Number of matrices with bounded products of rows and columnsAsymptotic Formula for a Mertens Style SumLeast prime in an arithmetic progression and the Selberg sieveBest upper bound on the number of divisors of $n$ that are larger than $N$.An upper bound to sum of ratios of gcd's and productsIndependence between the number of prime factors of $n$ and $n+2$On an open problem of GelfondProof of a theorem about the size of the number of sign changes of Hecke eigenvaluesBound on the number of primitive divisors of the $n$th Fibonacci number

Number of matrices with bounded products of rows and columns


Asymptotic Formula for a Mertens Style SumLeast prime in an arithmetic progression and the Selberg sieveBest upper bound on the number of divisors of $n$ that are larger than $N$.An upper bound to sum of ratios of gcd's and productsIndependence between the number of prime factors of $n$ and $n+2$On an open problem of GelfondProof of a theorem about the size of the number of sign changes of Hecke eigenvaluesBound on the number of primitive divisors of the $n$th Fibonacci number













7












$begingroup$


Fix an integer $d geq 2$ and for every real number $x$ let $M_d(x)$ be number of $d times d$ matrices $(a_ij)$ satisfying: every $a_ij$ is a positive integer, the product of every row does not exceed $x$, and the product of every column does not exceed $x$.



I'm looking for a good upper bound for $M_d(x)$ as $x to +infty$.



If we forget about the condition on the columns, since it is well known that the number of $d$-tuples $(b_1, dots, b_d)$ of positive integers satisfying $b_1 cdots b_d leq x$ is $ll_d x (log x)^d - 1$ (a generalization of Dirichlet divisor problem), we get the upper bound
$$M_d(x) ll_d x^d (log x)^d(d-1).$$



In the special case $d = 2$, we have that $a_12, a_21 leq min(x / a_11, x / a_22)$ and consequently
$$M_2(x) leq sum_a_11, a_22 leq x minleft(fracxa_11, fracxa_22right)^2 ll sum_a_11 leq a_22 leq x left(fracxa_22right)^2 ll x^2 log x ,$$
which is a better upper bound than the general one given in the above paragraph. However, I have no idea of how to generalize this trick to $d geq 3$ (if possible).



Has this problem been studied before? Do you have any idea/suggestion about it?










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New contributor



Kate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • $begingroup$
    Do you believe the $2times 2$ bound is sharp?
    $endgroup$
    – Igor Rivin
    9 hours ago










  • $begingroup$
    @IgorRivin I don't have any heuristic supporting such belief.
    $endgroup$
    – Kate
    8 hours ago










  • $begingroup$
    It is obviously not far from sharp, since diagonal matrices give you $x^2.$
    $endgroup$
    – Igor Rivin
    8 hours ago










  • $begingroup$
    What happens when you take logarithms of the aij? Gerhard "Maybe Row-Sum Literature Will Help" Paseman, 2019.08.17.
    $endgroup$
    – Gerhard Paseman
    6 hours ago










  • $begingroup$
    @GerhardPaseman I think logarithms do not help very much. They turn the problem from multiplicative to additive, but the variables are not integers anymore, making things much more difficult...
    $endgroup$
    – Kate
    5 hours ago















7












$begingroup$


Fix an integer $d geq 2$ and for every real number $x$ let $M_d(x)$ be number of $d times d$ matrices $(a_ij)$ satisfying: every $a_ij$ is a positive integer, the product of every row does not exceed $x$, and the product of every column does not exceed $x$.



I'm looking for a good upper bound for $M_d(x)$ as $x to +infty$.



If we forget about the condition on the columns, since it is well known that the number of $d$-tuples $(b_1, dots, b_d)$ of positive integers satisfying $b_1 cdots b_d leq x$ is $ll_d x (log x)^d - 1$ (a generalization of Dirichlet divisor problem), we get the upper bound
$$M_d(x) ll_d x^d (log x)^d(d-1).$$



In the special case $d = 2$, we have that $a_12, a_21 leq min(x / a_11, x / a_22)$ and consequently
$$M_2(x) leq sum_a_11, a_22 leq x minleft(fracxa_11, fracxa_22right)^2 ll sum_a_11 leq a_22 leq x left(fracxa_22right)^2 ll x^2 log x ,$$
which is a better upper bound than the general one given in the above paragraph. However, I have no idea of how to generalize this trick to $d geq 3$ (if possible).



