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Convert a string like 4h53m12s to a total number of seconds in JavaScript
Why are off grid solar setups only 12, 24, 48 VDC?
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Convert a string like 4h53m12s to a total number of seconds in JavaScript
Determine total number of seconds since the epochMilliseconds to Time string & Time string to MillisecondsConvert number into hours : minutesConvert string to spinal caseJavaScript get total functionConvert hours and minutes to total minutesConvert seconds to hours/minutes/seconds and pretty printConvert a string in time format to minutesConvert HTML input string to JavaScript Array literalConvert query string into object in JavaScript
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
At the moment I have this:
function getValue(str)
let result = 0;
var regex = /(d+[a-z]+)/g;
match = regex.exec(str);
while (match != null)
var match_str = match[0];
var last_char = match_str[match_str.length-1];
if ( last_char == 'h' )
result += parseInt(match_str) * 3600;
if ( last_char == 'm' )
result += parseInt(match_str) * 60;
if ( last_char == 's' )
result += parseInt(match_str);
match = regex.exec(str);
return result;
console.log( getValue("4h12m32s") );
It feels quite clumsy though. Also checking invalid values like 4hs
feels difficult.
Is there any clever trick for something similar?
javascript parsing datetime regex unit-conversion
$endgroup$
add a comment |
$begingroup$
At the moment I have this:
function getValue(str)
let result = 0;
var regex = /(d+[a-z]+)/g;
match = regex.exec(str);
while (match != null)
var match_str = match[0];
var last_char = match_str[match_str.length-1];
if ( last_char == 'h' )
result += parseInt(match_str) * 3600;
if ( last_char == 'm' )
result += parseInt(match_str) * 60;
if ( last_char == 's' )
result += parseInt(match_str);
match = regex.exec(str);
return result;
console.log( getValue("4h12m32s") );
It feels quite clumsy though. Also checking invalid values like 4hs
feels difficult.
Is there any clever trick for something similar?
javascript parsing datetime regex unit-conversion
$endgroup$
$begingroup$
+"4h12m32s".replace(/(d+)h(d+)m(d+)s/, (_, h, m, s) => (h * 3600) + (m * 60) + (s * 1))
;)
$endgroup$
– user11536834
7 hours ago
$begingroup$
(might as well enjoy that implicit type coercion)
$endgroup$
– user11536834
7 hours ago
$begingroup$
@user11536834 I would expect that each unit is optional. The current code allows that; your solution doesn't.
$endgroup$
– 200_success
7 hours ago
add a comment |
$begingroup$
At the moment I have this:
function getValue(str)
let result = 0;
var regex = /(d+[a-z]+)/g;
match = regex.exec(str);
while (match != null)
var match_str = match[0];
var last_char = match_str[match_str.length-1];
if ( last_char == 'h' )
result += parseInt(match_str) * 3600;
if ( last_char == 'm' )
result += parseInt(match_str) * 60;
if ( last_char == 's' )
result += parseInt(match_str);
match = regex.exec(str);
return result;
console.log( getValue("4h12m32s") );
It feels quite clumsy though. Also checking invalid values like 4hs
feels difficult.
Is there any clever trick for something similar?
javascript parsing datetime regex unit-conversion
$endgroup$
At the moment I have this:
function getValue(str)
let result = 0;
var regex = /(d+[a-z]+)/g;
match = regex.exec(str);
while (match != null)
var match_str = match[0];
var last_char = match_str[match_str.length-1];
if ( last_char == 'h' )
result += parseInt(match_str) * 3600;
if ( last_char == 'm' )
result += parseInt(match_str) * 60;
if ( last_char == 's' )
result += parseInt(match_str);
match = regex.exec(str);
return result;
console.log( getValue("4h12m32s") );
It feels quite clumsy though. Also checking invalid values like 4hs
feels difficult.
