Jimmy needs your help!Will Jimmy fall off his platform?How many Jimmys can fit?Move platforms!Code golf ABC's: The ASCII Box ChallengeJimmy these arrays downStewie's sequence: + * - / + * - /your Uncle help Drunk needsMicrogravity BallDon't get your head in a spin!Rosencrantz and Guildenstern are CodeWill Jimmy fall off his platform?How many Jimmys can fit?
I don't want to be introduced as a "Minority Novelist"
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Jimmy needs your help!
Will Jimmy fall off his platform?How many Jimmys can fit?Move platforms!Code golf ABC's: The ASCII Box ChallengeJimmy these arrays downStewie's sequence: + * - / + * - /your Uncle help Drunk needsMicrogravity BallDon't get your head in a spin!Rosencrantz and Guildenstern are CodeWill Jimmy fall off his platform?How many Jimmys can fit?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
It seems as of recent, there have been a lot a Jimmys falling to their death, as can be seen here, and here where you were asked to determine if Jimmy would fall. It is time we put a stop to this madness and try to save Jimmy.
Jimmy has three body parts /
, o
, and arranged like this
/o
Platforms are represented with -
. Jimmy will fall off their platform iff they have two or more body parts that are not directly above a platform.
Some examples:
/o
- -------
Jimmy will balance since all their body parts are above a -
.
/o
------ ---
Jimmy will balanced since two body parts are above -
s.
/o
-- ---- --
Jimmy will balance even though they are split between two platforms
/o
-
Jimmy will not balanced since two body parts are not above a platform.
Since my platform supply is running low, I only have platforms with a length of 5, and it is important we use as few as possible.
Your task is to take an input of Jimmys and output a string of platforms which will save all of the Jimmys in the input. Your output must use as few platforms as possible, but each platform must be 5 -
's wide.
Note that the rule of the platform being 5 -
wide, means that each platform must have a space between them. ----------
is not valid in the output since it will be considered a platform of length 10 and not two platforms of length 5.
Test Case's
/o /o/o // input
----- ----- // output
/o /o
----- -----
/o /o // same input as above
----- ----- // this is also valid output
/o /o
-----
Standard rules apply.
This is code-golf, may the shortest answer win!
code-golf string ascii-art
$endgroup$
|
show 11 more comments
$begingroup$
It seems as of recent, there have been a lot a Jimmys falling to their death, as can be seen here, and here where you were asked to determine if Jimmy would fall. It is time we put a stop to this madness and try to save Jimmy.
Jimmy has three body parts /
, o
, and arranged like this
/o
Platforms are represented with -
. Jimmy will fall off their platform iff they have two or more body parts that are not directly above a platform.
Some examples:
/o
- -------
Jimmy will balance since all their body parts are above a -
.
/o
------ ---
Jimmy will balanced since two body parts are above -
s.
/o
-- ---- --
Jimmy will balance even though they are split between two platforms
/o
-
Jimmy will not balanced since two body parts are not above a platform.
Since my platform supply is running low, I only have platforms with a length of 5, and it is important we use as few as possible.
Your task is to take an input of Jimmys and output a string of platforms which will save all of the Jimmys in the input. Your output must use as few platforms as possible, but each platform must be 5 -
's wide.
Note that the rule of the platform being 5 -
wide, means that each platform must have a space between them. ----------
is not valid in the output since it will be considered a platform of length 10 and not two platforms of length 5.
Test Case's
/o /o/o // input
----- ----- // output
/o /o
----- -----
/o /o // same input as above
----- ----- // this is also valid output
/o /o
-----
Standard rules apply.
This is code-golf, may the shortest answer win!
code-golf string ascii-art
$endgroup$
$begingroup$
Does board position matter if it could go multiple places or anywhere is fine as long as all Jimmys are saved? Is there always at least 1 Jimmy?
$endgroup$
– Veskah
8 hours ago
$begingroup$
@Veskah as long as all Jimmys are saved using the fewest possible platforms, position does not matter, so there will be multiple valid outputs for each input. There is no condition on how many Jimmys there will be in the input, an empty string would be a valid input.
