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Findminimum of Integral
FindMinimum, NMinimize, etc. with external processIntegration does not give real valueFindMinimum function does not produce minimum from near pointFindMinimum and WhenEventSimplifying Expressions for FindMinimumIssues with methods of FindMinimumCan you run FindMinimum excluding imaginary results?FindMinimum yields result, but still issues MachinePrecision digits errorFindMinimum Error - cvec: Constrained optimization is only supported with scalar valued variablesWhy is my integral not being evaluated?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
I am trying to find the value of $u$ that minimizes the following expression:
q = 1 - Exp[-u/b];
expr = Log[(1/(2 + b)) (1/(1 - q + q^2)) (q +
q^2 + (1 - q)^2 Exp[-u/2])/0.3553]; (*SEC BER equation *)
FindMinimum[Integrate[expr, b, 1, 10], u, 0, 10]
However, it does not yield any output. What's wrong with the code?
numerical-integration mathematical-optimization
asked 9 hours ago
jhon_wickjhon_wick
1796 bronze badges
$endgroup$
add a comment |
$begingroup$
I am trying to find the value of $u$ that minimizes the following expression:
q = 1 - Exp[-u/b];
expr = Log[(1/(2 + b)) (1/(1 - q + q^2)) (q +
q^2 + (1 - q)^2 Exp[-u/2])/0.3553]; (*SEC BER equation *)
FindMinimum[Integrate[expr, b, 1, 10], u, 0, 10]
However, it does not yield any output. What's wrong with the code?
numerical-integration mathematical-optimization
asked 9 hours ago
jhon_wickjhon_wick
1796 bronze badges
$endgroup$
1
$begingroup$
You may want to replace=by:=.
$endgroup$
– A.G.
9 hours ago
add a comment |
$begingroup$
I am trying to find the value of $u$ that minimizes the following expression:
q = 1 - Exp[-u/b];
expr = Log[(1/(2 + b)) (1/(1 - q + q^2)) (q +
q^2 + (1 - q)^2 Exp[-u/2])/0.3553]; (*SEC BER equation *)
FindMinimum[Integrate[expr, b, 1, 10], u, 0, 10]
However, it does not yield any output. What's wrong with the code?
numerical-integration mathematical-optimization
asked 9 hours ago
jhon_wickjhon_wick
1796 bronze badges
$endgroup$
I am trying to find the value of $u$ that minimizes the following expression:
q = 1 - Exp[-u/b];
expr = Log[(1/(2 + b)) (1/(1 - q + q^2)) (q +
q^2 + (1 - q)^2 Exp[-u/2])/0.3553]; (*SEC BER equation *)
FindMinimum[Integrate[expr, b, 1, 10], u, 0, 10]
However, it does not yield any output. What's wrong with the code?
numerical-integration mathematical-optimization
numerical-integration mathematical-optimization
asked 9 hours ago
jhon_wickjhon_wick
1796 bronze badges
asked 9 hours ago
jhon_wickjhon_wick
1796 bronze badges
asked 9 hours ago
jhon_wickjhon_wick
1796 bronze badges
asked 9 hours ago
jhon_wickjhon_wick
1796 bronze badges
asked 9 hours ago
jhon_wickjhon_wick
1796 bronze badges
1796 bronze badges
1
$begingroup$
You may want to replace=by:=.
$endgroup$
– A.G.
9 hours ago
add a comment |
1
$begingroup$
You may want to replace=by:=.
$endgroup$
– A.G.
9 hours ago
1
1
$begingroup$
You may want to replace
= by :=.$endgroup$
– A.G.
9 hours ago
$begingroup$
You may want to replace
= by :=.$endgroup$
– A.G.
9 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You can do something like this.
Clear[expr];
q = 1 - Exp[-u/b];
expr[u_?NumericQ] :=
NIntegrate[
Log[(1/(2 + b)) (1/(1 - q + q^2)) (q + q^2 + (1 - q)^2 Exp[-u/2])/0.3553], b, 1, 10];
Now easy to optimize.
FindMinimum[expr[u], u, 0, 10]
-10.5871, u -> 1.2105
answered 9 hours ago
PlatoManiacPlatoManiac
12.1k2 gold badges29 silver badges68 bronze badges
$endgroup$
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
You can do something like this.
Clear[expr];
q = 1 - Exp[-u/b];
expr[u_?NumericQ] :=
NIntegrate[
Log[(1/(2 + b)) (1/(1 - q + q^2)) (q + q^2 + (1 - q)^2 Exp[-u/2])/0.3553], b, 1, 10];
Now easy to optimize.
FindMinimum[expr[u], u, 0, 10]
-10.5871, u -> 1.2105
answered 9 hours ago
PlatoManiacPlatoManiac
12.1k2 gold badges29 silver badges68 bronze badges
$endgroup$
add a comment |
$begingroup$
You can do something like this.
Clear[expr];
q = 1 - Exp[-u/b];
expr[u_?NumericQ] :=
NIntegrate[
Log[(1/(2 + b)) (1/(1 - q + q^2)) (q + q^2 + (1 - q)^2 Exp[-u/2])/0.3553], b, 1, 10];
Now easy to optimize.
FindMinimum[expr[u], u, 0, 10]
-10.5871, u -> 1.2105
answered 9 hours ago
PlatoManiacPlatoManiac
12.1k2 gold badges29 silver badges68 bronze badges
$endgroup$
add a comment |
$begingroup$
You can do something like this.
Clear[expr];
q = 1 - Exp[-u/b];
expr[u_?NumericQ] :=
NIntegrate[
Log[(1/(2 + b)) (1/(1 - q + q^2)) (q + q^2 + (1 - q)^2 Exp[-u/2])/0.3553], b, 1, 10];
Now easy to optimize.
FindMinimum[expr[u], u, 0, 10]
-10.5871, u -> 1.2105
answered 9 hours ago
PlatoManiacPlatoManiac
12.1k2 gold badges29 silver badges68 bronze badges
$endgroup$
You can do something like this.
Clear[expr];
q = 1 - Exp[-u/b];
expr[u_?NumericQ] :=
NIntegrate[
Log[(1/(2 + b)) (1/(1 - q + q^2)) (q + q^2 + (1 - q)^2 Exp[-u/2])/0.3553], b, 1, 10];
Now easy to optimize.
FindMinimum[expr[u], u, 0, 10]
-10.5871, u -> 1.2105
answered 9 hours ago
PlatoManiacPlatoManiac
12.1k2 gold badges29 silver badges68 bronze badges
answered 9 hours ago
PlatoManiacPlatoManiac
12.1k2 gold badges29 silver badges68 bronze badges
answered 9 hours ago
PlatoManiacPlatoManiac
12.1k2 gold badges29 silver badges68 bronze badges
answered 9 hours ago
PlatoManiacPlatoManiac
12.1k2 gold badges29 silver badges68 bronze badges
12.1k2 gold badges29 silver badges68 bronze badges
add a comment |
add a comment |
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$begingroup$
You may want to replace
=by:=.$endgroup$
– A.G.
9 hours ago