Is there any clever trick for something similar?
function getValue(str)
let result = 0;
var regex = /(d+[a-z]+)/g;
match = regex.exec(str);
while (match != null)
var match_str = match[0];
var last_char = match_str[match_str.length-1];
if ( last_char == 'h' )
result += parseInt(match_str) * 3600;
if ( last_char == 'm' )
result += parseInt(match_str) * 60;
if ( last_char == 's' )
result += parseInt(match_str);
match = regex.exec(str);
return result;
console.log( getValue("4h12m32s") );
function getValue(str)
let result = 0;
var regex = /(d+[a-z]+)/g;
match = regex.exec(str);
while (match != null)
var match_str = match[0];
var last_char = match_str[match_str.length-1];
if ( last_char == 'h' )
result += parseInt(match_str) * 3600;
if ( last_char == 'm' )
result += parseInt(match_str) * 60;
if ( last_char == 's' )
result += parseInt(match_str);
match = regex.exec(str);
return result;
console.log( getValue("4h12m32s") );
javascript parsing datetime regex unit-conversion
javascript parsing datetime regex unit-conversion
edited 7 hours ago
200_success
135k21 gold badges172 silver badges442 bronze badges
135k21 gold badges172 silver badges442 bronze badges
asked 8 hours ago
Dirk BoerDirk Boer
3962 silver badges10 bronze badges
3962 silver badges10 bronze badges
$begingroup$
+"4h12m32s".replace(/(d+)h(d+)m(d+)s/, (_, h, m, s) => (h * 3600) + (m * 60) + (s * 1))
;)
$endgroup$
– user11536834
7 hours ago
$begingroup$
(might as well enjoy that implicit type coercion)
$endgroup$
– user11536834
7 hours ago
$begingroup$
@user11536834 I would expect that each unit is optional. The current code allows that; your solution doesn't.
$endgroup$
– 200_success
7 hours ago
add a comment |
$begingroup$
+"4h12m32s".replace(/(d+)h(d+)m(d+)s/, (_, h, m, s) => (h * 3600) + (m * 60) + (s * 1))
;)
$endgroup$
– user11536834
7 hours ago
$begingroup$
(might as well enjoy that implicit type coercion)
$endgroup$
– user11536834
7 hours ago
$begingroup$
@user11536834 I would expect that each unit is optional. The current code allows that; your solution doesn't.
$endgroup$
– 200_success
7 hours ago
$begingroup$
+"4h12m32s".replace(/(d+)h(d+)m(d+)s/, (_, h, m, s) => (h * 3600) + (m * 60) + (s * 1))
;)$endgroup$
– user11536834
7 hours ago
$begingroup$
+"4h12m32s".replace(/(d+)h(d+)m(d+)s/, (_, h, m, s) => (h * 3600) + (m * 60) + (s * 1))
;)$endgroup$
– user11536834
7 hours ago
$begingroup$
(might as well enjoy that implicit type coercion)
$endgroup$
– user11536834
7 hours ago
$begingroup$
(might as well enjoy that implicit type coercion)
$endgroup$
– user11536834
7 hours ago
$begingroup$
@user11536834 I would expect that each unit is optional. The current code allows that; your solution doesn't.
$endgroup$
– 200_success
7 hours ago
$begingroup$
@user11536834 I would expect that each unit is optional. The current code allows that; your solution doesn't.
$endgroup$
– 200_success
7 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
getValue(str)
is such a vague name for the function and its parameter, it could mean anything! Furthermore, "get" implies that this is a getter function that retrieves something, which is not the case.- Your regex is ineffective. Capturing parentheses could be useful, but you didn't actually use them right, such that you ended up having to pass a dirty string to
parseInt()
and extract the last character the harder way. - You neglected to scope
match
, such that it acts as a global variable. The regex-matching statement is written twice; the assignment could be done within the loop condition instead. - The
if
statements should be an if-else chain, since the conditions are mutually exclusive. However, since the branches are all so similar, a lookup table would be more elegant.
function durationSeconds(timeExpr)
var units = 'h': 3600, 'm': 60, 's': 1;
var regex = /(d+)([hms])/g;
let seconds = 0;
var match;
while ((match = regex.exec(timeExpr)))
seconds += parseInt(match[1]) * units[match[2]];
return seconds;
console.log( durationSeconds("4h12m32s") );
Alternatively, if you expect that the units will be in the conventional order, you don't have to loop at all.
function durationSeconds(timeExpr)
0)
+ 60 * (parseInt(match[2])
console.log( durationSeconds("4h32s") );
$endgroup$
add a comment |
$begingroup$
Named Capture Groups
JavaScript RegExp has named capture groups that can make life a lot simpler when dealing with complicated RegExp. Combined with destructuring assignment you can extract the named hours minutes and seconds as follows.
function toSeconds(time)
const groups: h = 0, m = 0, s = 0 = /(?<h>d*)h(?<m>d*)m(?<s>d*)/i.exec(time);
return h * 3.6e3 + m * 60 + s * 1; // * 1 to coerce s to Number
Missing digits are set to zero in the assignment defaults.
