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Non-inverting amplifier ; Single supply ; Bipolar input
Why does non-inverting input of non-inverting amplifier need a path for DC to groundOp-amp non-inverting amplifier with clamping?Is it possible to make a non-inverting amplifier with positive feedback?OpAmp: inverting and non-inverting amplifier both amplify the signal, how to know which one to use?A difference amplifier with a non-grounded non-inverting inputWhy would I use an inverting amplifier?Bias voltage of non-inverting op amplifier drops to 0 when input signal connectedNon-inverting OP Amp supplyMAX412 configuration for non inverting inputSingle supply non-inverting amplifier using op amp
$begingroup$
I am working on the non-inverting amplifier using a single supply, which can amplify bipolar input signal. Non-inverting amplifier is working fine without any issues, only the negative portion of the input is clipped. The schematic is shown below.
To amplify both positive and negative portion of the circuit, I gave DC bias voltage at non-inverting terminal, but in the output I was not getting any signal. Schematic is shown below. I even simulated the circuit and I got proper waveform amplifying both positive and negative signal, but while making, it is not working. I am getting flat line in the oscilloscope.
operational-amplifier amplifier non-inverting
$endgroup$
add a comment |
$begingroup$
I am working on the non-inverting amplifier using a single supply, which can amplify bipolar input signal. Non-inverting amplifier is working fine without any issues, only the negative portion of the input is clipped. The schematic is shown below.
To amplify both positive and negative portion of the circuit, I gave DC bias voltage at non-inverting terminal, but in the output I was not getting any signal. Schematic is shown below. I even simulated the circuit and I got proper waveform amplifying both positive and negative signal, but while making, it is not working. I am getting flat line in the oscilloscope.
operational-amplifier amplifier non-inverting
$endgroup$
$begingroup$
Which op-amp are you using? Link to the datasheet? What's your source impedance? Why 1K resistors for your non-inverting input bias, you could use much higher values for higher input impedance. Try 100K or more instead of 1K.
$endgroup$
– John D
8 hours ago
add a comment |
$begingroup$
I am working on the non-inverting amplifier using a single supply, which can amplify bipolar input signal. Non-inverting amplifier is working fine without any issues, only the negative portion of the input is clipped. The schematic is shown below.
To amplify both positive and negative portion of the circuit, I gave DC bias voltage at non-inverting terminal, but in the output I was not getting any signal. Schematic is shown below. I even simulated the circuit and I got proper waveform amplifying both positive and negative signal, but while making, it is not working. I am getting flat line in the oscilloscope.
operational-amplifier amplifier non-inverting
$endgroup$
I am working on the non-inverting amplifier using a single supply, which can amplify bipolar input signal. Non-inverting amplifier is working fine without any issues, only the negative portion of the input is clipped. The schematic is shown below.
To amplify both positive and negative portion of the circuit, I gave DC bias voltage at non-inverting terminal, but in the output I was not getting any signal. Schematic is shown below. I even simulated the circuit and I got proper waveform amplifying both positive and negative signal, but while making, it is not working. I am getting flat line in the oscilloscope.
operational-amplifier amplifier non-inverting
operational-amplifier amplifier non-inverting
asked 8 hours ago
TapasXTapasX
10410 bronze badges
10410 bronze badges
$begingroup$
Which op-amp are you using? Link to the datasheet? What's your source impedance? Why 1K resistors for your non-inverting input bias, you could use much higher values for higher input impedance. Try 100K or more instead of 1K.
$endgroup$
– John D
8 hours ago
add a comment |
$begingroup$
Which op-amp are you using? Link to the datasheet? What's your source impedance? Why 1K resistors for your non-inverting input bias, you could use much higher values for higher input impedance. Try 100K or more instead of 1K.
$endgroup$
– John D
8 hours ago
$begingroup$
Which op-amp are you using? Link to the datasheet? What's your source impedance? Why 1K resistors for your non-inverting input bias, you could use much higher values for higher input impedance. Try 100K or more instead of 1K.
$endgroup$
– John D
8 hours ago
$begingroup$
Which op-amp are you using? Link to the datasheet? What's your source impedance? Why 1K resistors for your non-inverting input bias, you could use much higher values for higher input impedance. Try 100K or more instead of 1K.
$endgroup$
– John D
8 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Your circuit still has DC gain. You need to add a cap between R1 and GND. The output will have a DC offset. If that needs to be removed, add a series cap between the output and whatever is downstream. Since you have not provided any frequency information, you're on your own to determine the values.
$endgroup$
add a comment |
$begingroup$
Good start, just one more thing to add...
