Delete elements less than the last largest elementDeleting multiple elements from a listChanging the precision of data in a list of matricesJoin nested lists based on first and last elements within each listUsing Select function to select elements based on last element of nested listDelete only when there are two (or more) 1smaking two columns from 1D-horizontal dataDelete some elements based on the keysHow to set a particular element of a list to a number?delete an element list recursivelyElegant way of partitioning in two starting from the second element?
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Delete elements less than the last largest element
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Delete elements less than the last largest element
Deleting multiple elements from a listChanging the precision of data in a list of matricesJoin nested lists based on first and last elements within each listUsing Select function to select elements based on last element of nested listDelete only when there are two (or more) 1smaking two columns from 1D-horizontal dataDelete some elements based on the keysHow to set a particular element of a list to a number?delete an element list recursivelyElegant way of partitioning in two starting from the second element?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
Here is my list. The first column contains its index and second column has data.
list=1, 170.93, 2, 170.4, 3, 174.08, 4, 160.65, 5, 166.44, 6,
169.75, 7, 175.86, 8, 177.6, 9, 180.27, 10, 182.82, 11,
182.02, 12, 186.65, 13, 184.53, 14, 186.17, 15,
177.29, 16, 172.06, 17, 175.58, 18, 168.09, 19,
172.33, 20, 165.1, 21, 154.88, 22, 161.28, 23, 165.25, 24,
165.15, 25, 171.03, 26, 174.55, 27, 182.57, 28,
191.02, 29, 191.11, 30, 184.93, 31, 188.85, 32, 191.44;
I want to delete all numbers that are smaller than the last largest element. For example, I want to delete 4th, 5th and 6th elements because they are smaller than the last largest element (3rd). Similarly, I want to delete elements from 13th to 27th elements because they are smaller than the last largest element (12th). 30th and 31st elements should be deleted because they are smaller than prior largest element (29th). Final results should contain increasing numbers. Here is the tabular representation of the data:
I did my best to explain my problem. Please write in the comment if it is not clear. I have a big data and I need to manipulate it as explained here. Any help would be greatly appreciated. Thanks
list-manipulation programming
asked 8 hours ago
DestinationLess_TravellerDestinationLess_Traveller
1295 bronze badges
$endgroup$
add a comment |
$begingroup$
Here is my list. The first column contains its index and second column has data.
list=1, 170.93, 2, 170.4, 3, 174.08, 4, 160.65, 5, 166.44, 6,
169.75, 7, 175.86, 8, 177.6, 9, 180.27, 10, 182.82, 11,
182.02, 12, 186.65, 13, 184.53, 14, 186.17, 15,
177.29, 16, 172.06, 17, 175.58, 18, 168.09, 19,
172.33, 20, 165.1, 21, 154.88, 22, 161.28, 23, 165.25, 24,
165.15, 25, 171.03, 26, 174.55, 27, 182.57, 28,
191.02, 29, 191.11, 30, 184.93, 31, 188.85, 32, 191.44;
I want to delete all numbers that are smaller than the last largest element. For example, I want to delete 4th, 5th and 6th elements because they are smaller than the last largest element (3rd). Similarly, I want to delete elements from 13th to 27th elements because they are smaller than the last largest element (12th). 30th and 31st elements should be deleted because they are smaller than prior largest element (29th). Final results should contain increasing numbers. Here is the tabular representation of the data:
I did my best to explain my problem. Please write in the comment if it is not clear. I have a big data and I need to manipulate it as explained here. Any help would be greatly appreciated. Thanks
list-manipulation programming
asked 8 hours ago
DestinationLess_TravellerDestinationLess_Traveller
1295 bronze badges
$endgroup$
4
$begingroup$
DeleteDuplicatesBy[ Transpose[list[[All, 1]], FoldList[Max, list[[All, 2]]]], Last]should do what you're after.
$endgroup$
– ciao
8 hours ago
$begingroup$
Should you also be deleting the second element since it is smaller than the first? I will note that the solution from @ciao does remove the second element.
$endgroup$
– Mark R
7 hours ago
$begingroup$
@ Mark R, yes you are right. I missed it. Thanks
$endgroup$
– DestinationLess_Traveller
7 hours ago
2
$begingroup$
DeleteDuplicates[list, #1[[2]] > #2[[2]] &]
$endgroup$
– Bob Hanlon
7 hours ago
$begingroup$
@ Bob, thanks for your simple answer. I really appreciate it.