However this is limited to strings that have hours, minutes, and seconds in the correct order (hence no need to match the "s"
) and will throw an error if there is a problem.
A more robust solution
You can also reduce the array created by symbol.matchAll
(it returns an iterator that you convert to an array via spread operator)
It RegExp[symbol.matchAll]
is the same call as String.matchAll(RegExp)
To handle as many variations as possible you can convert the time string to lowercase, soak up white spaces, allow for fractions, multiple periods, and negative periods.
Using an IIF to wrap the periods constant via closure the function looks like
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) => periods[type] * digits + time, 0);
)();
Or via the string
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [...time.toLowerCase().matchAll(/(-*d*.*d*)W*([hms])/g)]
.reduce((time, [, digits, type]) => periods[type] * digits + time, 0);
)();
The snippet below shows some of the results of a variety of inputs.
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) =>periods[type] * digits + time, 0);
)();
"1h,1m,1s,1,,1s2m3h,3h2m1s,2H2M2S,1h 1H1s1 S1m1M,1.1s,1.2s,s,1h-5m,1 1s,hms"
.split(",")
.forEach(time => log(""" + time + "" =" , toSeconds(time)+" seconds"));
function log(...data)
document.body.appendChild(
Object.assign(
document.createElement("div"), textContent: data.join(" ")
)
)
BTW in Javascript we put...
- the opening
{
on the same line as the statement, - use camelCase for naming.
And from many years of C style language experience I would advise you to always delimit statement blocks with
eg Bad
if (foo) bar = foo
, Good if (foo) bar = foo
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
getValue(str)
is such a vague name for the function and its parameter, it could mean anything! Furthermore, "get" implies that this is a getter function that retrieves something, which is not the case.- Your regex is ineffective. Capturing parentheses could be useful, but you didn't actually use them right, such that you ended up having to pass a dirty string to
parseInt()
and extract the last character the harder way. - You neglected to scope
match
, such that it acts as a global variable. The regex-matching statement is written twice; the assignment could be done within the loop condition instead. - The
if
statements should be an if-else chain, since the conditions are mutually exclusive. However, since the branches are all so similar, a lookup table would be more elegant.
function durationSeconds(timeExpr)
var units = 'h': 3600, 'm': 60, 's': 1;
var regex = /(d+)([hms])/g;
let seconds = 0;
var match;
while ((match = regex.exec(timeExpr)))
seconds += parseInt(match[1]) * units[match[2]];
return seconds;
console.log( durationSeconds("4h12m32s") );
Alternatively, if you expect that the units will be in the conventional order, you don't have to loop at all.
function durationSeconds(timeExpr)
0)
+ 60 * (parseInt(match[2])
console.log( durationSeconds("4h32s") );
$endgroup$
add a comment |
$begingroup$
getValue(str)
is such a vague name for the function and its parameter, it could mean anything! Furthermore, "get" implies that this is a getter function that retrieves something, which is not the case.- Your regex is ineffective. Capturing parentheses could be useful, but you didn't actually use them right, such that you ended up having to pass a dirty string to
parseInt()
and extract the last character the harder way. - You neglected to scope
match
, such that it acts as a global variable. The regex-matching statement is written twice; the assignment could be done within the loop condition instead. - The
if
statements should be an if-else chain, since the conditions are mutually exclusive. However, since the branches are all so similar, a lookup table would be more elegant.
function durationSeconds(timeExpr)
var units = 'h': 3600, 'm': 60, 's': 1;
var regex = /(d+)([hms])/g;
let seconds = 0;
var match;
while ((match = regex.exec(timeExpr)))
seconds += parseInt(match[1]) * units[match[2]];
return seconds;
console.log( durationSeconds("4h12m32s") );
Alternatively, if you expect that the units will be in the conventional order, you don't have to loop at all.
function durationSeconds(timeExpr)
0)
+ 60 * (parseInt(match[2])
console.log( durationSeconds("4h32s") );
$endgroup$
add a comment |
$begingroup$
getValue(str)
is such a vague name for the function and its parameter, it could mean anything! Furthermore, "get" implies that this is a getter function that retrieves something, which is not the case.- Your regex is ineffective. Capturing parentheses could be useful, but you didn't actually use them right, such that you ended up having to pass a dirty string to
parseInt()
and extract the last character the harder way. - You neglected to scope
match
, such that it acts as a global variable. The regex-matching statement is written twice; the assignment could be done within the loop condition instead. - The
if
statements should be an if-else chain, since the conditions are mutually exclusive. However, since the branches are all so similar, a lookup table would be more elegant.