Has this problem been studied before? Do you have any idea/suggestion about it?










share|cite|improve this question









New contributor



Kate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













  • $begingroup$
    Do you believe the $2times 2$ bound is sharp?
    $endgroup$
    – Igor Rivin
    9 hours ago










  • $begingroup$
    @IgorRivin I don't have any heuristic supporting such belief.
    $endgroup$
    – Kate
    8 hours ago










  • $begingroup$
    It is obviously not far from sharp, since diagonal matrices give you $x^2.$
    $endgroup$
    – Igor Rivin
    8 hours ago










  • $begingroup$
    What happens when you take logarithms of the aij? Gerhard "Maybe Row-Sum Literature Will Help" Paseman, 2019.08.17.
    $endgroup$
    – Gerhard Paseman
    6 hours ago










  • $begingroup$
    @GerhardPaseman I think logarithms do not help very much. They turn the problem from multiplicative to additive, but the variables are not integers anymore, making things much more difficult...
    $endgroup$
    – Kate
    5 hours ago













7












7








7





$begingroup$


Fix an integer $d geq 2$ and for every real number $x$ let $M_d(x)$ be number of $d times d$ matrices $(a_ij)$ satisfying: every $a_ij$ is a positive integer, the product of every row does not exceed $x$, and the product of every column does not exceed $x$.



I'm looking for a good upper bound for $M_d(x)$ as $x to +infty$.



If we forget about the condition on the columns, since it is well known that the number of $d$-tuples $(b_1, dots, b_d)$ of positive integers satisfying $b_1 cdots b_d leq x$ is $ll_d x (log x)^d - 1$ (a generalization of Dirichlet divisor problem), we get the upper bound
$$M_d(x) ll_d x^d (log x)^d(d-1).$$



In the special case $d = 2$, we have that $a_12, a_21 leq min(x / a_11, x / a_22)$ and consequently
$$M_2(x) leq sum_a_11, a_22 leq x minleft(fracxa_11, fracxa_22right)^2 ll sum_a_11 leq a_22 leq x left(fracxa_22right)^2 ll x^2 log x ,$$
which is a better upper bound than the general one given in the above paragraph. However, I have no idea of how to generalize this trick to $d geq 3$ (if possible).



Has this problem been studied before? Do you have any idea/suggestion about it?










share|cite|improve this question









New contributor



Kate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




Fix an integer $d geq 2$ and for every real number $x$ let $M_d(x)$ be number of $d times d$ matrices $(a_ij)$ satisfying: every $a_ij$ is a positive integer, the product of every row does not exceed $x$, and the product of every column does not exceed $x$.



I'm looking for a good upper bound for $M_d(x)$ as $x to +infty$.



If we forget about the condition on the columns, since it is well known that the number of $d$-tuples $(b_1, dots, b_d)$ of positive integers satisfying $b_1 cdots b_d leq x$ is $ll_d x (log x)^d - 1$ (a generalization of Dirichlet divisor problem), we get the upper bound
$$M_d(x) ll_d x^d (log x)^d(d-1).$$



In the special case $d = 2$, we have that $a_12, a_21 leq min(x / a_11, x / a_22)$ and consequently
$$M_2(x) leq sum_a_11, a_22 leq x minleft(fracxa_11, fracxa_22right)^2 ll sum_a_11 leq a_22 leq x left(fracxa_22right)^2 ll x^2 log x ,$$
which is a better upper bound than the general one given in the above paragraph. However, I have no idea of how to generalize this trick to $d geq 3$ (if possible).



Has this problem been studied before? Do you have any idea/suggestion about it?







nt.number-theory matrices analytic-number-theory divisors






share|cite|improve this question









New contributor



Kate is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|cite|improve this question









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share|cite|improve this question




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edited 6 hours ago









GH from MO

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asked 9 hours ago









KateKate

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  • $begingroup$
    Do you believe the $2times 2$ bound is sharp?
    $endgroup$
    – Igor Rivin
    9 hours ago










  • $begingroup$
    @IgorRivin I don't have any heuristic supporting such belief.
    $endgroup$
    – Kate
    8 hours ago










  • $begingroup$
    It is obviously not far from sharp, since diagonal matrices give you $x^2.$
    $endgroup$
    – Igor Rivin
    8 hours ago










