operator-2operand-3operator-3operand-4
            % Simple example:
            % dataa+b-c*d
            newcommanddata[7]%
            ensuremath%
            mathrm#1 & mathrm#2 & mathrm#3 & mathrm#4 & mathrm#5 & mathrm#6 & mathrm#7
            %
            %
            begindocument
            $displaystyle
            setstretch1.5
            beginarray*23c
            data^12 C+ ^1 H longrightarrow ^13 N +gamma \
            &&&& data^13 Nlongrightarrow ^13 C + e^+ +nu \
            &&&&&& data^13 C+ ^1 H longrightarrow ^14 N +gamma \
            &&&&&&&&&& data^14 N+ ^1 H longrightarrow ^15 O +gamma \
            &&&&&&&&&&&&&& data^15 Olongrightarrow ^15 N + e^+ +nu \
            &&&&&&&&&&&&&&&& data^15 N+ ^1 H longrightarrow ^12 C +^4 He\
            endarray
            $
            enddocument





            share|improve this answer
































              0














              Enough simple?



              documentclassreport
              usepackagemhchem,parskip
              defaphantomce^12C + ^1H ->
              defbphantomce^13N ->
              begindocument
              ce^12C + ^1H -> ^13N + gammapar
              ace^13N -> ^13C + $e^+$ + nupar
              abce^13C + ^1H -> ^14N + gamma
              enddocument



              mwe







              share|improve this answer























                Your Answer








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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                3














                It's a matter of opinion whether this is less clunky...it eliminates all & tab characters, but requires multiple stackunders and some bracing.



                The appearance is a bit different, however "the same elements of each reaction are below each other", as requested by the OP. While there are no other alignments that apply one may observe that the spacing on any given line is "correct".



                documentclass[border=10 pt]standalone
                usepackagemathtools,setspace,stackengine
                begindocument
                renewcommandstackalignmentl
                renewcommandstacktypeL
                setstackgapL1.4baselineskip
                stackMath
                $displaystyle
                ^12mathrmC+^1mathrmHlongrightarrow stackunder^13mathrmN+gamma
                ^13mathrmNlongrightarrow stackunder^13mathrmC+e^++nu
                ^13mathrmC+^mathrmlmathrmHlongrightarrow stackunder^14mathrmN+gamma
                ^14mathrmN+^mathrmlmathrmHlongrightarrow stackunder^15mathrmO+gamma
                ^15mathrmOlongrightarrow stackunder^15mathrmN+e^++nu
                ^15mathrmN+^1mathrmHlongrightarrow ^12mathrmC+^4mathrmHe

                $
                enddocument


                enter image description here






                share|improve this answer



























                  3














                  It's a matter of opinion whether this is less clunky...it eliminates all & tab characters, but requires multiple stackunders and some bracing.



                  The appearance is a bit different, however "the same elements of each reaction are below each other", as requested by the OP. While there are no other alignments that apply one may observe that the spacing on any given line is "correct".



                  documentclass[border=10 pt]standalone
                  usepackagemathtools,setspace,stackengine
                  begindocument
                  renewcommandstackalignmentl
                  renewcommandstacktypeL
                  setstackgapL1.4baselineskip
                  stackMath
                  $displaystyle
                  ^12mathrmC+^1mathrmHlongrightarrow stackunder^13mathrmN+gamma
                  ^13mathrmNlongrightarrow stackunder^13mathrmC+e^++nu
                  ^13mathrmC+^mathrmlmathrmHlongrightarrow stackunder^14mathrmN+gamma
                  ^14mathrmN+^mathrmlmathrmHlongrightarrow stackunder^15mathrmO+gamma
                  ^15mathrmOlongrightarrow stackunder^15mathrmN+e^++nu
                  ^15mathrmN+^1mathrmHlongrightarrow ^12mathrmC+^4mathrmHe

                  $
                  enddocument


                  enter image description here






                  share|improve this answer

























                    3












                    3








                    3







                    It's a matter of opinion whether this is less clunky...it eliminates all & tab characters, but requires multiple stackunders and some bracing.



                    The appearance is a bit different, however "the same elements of each reaction are below each other", as requested by the OP. While there are no other alignments that apply one may observe that the spacing on any given line is "correct".



                    documentclass[border=10 pt]standalone
                    usepackagemathtools,setspace,stackengine
                    begindocument
                    renewcommandstackalignmentl
                    renewcommandstacktypeL
                    setstackgapL1.4baselineskip
                    stackMath
                    $displaystyle
                    ^12mathrmC+^1mathrmHlongrightarrow stackunder^13mathrmN+gamma
                    ^13mathrmNlongrightarrow stackunder^13mathrmC+e^++nu
                    ^13mathrmC+^mathrmlmathrmHlongrightarrow stackunder^14mathrmN+gamma
                    ^14mathrmN+^mathrmlmathrmHlongrightarrow stackunder^15mathrmO+gamma
                    ^15mathrmOlongrightarrow stackunder^15mathrmN+e^++nu
                    ^15mathrmN+^1mathrmHlongrightarrow ^12mathrmC+^4mathrmHe

                    $
                    enddocument


                    enter image description here






                    share|improve this answer













                    It's a matter of opinion whether this is less clunky...it eliminates all & tab characters, but requires multiple stackunders and some bracing.