function durationSeconds(timeExpr)
var units = 'h': 3600, 'm': 60, 's': 1;
var regex = /(d+)([hms])/g;
let seconds = 0;
var match;
while ((match = regex.exec(timeExpr)))
seconds += parseInt(match[1]) * units[match[2]];
return seconds;
console.log( durationSeconds("4h12m32s") );
Alternatively, if you expect that the units will be in the conventional order, you don't have to loop at all.
function durationSeconds(timeExpr)
0)
+ 60 * (parseInt(match[2])
console.log( durationSeconds("4h32s") );
$endgroup$
getValue(str)
is such a vague name for the function and its parameter, it could mean anything! Furthermore, "get" implies that this is a getter function that retrieves something, which is not the case.- Your regex is ineffective. Capturing parentheses could be useful, but you didn't actually use them right, such that you ended up having to pass a dirty string to
parseInt()
and extract the last character the harder way. - You neglected to scope
match
, such that it acts as a global variable. The regex-matching statement is written twice; the assignment could be done within the loop condition instead. - The
if
statements should be an if-else chain, since the conditions are mutually exclusive. However, since the branches are all so similar, a lookup table would be more elegant.
function durationSeconds(timeExpr)
var units = 'h': 3600, 'm': 60, 's': 1;
var regex = /(d+)([hms])/g;
let seconds = 0;
var match;
while ((match = regex.exec(timeExpr)))
seconds += parseInt(match[1]) * units[match[2]];
return seconds;
console.log( durationSeconds("4h12m32s") );
Alternatively, if you expect that the units will be in the conventional order, you don't have to loop at all.
function durationSeconds(timeExpr)
0)
+ 60 * (parseInt(match[2])
console.log( durationSeconds("4h32s") );
function durationSeconds(timeExpr)
var units = 'h': 3600, 'm': 60, 's': 1;
var regex = /(d+)([hms])/g;
let seconds = 0;
var match;
while ((match = regex.exec(timeExpr)))
seconds += parseInt(match[1]) * units[match[2]];
return seconds;
console.log( durationSeconds("4h12m32s") );
function durationSeconds(timeExpr)
var units = 'h': 3600, 'm': 60, 's': 1;
var regex = /(d+)([hms])/g;
let seconds = 0;
var match;
while ((match = regex.exec(timeExpr)))
seconds += parseInt(match[1]) * units[match[2]];
return seconds;
console.log( durationSeconds("4h12m32s") );
function durationSeconds(timeExpr)
0)
+ 60 * (parseInt(match[2])
console.log( durationSeconds("4h32s") );
function durationSeconds(timeExpr)
0)
+ 60 * (parseInt(match[2])
console.log( durationSeconds("4h32s") );
edited 6 hours ago
answered 7 hours ago
200_success200_success
135k21 gold badges172 silver badges442 bronze badges
135k21 gold badges172 silver badges442 bronze badges
add a comment |
add a comment |
$begingroup$
Named Capture Groups
JavaScript RegExp has named capture groups that can make life a lot simpler when dealing with complicated RegExp. Combined with destructuring assignment you can extract the named hours minutes and seconds as follows.
function toSeconds(time)
const groups: h = 0, m = 0, s = 0 = /(?<h>d*)h(?<m>d*)m(?<s>d*)/i.exec(time);
return h * 3.6e3 + m * 60 + s * 1; // * 1 to coerce s to Number
Missing digits are set to zero in the assignment defaults.
However this is limited to strings that have hours, minutes, and seconds in the correct order (hence no need to match the "s"
) and will throw an error if there is a problem.
A more robust solution
You can also reduce the array created by symbol.matchAll
(it returns an iterator that you convert to an array via spread operator)
It RegExp[symbol.matchAll]
is the same call as String.matchAll(RegExp)
To handle as many variations as possible you can convert the time string to lowercase, soak up white spaces, allow for fractions, multiple periods, and negative periods.
Using an IIF to wrap the periods constant via closure the function looks like
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) => periods[type] * digits + time, 0);
)();
Or via the string
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [...time.toLowerCase().matchAll(/(-*d*.*d*)W*([hms])/g)]
.reduce((time, [, digits, type]) => periods[type] * digits + time, 0);
)();
The snippet below shows some of the results of a variety of inputs.