$endgroup$
– Quinn
8 hours ago
2
$begingroup$
Test case 4 looks like a scary face
$endgroup$
– Expired Data
8 hours ago
$begingroup$
Jimmy's not happy with you.
$endgroup$
– connectyourcharger
7 hours ago
2
$begingroup$
I can see so many Jimmy follow-ups in the future.
$endgroup$
– connectyourcharger
6 hours ago
|
show 11 more comments
$begingroup$
It seems as of recent, there have been a lot a Jimmys falling to their death, as can be seen here, and here where you were asked to determine if Jimmy would fall. It is time we put a stop to this madness and try to save Jimmy.
Jimmy has three body parts /
, o
, and arranged like this
/o
Platforms are represented with -
. Jimmy will fall off their platform iff they have two or more body parts that are not directly above a platform.
Some examples:
/o
- -------
Jimmy will balance since all their body parts are above a -
.
/o
------ ---
Jimmy will balanced since two body parts are above -
s.
/o
-- ---- --
Jimmy will balance even though they are split between two platforms
/o
-
Jimmy will not balanced since two body parts are not above a platform.
Since my platform supply is running low, I only have platforms with a length of 5, and it is important we use as few as possible.
Your task is to take an input of Jimmys and output a string of platforms which will save all of the Jimmys in the input. Your output must use as few platforms as possible, but each platform must be 5 -
's wide.
Note that the rule of the platform being 5 -
wide, means that each platform must have a space between them. ----------
is not valid in the output since it will be considered a platform of length 10 and not two platforms of length 5.
Test Case's
/o /o/o // input
----- ----- // output
/o /o
----- -----
/o /o // same input as above
----- ----- // this is also valid output
/o /o
-----
Standard rules apply.
This is code-golf, may the shortest answer win!
code-golf string ascii-art
$endgroup$
It seems as of recent, there have been a lot a Jimmys falling to their death, as can be seen here, and here where you were asked to determine if Jimmy would fall. It is time we put a stop to this madness and try to save Jimmy.
Jimmy has three body parts /
, o
, and arranged like this
/o
Platforms are represented with -
. Jimmy will fall off their platform iff they have two or more body parts that are not directly above a platform.
Some examples:
/o
- -------
Jimmy will balance since all their body parts are above a -
.
/o
------ ---
Jimmy will balanced since two body parts are above -
s.
/o
-- ---- --
Jimmy will balance even though they are split between two platforms
/o
-
Jimmy will not balanced since two body parts are not above a platform.
Since my platform supply is running low, I only have platforms with a length of 5, and it is important we use as few as possible.
Your task is to take an input of Jimmys and output a string of platforms which will save all of the Jimmys in the input. Your output must use as few platforms as possible, but each platform must be 5 -
's wide.
Note that the rule of the platform being 5 -
wide, means that each platform must have a space between them. ----------
is not valid in the output since it will be considered a platform of length 10 and not two platforms of length 5.
Test Case's
/o /o/o // input
----- ----- // output
/o /o
----- -----
/o /o // same input as above
----- ----- // this is also valid output
/o /o
-----
Standard rules apply.
This is code-golf, may the shortest answer win!
code-golf string ascii-art
code-golf string ascii-art
edited 7 hours ago
Quinn
asked 8 hours ago
QuinnQuinn
2547 bronze badges
2547 bronze badges
$begingroup$
Does board position matter if it could go multiple places or anywhere is fine as long as all Jimmys are saved? Is there always at least 1 Jimmy?
$endgroup$
– Veskah
8 hours ago
$begingroup$
@Veskah as long as all Jimmys are saved using the fewest possible platforms, position does not matter, so there will be multiple valid outputs for each input. There is no condition on how many Jimmys there will be in the input, an empty string would be a valid input.
$endgroup$
– Quinn
8 hours ago
2
$begingroup$
Test case 4 looks like a scary face
$endgroup$
– Expired Data
8 hours ago
$begingroup$
Jimmy's not happy with you.
$endgroup$
– connectyourcharger
7 hours ago
2
$begingroup$
I can see so many Jimmy follow-ups in the future.