  • $begingroup$
    What happens when you take logarithms of the aij? Gerhard "Maybe Row-Sum Literature Will Help" Paseman, 2019.08.17.
    $endgroup$
    – Gerhard Paseman
    6 hours ago










  • $begingroup$
    @GerhardPaseman I think logarithms do not help very much. They turn the problem from multiplicative to additive, but the variables are not integers anymore, making things much more difficult...
    $endgroup$
    – Kate
    5 hours ago
















  • $begingroup$
    Do you believe the $2times 2$ bound is sharp?
    $endgroup$
    – Igor Rivin
    9 hours ago










  • $begingroup$
    @IgorRivin I don't have any heuristic supporting such belief.
    $endgroup$
    – Kate
    8 hours ago










  • $begingroup$
    It is obviously not far from sharp, since diagonal matrices give you $x^2.$
    $endgroup$
    – Igor Rivin
    8 hours ago










  • $begingroup$
    What happens when you take logarithms of the aij? Gerhard "Maybe Row-Sum Literature Will Help" Paseman, 2019.08.17.
    $endgroup$
    – Gerhard Paseman
    6 hours ago










  • $begingroup$
    @GerhardPaseman I think logarithms do not help very much. They turn the problem from multiplicative to additive, but the variables are not integers anymore, making things much more difficult...
    $endgroup$
    – Kate
    5 hours ago















$begingroup$
Do you believe the $2times 2$ bound is sharp?
$endgroup$
– Igor Rivin
9 hours ago




$begingroup$
Do you believe the $2times 2$ bound is sharp?
$endgroup$
– Igor Rivin
9 hours ago












$begingroup$
@IgorRivin I don't have any heuristic supporting such belief.
$endgroup$
– Kate
8 hours ago




$begingroup$
@IgorRivin I don't have any heuristic supporting such belief.
$endgroup$
– Kate
8 hours ago












$begingroup$
It is obviously not far from sharp, since diagonal matrices give you $x^2.$
$endgroup$
– Igor Rivin
8 hours ago




$begingroup$
It is obviously not far from sharp, since diagonal matrices give you $x^2.$
$endgroup$
– Igor Rivin
8 hours ago












$begingroup$
What happens when you take logarithms of the aij? Gerhard "Maybe Row-Sum Literature Will Help" Paseman, 2019.08.17.
$endgroup$
– Gerhard Paseman
6 hours ago




$begingroup$
What happens when you take logarithms of the aij? Gerhard "Maybe Row-Sum Literature Will Help" Paseman, 2019.08.17.
$endgroup$
– Gerhard Paseman
6 hours ago












$begingroup$
@GerhardPaseman I think logarithms do not help very much. They turn the problem from multiplicative to additive, but the variables are not integers anymore, making things much more difficult...
$endgroup$
– Kate
5 hours ago




$begingroup$
@GerhardPaseman I think logarithms do not help very much. They turn the problem from multiplicative to additive, but the variables are not integers anymore, making things much more difficult...
$endgroup$
– Kate
5 hours ago










2 Answers
2






active

oldest

votes


















4












$begingroup$

This problem was considered in passing in the proof of Theorem 4.1 in Granville and Soundararajan, see the argument starting at the bottom of page 17. They show (in your notation) that $M_d(x)$ is of order $x^d (log x)^(d-1)^2$. You should also look at work of Harper, Nikeghbali and Radziwill which shows an asymptotic formula for closely related objects (see Theorem 3 there).






share|cite|improve this answer









$endgroup$










  • 1




    $begingroup$
    Thank you very much!
    $endgroup$
    – Kate
    5 hours ago



















3












$begingroup$

Nice question. Some thoughts on lower bounds: for $d=2$, the order of magnitude $x^2log x$ is correct—here is an argument giving such a lower bound.



For any real numbers $U,V$ such that $UV=x$ (and say $U,Vge2$), any $2times 2$ matrix such that $a_11,a_22inbig(frac U2,Ubig]$ and $a_21,a_12inbig(frac V2,Vbig]$ is counted by $M_2(x)$, and the number of such matrices is $gg U^2V^2 = x^2$. We can sum this dyadic-interval lower bound over $U=2^k$ for a suitable range of $k$ to obtain the lower bound $M_2(x) gg x^2log x$.