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) =>periods[type] * digits + time, 0);
)();
"1h,1m,1s,1,,1s2m3h,3h2m1s,2H2M2S,1h 1H1s1 S1m1M,1.1s,1.2s,s,1h-5m,1 1s,hms"
.split(",")
.forEach(time => log(""" + time + "" =" , toSeconds(time)+" seconds"));
function log(...data)
document.body.appendChild(
Object.assign(
document.createElement("div"), textContent: data.join(" ")
)
)
BTW in Javascript we put...
- the opening
{
on the same line as the statement, - use camelCase for naming.
And from many years of C style language experience I would advise you to always delimit statement blocks with
eg Bad
if (foo) bar = foo
, Good if (foo) bar = foo
$endgroup$
add a comment |
$begingroup$
Named Capture Groups
JavaScript RegExp has named capture groups that can make life a lot simpler when dealing with complicated RegExp. Combined with destructuring assignment you can extract the named hours minutes and seconds as follows.
function toSeconds(time)
const groups: h = 0, m = 0, s = 0 = /(?<h>d*)h(?<m>d*)m(?<s>d*)/i.exec(time);
return h * 3.6e3 + m * 60 + s * 1; // * 1 to coerce s to Number
Missing digits are set to zero in the assignment defaults.
However this is limited to strings that have hours, minutes, and seconds in the correct order (hence no need to match the "s"
) and will throw an error if there is a problem.
A more robust solution
You can also reduce the array created by symbol.matchAll
(it returns an iterator that you convert to an array via spread operator)
It RegExp[symbol.matchAll]
is the same call as String.matchAll(RegExp)
To handle as many variations as possible you can convert the time string to lowercase, soak up white spaces, allow for fractions, multiple periods, and negative periods.
Using an IIF to wrap the periods constant via closure the function looks like
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) => periods[type] * digits + time, 0);
)();
Or via the string
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [...time.toLowerCase().matchAll(/(-*d*.*d*)W*([hms])/g)]
.reduce((time, [, digits, type]) => periods[type] * digits + time, 0);
)();
The snippet below shows some of the results of a variety of inputs.
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) =>periods[type] * digits + time, 0);
)();
"1h,1m,1s,1,,1s2m3h,3h2m1s,2H2M2S,1h 1H1s1 S1m1M,1.1s,1.2s,s,1h-5m,1 1s,hms"
.split(",")
.forEach(time => log(""" + time + "" =" , toSeconds(time)+" seconds"));
function log(...data)
document.body.appendChild(
Object.assign(
document.createElement("div"), textContent: data.join(" ")
)
)
BTW in Javascript we put...
- the opening
{
on the same line as the statement, - use camelCase for naming.
And from many years of C style language experience I would advise you to always delimit statement blocks with
eg Bad
if (foo) bar = foo
, Good if (foo) bar = foo
$endgroup$
add a comment |
$begingroup$
Named Capture Groups
JavaScript RegExp has named capture groups that can make life a lot simpler when dealing with complicated RegExp. Combined with destructuring assignment you can extract the named hours minutes and seconds as follows.
function toSeconds(time)
const groups: h = 0, m = 0, s = 0 = /(?<h>d*)h(?<m>d*)m(?<s>d*)/i.exec(time);
return h * 3.6e3 + m * 60 + s * 1; // * 1 to coerce s to Number
Missing digits are set to zero in the assignment defaults.
However this is limited to strings that have hours, minutes, and seconds in the correct order (hence no need to match the "s"
) and will throw an error if there is a problem.
A more robust solution
You can also reduce the array created by symbol.matchAll
(it returns an iterator that you convert to an array via spread operator)
It RegExp[symbol.matchAll]
is the same call as String.matchAll(RegExp)
To handle as many variations as possible you can convert the time string to lowercase, soak up white spaces, allow for fractions, multiple periods, and negative periods.
Using an IIF to wrap the periods constant via closure the function looks like
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) => periods[type] * digits + time, 0);
)();
Or via the string
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [...time.toLowerCase().matchAll(/(-*d*.*d*)W*([hms])/g)]
.reduce((time, [, digits, type]) => periods[type] * digits + time, 0);
)();
The snippet below shows some of the results of a variety of inputs.
