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How to execute a program from terminal redirecting stdout and stderr to systemd's journal?

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2

Is there an easy way to run a command from the terminal the same way it is run from GNOME's Alt + F2, redirecting stdout and stderr to systemd's journal?

I've tried gmrun (does not redirect outputs), gtk-launch (works only for .desktop files in /usr/share/applications).

Is there a GNOME or a systemd command to do this?

systemd gnome

share|improve this question

edited 8 hours ago

terdon♦

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Yves DorfsmanYves Dorfsman

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• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  See unix.stackexchange.com/questions/205883/… then you can figure out how to do this
  
  – 炸鱼薯条德里克
  8 hours ago
  

  
  
  
  

add a comment | 

2

Is there an easy way to run a command from the terminal the same way it is run from GNOME's Alt + F2, redirecting stdout and stderr to systemd's journal?

I've tried gmrun (does not redirect outputs), gtk-launch (works only for .desktop files in /usr/share/applications).

Is there a GNOME or a systemd command to do this?

systemd gnome

share|improve this question

edited 8 hours ago

terdon♦

138k3333 gold badges283283 silver badges461461 bronze badges

asked 8 hours ago

Yves DorfsmanYves Dorfsman

11122 bronze badges

New contributor

Yves Dorfsman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  See unix.stackexchange.com/questions/205883/… then you can figure out how to do this
  
  – 炸鱼薯条德里克
  8 hours ago
  

  
  
  
  

add a comment | 

Is there an easy way to run a command from the terminal the same way it is run from GNOME's Alt + F2, redirecting stdout and stderr to systemd's journal?

I've tried gmrun (does not redirect outputs), gtk-launch (works only for .desktop files in /usr/share/applications).

Is there a GNOME or a systemd command to do this?

systemd gnome

share|improve this question

edited 8 hours ago

terdon♦

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asked 8 hours ago

Yves DorfsmanYves Dorfsman

11122 bronze badges

New contributor

Yves Dorfsman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 8 hours ago

terdon♦

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asked 8 hours ago

Yves DorfsmanYves Dorfsman

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Yves Dorfsman is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 8 hours ago

terdon♦

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asked 8 hours ago

Yves DorfsmanYves Dorfsman

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edited 8 hours ago

terdon♦

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edited 8 hours ago

terdon♦

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asked 8 hours ago

Yves DorfsmanYves Dorfsman

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asked 8 hours ago

Yves DorfsmanYves Dorfsman

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2 Answers
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3

I think that you should use the logger(1) utility, which works no matter if your system is using systemd or rsyslogd.

your_prog 2>&1 | logger -t your_prog

On systems with systemd, there's also systemd-cat which is specifically using systemd's "streaming" logging api (sd_journal_stream_fd(3), /run/systemd/journal/stdout) instead of the standard syslog(3):

your_prog 2>&1 | systemd-cat -t your_prog

systemd-cat -t your_prog your_prog

To save another search: If you want to pipe only the stderr but not the stdout, you can use

log_stderr() logger -t "$1"; 3>&1; 
log_stderr your_prog

share|improve this answer

edited 6 hours ago

answered 6 hours ago

mosvymosvy

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1

systemd-run --user ...

Unfortunately, the most user-friendly mode is not used by default.

By default, services created with systemd-run default to the simple type [...] Consider using the exec service type (i.e. --property=Type=exec) to ensure that systemd-run returns successfully only if the specified command line has been successfully started.

This more useful setting was added later. Personally, I do not think I would remember this detail. So I would prefer to use a short wrapper script.

share|improve this answer

edited 6 hours ago

answered 6 hours ago

sourcejedisourcejedi

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3

I think that you should use the logger(1) utility, which works no matter if your system is using systemd or rsyslogd.

your_prog 2>&1 | logger -t your_prog

On systems with systemd, there's also systemd-cat which is specifically using systemd's "streaming" logging api (sd_journal_stream_fd(3), /run/systemd/journal/stdout) instead of the standard syslog(3):

your_prog 2>&1 | systemd-cat -t your_prog

systemd-cat -t your_prog your_prog

To save another search: If you want to pipe only the stderr but not the stdout, you can use

log_stderr() logger -t "$1"; 3>&1; 
log_stderr your_prog

share|improve this answer

edited 6 hours ago

answered 6 hours ago

mosvymosvy

14.8k22 gold badges1818 silver badges4848 bronze badges

add a comment | 

3

I think that you should use the logger(1) utility, which works no matter if your system is using systemd or rsyslogd.

