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Can artificial satellite positions affect tides?
What are the benefits of tides? Should we look for them on exoplanets?Why is momentum transferred to the moon?Would an asteroid collision affect Moon's orbit, and what consequence would that have for Earth?Tides on other bodiesCould daily variations of weight on Earth really be 0.003%?Could the Galilean moons tidally lock Jupiter?The sorting of perturbational effects by the power
$begingroup$
The Moon's position affects tides. So, is there any possibility for man-made satellite positions to also affect tides?
tides
edited 11 hours ago
RonJohn
249111
asked yesterday
namename
594
$endgroup$
add a comment |
$begingroup$
The Moon's position affects tides. So, is there any possibility for man-made satellite positions to also affect tides?
tides
edited 11 hours ago
RonJohn
249111
asked yesterday
namename
594
$endgroup$
$begingroup$
Related: Do flights affect tides?
$endgroup$
– WBT
7 hours ago
add a comment |
$begingroup$
The Moon's position affects tides. So, is there any possibility for man-made satellite positions to also affect tides?
tides
edited 11 hours ago
RonJohn
249111
asked yesterday
namename
594
$endgroup$
The Moon's position affects tides. So, is there any possibility for man-made satellite positions to also affect tides?
tides
tides
edited 11 hours ago
RonJohn
249111
asked yesterday
namename
594
edited 11 hours ago
RonJohn
249111
asked yesterday
namename
594
edited 11 hours ago
RonJohn
249111
edited 11 hours ago
RonJohn
249111
edited 11 hours ago
RonJohn
249111
249111
asked yesterday
namename
594
asked yesterday
namename
594
asked yesterday
namename
594
594
$begingroup$
Related: Do flights affect tides?
$endgroup$
– WBT
7 hours ago
add a comment |
$begingroup$
Related: Do flights affect tides?
$endgroup$
– WBT
7 hours ago
$begingroup$
Related: Do flights affect tides?
$endgroup$
– WBT
7 hours ago
$begingroup$
Related: Do flights affect tides?
$endgroup$
– WBT
7 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Note: this is a 'Fermi estimate' answer, so I'm going to round off and ignore minor effects.
Tides are caused by gravity, and gravity is a really weak force. The mass of the Moon is 7 x 1022 kg, and it causes tides where the difference between water levels is on the order of 10 m.
Satellites are on the order of 103 kg, and they're 103 times closer, so the tidal effect caused by the average satellite is 1013 times smaller, and that's too small to be measurable.
Another factor is the number of satellites: 1000 sats in orbits evenly distributed around Earth will cancel out each other's tidal effects.
answered yesterday
HobbesHobbes
98.9k2283442
$endgroup$
15
$begingroup$
Another small correction: the amplitude of tides is proportional not to the strength of the gravity force, which is proportional to $r^-2$, but to its gradient, which is proportional to $r^-3$. So a satellite's tides would be "only" about $10^10$ times smaller than the Moon's.
$endgroup$
– Litho
23 hours ago
7
$begingroup$
Good answer, but tides are actually only about 0.5m. Everything bigger than that is caused by the water sloshing around in the ocean bed – or, if you want to put it more respectably, by the rhythm of the tidal pull exciting a resonance in the given body of water.
$endgroup$
– Martin Kochanski
20 hours ago
1
$begingroup$
It might help to be clearer that a fact of $10^3$ in distance means a factor of $10^9$ in tidal effect.
$endgroup$
– dmckee
11 hours ago
1
$begingroup$
Technically, a satellite will affect tides, just like every other object with mass in the universe. However, the impact would be so incredibly small that it would be immeasurable
$endgroup$
– Ferdz
10 hours ago
4
$begingroup$
I just did the numbers quickly, but I think Pluto has a substantially larger effect on the tides than a satelite does.
$endgroup$
– Cort Ammon
10 hours ago
|
show 3 more comments
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1 Answer
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1 Answer
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active
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$begingroup$
Note: this is a 'Fermi estimate' answer, so I'm going to round off and ignore minor effects.
Tides are caused by gravity, and gravity is a really weak force. The mass of the Moon is 7 x 1022 kg, and it causes tides where the difference between water levels is on the order of 10 m.
Satellites are on the order of 103 kg, and they're 103 times closer, so the tidal effect caused by the average satellite is 1013 times smaller, and that's too small to be measurable.
Another factor is the number of satellites: 1000 sats in orbits evenly distributed around Earth will cancel out each other's tidal effects.
answered yesterday
HobbesHobbes
98.9k2283442
$endgroup$
15
$begingroup$
Another small correction: the amplitude of tides is proportional not to the strength of the gravity force, which is proportional to $r^-2$, but to its gradient, which is proportional to $r^-3$. So a satellite's tides would be "only" about $10^10$ times smaller than the Moon's.