$endgroup$
– connectyourcharger
6 hours ago
|
show 11 more comments
$begingroup$
Does board position matter if it could go multiple places or anywhere is fine as long as all Jimmys are saved? Is there always at least 1 Jimmy?
$endgroup$
– Veskah
8 hours ago
$begingroup$
@Veskah as long as all Jimmys are saved using the fewest possible platforms, position does not matter, so there will be multiple valid outputs for each input. There is no condition on how many Jimmys there will be in the input, an empty string would be a valid input.
$endgroup$
– Quinn
8 hours ago
2
$begingroup$
Test case 4 looks like a scary face
$endgroup$
– Expired Data
8 hours ago
$begingroup$
Jimmy's not happy with you.
$endgroup$
– connectyourcharger
7 hours ago
2
$begingroup$
I can see so many Jimmy follow-ups in the future.
$endgroup$
– connectyourcharger
6 hours ago
$begingroup$
Does board position matter if it could go multiple places or anywhere is fine as long as all Jimmys are saved? Is there always at least 1 Jimmy?
$endgroup$
– Veskah
8 hours ago
$begingroup$
Does board position matter if it could go multiple places or anywhere is fine as long as all Jimmys are saved? Is there always at least 1 Jimmy?
$endgroup$
– Veskah
8 hours ago
$begingroup$
@Veskah as long as all Jimmys are saved using the fewest possible platforms, position does not matter, so there will be multiple valid outputs for each input. There is no condition on how many Jimmys there will be in the input, an empty string would be a valid input.
$endgroup$
– Quinn
8 hours ago
$begingroup$
@Veskah as long as all Jimmys are saved using the fewest possible platforms, position does not matter, so there will be multiple valid outputs for each input. There is no condition on how many Jimmys there will be in the input, an empty string would be a valid input.
$endgroup$
– Quinn
8 hours ago
2
2
$begingroup$
Test case 4 looks like a scary face
$endgroup$
– Expired Data
8 hours ago
$begingroup$
Test case 4 looks like a scary face
$endgroup$
– Expired Data
8 hours ago
$begingroup$
Jimmy's not happy with you.
$endgroup$
– connectyourcharger
7 hours ago
$begingroup$
Jimmy's not happy with you.
$endgroup$
– connectyourcharger
7 hours ago
2
2
$begingroup$
I can see so many Jimmy follow-ups in the future.
$endgroup$
– connectyourcharger
6 hours ago
$begingroup$
I can see so many Jimmy follow-ups in the future.
$endgroup$
– connectyourcharger
6 hours ago
|
show 11 more comments
3 Answers
3
active
oldest
votes
$begingroup$
Python 2, 72 71 70 bytes
lambda s:S('/',' ',S("[^/ ].5","----- ",s+' '*5))
import re;S=re.sub
Try it online!
Not the prettiest, not sure how to better handle those leftover slashes...
$endgroup$
add a comment |
$begingroup$
Python 3, 158 164 160 bytes
a=input();r=""
for i,c in enumerate(a):
try:r[i]
except:
if c in"/o":
r+=(a[i+5<len(a)and i+5or len(a)-1]=="o"and" "or"")+"----- "
else:r+=" "
print(r)
Try it online!
This is my first code golf answer, and I'm happy it's on a Jimmy question!
Explanation:
a=input();r=""
: Take in input and initialize a new stringr
.for i,c in enumerate(a):
: Enumerate over the input.try:r[i] ... except:
: See ifr[i]
exists - if not, process theexcept
block.if c in"/o":
: Check if the current character is in Jimmy's first two body parts.r+=(a[i+5<len(a)and i+5or len(a)-1]=="o"and" "or"")+"----- "
: If so, add a new segment. Add a space before our new segment if another Jimmy head is present in five characters.else:r+=" "
: Otherwise, just add a space.print(r)
: Print our final result.
$endgroup$
$begingroup$
Pretty close, but I think this actually doesn't works for all test cases. It should use as few platforms as possible and your last example uses 2 when it could be done with 1
$endgroup$
– Quinn
4 hours ago
$begingroup$
@Quinn Shoot. Err, non-competing until I fix that.