$endgroup$
– DestinationLess_Traveller
2 hours ago
add a comment |
$begingroup$
Here is my list. The first column contains its index and second column has data.
list=1, 170.93, 2, 170.4, 3, 174.08, 4, 160.65, 5, 166.44, 6,
169.75, 7, 175.86, 8, 177.6, 9, 180.27, 10, 182.82, 11,
182.02, 12, 186.65, 13, 184.53, 14, 186.17, 15,
177.29, 16, 172.06, 17, 175.58, 18, 168.09, 19,
172.33, 20, 165.1, 21, 154.88, 22, 161.28, 23, 165.25, 24,
165.15, 25, 171.03, 26, 174.55, 27, 182.57, 28,
191.02, 29, 191.11, 30, 184.93, 31, 188.85, 32, 191.44;
I want to delete all numbers that are smaller than the last largest element. For example, I want to delete 4th, 5th and 6th elements because they are smaller than the last largest element (3rd). Similarly, I want to delete elements from 13th to 27th elements because they are smaller than the last largest element (12th). 30th and 31st elements should be deleted because they are smaller than prior largest element (29th). Final results should contain increasing numbers. Here is the tabular representation of the data:
I did my best to explain my problem. Please write in the comment if it is not clear. I have a big data and I need to manipulate it as explained here. Any help would be greatly appreciated. Thanks
list-manipulation programming
asked 8 hours ago
DestinationLess_TravellerDestinationLess_Traveller
1295 bronze badges
$endgroup$
Here is my list. The first column contains its index and second column has data.
list=1, 170.93, 2, 170.4, 3, 174.08, 4, 160.65, 5, 166.44, 6,
169.75, 7, 175.86, 8, 177.6, 9, 180.27, 10, 182.82, 11,
182.02, 12, 186.65, 13, 184.53, 14, 186.17, 15,
177.29, 16, 172.06, 17, 175.58, 18, 168.09, 19,
172.33, 20, 165.1, 21, 154.88, 22, 161.28, 23, 165.25, 24,
165.15, 25, 171.03, 26, 174.55, 27, 182.57, 28,
191.02, 29, 191.11, 30, 184.93, 31, 188.85, 32, 191.44;
I want to delete all numbers that are smaller than the last largest element. For example, I want to delete 4th, 5th and 6th elements because they are smaller than the last largest element (3rd). Similarly, I want to delete elements from 13th to 27th elements because they are smaller than the last largest element (12th). 30th and 31st elements should be deleted because they are smaller than prior largest element (29th). Final results should contain increasing numbers. Here is the tabular representation of the data:
I did my best to explain my problem. Please write in the comment if it is not clear. I have a big data and I need to manipulate it as explained here. Any help would be greatly appreciated. Thanks
list-manipulation programming
list-manipulation programming
asked 8 hours ago
DestinationLess_TravellerDestinationLess_Traveller
1295 bronze badges
asked 8 hours ago
DestinationLess_TravellerDestinationLess_Traveller
1295 bronze badges
asked 8 hours ago
DestinationLess_TravellerDestinationLess_Traveller
1295 bronze badges
asked 8 hours ago
DestinationLess_TravellerDestinationLess_Traveller
1295 bronze badges
asked 8 hours ago
DestinationLess_TravellerDestinationLess_Traveller
1295 bronze badges
1295 bronze badges
4
$begingroup$
DeleteDuplicatesBy[ Transpose[list[[All, 1]], FoldList[Max, list[[All, 2]]]], Last]should do what you're after.
$endgroup$
– ciao
8 hours ago
$begingroup$
Should you also be deleting the second element since it is smaller than the first? I will note that the solution from @ciao does remove the second element.
$endgroup$
– Mark R
7 hours ago
$begingroup$
@ Mark R, yes you are right. I missed it. Thanks
$endgroup$
– DestinationLess_Traveller
7 hours ago
2
$begingroup$
DeleteDuplicates[list, #1[[2]] > #2[[2]] &]
$endgroup$
– Bob Hanlon
7 hours ago
$begingroup$
@ Bob, thanks for your simple answer. I really appreciate it.
$endgroup$
– DestinationLess_Traveller
2 hours ago
add a comment |
4
$begingroup$
DeleteDuplicatesBy[ Transpose[list[[All, 1]], FoldList[Max, list[[All, 2]]]], Last]should do what you're after.
