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How can you tell the version of Ubuntu on a system in a .sh (bash) script?

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2

So I am trying to create a bash/executable, and it in I need to know the version number of Ubuntu on the system. All the ways I have found online consist of lsb_release -r, however I cannot output this into a variable.

Is there any way to get the current version of Ubuntu and save as a variable in a shell executable?

command-line bash scripts

share|improve this question

edited 2 hours ago

Eliah Kagan

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asked 9 hours ago

a.mosallaeia.mosallaei

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• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes, I do appreciate it. Sorry, I wasn't aware there was documentation on this. I appreciate it anyhow
  
  – a.mosallaei
  8 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes, I have done it. Thanks
  
  – a.mosallaei
  8 hours ago
  

  
  
  
  

add a comment | 

2

So I am trying to create a bash/executable, and it in I need to know the version number of Ubuntu on the system. All the ways I have found online consist of lsb_release -r, however I cannot output this into a variable.

Is there any way to get the current version of Ubuntu and save as a variable in a shell executable?

command-line bash scripts

share|improve this question

edited 2 hours ago

Eliah Kagan

87.4k2222 gold badges243243 silver badges385385 bronze badges

asked 9 hours ago

a.mosallaeia.mosallaei

3344 bronze badges

New contributor

a.mosallaei is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes, I do appreciate it. Sorry, I wasn't aware there was documentation on this. I appreciate it anyhow
  
  – a.mosallaei
  8 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Yes, I have done it. Thanks
  
  – a.mosallaei
  8 hours ago
  

  
  
  
  

add a comment | 

So I am trying to create a bash/executable, and it in I need to know the version number of Ubuntu on the system. All the ways I have found online consist of lsb_release -r, however I cannot output this into a variable.

Is there any way to get the current version of Ubuntu and save as a variable in a shell executable?

command-line bash scripts

share|improve this question

edited 2 hours ago

Eliah Kagan

87.4k2222 gold badges243243 silver badges385385 bronze badges

asked 9 hours ago

a.mosallaeia.mosallaei

3344 bronze badges

New contributor

a.mosallaei is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 2 hours ago

Eliah Kagan

87.4k2222 gold badges243243 silver badges385385 bronze badges

asked 9 hours ago

a.mosallaeia.mosallaei

3344 bronze badges

New contributor

a.mosallaei is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 2 hours ago

Eliah Kagan

87.4k2222 gold badges243243 silver badges385385 bronze badges

asked 9 hours ago

a.mosallaeia.mosallaei

3344 bronze badges

New contributor

a.mosallaei is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited 2 hours ago

Eliah Kagan

87.4k2222 gold badges243243 silver badges385385 bronze badges

edited 2 hours ago

Eliah Kagan

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asked 9 hours ago

a.mosallaeia.mosallaei

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New contributor

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asked 9 hours ago

a.mosallaeia.mosallaei

3344 bronze badges

1 Answer
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5

Var=$(lsb_release -r)
echo "$Var"

Should do the trick.

For the numeric portion only add this:

NumOnly=$(cut -f2 <<< "$Var")
echo "$NumOnly"

share|improve this answer

edited 2 hours ago

answered 8 hours ago

WinEunuuchs2UnixWinEunuuchs2Unix

55.7k1515 gold badges107107 silver badges215215 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  so yes thank you, it does work, it outputs Release: 18.04. However is there a way to just get the number? I want to be able to use this variable in an if/else function in the script. The purpose of the if/else is to download the correct version of my application for the distro of ubuntu.
  
  – a.mosallaei
  8 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ah nevermind. @user68186 solved my issue. Thank you guys so much!
  
  – a.mosallaei
  8 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I was going to write the answer but you beat me to it! :-) I am happy to contribute.
  
  – user68186
  8 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @a.mosallaei alternatively, NumOnly=$(lsb_release -r | cut -f2)
  
  – RonJohn
  44 mins ago
  
  

  
  
  
  

add a comment | 

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5

Var=$(lsb_release -r)
echo "$Var"

Should do the trick.

For the numeric portion only add this:

NumOnly=$(cut -f2 <<< "$Var")
echo "$NumOnly"

share|improve this answer

edited 2 hours ago

answered 8 hours ago

WinEunuuchs2UnixWinEunuuchs2Unix

55.7k1515 gold badges107107 silver badges215215 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  so yes thank you, it does work, it outputs Release: 18.04. However is there a way to just get the number? I want to be able to use this variable in an if/else function in the script. The purpose of the if/else is to download the correct version of my application for the distro of ubuntu.
  
  – a.mosallaei
  8 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ah nevermind. @user68186 solved my issue. Thank you guys so much!
  
  – a.mosallaei
  8 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I was going to write the answer but you beat me to it! :-) I am happy to contribute.
  
  – user68186
  8 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @a.mosallaei alternatively, NumOnly=$(lsb_release -r | cut -f2)
  
  – RonJohn
  44 mins ago
  
  

  
  
  
  

add a comment | 

5

Var=$(lsb_release -r)
echo "$Var"

Should do the trick.

For the numeric portion only add this:

NumOnly=$(cut -f2 <<< "$Var")
echo "$NumOnly"

share|improve this answer

edited 2 hours ago

answered 8 hours ago

WinEunuuchs2UnixWinEunuuchs2Unix

55.7k1515 gold badges107107 silver badges215215 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  so yes thank you, it does work, it outputs Release: 18.04. However is there a way to just get the number? I want to be able to use this variable in an if/else function in the script. The purpose of the if/else is to download the correct version of my application for the distro of ubuntu.
  
  – a.mosallaei
  8 hours ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ah nevermind. @user68186 solved my issue. Thank you guys so much!
  
  – a.mosallaei
  8 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I was going to write the answer but you beat me to it! :-) I am happy to contribute.
  
  – user68186
  8 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @a.mosallaei alternatively, NumOnly=$(lsb_release -r | cut -f2)
  
  – RonJohn
  44 mins ago
  
  

  
  
  
  

add a comment | 

Var=$(lsb_release -r)
echo "$Var"

Should do the trick.

For the numeric portion only add this:

NumOnly=$(cut -f2 <<< "$Var")
echo "$NumOnly"

share|improve this answer

edited 2 hours ago

answered 8 hours ago

WinEunuuchs2UnixWinEunuuchs2Unix

55.7k1515 gold badges107107 silver badges215215 bronze badges

Var=$(lsb_release -r)
echo "$Var"

NumOnly=$(cut -f2 <<< "$Var")
echo "$NumOnly"

share|improve this answer

edited 2 hours ago

answered 8 hours ago

WinEunuuchs2UnixWinEunuuchs2Unix

55.7k1515 gold badges107107 silver badges215215 bronze badges

answered 8 hours ago

WinEunuuchs2UnixWinEunuuchs2Unix

55.7k1515 gold badges107107 silver badges215215 bronze badges

answered 8 hours ago

WinEunuuchs2UnixWinEunuuchs2Unix

55.7k1515 gold badges107107 silver badges215215 bronze badges