A similar argument gives a lower bound for general $dge3$. If $U_1U_2cdots U_d=x$, with the convention that $U_d+j=U_j$, then the matrices such that $a_ij in big( fracU_i+j2, U_i+jbig]$ for all $1le i,jle d$ contribute $gg U_1^d cdots U_d^d = x^d$ to $M_d(x)$. We then sum over all $U_1=2^k_1,dots,U_d=2^k_d$ such that $k_1+cdots+k_dle(log x)/log 2$; the number of such $d$-tuples of positive integers is $gg_d(log x)^d$, giving the lower bound $M_d(x) gg_d x^d(log x)^d$.






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    2 Answers
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    2 Answers
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    4












    $begingroup$

    This problem was considered in passing in the proof of Theorem 4.1 in Granville and Soundararajan, see the argument starting at the bottom of page 17. They show (in your notation) that $M_d(x)$ is of order $x^d (log x)^(d-1)^2$. You should also look at work of Harper, Nikeghbali and Radziwill which shows an asymptotic formula for closely related objects (see Theorem 3 there).






    share|cite|improve this answer









    $endgroup$










    • 1




      $begingroup$
      Thank you very much!
      $endgroup$
      – Kate
      5 hours ago
















    4












    $begingroup$

    This problem was considered in passing in the proof of Theorem 4.1 in Granville and Soundararajan, see the argument starting at the bottom of page 17. They show (in your notation) that $M_d(x)$ is of order $x^d (log x)^(d-1)^2$. You should also look at work of Harper, Nikeghbali and Radziwill which shows an asymptotic formula for closely related objects (see Theorem 3 there).






    share|cite|improve this answer









    $endgroup$










    • 1




      $begingroup$
      Thank you very much!
      $endgroup$
      – Kate
      5 hours ago














    4












    4








    4





    $begingroup$

    This problem was considered in passing in the proof of Theorem 4.1 in Granville and Soundararajan, see the argument starting at the bottom of page 17. They show (in your notation) that $M_d(x)$ is of order $x^d (log x)^(d-1)^2$. You should also look at work of Harper, Nikeghbali and Radziwill which shows an asymptotic formula for closely related objects (see Theorem 3 there).






    share|cite|improve this answer









    $endgroup$



    This problem was considered in passing in the proof of Theorem 4.1 in Granville and Soundararajan, see the argument starting at the bottom of page 17. They show (in your notation) that $M_d(x)$ is of order $x^d (log x)^(d-1)^2$. You should also look at work of Harper, Nikeghbali and Radziwill which shows an asymptotic formula for closely related objects (see Theorem 3 there).







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered 5 hours ago









    LuciaLucia

    36.5k5 gold badges157 silver badges185 bronze badges




    36.5k5 gold badges157 silver badges185 bronze badges










    • 1




      $begingroup$
      Thank you very much!
      $endgroup$
      – Kate
      5 hours ago













    • 1




      $begingroup$
      Thank you very much!
      $endgroup$
      – Kate
      5 hours ago








    1




    1




    $begingroup$
    Thank you very much!
    $endgroup$
    – Kate
    5 hours ago





    $begingroup$
    Thank you very much!
    $endgroup$
    – Kate
    5 hours ago












    3












    $begingroup$

    Nice question. Some thoughts on lower bounds: for $d=2$, the order of magnitude $x^2log x$ is correct—here is an argument giving such a lower bound.



    For any real numbers $U,V$ such that $UV=x$ (and say $U,Vge2$), any $2times 2$ matrix such that $a_11,a_22inbig(frac U2,Ubig]$ and $a_21,a_12inbig(frac V2,Vbig]$ is counted by $M_2(x)$, and the number of such matrices is $gg U^2V^2 = x^2$. We can sum this dyadic-interval lower bound over $U=2^k$ for a suitable range of $k$ to obtain the lower bound $M_2(x) gg x^2log x$.



    A similar argument gives a lower bound for general $dge3$. If $U_1U_2cdots U_d=x$, with the convention that $U_d+j=U_j$, then the matrices such that $a_ij in big( fracU_i+j2, U_i+jbig]$ for all $1le i,jle d$ contribute $gg U_1^d cdots U_d^d = x^d$ to $M_d(x)$. We then sum over all $U_1=2^k_1,dots,U_d=2^k_d$ such that $k_1+cdots+k_dle(log x)/log 2$; the number of such $d$-tuples of positive integers is $gg_d(log x)^d$, giving the lower bound $M_d(x) gg_d x^d(log x)^d$.






    share|cite|improve this answer











    $endgroup$



















      3












      $begingroup$

      Nice question. Some thoughts on lower bounds: for $d=2$, the order of magnitude $x^2log x$ is correct—here is an argument giving such a lower bound.



