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An ES6 array of numbers - Double last number, delete the first number


Finding the longest non-decreasing subsequence in a gridHello, First Name Last NameMove array element to the first positionPig Dice Game: Luck game to get to 100 pointsMapping one array onto another where columns from first array become rows in second arrayShuffling an array keeping some elements fixedJavaScript Armstrong Number Validator (ES6)Simple function returning 1 if the Mean = Mode, or 0 if notAdd one to the last array element






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








4












$begingroup$


I'm writing a JavaScript function for an array, based on a geographic sequence. $[1, 2, 4, 8, 16]$, etc.




This function needs to populate the next number in the sequence
$$item_n = item_n-1 * 2$$
If there are more than $10$ items in the array, remove the first
(smallest) number.



If the array reaches $2^15$ (no idea what this is), reset the array to
its original contents - $[1, 2, 4, 8, 16]$.




I have it working, but I feel this could be written more efficiently...



updateSequence() 
var sequence = this.get("geometricSequence");

// Modify the sequence here
function* values(sequence)
for (let prop of Object.keys(sequence))
yield sequence[prop];

let arr = Array.from(values(sequence));

const lastIndex = arr.length - 1;
const lastValue = parseInt(arr[lastIndex]) * 2;
arr.push(lastValue);
if (lastIndex > 9)
arr.slice(0, 1);

if (lastValue > 32768)
arr = [1, 2, 4, 8, 16];

this.set('geometricSequence', arr);










share|improve this question









New contributor



Jim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    Could you include the code for this.get("geometricSequence") and an example how this data looks?
    $endgroup$
    – dfhwze
    10 hours ago

















4












$begingroup$


I'm writing a JavaScript function for an array, based on a geographic sequence. $[1, 2, 4, 8, 16]$, etc.




This function needs to populate the next number in the sequence
$$item_n = item_n-1 * 2$$
If there are more than $10$ items in the array, remove the first
(smallest) number.



If the array reaches $2^15$ (no idea what this is), reset the array to
its original contents - $[1, 2, 4, 8, 16]$.




I have it working, but I feel this could be written more efficiently...



updateSequence() 
var sequence = this.get("geometricSequence");

// Modify the sequence here
function* values(sequence)
for (let prop of Object.keys(sequence))
yield sequence[prop];

let arr = Array.from(values(sequence));

const lastIndex = arr.length - 1;
const lastValue = parseInt(arr[lastIndex]) * 2;
arr.push(lastValue);
if (lastIndex > 9)
arr.slice(0, 1);

if (lastValue > 32768)
arr = [1, 2, 4, 8, 16];

this.set('geometricSequence', arr);










share|improve this question









New contributor



Jim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    Could you include the code for this.get("geometricSequence") and an example how this data looks?
    $endgroup$
    – dfhwze
    10 hours ago













4












4








4





$begingroup$


I'm writing a JavaScript function for an array, based on a geographic sequence. $[1, 2, 4, 8, 16]$, etc.




This function needs to populate the next number in the sequence
$$item_n = item_n-1 * 2$$
If there are more than $10$ items in the array, remove the first
(smallest) number.



If the array reaches $2^15$ (no idea what this is), reset the array to
its original contents - $[1, 2, 4, 8, 16]$.




I have it working, but I feel this could be written more efficiently...



updateSequence() 
var sequence = this.get("geometricSequence");

// Modify the sequence here
function* values(sequence)
for (let prop of Object.keys(sequence))
yield sequence[prop];

let arr = Array.from(values(sequence));

const lastIndex = arr.length - 1;
const lastValue = parseInt(arr[lastIndex]) * 2;
arr.push(lastValue);
if (lastIndex > 9)
arr.slice(0, 1);

if (lastValue > 32768)
arr = [1, 2, 4, 8, 16];

this.set('geometricSequence', arr);










share|improve this question









New contributor



Jim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




I'm writing a JavaScript function for an array, based on a geographic sequence. $[1, 2, 4, 8, 16]$, etc.




This function needs to populate the next number in the sequence
$$item_n = item_n-1 * 2$$
If there are more than $10$ items in the array, remove the first
(smallest) number.



If the array reaches $2^15$ (no idea what this is), reset the array to
its original contents - $[1, 2, 4, 8, 16]$.