$endgroup$
– connectyourcharger
3 hours ago
$begingroup$
@connectyourcharger "non-competing" doesn't validate an invalid solution. I recommend deleting it if you're not going to fix it for some time (e.g. the next few minutes).
$endgroup$
– Erik the Outgolfer
3 hours ago
$begingroup$
@Quinn I fixed it now.
$endgroup$
– connectyourcharger
2 hours ago
$begingroup$
@connectyourcharger Nice!
$endgroup$
– Quinn
1 hour ago
add a comment |
$begingroup$
JavaScript (ES6), 56 bytes
s=>[...s+1e4].map(c=>(+s?--s:c>?s=5:0)?'-':' ').join``
Try it online!
Or 49 bytes if returning an array of characters is acceptable.
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Python 2, 72 71 70 bytes
lambda s:S('/',' ',S("[^/ ].5","----- ",s+' '*5))
import re;S=re.sub
Try it online!
Not the prettiest, not sure how to better handle those leftover slashes...
$endgroup$
add a comment |
$begingroup$
Python 2, 72 71 70 bytes
lambda s:S('/',' ',S("[^/ ].5","----- ",s+' '*5))
import re;S=re.sub
Try it online!
Not the prettiest, not sure how to better handle those leftover slashes...
$endgroup$
add a comment |
$begingroup$
Python 2, 72 71 70 bytes
lambda s:S('/',' ',S("[^/ ].5","----- ",s+' '*5))
import re;S=re.sub
Try it online!
Not the prettiest, not sure how to better handle those leftover slashes...
$endgroup$
Python 2, 72 71 70 bytes
lambda s:S('/',' ',S("[^/ ].5","----- ",s+' '*5))
import re;S=re.sub
Try it online!
Not the prettiest, not sure how to better handle those leftover slashes...
edited 6 hours ago
answered 6 hours ago


negative sevennegative seven
5212 silver badges8 bronze badges
5212 silver badges8 bronze badges
add a comment |
add a comment |
$begingroup$
Python 3, 158 164 160 bytes
a=input();r=""
for i,c in enumerate(a):
try:r[i]
except:
if c in"/o":
r+=(a[i+5<len(a)and i+5or len(a)-1]=="o"and" "or"")+"----- "
else:r+=" "
print(r)
Try it online!
This is my first code golf answer, and I'm happy it's on a Jimmy question!
Explanation:
a=input();r=""
: Take in input and initialize a new stringr
.for i,c in enumerate(a):
: Enumerate over the input.try:r[i] ... except:
: See ifr[i]
exists - if not, process theexcept
block.if c in"/o":
: Check if the current character is in Jimmy's first two body parts.r+=(a[i+5<len(a)and i+5or len(a)-1]=="o"and" "or"")+"----- "
: If so, add a new segment. Add a space before our new segment if another Jimmy head is present in five characters.else:r+=" "
: Otherwise, just add a space.print(r)
: Print our final result.
$endgroup$
$begingroup$
Pretty close, but I think this actually doesn't works for all test cases. It should use as few platforms as possible and your last example uses 2 when it could be done with 1
$endgroup$
– Quinn
4 hours ago
$begingroup$
@Quinn Shoot. Err, non-competing until I fix that.
$endgroup$
– connectyourcharger
3 hours ago
$begingroup$
@connectyourcharger "non-competing" doesn't validate an invalid solution. I recommend deleting it if you're not going to fix it for some time (e.g. the next few minutes).
$endgroup$
– Erik the Outgolfer
3 hours ago
$begingroup$
@Quinn I fixed it now.
$endgroup$
– connectyourcharger
2 hours ago
$begingroup$
@connectyourcharger Nice!
$endgroup$
– Quinn
1 hour ago
add a comment |
$begingroup$
Python 3, 158 164 160 bytes
a=input();r=""
for i,c in enumerate(a):
try:r[i]
except:
if c in"/o":
r+=(a[i+5<len(a)and i+5or len(a)-1]=="o"and" "or"")+"----- "
else:r+=" "
print(r)
Try it online!
This is my first code golf answer, and I'm happy it's on a Jimmy question!