$endgroup$
– Litho
23 hours ago
7
$begingroup$
Good answer, but tides are actually only about 0.5m. Everything bigger than that is caused by the water sloshing around in the ocean bed – or, if you want to put it more respectably, by the rhythm of the tidal pull exciting a resonance in the given body of water.
$endgroup$
– Martin Kochanski
20 hours ago
1
$begingroup$
It might help to be clearer that a fact of $10^3$ in distance means a factor of $10^9$ in tidal effect.
$endgroup$
– dmckee
11 hours ago
1
$begingroup$
Technically, a satellite will affect tides, just like every other object with mass in the universe. However, the impact would be so incredibly small that it would be immeasurable
$endgroup$
– Ferdz
10 hours ago
4
$begingroup$
I just did the numbers quickly, but I think Pluto has a substantially larger effect on the tides than a satelite does.
$endgroup$
– Cort Ammon
10 hours ago
|
show 3 more comments
$begingroup$
Note: this is a 'Fermi estimate' answer, so I'm going to round off and ignore minor effects.
Tides are caused by gravity, and gravity is a really weak force. The mass of the Moon is 7 x 1022 kg, and it causes tides where the difference between water levels is on the order of 10 m.
Satellites are on the order of 103 kg, and they're 103 times closer, so the tidal effect caused by the average satellite is 1013 times smaller, and that's too small to be measurable.
Another factor is the number of satellites: 1000 sats in orbits evenly distributed around Earth will cancel out each other's tidal effects.
answered yesterday
HobbesHobbes
98.9k2283442
$endgroup$
15
$begingroup$
Another small correction: the amplitude of tides is proportional not to the strength of the gravity force, which is proportional to $r^-2$, but to its gradient, which is proportional to $r^-3$. So a satellite's tides would be "only" about $10^10$ times smaller than the Moon's.
$endgroup$
– Litho
23 hours ago
7
$begingroup$
Good answer, but tides are actually only about 0.5m. Everything bigger than that is caused by the water sloshing around in the ocean bed – or, if you want to put it more respectably, by the rhythm of the tidal pull exciting a resonance in the given body of water.
$endgroup$
– Martin Kochanski
20 hours ago
1
$begingroup$
It might help to be clearer that a fact of $10^3$ in distance means a factor of $10^9$ in tidal effect.
$endgroup$
– dmckee
11 hours ago
1
$begingroup$
Technically, a satellite will affect tides, just like every other object with mass in the universe. However, the impact would be so incredibly small that it would be immeasurable
$endgroup$
– Ferdz
10 hours ago
4
$begingroup$
I just did the numbers quickly, but I think Pluto has a substantially larger effect on the tides than a satelite does.
$endgroup$
– Cort Ammon
10 hours ago
|
show 3 more comments
$begingroup$
Note: this is a 'Fermi estimate' answer, so I'm going to round off and ignore minor effects.
Tides are caused by gravity, and gravity is a really weak force. The mass of the Moon is 7 x 1022 kg, and it causes tides where the difference between water levels is on the order of 10 m.
Satellites are on the order of 103 kg, and they're 103 times closer, so the tidal effect caused by the average satellite is 1013 times smaller, and that's too small to be measurable.
Another factor is the number of satellites: 1000 sats in orbits evenly distributed around Earth will cancel out each other's tidal effects.
answered yesterday
HobbesHobbes
98.9k2283442
$endgroup$
Note: this is a 'Fermi estimate' answer, so I'm going to round off and ignore minor effects.
Tides are caused by gravity, and gravity is a really weak force. The mass of the Moon is 7 x 1022 kg, and it causes tides where the difference between water levels is on the order of 10 m.
Satellites are on the order of 103 kg, and they're 103 times closer, so the tidal effect caused by the average satellite is 1013 times smaller, and that's too small to be measurable.
Another factor is the number of satellites: 1000 sats in orbits evenly distributed around Earth will cancel out each other's tidal effects.
answered yesterday
HobbesHobbes
98.9k2283442
edited 19 hours ago
answered yesterday
HobbesHobbes
98.9k2283442
answered yesterday
HobbesHobbes
98.9k2283442
answered yesterday
HobbesHobbes
98.9k2283442
98.9k2283442
15
$begingroup$
Another small correction: the amplitude of tides is proportional not to the strength of the gravity force, which is proportional to $r^-2$, but to its gradient, which is proportional to $r^-3$. So a satellite's tides would be "only" about $10^10$ times smaller than the Moon's.