                    The appearance is a bit different, however "the same elements of each reaction are below each other", as requested by the OP. While there are no other alignments that apply one may observe that the spacing on any given line is "correct".



                    documentclass[border=10 pt]standalone
                    usepackagemathtools,setspace,stackengine
                    begindocument
                    renewcommandstackalignmentl
                    renewcommandstacktypeL
                    setstackgapL1.4baselineskip
                    stackMath
                    $displaystyle
                    ^12mathrmC+^1mathrmHlongrightarrow stackunder^13mathrmN+gamma
                    ^13mathrmNlongrightarrow stackunder^13mathrmC+e^++nu
                    ^13mathrmC+^mathrmlmathrmHlongrightarrow stackunder^14mathrmN+gamma
                    ^14mathrmN+^mathrmlmathrmHlongrightarrow stackunder^15mathrmO+gamma
                    ^15mathrmOlongrightarrow stackunder^15mathrmN+e^++nu
                    ^15mathrmN+^1mathrmHlongrightarrow ^12mathrmC+^4mathrmHe

                    $
                    enddocument


                    enter image description here







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 8 hours ago









                    Steven B. SegletesSteven B. Segletes

                    166k9209426




                    166k9209426





















                        2














                        I suggest to align your entries like the way I did (using Tab) to make it easier to read and modify if needed.
                        I have used newcommand to create a way for you to enter the data of a row and every cell in the array is encapsulated by mathrm....
                        Also, I changed the 23 cs you had in the array to *23c.



                        Output



                        documentclass[border=10 pt]standalone
                        usepackagemathtools,setspace
                        % Usage:
                        % dataoperand-1operator-1operand-2operator-2operand-3operator-3operand-4
                        % Simple example:
                        % dataa+b-c*d
                        newcommanddata[7]%
                        ensuremath%
                        mathrm#1 & mathrm#2 & mathrm#3 & mathrm#4 & mathrm#5 & mathrm#6 & mathrm#7
                        %
                        %
                        begindocument
                        $displaystyle
                        setstretch1.5
                        beginarray*23c
                        data^12 C+ ^1 H longrightarrow ^13 N +gamma \
                        &&&& data^13 Nlongrightarrow ^13 C + e^+ +nu \
                        &&&&&& data^13 C+ ^1 H longrightarrow ^14 N +gamma \
                        &&&&&&&&&& data^14 N+ ^1 H longrightarrow ^15 O +gamma \
                        &&&&&&&&&&&&&& data^15 Olongrightarrow ^15 N + e^+ +nu \
                        &&&&&&&&&&&&&&&& data^15 N+ ^1 H longrightarrow ^12 C +^4 He\
                        endarray
                        $
                        enddocument





                        share|improve this answer





























                          2














                          I suggest to align your entries like the way I did (using Tab) to make it easier to read and modify if needed.
                          I have used newcommand to create a way for you to enter the data of a row and every cell in the array is encapsulated by mathrm....
                          Also, I changed the 23 cs you had in the array to *23c.



                          Output



                          documentclass[border=10 pt]standalone
                          usepackagemathtools,setspace
                          % Usage:
                          % dataoperand-1operator-1operand-2operator-2operand-3operator-3operand-4
                          % Simple example:
                          % dataa+b-c*d
                          newcommanddata[7]%
                          ensuremath%
                          mathrm#1 & mathrm#2 & mathrm#3 & mathrm#4 & mathrm#5 & mathrm#6 & mathrm#7
                          %
                          %
                          begindocument
                          $displaystyle
                          setstretch1.5
                          beginarray*23c
                          data^12 C+ ^1 H longrightarrow ^13 N +gamma \
                          &&&& data^13 Nlongrightarrow ^13 C + e^+ +nu \
                          &&&&&& data^13 C+ ^1 H longrightarrow ^14 N +gamma \
                          &&&&&&&&&& data^14 N+ ^1 H longrightarrow ^15 O +gamma \
                          &&&&&&&&&&&&&& data^15 Olongrightarrow ^15 N + e^+ +nu \
                          &&&&&&&&&&&&&&&& data^15 N+ ^1 H longrightarrow ^12 C +^4 He\
                          endarray
                          $
                          enddocument





                          share|improve this answer



























                            2












                            2








                            2







                            I suggest to align your entries like the way I did (using Tab) to make it easier to read and modify if needed.
                            I have used newcommand to create a way for you to enter the data of a row and every cell in the array is encapsulated by mathrm....
                            Also, I changed the 23 cs you had in the array to *23c.