      For any real numbers $U,V$ such that $UV=x$ (and say $U,Vge2$), any $2times 2$ matrix such that $a_11,a_22inbig(frac U2,Ubig]$ and $a_21,a_12inbig(frac V2,Vbig]$ is counted by $M_2(x)$, and the number of such matrices is $gg U^2V^2 = x^2$. We can sum this dyadic-interval lower bound over $U=2^k$ for a suitable range of $k$ to obtain the lower bound $M_2(x) gg x^2log x$.



      A similar argument gives a lower bound for general $dge3$. If $U_1U_2cdots U_d=x$, with the convention that $U_d+j=U_j$, then the matrices such that $a_ij in big( fracU_i+j2, U_i+jbig]$ for all $1le i,jle d$ contribute $gg U_1^d cdots U_d^d = x^d$ to $M_d(x)$. We then sum over all $U_1=2^k_1,dots,U_d=2^k_d$ such that $k_1+cdots+k_dle(log x)/log 2$; the number of such $d$-tuples of positive integers is $gg_d(log x)^d$, giving the lower bound $M_d(x) gg_d x^d(log x)^d$.






      share|cite|improve this answer











      $endgroup$

















        3












        3








        3





        $begingroup$

        Nice question. Some thoughts on lower bounds: for $d=2$, the order of magnitude $x^2log x$ is correct—here is an argument giving such a lower bound.



        For any real numbers $U,V$ such that $UV=x$ (and say $U,Vge2$), any $2times 2$ matrix such that $a_11,a_22inbig(frac U2,Ubig]$ and $a_21,a_12inbig(frac V2,Vbig]$ is counted by $M_2(x)$, and the number of such matrices is $gg U^2V^2 = x^2$. We can sum this dyadic-interval lower bound over $U=2^k$ for a suitable range of $k$ to obtain the lower bound $M_2(x) gg x^2log x$.



        A similar argument gives a lower bound for general $dge3$. If $U_1U_2cdots U_d=x$, with the convention that $U_d+j=U_j$, then the matrices such that $a_ij in big( fracU_i+j2, U_i+jbig]$ for all $1le i,jle d$ contribute $gg U_1^d cdots U_d^d = x^d$ to $M_d(x)$. We then sum over all $U_1=2^k_1,dots,U_d=2^k_d$ such that $k_1+cdots+k_dle(log x)/log 2$; the number of such $d$-tuples of positive integers is $gg_d(log x)^d$, giving the lower bound $M_d(x) gg_d x^d(log x)^d$.






        share|cite|improve this answer











        $endgroup$



        Nice question. Some thoughts on lower bounds: for $d=2$, the order of magnitude $x^2log x$ is correct—here is an argument giving such a lower bound.



        For any real numbers $U,V$ such that $UV=x$ (and say $U,Vge2$), any $2times 2$ matrix such that $a_11,a_22inbig(frac U2,Ubig]$ and $a_21,a_12inbig(frac V2,Vbig]$ is counted by $M_2(x)$, and the number of such matrices is $gg U^2V^2 = x^2$. We can sum this dyadic-interval lower bound over $U=2^k$ for a suitable range of $k$ to obtain the lower bound $M_2(x) gg x^2log x$.



        A similar argument gives a lower bound for general $dge3$. If $U_1U_2cdots U_d=x$, with the convention that $U_d+j=U_j$, then the matrices such that $a_ij in big( fracU_i+j2, U_i+jbig]$ for all $1le i,jle d$ contribute $gg U_1^d cdots U_d^d = x^d$ to $M_d(x)$. We then sum over all $U_1=2^k_1,dots,U_d=2^k_d$ such that $k_1+cdots+k_dle(log x)/log 2$; the number of such $d$-tuples of positive integers is $gg_d(log x)^d$, giving the lower bound $M_d(x) gg_d x^d(log x)^d$.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited 5 hours ago

























        answered 6 hours ago









        Greg MartinGreg Martin

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