Write The Shortest Program To Check If A Binary Tree Is BalancedConvert binary search tree into ordered linked listPrint a non-clashing binary search treeTree traversingPre-order + post-order to in-orderIs it a Linearized Tree? (Breadth-first Edition)Compute the height of a radix treeRooting for Trees With the Right NodesBinary tree rotationsIs this a BST pre-order traversal?Write The Shortest Program to Calculate Height of a Binary Tree

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Write The Shortest Program To Check If A Binary Tree Is Balanced


Convert binary search tree into ordered linked listPrint a non-clashing binary search treeTree traversingPre-order + post-order to in-orderIs it a Linearized Tree? (Breadth-first Edition)Compute the height of a radix treeRooting for Trees With the Right NodesBinary tree rotationsIs this a BST pre-order traversal?Write The Shortest Program to Calculate Height of a Binary Tree






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








2












$begingroup$


For each node in a balanced, binary tree, the maximum difference in the heights of the left child subtree and the right child subtree are at most 1.



The height of a binary tree is the distance from the root node to the node child that is farthest from the root.



Below is an example:



 2 <-- root: Height 1
/
7 5 <-- Height 2
/
2 6 9 <-- Height 3
/ /
5 11 4 <-- Height 4


Height of binary tree: 4



The following are binary trees and a report on whether or not they are balanced:



Test Case 1



The tree above is unbalanced.



Test Case 2



The above tree is balanced.



Write the shortest program possible that accepts as input the root of a binary tree and returns a falsey value if the tree is unbalanced and a truthy value if the tree is balanced.



Input



The root of a binary tree. This may be in the form of a reference to the root object or even a list that is a valid representation of a binary tree.



Output



Returns truthy value: If the tree is balanced



Returns falsey value: If the tree is unbalanced.



Definition of a Binary Tree



A tree is an object that contains a value and either two other trees or pointers to them.



The structure of the binary tree looks something like the following:



typedef struct T

struct T *l;
struct T *r;
int v;
T;


If using a list representation for a binary tree, it may look something like the following:



[root_value, left_node, right_node]









share|improve this question







New contributor



T. Salim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




















    2












    $begingroup$


    For each node in a balanced, binary tree, the maximum difference in the heights of the left child subtree and the right child subtree are at most 1.



    The height of a binary tree is the distance from the root node to the node child that is farthest from the root.



    Below is an example:



     2 <-- root: Height 1
    /
    7 5 <-- Height 2
    /
    2 6 9 <-- Height 3
    / /
    5 11 4 <-- Height 4


    Height of binary tree: 4



    The following are binary trees and a report on whether or not they are balanced:



    Test Case 1



    The tree above is unbalanced.



    Test Case 2



    The above tree is balanced.



    Write the shortest program possible that accepts as input the root of a binary tree and returns a falsey value if the tree is unbalanced and a truthy value if the tree is balanced.



    Input



    The root of a binary tree. This may be in the form of a reference to the root object or even a list that is a valid representation of a binary tree.



    Output



    Returns truthy value: If the tree is balanced



    Returns falsey value: If the tree is unbalanced.



    Definition of a Binary Tree



    A tree is an object that contains a value and either two other trees or pointers to them.



    The structure of the binary tree looks something like the following:



    typedef struct T

    struct T *l;
    struct T *r;
    int v;
    T;


    If using a list representation for a binary tree, it may look something like the following:



    [root_value, left_node, right_node]









    share|improve this question







    New contributor



    T. Salim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$
















      2












      2








      2





      $begingroup$


      For each node in a balanced, binary tree, the maximum difference in the heights of the left child subtree and the right child subtree are at most 1.



      The height of a binary tree is the distance from the root node to the node child that is farthest from the root.



      Below is an example:



       2 <-- root: Height 1
      /
      7 5 <-- Height 2
      /
      2 6 9 <-- Height 3
      / /
      5 11 4 <-- Height 4


      Height of binary tree: 4



      The following are binary trees and a report on whether or not they are balanced:



      Test Case 1



      The tree above is unbalanced.



      Test Case 2



      The above tree is balanced.



      Write the shortest program possible that accepts as input the root of a binary tree and returns a falsey value if the tree is unbalanced and a truthy value if the tree is balanced.



      Input



      The root of a binary tree. This may be in the form of a reference to the root object or even a list that is a valid representation of a binary tree.



      Output



      Returns truthy value: If the tree is balanced



      Returns falsey value: If the tree is unbalanced.



      Definition of a Binary Tree



      A tree is an object that contains a value and either two other trees or pointers to them.