$endgroup$
– Litho
23 hours ago
7
$begingroup$
Good answer, but tides are actually only about 0.5m. Everything bigger than that is caused by the water sloshing around in the ocean bed – or, if you want to put it more respectably, by the rhythm of the tidal pull exciting a resonance in the given body of water.
$endgroup$
– Martin Kochanski
20 hours ago
1
$begingroup$
It might help to be clearer that a fact of $10^3$ in distance means a factor of $10^9$ in tidal effect.
$endgroup$
– dmckee
11 hours ago
1
$begingroup$
Technically, a satellite will affect tides, just like every other object with mass in the universe. However, the impact would be so incredibly small that it would be immeasurable
$endgroup$
– Ferdz
10 hours ago
4
$begingroup$
I just did the numbers quickly, but I think Pluto has a substantially larger effect on the tides than a satelite does.
$endgroup$
– Cort Ammon
10 hours ago
|
show 3 more comments
15
$begingroup$
Another small correction: the amplitude of tides is proportional not to the strength of the gravity force, which is proportional to $r^-2$, but to its gradient, which is proportional to $r^-3$. So a satellite's tides would be "only" about $10^10$ times smaller than the Moon's.
$endgroup$
– Litho
23 hours ago
7
$begingroup$
Good answer, but tides are actually only about 0.5m. Everything bigger than that is caused by the water sloshing around in the ocean bed – or, if you want to put it more respectably, by the rhythm of the tidal pull exciting a resonance in the given body of water.
$endgroup$
– Martin Kochanski
20 hours ago
1
$begingroup$
It might help to be clearer that a fact of $10^3$ in distance means a factor of $10^9$ in tidal effect.
$endgroup$
– dmckee
11 hours ago
1
$begingroup$
Technically, a satellite will affect tides, just like every other object with mass in the universe. However, the impact would be so incredibly small that it would be immeasurable
$endgroup$
– Ferdz
10 hours ago
4
$begingroup$
I just did the numbers quickly, but I think Pluto has a substantially larger effect on the tides than a satelite does.
$endgroup$
– Cort Ammon
10 hours ago
15
15
$begingroup$
Another small correction: the amplitude of tides is proportional not to the strength of the gravity force, which is proportional to $r^-2$, but to its gradient, which is proportional to $r^-3$. So a satellite's tides would be "only" about $10^10$ times smaller than the Moon's.
$endgroup$
– Litho
23 hours ago
$begingroup$
Another small correction: the amplitude of tides is proportional not to the strength of the gravity force, which is proportional to $r^-2$, but to its gradient, which is proportional to $r^-3$. So a satellite's tides would be "only" about $10^10$ times smaller than the Moon's.
$endgroup$
– Litho
23 hours ago
7
7
$begingroup$
Good answer, but tides are actually only about 0.5m. Everything bigger than that is caused by the water sloshing around in the ocean bed – or, if you want to put it more respectably, by the rhythm of the tidal pull exciting a resonance in the given body of water.
$endgroup$
– Martin Kochanski
20 hours ago
$begingroup$
Good answer, but tides are actually only about 0.5m. Everything bigger than that is caused by the water sloshing around in the ocean bed – or, if you want to put it more respectably, by the rhythm of the tidal pull exciting a resonance in the given body of water.
$endgroup$
– Martin Kochanski
20 hours ago
1
1
$begingroup$
It might help to be clearer that a fact of $10^3$ in distance means a factor of $10^9$ in tidal effect.
$endgroup$
– dmckee
11 hours ago
$begingroup$
It might help to be clearer that a fact of $10^3$ in distance means a factor of $10^9$ in tidal effect.
$endgroup$
– dmckee
11 hours ago
1
1
$begingroup$
Technically, a satellite will affect tides, just like every other object with mass in the universe. However, the impact would be so incredibly small that it would be immeasurable
$endgroup$
– Ferdz
10 hours ago
$begingroup$
Technically, a satellite will affect tides, just like every other object with mass in the universe. However, the impact would be so incredibly small that it would be immeasurable
$endgroup$
– Ferdz
10 hours ago
4
4
$begingroup$
I just did the numbers quickly, but I think Pluto has a substantially larger effect on the tides than a satelite does.
$endgroup$
– Cort Ammon
10 hours ago
$begingroup$
I just did the numbers quickly, but I think Pluto has a substantially larger effect on the tides than a satelite does.
$endgroup$
– Cort Ammon
10 hours ago
|
show 3 more comments
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$begingroup$
Related: Do flights affect tides?
$endgroup$
– WBT
7 hours ago