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Bash grep result from command whole line


how to execute lines coming from a grep result?Peculiar piping grep/head behaviorHow to use the grep result in command line?Bash : compare two strings with spaceGrep from a line to a linelimit grep context to a part of the result lineFor a large directory, create a variable of the filenames which include lines which include the text string stored in another variablegrep and output whole wordIssues with using multiple * in the grep commandHow to download a web page content to a text file exactly as the web page is?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















I have a script where I want to list usbs, using the command lsblk.



The command:



$ lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb


which results in



sdb usb Kingston DataTraveler 2.0
sdc usb Kingston DT 101 G2


So I want to save the result in a variable to work later, I write



$ usbs=$(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb)


What I was expecting is that the variable usbs stores the result in two whole lines like above. But if I run



for i in $usbs[@]; do
echo $i
done


I get the result split into words:



sdb
usb
Kingston
DataTraveler
2.0
sdc
usb
Kingston
DT
101
G2


Question:
Is there a way in wich, using the grep command, I can store the result of the command like two whole lines?



Note:
I prefer to know if there's a simple solution instead of dumping the result in a file and then read it.










share|improve this question







New contributor



guillermo chamorro is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.














  • 1





    Try echo "$#usbs[@]" to see the number of items in the usbs "array", or "$!usbs[@]" to list its indices. Or print it with echo "$usbs". It is likely storing what you are expecting it to.

    – fra-san
    2 hours ago







  • 1





    Double-quote your variables (and $(...) constructs) when you reference them and the shell will keep your whitespace intact. But be aware the shell won't automatically assign array elements based on newlines. It will still be one string, just with a newline in the middle.

    – roaima
    2 hours ago












  • @Christopher I like your solution but gave me a headache :), because subsecuents comands use the IFS set before... it took me some time to figure what was happening, it does it silently.

    – guillermo chamorro
    1 hour ago











  • var=$(...) is equivalent to var="$(...)"

    – Jesse_b
    23 mins ago

















1















I have a script where I want to list usbs, using the command lsblk.



The command:



$ lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb


which results in



sdb usb Kingston DataTraveler 2.0
sdc usb Kingston DT 101 G2


So I want to save the result in a variable to work later, I write



$ usbs=$(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb)


What I was expecting is that the variable usbs stores the result in two whole lines like above. But if I run



for i in $usbs[@]; do
echo $i
done


I get the result split into words:



sdb
usb
Kingston
DataTraveler
2.0
sdc
usb
Kingston
DT
101
G2


Question:
Is there a way in wich, using the grep command, I can store the result of the command like two whole lines?



Note:
I prefer to know if there's a simple solution instead of dumping the result in a file and then read it.










share|improve this question







New contributor



guillermo chamorro is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.














  • 1





    Try echo "$#usbs[@]" to see the number of items in the usbs "array", or "$!usbs[@]" to list its indices. Or print it with echo "$usbs". It is likely storing what you are expecting it to.

    – fra-san
    2 hours ago







  • 1





    Double-quote your variables (and $(...) constructs) when you reference them and the shell will keep your whitespace intact. But be aware the shell won't automatically assign array elements based on newlines. It will still be one string, just with a newline in the middle.

    – roaima
    2 hours ago












  • @Christopher I like your solution but gave me a headache :), because subsecuents comands use the IFS set before... it took me some time to figure what was happening, it does it silently.

    – guillermo chamorro
    1 hour ago











  • var=$(...) is equivalent to var="$(...)"

    – Jesse_b
    23 mins ago













1












1








1








I have a script where I want to list usbs, using the command lsblk.



The command:



$ lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb


which results in



sdb usb Kingston DataTraveler 2.0
sdc usb Kingston DT 101 G2


So I want to save the result in a variable to work later, I write



$ usbs=$(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb)


What I was expecting is that the variable usbs stores the result in two whole lines like above. But if I run



for i in $usbs[@]; do
echo $i
done


I get the result split into words:



sdb
usb
Kingston
DataTraveler
2.0
sdc
usb
Kingston
DT
101
G2


Question:
Is there a way in wich, using the grep command, I can store the result of the command like two whole lines?