R1 cannot be DC-grounded. It must be AC-grounded with a capacitor. You would choose the capacitor value so that its reactance is equal to (or less than) R1 at the lowest frequency that's important to you. For example, if R1 is 1000 ohms, and you are amplifying audio where 20 Hz is the lowest audio frequency, C1 (below) is about 10uF.
With such a low DC supply voltage, a rail-to-rail opamp is a good choice...many common opamps cannot provide enough output signal swing with a +5V supply.
simulate this circuit – Schematic created using CircuitLab
$endgroup$
add a comment |
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2 Answers
2
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2 Answers
2
active
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active
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$begingroup$
Your circuit still has DC gain. You need to add a cap between R1 and GND. The output will have a DC offset. If that needs to be removed, add a series cap between the output and whatever is downstream. Since you have not provided any frequency information, you're on your own to determine the values.
$endgroup$
add a comment |
$begingroup$
Your circuit still has DC gain. You need to add a cap between R1 and GND. The output will have a DC offset. If that needs to be removed, add a series cap between the output and whatever is downstream. Since you have not provided any frequency information, you're on your own to determine the values.
$endgroup$
add a comment |
$begingroup$
Your circuit still has DC gain. You need to add a cap between R1 and GND. The output will have a DC offset. If that needs to be removed, add a series cap between the output and whatever is downstream. Since you have not provided any frequency information, you're on your own to determine the values.
$endgroup$
Your circuit still has DC gain. You need to add a cap between R1 and GND. The output will have a DC offset. If that needs to be removed, add a series cap between the output and whatever is downstream. Since you have not provided any frequency information, you're on your own to determine the values.
answered 8 hours ago
Matt YoungMatt Young
12.7k4 gold badges26 silver badges60 bronze badges
12.7k4 gold badges26 silver badges60 bronze badges
add a comment |
add a comment |
$begingroup$
Good start, just one more thing to add...
R1 cannot be DC-grounded. It must be AC-grounded with a capacitor. You would choose the capacitor value so that its reactance is equal to (or less than) R1 at the lowest frequency that's important to you. For example, if R1 is 1000 ohms, and you are amplifying audio where 20 Hz is the lowest audio frequency, C1 (below) is about 10uF.
With such a low DC supply voltage, a rail-to-rail opamp is a good choice...many common opamps cannot provide enough output signal swing with a +5V supply.
simulate this circuit – Schematic created using CircuitLab
$endgroup$
add a comment |
$begingroup$
Good start, just one more thing to add...
R1 cannot be DC-grounded. It must be AC-grounded with a capacitor. You would choose the capacitor value so that its reactance is equal to (or less than) R1 at the lowest frequency that's important to you. For example, if R1 is 1000 ohms, and you are amplifying audio where 20 Hz is the lowest audio frequency, C1 (below) is about 10uF.
With such a low DC supply voltage, a rail-to-rail opamp is a good choice...many common opamps cannot provide enough output signal swing with a +5V supply.
simulate this circuit – Schematic created using CircuitLab
$endgroup$
add a comment |
$begingroup$
Good start, just one more thing to add...
R1 cannot be DC-grounded. It must be AC-grounded with a capacitor. You would choose the capacitor value so that its reactance is equal to (or less than) R1 at the lowest frequency that's important to you. For example, if R1 is 1000 ohms, and you are amplifying audio where 20 Hz is the lowest audio frequency, C1 (below) is about 10uF.
With such a low DC supply voltage, a rail-to-rail opamp is a good choice...many common opamps cannot provide enough output signal swing with a +5V supply.
simulate this circuit – Schematic created using CircuitLab
$endgroup$
Good start, just one more thing to add...
R1 cannot be DC-grounded. It must be AC-grounded with a capacitor. You would choose the capacitor value so that its reactance is equal to (or less than) R1 at the lowest frequency that's important to you. For example, if R1 is 1000 ohms, and you are amplifying audio where 20 Hz is the lowest audio frequency, C1 (below) is about 10uF.
With such a low DC supply voltage, a rail-to-rail opamp is a good choice...many common opamps cannot provide enough output signal swing with a +5V supply.
simulate this circuit – Schematic created using CircuitLab
answered 8 hours ago
glen_geekglen_geek
10k1 gold badge10 silver badges16 bronze badges
10k1 gold badge10 silver badges16 bronze badges
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$begingroup$
Which op-amp are you using? Link to the datasheet? What's your source impedance? Why 1K resistors for your non-inverting input bias, you could use much higher values for higher input impedance. Try 100K or more instead of 1K.
$endgroup$
– John D
8 hours ago