                            Output



                            documentclass[border=10 pt]standalone
                            usepackagemathtools,setspace
                            % Usage:
                            % dataoperand-1operator-1operand-2operator-2operand-3operator-3operand-4
                            % Simple example:
                            % dataa+b-c*d
                            newcommanddata[7]%
                            ensuremath%
                            mathrm#1 & mathrm#2 & mathrm#3 & mathrm#4 & mathrm#5 & mathrm#6 & mathrm#7
                            %
                            %
                            begindocument
                            $displaystyle
                            setstretch1.5
                            beginarray*23c
                            data^12 C+ ^1 H longrightarrow ^13 N +gamma \
                            &&&& data^13 Nlongrightarrow ^13 C + e^+ +nu \
                            &&&&&& data^13 C+ ^1 H longrightarrow ^14 N +gamma \
                            &&&&&&&&&& data^14 N+ ^1 H longrightarrow ^15 O +gamma \
                            &&&&&&&&&&&&&& data^15 Olongrightarrow ^15 N + e^+ +nu \
                            &&&&&&&&&&&&&&&& data^15 N+ ^1 H longrightarrow ^12 C +^4 He\
                            endarray
                            $
                            enddocument





                            share|improve this answer















                            I suggest to align your entries like the way I did (using Tab) to make it easier to read and modify if needed.
                            I have used newcommand to create a way for you to enter the data of a row and every cell in the array is encapsulated by mathrm....
                            Also, I changed the 23 cs you had in the array to *23c.



                            Output



                            documentclass[border=10 pt]standalone
                            usepackagemathtools,setspace
                            % Usage:
                            % dataoperand-1operator-1operand-2operator-2operand-3operator-3operand-4
                            % Simple example:
                            % dataa+b-c*d
                            newcommanddata[7]%
                            ensuremath%
                            mathrm#1 & mathrm#2 & mathrm#3 & mathrm#4 & mathrm#5 & mathrm#6 & mathrm#7
                            %
                            %
                            begindocument
                            $displaystyle
                            setstretch1.5
                            beginarray*23c
                            data^12 C+ ^1 H longrightarrow ^13 N +gamma \
                            &&&& data^13 Nlongrightarrow ^13 C + e^+ +nu \
                            &&&&&& data^13 C+ ^1 H longrightarrow ^14 N +gamma \
                            &&&&&&&&&& data^14 N+ ^1 H longrightarrow ^15 O +gamma \
                            &&&&&&&&&&&&&& data^15 Olongrightarrow ^15 N + e^+ +nu \
                            &&&&&&&&&&&&&&&& data^15 N+ ^1 H longrightarrow ^12 C +^4 He\
                            endarray
                            $
                            enddocument






                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited 8 hours ago

























                            answered 8 hours ago









                            M. Al JumailyM. Al Jumaily

                            1,1361210




                            1,1361210





















                                0














                                Enough simple?



                                documentclassreport
                                usepackagemhchem,parskip
                                defaphantomce^12C + ^1H ->
                                defbphantomce^13N ->
                                begindocument
                                ce^12C + ^1H -> ^13N + gammapar
                                ace^13N -> ^13C + $e^+$ + nupar
                                abce^13C + ^1H -> ^14N + gamma
                                enddocument



                                mwe







                                share|improve this answer



























                                  0














                                  Enough simple?



                                  documentclassreport
                                  usepackagemhchem,parskip
                                  defaphantomce^12C + ^1H ->
                                  defbphantomce^13N ->
                                  begindocument
                                  ce^12C + ^1H -> ^13N + gammapar
                                  ace^13N -> ^13C + $e^+$ + nupar
                                  abce^13C + ^1H -> ^14N + gamma
                                  enddocument



                                  mwe







                                  share|improve this answer

























                                    0












                                    0








                                    0







                                    Enough simple?



                                    documentclassreport
                                    usepackagemhchem,parskip
                                    defaphantomce^12C + ^1H ->
                                    defbphantomce^13N ->
                                    begindocument
                                    ce^12C + ^1H -> ^13N + gammapar
                                    ace^13N -> ^13C + $e^+$ + nupar
                                    abce^13C + ^1H -> ^14N + gamma
                                    enddocument



                                    mwe







                                    share|improve this answer













                                    Enough simple?



                                    documentclassreport
                                    usepackagemhchem,parskip
                                    defaphantomce^12C + ^1H ->
                                    defbphantomce^13N ->
                                    begindocument
                                    ce^12C + ^1H -> ^13N + gammapar
                                    ace^13N -> ^13C + $e^+$ + nupar
                                    abce^13C + ^1H -> ^14N + gamma
                                    enddocument



                                    mwe








                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered 1 hour ago









                                    FranFran

                                    54.3k6122184




                                    54.3k6122184



























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