Note:
I prefer to know if there's a simple solution instead of dumping the result in a file and then read it.










share|improve this question







New contributor



guillermo chamorro is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I have a script where I want to list usbs, using the command lsblk.



The command:



$ lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb


which results in



sdb usb Kingston DataTraveler 2.0
sdc usb Kingston DT 101 G2


So I want to save the result in a variable to work later, I write



$ usbs=$(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb)


What I was expecting is that the variable usbs stores the result in two whole lines like above. But if I run



for i in $usbs[@]; do
echo $i
done


I get the result split into words:



sdb
usb
Kingston
DataTraveler
2.0
sdc
usb
Kingston
DT
101
G2


Question:
Is there a way in wich, using the grep command, I can store the result of the command like two whole lines?



Note:
I prefer to know if there's a simple solution instead of dumping the result in a file and then read it.







bash grep lsblk






share|improve this question







New contributor



guillermo chamorro is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question







New contributor



guillermo chamorro is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question






New contributor



guillermo chamorro is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 3 hours ago









guillermo chamorroguillermo chamorro

1093




1093




New contributor



guillermo chamorro is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




guillermo chamorro is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









  • 1





    Try echo "$#usbs[@]" to see the number of items in the usbs "array", or "$!usbs[@]" to list its indices. Or print it with echo "$usbs". It is likely storing what you are expecting it to.

    – fra-san
    2 hours ago







  • 1





    Double-quote your variables (and $(...) constructs) when you reference them and the shell will keep your whitespace intact. But be aware the shell won't automatically assign array elements based on newlines. It will still be one string, just with a newline in the middle.

    – roaima
    2 hours ago












  • @Christopher I like your solution but gave me a headache :), because subsecuents comands use the IFS set before... it took me some time to figure what was happening, it does it silently.

    – guillermo chamorro
    1 hour ago











  • var=$(...) is equivalent to var="$(...)"

    – Jesse_b
    23 mins ago












  • 1





    Try echo "$#usbs[@]" to see the number of items in the usbs "array", or "$!usbs[@]" to list its indices. Or print it with echo "$usbs". It is likely storing what you are expecting it to.

    – fra-san
    2 hours ago







  • 1





    Double-quote your variables (and $(...) constructs) when you reference them and the shell will keep your whitespace intact. But be aware the shell won't automatically assign array elements based on newlines. It will still be one string, just with a newline in the middle.

    – roaima
    2 hours ago












  • @Christopher I like your solution but gave me a headache :), because subsecuents comands use the IFS set before... it took me some time to figure what was happening, it does it silently.

    – guillermo chamorro
    1 hour ago











  • var=$(...) is equivalent to var="$(...)"

    – Jesse_b
    23 mins ago







1




1





Try echo "$#usbs[@]" to see the number of items in the usbs "array", or "$!usbs[@]" to list its indices. Or print it with echo "$usbs". It is likely storing what you are expecting it to.

– fra-san
2 hours ago






Try echo "$#usbs[@]" to see the number of items in the usbs "array", or "$!usbs[@]" to list its indices. Or print it with echo "$usbs". It is likely storing what you are expecting it to.

– fra-san
2 hours ago





1




1





Double-quote your variables (and $(...) constructs) when you reference them and the shell will keep your whitespace intact. But be aware the shell won't automatically assign array elements based on newlines. It will still be one string, just with a newline in the middle.

– roaima
2 hours ago






Double-quote your variables (and $(...) constructs) when you reference them and the shell will keep your whitespace intact. But be aware the shell won't automatically assign array elements based on newlines. It will still be one string, just with a newline in the middle.

– roaima
2 hours ago














@Christopher I like your solution but gave me a headache :), because subsecuents comands use the IFS set before... it took me some time to figure what was happening, it does it silently.

– guillermo chamorro
1 hour ago





@Christopher I like your solution but gave me a headache :), because subsecuents comands use the IFS set before... it took me some time to figure what was happening, it does it silently.

– guillermo chamorro
1 hour ago













var=$(...) is equivalent to var="$(...)"

– Jesse_b
23 mins ago





var=$(...) is equivalent to var="$(...)"