$endgroup$
– ciao
8 hours ago
$begingroup$
Should you also be deleting the second element since it is smaller than the first? I will note that the solution from @ciao does remove the second element.
$endgroup$
– Mark R
7 hours ago
$begingroup$
@ Mark R, yes you are right. I missed it. Thanks
$endgroup$
– DestinationLess_Traveller
7 hours ago
2
$begingroup$
DeleteDuplicates[list, #1[[2]] > #2[[2]] &]
$endgroup$
– Bob Hanlon
7 hours ago
$begingroup$
@ Bob, thanks for your simple answer. I really appreciate it.
$endgroup$
– DestinationLess_Traveller
2 hours ago
4
4
$begingroup$
DeleteDuplicatesBy[ Transpose[list[[All, 1]], FoldList[Max, list[[All, 2]]]], Last] should do what you're after.$endgroup$
– ciao
8 hours ago
$begingroup$
DeleteDuplicatesBy[ Transpose[list[[All, 1]], FoldList[Max, list[[All, 2]]]], Last] should do what you're after.$endgroup$
– ciao
8 hours ago
$begingroup$
Should you also be deleting the second element since it is smaller than the first? I will note that the solution from @ciao does remove the second element.
$endgroup$
– Mark R
7 hours ago
$begingroup$
Should you also be deleting the second element since it is smaller than the first? I will note that the solution from @ciao does remove the second element.
$endgroup$
– Mark R
7 hours ago
$begingroup$
@ Mark R, yes you are right. I missed it. Thanks
$endgroup$
– DestinationLess_Traveller
7 hours ago
$begingroup$
@ Mark R, yes you are right. I missed it. Thanks
$endgroup$
– DestinationLess_Traveller
7 hours ago
2
2
$begingroup$
DeleteDuplicates[list, #1[[2]] > #2[[2]] &]$endgroup$
– Bob Hanlon
7 hours ago
$begingroup$
DeleteDuplicates[list, #1[[2]] > #2[[2]] &]$endgroup$
– Bob Hanlon
7 hours ago
$begingroup$
@ Bob, thanks for your simple answer. I really appreciate it.
$endgroup$
– DestinationLess_Traveller
2 hours ago
$begingroup$
@ Bob, thanks for your simple answer. I really appreciate it.
$endgroup$
– DestinationLess_Traveller
2 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
TakeList[list, Length /@ Split[FoldList[Max, list[[All, 2]]]]][[All, 1]]
1, 170.93, 3, 174.08, 7, 175.86, 8, 177.6, 9, 180.27, 10,
182.82, 12, 186.65, 28, 191.02, 29, 191.11, 32, 191.44
Also
max = list[[1, -1]];
Split[list, Or[Last[#2] < max, max = Last[#2]] &][[All, 1]]
same result
DeleteDuplicates[Join @@ FoldList[MaximalBy[Last] @* Append, First @ list,
Rest @ list]]
same result
The first method is much faster.
answered 8 hours ago
kglrkglr
203k10 gold badges232 silver badges463 bronze badges
$endgroup$
$begingroup$
Thank you kglr.
$endgroup$
– DestinationLess_Traveller
6 hours ago
$begingroup$
@DestinationLess_Traveller, thank you for the accept.
$endgroup$
– kglr
6 hours ago
add a comment |
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1 Answer
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1 Answer
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votes
$begingroup$
TakeList[list, Length /@ Split[FoldList[Max, list[[All, 2]]]]][[All, 1]]
1, 170.93, 3, 174.08, 7, 175.86, 8, 177.6, 9, 180.27, 10,
182.82, 12, 186.65, 28, 191.02, 29, 191.11, 32, 191.44
Also
max = list[[1, -1]];
Split[list, Or[Last[#2] < max, max = Last[#2]] &][[All, 1]]
same result
DeleteDuplicates[Join @@ FoldList[MaximalBy[Last] @* Append, First @ list,
Rest @ list]]
same result
The first method is much faster.
answered 8 hours ago
kglrkglr
203k10 gold badges232 silver badges463 bronze badges
$endgroup$
$begingroup$
Thank you kglr.
$endgroup$
– DestinationLess_Traveller
6 hours ago
$begingroup$
@DestinationLess_Traveller, thank you for the accept.