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) =>periods[type] * digits + time, 0);
)();
"1h,1m,1s,1,,1s2m3h,3h2m1s,2H2M2S,1h 1H1s1 S1m1M,1.1s,1.2s,s,1h-5m,1 1s,hms"
.split(",")
.forEach(time => log(""" + time + "" =" , toSeconds(time)+" seconds"));
function log(...data)
document.body.appendChild(
Object.assign(
document.createElement("div"), textContent: data.join(" ")
)
)
BTW in Javascript we put...
- the opening
{
on the same line as the statement, - use camelCase for naming.
And from many years of C style language experience I would advise you to always delimit statement blocks with
eg Bad
if (foo) bar = foo
, Good if (foo) bar = foo
$endgroup$
Named Capture Groups
JavaScript RegExp has named capture groups that can make life a lot simpler when dealing with complicated RegExp. Combined with destructuring assignment you can extract the named hours minutes and seconds as follows.
function toSeconds(time)
const groups: h = 0, m = 0, s = 0 = /(?<h>d*)h(?<m>d*)m(?<s>d*)/i.exec(time);
return h * 3.6e3 + m * 60 + s * 1; // * 1 to coerce s to Number
Missing digits are set to zero in the assignment defaults.
However this is limited to strings that have hours, minutes, and seconds in the correct order (hence no need to match the "s"
) and will throw an error if there is a problem.
A more robust solution
You can also reduce the array created by symbol.matchAll
(it returns an iterator that you convert to an array via spread operator)
It RegExp[symbol.matchAll]
is the same call as String.matchAll(RegExp)
To handle as many variations as possible you can convert the time string to lowercase, soak up white spaces, allow for fractions, multiple periods, and negative periods.
Using an IIF to wrap the periods constant via closure the function looks like
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) => periods[type] * digits + time, 0);
)();
Or via the string
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [...time.toLowerCase().matchAll(/(-*d*.*d*)W*([hms])/g)]
.reduce((time, [, digits, type]) => periods[type] * digits + time, 0);
)();
The snippet below shows some of the results of a variety of inputs.
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) =>periods[type] * digits + time, 0);
)();
"1h,1m,1s,1,,1s2m3h,3h2m1s,2H2M2S,1h 1H1s1 S1m1M,1.1s,1.2s,s,1h-5m,1 1s,hms"
.split(",")
.forEach(time => log(""" + time + "" =" , toSeconds(time)+" seconds"));
function log(...data)
document.body.appendChild(
Object.assign(
document.createElement("div"), textContent: data.join(" ")
)
)
BTW in Javascript we put...
- the opening
{
on the same line as the statement, - use camelCase for naming.
And from many years of C style language experience I would advise you to always delimit statement blocks with
eg Bad
if (foo) bar = foo
, Good if (foo) bar = foo
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) =>periods[type] * digits + time, 0);
)();
"1h,1m,1s,1,,1s2m3h,3h2m1s,2H2M2S,1h 1H1s1 S1m1M,1.1s,1.2s,s,1h-5m,1 1s,hms"
.split(",")
.forEach(time => log(""" + time + "" =" , toSeconds(time)+" seconds"));
function log(...data)
document.body.appendChild(
Object.assign(
document.createElement("div"), textContent: data.join(" ")
)
)
const toSeconds = (() =>
const periods = h: 3600, m: 60, s: 1;
return time => [.../(-*d*.*d*)W*([hms])/g[Symbol.matchAll](time.toLowerCase())]
.reduce((time, [, digits, type]) =>periods[type] * digits + time, 0);
)();
"1h,1m,1s,1,,1s2m3h,3h2m1s,2H2M2S,1h 1H1s1 S1m1M,1.1s,1.2s,s,1h-5m,1 1s,hms"
.split(",")
.forEach(time => log(""" + time + "" =" , toSeconds(time)+" seconds"));
function log(...data)
document.body.appendChild(
Object.assign(
document.createElement("div"), textContent: data.join(" ")
)
)
answered 40 mins ago
Blindman67Blindman67
12.5k1 gold badge6 silver badges25 bronze badges
12.5k1 gold badge6 silver badges25 bronze badges
add a comment |
add a comment |
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$begingroup$
+"4h12m32s".replace(/(d+)h(d+)m(d+)s/, (_, h, m, s) => (h * 3600) + (m * 60) + (s * 1))
;)$endgroup$
– user11536834
7 hours ago
$begingroup$
(might as well enjoy that implicit type coercion)
$endgroup$
– user11536834
7 hours ago
$begingroup$
@user11536834 I would expect that each unit is optional. The current code allows that; your solution doesn't.
$endgroup$
– 200_success
7 hours ago