I have it working, but I feel this could be written more efficiently...



updateSequence() 
var sequence = this.get("geometricSequence");

// Modify the sequence here
function* values(sequence)
for (let prop of Object.keys(sequence))
yield sequence[prop];

let arr = Array.from(values(sequence));

const lastIndex = arr.length - 1;
const lastValue = parseInt(arr[lastIndex]) * 2;
arr.push(lastValue);
if (lastIndex > 9)
arr.slice(0, 1);

if (lastValue > 32768)
arr = [1, 2, 4, 8, 16];

this.set('geometricSequence', arr);







javascript array ecmascript-6






share|improve this question









New contributor



Jim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









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Jim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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share|improve this question




share|improve this question








edited 1 hour ago









Jamal

31.9k12 gold badges123 silver badges230 bronze badges




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asked 10 hours ago









JimJim

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  • $begingroup$
    Could you include the code for this.get("geometricSequence") and an example how this data looks?
    $endgroup$
    – dfhwze
    10 hours ago
















  • $begingroup$
    Could you include the code for this.get("geometricSequence") and an example how this data looks?
    $endgroup$
    – dfhwze
    10 hours ago















$begingroup$
Could you include the code for this.get("geometricSequence") and an example how this data looks?
$endgroup$
– dfhwze
10 hours ago




$begingroup$
Could you include the code for this.get("geometricSequence") and an example how this data looks?
$endgroup$
– dfhwze
10 hours ago










2 Answers
2






active

oldest

votes


















2














$begingroup$

This will be cleaner if you implement it as a pure function, which takes the sequence as an argument. You can make [1, 2, 4, 8, 16] a default value for that argument, so that you can start the sequence with nothing. Taking this approach, the function simplifies to:



function updateSequence(arr = updateSequence.default) 
const last = arr[arr.length-1]
if (last == 32768) return updateSequence.default

const ret = arr.concat(last * 2)
return ret.length > 10 ? ret.slice(1) : ret

updateSequence.default = [1, 2, 4, 8, 16]


You can test that it works like this:



// test it
var arr = updateSequence()
for (i=0; i<15; i++)
console.log(arr)
arr = updateSequence(arr)



which prints the following:



[ 1, 2, 4, 8, 16, 32 ]
[ 1, 2, 4, 8, 16, 32, 64 ]
[ 1, 2, 4, 8, 16, 32, 64, 128 ]
[ 1, 2, 4, 8, 16, 32, 64, 128, 256 ]
[ 1, 2, 4, 8, 16, 32, 64, 128, 256, 512 ]
[ 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024 ]
[ 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048 ]
[ 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096 ]
[ 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192 ]
[ 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384 ]
[ 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768 ]
[ 1, 2, 4, 8, 16 ]
[ 1, 2, 4, 8, 16, 32 ]
[ 1, 2, 4, 8, 16, 32, 64 ]
[ 1, 2, 4, 8, 16, 32, 64, 128 ]





share|improve this answer









$endgroup$






















    1














    $begingroup$

    Since obj.get("geometricSequence"); presumably already contains an array, you can skip the whole shenanigans with the iterator and directly work on that. Also, if you change the order of the if statements at the end you can save some work by not doing slices on an array you eventually gonna replace later anyway. So:



    updateSequence() 
    let arr = this.get("geometricSequence");

    const lastIndex = arr.length - 1;
    const lastValue = parseInt(arr[lastIndex]) * 2;

    arr.push(lastValue);

    if (lastValue > 32768)
    arr = [1, 2, 4, 8, 16];
    else if (lastIndex > 9)
    arr.slice(0, 1);

    this.set('geometricSequence', arr);






    share|improve this answer








    New contributor



    Holli is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.





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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2














      $begingroup$

      This will be cleaner if you implement it as a pure function, which takes the sequence as an argument. You can make [1, 2, 4, 8, 16] a default value for that argument, so that you can start the sequence with nothing. Taking this approach, the function simplifies to:



      function updateSequence(arr = updateSequence.default) 
      const last = arr[arr.length-1]
      if (last == 32768) return updateSequence.default

      const ret = arr.concat(last * 2)
      return ret.length > 10 ? ret.slice(1) : ret

      updateSequence.default = [1, 2, 4, 8, 16]


      You can test that it works like this:



      // test it
      var arr = updateSequence()
      for (i=0; i<15; i++)
      console.log(arr)
      arr = updateSequence(arr)



      which prints the following:



      [ 1, 2, 4, 8, 16, 32 ]
      [ 1, 2, 4, 8, 16, 32, 64 ]
      [ 1, 2, 4, 8, 16, 32, 64, 128 ]
      [ 1, 2, 4, 8, 16, 32, 64, 128, 256 ]
      [ 1, 2, 4, 8, 16, 32, 64, 128, 256, 512 ]
      [ 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024 ]
      [ 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048 ]
      [ 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096 ]
      [ 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192 ]
      [ 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384 ]
      [ 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768 ]
      [ 1, 2, 4, 8, 16 ]
      [ 1, 2, 4, 8, 16, 32 ]
      [ 1, 2, 4, 8, 16, 32, 64 ]
      [ 1, 2, 4, 8, 16, 32, 64, 128 ]





      share|improve this answer









      $endgroup$



















        2














        $begingroup$

        This will be cleaner if you implement it as a pure function, which takes the sequence as an argument. You can make [1, 2, 4, 8, 16] a default value for that argument, so that you can start the sequence with nothing. Taking this approach, the function simplifies to:



        function updateSequence(arr = updateSequence.default) 
        const last = arr[arr.length-1]
        if (last == 32768) return updateSequence.default

        const ret = arr.concat(last * 2)
        return ret.length > 10 ? ret.slice(1) : ret

        updateSequence.default = [1, 2, 4, 8, 16]


        You can test that it works like this:



        // test it
        var arr = updateSequence()
        for (i=0; i<15; i++)
        console.log(arr)
        arr = updateSequence(arr)



        which prints the following:



        [ 1, 2, 4, 8, 16, 32 ]
        [ 1, 2, 4, 8, 16, 32, 64 ]
        [ 1, 2, 4, 8, 16, 32, 64, 128 ]
        [ 1, 2, 4, 8, 16, 32, 64, 128, 256 ]
        [ 1, 2, 4, 8, 16, 32, 64, 128, 256, 512 ]
        [ 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024 ]
        [ 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048 ]
        [ 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096 ]
        [ 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192 ]
        [ 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384 ]
        [ 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768 ]
        [ 1, 2, 4, 8, 16 ]
        [ 1, 2, 4, 8, 16, 32 ]
        [ 1, 2, 4, 8, 16, 32, 64 ]
        [ 1, 2, 4, 8, 16, 32, 64, 128 ]





        share|improve this answer









        $endgroup$

















          2














          2










          2







          $begingroup$

          This will be cleaner if you implement it as a pure function, which takes the sequence as an argument. You can make [1, 2, 4, 8, 16] a default value for that argument, so that you can start the sequence with nothing. Taking this approach, the function simplifies to:



          function updateSequence(arr = updateSequence.default) 
          const last = arr[arr.length-1]
          if (last == 32768) return updateSequence.default

          const ret = arr.concat(last * 2)
          return ret.length > 10 ? ret.slice(1) : ret

          updateSequence.default = [1, 2, 4, 8, 16]


          You can test that it works like this:



          // test it
          var arr = updateSequence()
          for (i=0; i<15; i++)
          console.log(arr)
          arr = updateSequence(arr)



          which prints the following:



          [ 1, 2, 4, 8, 16, 32 ]
          [ 1, 2, 4, 8, 16, 32, 64 ]
          [ 1, 2, 4, 8, 16, 32, 64, 128 ]
          [ 1, 2, 4, 8, 16, 32, 64, 128, 256 ]
          [ 1, 2, 4, 8, 16, 32, 64, 128, 256, 512 ]
          [ 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024 ]
          [ 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048 ]
          [ 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096 ]
          [ 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192 ]
          [ 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384 ]
          [ 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768 ]
          [ 1, 2, 4, 8, 16 ]
          [ 1, 2, 4, 8, 16, 32 ]
          [ 1, 2, 4, 8, 16, 32, 64 ]
          [ 1, 2, 4, 8, 16, 32, 64, 128 ]





          share|improve this answer









          $endgroup$



          This will be cleaner if you implement it as a pure function, which takes the sequence as an argument. You can make [1, 2, 4, 8, 16] a default value for that argument, so that you can start the sequence with nothing. Taking this approach, the function simplifies to:



          function updateSequence(arr = updateSequence.default) 
          const last = arr[arr.length-1]
          if (last == 32768) return updateSequence.default

          const ret = arr.concat(last * 2)
          return ret.length > 10 ? ret.slice(1) : ret

          updateSequence.default = [1, 2, 4, 8, 16]


          You can test that it works like this:



          // test it
          var arr = updateSequence()
          for (i=0; i<15; i++)
          console.log(arr)
          arr = updateSequence(arr)



          which prints the following:



          [ 1, 2, 4, 8, 16, 32 ]
          [ 1, 2, 4, 8, 16, 32, 64 ]
          [ 1, 2, 4, 8, 16, 32, 64, 128 ]
          [ 1, 2, 4, 8, 16, 32, 64, 128, 256 ]
          [ 1, 2, 4, 8, 16, 32, 64, 128, 256, 512 ]
          [ 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024 ]
          [ 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048 ]
          [ 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096 ]
          [ 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192 ]
          [ 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384 ]
          [ 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768 ]
          [ 1, 2, 4, 8, 16 ]
          [ 1, 2, 4, 8, 16, 32 ]
          [ 1, 2, 4, 8, 16, 32, 64 ]
          [ 1, 2, 4, 8, 16, 32, 64, 128 ]






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 4 hours ago









          JonahJonah

          3,7517 silver badges19 bronze badges




          3,7517 silver badges19 bronze badges


























              1














              $begingroup$

              Since obj.get("geometricSequence"); presumably already contains an array, you can skip the whole shenanigans with the iterator and directly work on that. Also, if you change the order of the if statements at the end you can save some work by not doing slices on an array you eventually gonna replace later anyway. So:



              updateSequence() 
              let arr = this.get("geometricSequence");

              const lastIndex = arr.length - 1;
              const lastValue = parseInt(arr[lastIndex]) * 2;

              arr.push(lastValue);

              if (lastValue > 32768)
              arr = [1, 2, 4, 8, 16];
              else if (lastIndex > 9)
              arr.slice(0, 1);

              this.set('geometricSequence', arr);






              share|improve this answer








              New contributor



              Holli is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.





              $endgroup$



















                1














                $begingroup$

                Since obj.get("geometricSequence"); presumably already contains an array, you can skip the whole shenanigans with the iterator and directly work on that. Also, if you change the order of the if statements at the end you can save some work by not doing slices on an array you eventually gonna replace later anyway. So:



                updateSequence() 
                let arr = this.get("geometricSequence");

                const lastIndex = arr.length - 1;
                const lastValue = parseInt(arr[lastIndex]) * 2;

                arr.push(lastValue);

                if (lastValue > 32768)
                arr = [1, 2, 4, 8, 16];
                else if (lastIndex > 9)
                arr.slice(0, 1);

                this.set('geometricSequence', arr);






                share|improve this answer








                New contributor



                Holli is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





                $endgroup$

















                  1














                  1










                  1







                  $begingroup$

                  Since obj.get("geometricSequence"); presumably already contains an array, you can skip the whole shenanigans with the iterator and directly work on that. Also, if you change the order of the if statements at the end you can save some work by not doing slices on an array you eventually gonna replace later anyway. So:



                  updateSequence() 
                  let arr = this.get("geometricSequence");

                  const lastIndex = arr.length - 1;
                  const lastValue = parseInt(arr[lastIndex]) * 2;

                  arr.push(lastValue);

                  if (lastValue > 32768)
                  arr = [1, 2, 4, 8, 16];
                  else if (lastIndex > 9)
                  arr.slice(0, 1);

                  this.set('geometricSequence', arr);






                  share|improve this answer








                  New contributor



                  Holli is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.





                  $endgroup$



                  Since obj.get("geometricSequence"); presumably already contains an array, you can skip the whole shenanigans with the iterator and directly work on that. Also, if you change the order of the if statements at the end you can save some work by not doing slices on an array you eventually gonna replace later anyway. So:



                  updateSequence() 
                  let arr = this.get("geometricSequence");

                  const lastIndex = arr.length - 1;
                  const lastValue = parseInt(arr[lastIndex]) * 2;

                  arr.push(lastValue);

                  if (lastValue > 32768)
                  arr = [1, 2, 4, 8, 16];
                  else if (lastIndex > 9)
                  arr.slice(0, 1);

                  this.set('geometricSequence', arr);







                  share|improve this answer








                  New contributor



                  Holli is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.








                  share|improve this answer



                  share|improve this answer






                  New contributor



                  Holli is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.








                  answered 8 hours ago









                  HolliHolli

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                  1313 bronze badges




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                      19. јануар Садржај Догађаји Рођења Смрти Празници и дани сећања Види још Референце Мени за навигацијуу

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                      Кастелфранко ди Сопра Становништво Референце Спољашње везе Мени за навигацију43°37′18″ СГШ; 11°33′32″ ИГД / 43.62156° СГШ; 11.55885° ИГД / 43.62156; 11.5588543°37′18″ СГШ; 11°33′32″ ИГД / 43.62156° СГШ; 11.55885° ИГД / 43.62156; 11.558853179688„The GeoNames geographical database”„Istituto Nazionale di Statistica”проширитиууWorldCat156923403n850174324558639-1cb14643287r(подаци)