$endgroup$
– kglr
6 hours ago
add a comment |
$begingroup$
TakeList[list, Length /@ Split[FoldList[Max, list[[All, 2]]]]][[All, 1]]
1, 170.93, 3, 174.08, 7, 175.86, 8, 177.6, 9, 180.27, 10,
182.82, 12, 186.65, 28, 191.02, 29, 191.11, 32, 191.44
Also
max = list[[1, -1]];
Split[list, Or[Last[#2] < max, max = Last[#2]] &][[All, 1]]
same result
DeleteDuplicates[Join @@ FoldList[MaximalBy[Last] @* Append, First @ list,
Rest @ list]]
same result
The first method is much faster.
answered 8 hours ago
kglrkglr
203k10 gold badges232 silver badges463 bronze badges
$endgroup$
$begingroup$
Thank you kglr.
$endgroup$
– DestinationLess_Traveller
6 hours ago
$begingroup$
@DestinationLess_Traveller, thank you for the accept.
$endgroup$
– kglr
6 hours ago
add a comment |
$begingroup$
TakeList[list, Length /@ Split[FoldList[Max, list[[All, 2]]]]][[All, 1]]
1, 170.93, 3, 174.08, 7, 175.86, 8, 177.6, 9, 180.27, 10,
182.82, 12, 186.65, 28, 191.02, 29, 191.11, 32, 191.44
Also
max = list[[1, -1]];
Split[list, Or[Last[#2] < max, max = Last[#2]] &][[All, 1]]
same result
DeleteDuplicates[Join @@ FoldList[MaximalBy[Last] @* Append, First @ list,
Rest @ list]]
same result
The first method is much faster.
answered 8 hours ago
kglrkglr
203k10 gold badges232 silver badges463 bronze badges
$endgroup$
TakeList[list, Length /@ Split[FoldList[Max, list[[All, 2]]]]][[All, 1]]
1, 170.93, 3, 174.08, 7, 175.86, 8, 177.6, 9, 180.27, 10,
182.82, 12, 186.65, 28, 191.02, 29, 191.11, 32, 191.44
Also
max = list[[1, -1]];
Split[list, Or[Last[#2] < max, max = Last[#2]] &][[All, 1]]
same result
DeleteDuplicates[Join @@ FoldList[MaximalBy[Last] @* Append, First @ list,
Rest @ list]]
same result
The first method is much faster.
answered 8 hours ago
kglrkglr
203k10 gold badges232 silver badges463 bronze badges
edited 7 hours ago
answered 8 hours ago
kglrkglr
203k10 gold badges232 silver badges463 bronze badges
answered 8 hours ago
kglrkglr
203k10 gold badges232 silver badges463 bronze badges
answered 8 hours ago
kglrkglr
203k10 gold badges232 silver badges463 bronze badges
203k10 gold badges232 silver badges463 bronze badges
$begingroup$
Thank you kglr.
$endgroup$
– DestinationLess_Traveller
6 hours ago
$begingroup$
@DestinationLess_Traveller, thank you for the accept.
$endgroup$
– kglr
6 hours ago
add a comment |
$begingroup$
Thank you kglr.
$endgroup$
– DestinationLess_Traveller
6 hours ago
$begingroup$
@DestinationLess_Traveller, thank you for the accept.
$endgroup$
– kglr
6 hours ago
$begingroup$
Thank you kglr.
$endgroup$
– DestinationLess_Traveller
6 hours ago
$begingroup$
Thank you kglr.
$endgroup$
– DestinationLess_Traveller
6 hours ago
$begingroup$
@DestinationLess_Traveller, thank you for the accept.
$endgroup$
– kglr
6 hours ago
$begingroup$
@DestinationLess_Traveller, thank you for the accept.
$endgroup$
– kglr
6 hours ago
add a comment |
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4
$begingroup$
DeleteDuplicatesBy[ Transpose[list[[All, 1]], FoldList[Max, list[[All, 2]]]], Last]should do what you're after.$endgroup$
– ciao
8 hours ago
$begingroup$
Should you also be deleting the second element since it is smaller than the first? I will note that the solution from @ciao does remove the second element.
$endgroup$
– Mark R
7 hours ago
$begingroup$
@ Mark R, yes you are right. I missed it. Thanks
$endgroup$
– DestinationLess_Traveller
7 hours ago
2
$begingroup$
DeleteDuplicates[list, #1[[2]] > #2[[2]] &]$endgroup$
– Bob Hanlon
7 hours ago
$begingroup$
@ Bob, thanks for your simple answer. I really appreciate it.
$endgroup$
– DestinationLess_Traveller
2 hours ago