your_prog 2>&1 | logger -t your_prog

On systems with systemd, there's also systemd-cat which is specifically using systemd's "streaming" logging api (sd_journal_stream_fd(3), /run/systemd/journal/stdout) instead of the standard syslog(3):

your_prog 2>&1 | systemd-cat -t your_prog

systemd-cat -t your_prog your_prog

To save another search: If you want to pipe only the stderr but not the stdout, you can use

log_stderr() logger -t "$1"; 3>&1; 
log_stderr your_prog

share|improve this answer

edited 6 hours ago

answered 6 hours ago

mosvymosvy

14.8k22 gold badges1818 silver badges4848 bronze badges

add a comment | 

I think that you should use the logger(1) utility, which works no matter if your system is using systemd or rsyslogd.

your_prog 2>&1 | logger -t your_prog

On systems with systemd, there's also systemd-cat which is specifically using systemd's "streaming" logging api (sd_journal_stream_fd(3), /run/systemd/journal/stdout) instead of the standard syslog(3):

your_prog 2>&1 | systemd-cat -t your_prog

systemd-cat -t your_prog your_prog

To save another search: If you want to pipe only the stderr but not the stdout, you can use

log_stderr() logger -t "$1"; 3>&1; 
log_stderr your_prog

share|improve this answer

edited 6 hours ago

answered 6 hours ago

mosvymosvy

14.8k22 gold badges1818 silver badges4848 bronze badges

your_prog 2>&1 | logger -t your_prog

your_prog 2>&1 | systemd-cat -t your_prog

systemd-cat -t your_prog your_prog

log_stderr() logger -t "$1"; 3>&1; 
log_stderr your_prog

share|improve this answer

edited 6 hours ago

answered 6 hours ago

mosvymosvy

14.8k22 gold badges1818 silver badges4848 bronze badges

answered 6 hours ago

mosvymosvy

14.8k22 gold badges1818 silver badges4848 bronze badges

answered 6 hours ago

mosvymosvy

14.8k22 gold badges1818 silver badges4848 bronze badges

1

systemd-run --user ...

Unfortunately, the most user-friendly mode is not used by default.

By default, services created with systemd-run default to the simple type [...] Consider using the exec service type (i.e. --property=Type=exec) to ensure that systemd-run returns successfully only if the specified command line has been successfully started.

This more useful setting was added later. Personally, I do not think I would remember this detail. So I would prefer to use a short wrapper script.

share|improve this answer

edited 6 hours ago

answered 6 hours ago

sourcejedisourcejedi

28k55 gold badges4747 silver badges128128 bronze badges

add a comment | 

1

systemd-run --user ...

Unfortunately, the most user-friendly mode is not used by default.

By default, services created with systemd-run default to the simple type [...] Consider using the exec service type (i.e. --property=Type=exec) to ensure that systemd-run returns successfully only if the specified command line has been successfully started.

This more useful setting was added later. Personally, I do not think I would remember this detail. So I would prefer to use a short wrapper script.

share|improve this answer

edited 6 hours ago

answered 6 hours ago

sourcejedisourcejedi

28k55 gold badges4747 silver badges128128 bronze badges

add a comment | 

systemd-run --user ...

Unfortunately, the most user-friendly mode is not used by default.

By default, services created with systemd-run default to the simple type [...] Consider using the exec service type (i.e. --property=Type=exec) to ensure that systemd-run returns successfully only if the specified command line has been successfully started.

This more useful setting was added later. Personally, I do not think I would remember this detail. So I would prefer to use a short wrapper script.

share|improve this answer

edited 6 hours ago

answered 6 hours ago

sourcejedisourcejedi

28k55 gold badges4747 silver badges128128 bronze badges

share|improve this answer

edited 6 hours ago

answered 6 hours ago

sourcejedisourcejedi

28k55 gold badges4747 silver badges128128 bronze badges

answered 6 hours ago

sourcejedisourcejedi

28k55 gold badges4747 silver badges128128 bronze badges

answered 6 hours ago

sourcejedisourcejedi

28k55 gold badges4747 silver badges128128 bronze badges