Explanation:
a=input();r=""
: Take in input and initialize a new stringr
.for i,c in enumerate(a):
: Enumerate over the input.try:r[i] ... except:
: See ifr[i]
exists - if not, process theexcept
block.if c in"/o":
: Check if the current character is in Jimmy's first two body parts.r+=(a[i+5<len(a)and i+5or len(a)-1]=="o"and" "or"")+"----- "
: If so, add a new segment. Add a space before our new segment if another Jimmy head is present in five characters.else:r+=" "
: Otherwise, just add a space.print(r)
: Print our final result.
$endgroup$
$begingroup$
Pretty close, but I think this actually doesn't works for all test cases. It should use as few platforms as possible and your last example uses 2 when it could be done with 1
$endgroup$
– Quinn
4 hours ago
$begingroup$
@Quinn Shoot. Err, non-competing until I fix that.
$endgroup$
– connectyourcharger
3 hours ago
$begingroup$
@connectyourcharger "non-competing" doesn't validate an invalid solution. I recommend deleting it if you're not going to fix it for some time (e.g. the next few minutes).
$endgroup$
– Erik the Outgolfer
3 hours ago
$begingroup$
@Quinn I fixed it now.
$endgroup$
– connectyourcharger
2 hours ago
$begingroup$
@connectyourcharger Nice!
$endgroup$
– Quinn
1 hour ago
add a comment |
$begingroup$
Python 3, 158 164 160 bytes
a=input();r=""
for i,c in enumerate(a):
try:r[i]
except:
if c in"/o":
r+=(a[i+5<len(a)and i+5or len(a)-1]=="o"and" "or"")+"----- "
else:r+=" "
print(r)
Try it online!
This is my first code golf answer, and I'm happy it's on a Jimmy question!
Explanation:
a=input();r=""
: Take in input and initialize a new stringr
.for i,c in enumerate(a):
: Enumerate over the input.try:r[i] ... except:
: See ifr[i]
exists - if not, process theexcept
block.if c in"/o":
: Check if the current character is in Jimmy's first two body parts.r+=(a[i+5<len(a)and i+5or len(a)-1]=="o"and" "or"")+"----- "
: If so, add a new segment. Add a space before our new segment if another Jimmy head is present in five characters.else:r+=" "
: Otherwise, just add a space.print(r)
: Print our final result.
$endgroup$
Python 3, 158 164 160 bytes
a=input();r=""
for i,c in enumerate(a):
try:r[i]
except:
if c in"/o":
r+=(a[i+5<len(a)and i+5or len(a)-1]=="o"and" "or"")+"----- "
else:r+=" "
print(r)
Try it online!
This is my first code golf answer, and I'm happy it's on a Jimmy question!
Explanation:
a=input();r=""
: Take in input and initialize a new stringr
.for i,c in enumerate(a):
: Enumerate over the input.try:r[i] ... except:
: See ifr[i]
exists - if not, process theexcept
block.if c in"/o":
: Check if the current character is in Jimmy's first two body parts.r+=(a[i+5<len(a)and i+5or len(a)-1]=="o"and" "or"")+"----- "
: If so, add a new segment. Add a space before our new segment if another Jimmy head is present in five characters.else:r+=" "
: Otherwise, just add a space.print(r)
: Print our final result.
edited 2 hours ago
answered 5 hours ago


connectyourchargerconnectyourcharger
5781 gold badge3 silver badges16 bronze badges
5781 gold badge3 silver badges16 bronze badges
$begingroup$
Pretty close, but I think this actually doesn't works for all test cases. It should use as few platforms as possible and your last example uses 2 when it could be done with 1
$endgroup$
– Quinn
4 hours ago
$begingroup$
@Quinn Shoot. Err, non-competing until I fix that.
$endgroup$
– connectyourcharger
3 hours ago
$begingroup$
@connectyourcharger "non-competing" doesn't validate an invalid solution. I recommend deleting it if you're not going to fix it for some time (e.g. the next few minutes).
$endgroup$
– Erik the Outgolfer
3 hours ago
$begingroup$
@Quinn I fixed it now.
$endgroup$
– connectyourcharger
2 hours ago
$begingroup$
@connectyourcharger Nice!