– Jesse_b
23 mins ago










1 Answer
1






active

oldest

votes


















4














This is a good situation to use readarray/mapfile:



readarray -t usbs < <(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb)


This will create an array with your output where each line is separated into it's own element.



In your case it would make an array like:



usbs=(
'sdb usb Kingston DataTraveler 2.0'
'sdc usb Kingston DT 101 G2'
)



As is you are assigning your entire output to a single variable (not an array) which essentially does this:



usbs='sdb usb Kingston DataTraveler 2.0
sdc usb Kingston DT 101 G2 '



In order to make it an array you would do:



usbs=($(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb))


but this would make each word separated by whitespace into its own element, equivalent to:



usbs=(
sdb
usb
Kingston
DataTraveler
2.0
sdc
usb
Kingston
DT
101
G2
)





share|improve this answer























    Your Answer








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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    This is a good situation to use readarray/mapfile:



    readarray -t usbs < <(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb)


    This will create an array with your output where each line is separated into it's own element.



    In your case it would make an array like:



    usbs=(
    'sdb usb Kingston DataTraveler 2.0'
    'sdc usb Kingston DT 101 G2'
    )



    As is you are assigning your entire output to a single variable (not an array) which essentially does this:



    usbs='sdb usb Kingston DataTraveler 2.0
    sdc usb Kingston DT 101 G2 '



    In order to make it an array you would do:



    usbs=($(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb))


    but this would make each word separated by whitespace into its own element, equivalent to:



    usbs=(
    sdb
    usb
    Kingston
    DataTraveler
    2.0
    sdc
    usb
    Kingston
    DT
    101
    G2
    )





    share|improve this answer



























      4














      This is a good situation to use readarray/mapfile:



      readarray -t usbs < <(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb)


      This will create an array with your output where each line is separated into it's own element.



      In your case it would make an array like:



      usbs=(
      'sdb usb Kingston DataTraveler 2.0'
      'sdc usb Kingston DT 101 G2'
      )



      As is you are assigning your entire output to a single variable (not an array) which essentially does this:



      usbs='sdb usb Kingston DataTraveler 2.0
      sdc usb Kingston DT 101 G2 '



      In order to make it an array you would do:



      usbs=($(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb))


      but this would make each word separated by whitespace into its own element, equivalent to:



      usbs=(
      sdb
      usb
      Kingston
      DataTraveler
      2.0
      sdc
      usb
      Kingston
      DT
      101
      G2
      )





      share|improve this answer

























        4












        4








        4







        This is a good situation to use readarray/mapfile:



        readarray -t usbs < <(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb)


        This will create an array with your output where each line is separated into it's own element.



        In your case it would make an array like:



        usbs=(
        'sdb usb Kingston DataTraveler 2.0'
        'sdc usb Kingston DT 101 G2'
        )



        As is you are assigning your entire output to a single variable (not an array) which essentially does this:



        usbs='sdb usb Kingston DataTraveler 2.0
        sdc usb Kingston DT 101 G2 '



        In order to make it an array you would do:



        usbs=($(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb))


        but this would make each word separated by whitespace into its own element, equivalent to:



        usbs=(
        sdb
        usb
        Kingston
        DataTraveler
        2.0
        sdc
        usb
        Kingston
        DT
        101
        G2
        )





        share|improve this answer













        This is a good situation to use readarray/mapfile:



        readarray -t usbs < <(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb)


        This will create an array with your output where each line is separated into it's own element.



        In your case it would make an array like:



        usbs=(
        'sdb usb Kingston DataTraveler 2.0'
        'sdc usb Kingston DT 101 G2'
        )



        As is you are assigning your entire output to a single variable (not an array) which essentially does this:



        usbs='sdb usb Kingston DataTraveler 2.0
        sdc usb Kingston DT 101 G2 '



        In order to make it an array you would do:



        usbs=($(lsblk -o NAME,TRAN,VENDOR,MODEL | grep usb))


        but this would make each word separated by whitespace into its own element, equivalent to:



        usbs=(
        sdb
        usb
        Kingston
        DataTraveler
        2.0
        sdc
        usb
        Kingston
        DT
        101
        G2
        )






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 3 hours ago









        Jesse_bJesse_b

        15.2k33574




        15.2k33574




















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