$endgroup$
– Quinn
1 hour ago
add a comment |
$begingroup$
Pretty close, but I think this actually doesn't works for all test cases. It should use as few platforms as possible and your last example uses 2 when it could be done with 1
$endgroup$
– Quinn
4 hours ago
$begingroup$
@Quinn Shoot. Err, non-competing until I fix that.
$endgroup$
– connectyourcharger
3 hours ago
$begingroup$
@connectyourcharger "non-competing" doesn't validate an invalid solution. I recommend deleting it if you're not going to fix it for some time (e.g. the next few minutes).
$endgroup$
– Erik the Outgolfer
3 hours ago
$begingroup$
@Quinn I fixed it now.
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– connectyourcharger
2 hours ago
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@connectyourcharger Nice!
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– Quinn
1 hour ago
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Pretty close, but I think this actually doesn't works for all test cases. It should use as few platforms as possible and your last example uses 2 when it could be done with 1
$endgroup$
– Quinn
4 hours ago
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Pretty close, but I think this actually doesn't works for all test cases. It should use as few platforms as possible and your last example uses 2 when it could be done with 1
$endgroup$
– Quinn
4 hours ago
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@Quinn Shoot. Err, non-competing until I fix that.
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– connectyourcharger
3 hours ago
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@Quinn Shoot. Err, non-competing until I fix that.
$endgroup$
– connectyourcharger
3 hours ago
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@connectyourcharger "non-competing" doesn't validate an invalid solution. I recommend deleting it if you're not going to fix it for some time (e.g. the next few minutes).
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– Erik the Outgolfer
3 hours ago
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@connectyourcharger "non-competing" doesn't validate an invalid solution. I recommend deleting it if you're not going to fix it for some time (e.g. the next few minutes).
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– Erik the Outgolfer
3 hours ago
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@Quinn I fixed it now.
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– connectyourcharger
2 hours ago
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@Quinn I fixed it now.
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– connectyourcharger
2 hours ago
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@connectyourcharger Nice!
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– Quinn
1 hour ago
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@connectyourcharger Nice!
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– Quinn
1 hour ago
add a comment |
$begingroup$
JavaScript (ES6), 56 bytes
s=>[...s+1e4].map(c=>(+s?--s:c>?s=5:0)?'-':' ').join``
Try it online!
Or 49 bytes if returning an array of characters is acceptable.
$endgroup$
add a comment |
$begingroup$
JavaScript (ES6), 56 bytes
s=>[...s+1e4].map(c=>(+s?--s:c>?s=5:0)?'-':' ').join``
Try it online!
Or 49 bytes if returning an array of characters is acceptable.
$endgroup$
add a comment |
$begingroup$
JavaScript (ES6), 56 bytes
s=>[...s+1e4].map(c=>(+s?--s:c>?s=5:0)?'-':' ').join``
Try it online!
Or 49 bytes if returning an array of characters is acceptable.
$endgroup$
JavaScript (ES6), 56 bytes
s=>[...s+1e4].map(c=>(+s?--s:c>?s=5:0)?'-':' ').join``
Try it online!
Or 49 bytes if returning an array of characters is acceptable.
answered 4 hours ago


ArnauldArnauld
87.8k7 gold badges102 silver badges359 bronze badges
87.8k7 gold badges102 silver badges359 bronze badges
add a comment |
add a comment |
If this is an answer to a challenge…
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$begingroup$
Does board position matter if it could go multiple places or anywhere is fine as long as all Jimmys are saved? Is there always at least 1 Jimmy?
$endgroup$
– Veskah
8 hours ago
$begingroup$
@Veskah as long as all Jimmys are saved using the fewest possible platforms, position does not matter, so there will be multiple valid outputs for each input. There is no condition on how many Jimmys there will be in the input, an empty string would be a valid input.
$endgroup$
– Quinn
8 hours ago
2
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Test case 4 looks like a scary face
$endgroup$
– Expired Data
8 hours ago
$begingroup$
Jimmy's not happy with you.
$endgroup$
– connectyourcharger
7 hours ago
2
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I can see so many Jimmy follow-ups in the future.
$endgroup$
– connectyourcharger
6 hours ago