      The structure of the binary tree looks something like the following:



      typedef struct T

      struct T *l;
      struct T *r;
      int v;
      T;


      If using a list representation for a binary tree, it may look something like the following:



      [root_value, left_node, right_node]









      share|improve this question







      New contributor



      T. Salim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      $endgroup$




      For each node in a balanced, binary tree, the maximum difference in the heights of the left child subtree and the right child subtree are at most 1.



      The height of a binary tree is the distance from the root node to the node child that is farthest from the root.



      Below is an example:



       2 <-- root: Height 1
      /
      7 5 <-- Height 2
      /
      2 6 9 <-- Height 3
      / /
      5 11 4 <-- Height 4


      Height of binary tree: 4



      The following are binary trees and a report on whether or not they are balanced:



      Test Case 1



      The tree above is unbalanced.



      Test Case 2



      The above tree is balanced.



      Write the shortest program possible that accepts as input the root of a binary tree and returns a falsey value if the tree is unbalanced and a truthy value if the tree is balanced.



      Input



      The root of a binary tree. This may be in the form of a reference to the root object or even a list that is a valid representation of a binary tree.



      Output



      Returns truthy value: If the tree is balanced



      Returns falsey value: If the tree is unbalanced.



      Definition of a Binary Tree



      A tree is an object that contains a value and either two other trees or pointers to them.



      The structure of the binary tree looks something like the following:



      typedef struct T

      struct T *l;
      struct T *r;
      int v;
      T;


      If using a list representation for a binary tree, it may look something like the following:



      [root_value, left_node, right_node]






      code-golf binary-tree tree-traversal






      share|improve this question







      New contributor



      T. Salim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share|improve this question







      New contributor



      T. Salim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share|improve this question




      share|improve this question






      New contributor



      T. Salim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      asked 8 hours ago









      T. SalimT. Salim

      1401 silver badge9 bronze badges




      1401 silver badge9 bronze badges




      New contributor



      T. Salim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      T. Salim is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.

























          3 Answers
          3






          active

          oldest

          votes


















          4












          $begingroup$


          Jelly, 11 bytes



          ḊµŒḊ€IỊ;߀Ạ


          Try it online!



          The empty tree is represented by [].






          share|improve this answer









          $endgroup$














          • $begingroup$
            Thanks Erik for being amongst the first to answer this question. Jelly certainly is a very popular language on this site. I think I should take the liberty to implement this language. Good to learn from a robust golf-scripting language.
            $endgroup$
            – T. Salim
            6 hours ago


















          1












          $begingroup$


          Prolog (SWI), 49 bytes



          N+_/B/C:-X+B,Y+C,abs(X-Y)<2,N is max(X,Y)+1.
          0+e.


          Try it online!



          Represents trees as Value/Left_Child/Right_Child, with the empty tree being the atom e. Defines +/2, which outputs through success or failure, with an unbound variable (or one already equal to the tree's height) on the left and the tree on the right--if the height argument is unacceptable, add 9 bytes to define -T:-_+T..



          N + _/B/C :- % If the second argument is a tree of the form _Value/B/C,
          X+B, % X is the height of its left child which is balanced,
          Y+C, % Y is the height of its right child which is balanced,
          abs(X-Y) < 2, % the absolute difference between X and Y is strictly less than 2,
          N is max(X,Y)+1. % and N is the height of the full tree.
          0 + e. % If, on the other hand, the second argument is e, the first is 0.





          share|improve this answer









          $endgroup$






















            1












            $begingroup$

            JavaScript, 162 bytes





            f=x=>for(f=0,s=[[x,1]];s[0];)if(!((d=(t=s.pop())[0]).a&&d.breturn 1


            Try it online!



            The format of the input is an object



            root=a:node,b:node,c:value


            Explanation



            for(f=0,s=[[x,1]];s[0];)


            Continuing the breadth first search, return zero if any element is two deeper than the depth of the first node missing branches.



            return 1}


            If no such node is found, return 1






            share|improve this answer











            $endgroup$










            • 1




              $begingroup$
              There is probably some way to do the breadth first search better but I couldn't think of it.
              $endgroup$
              – fəˈnɛtɪk
              5 hours ago













            Your Answer






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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            4












            $begingroup$


            Jelly, 11 bytes



            ḊµŒḊ€IỊ;߀Ạ


            Try it online!



            The empty tree is represented by [].






            share|improve this answer









            $endgroup$














            • $begingroup$
              Thanks Erik for being amongst the first to answer this question. Jelly certainly is a very popular language on this site. I think I should take the liberty to implement this language. Good to learn from a robust golf-scripting language.
              $endgroup$
              – T. Salim
              6 hours ago















            4












            $begingroup$


            Jelly, 11 bytes



            ḊµŒḊ€IỊ;߀Ạ


            Try it online!



            The empty tree is represented by [].






            share|improve this answer









            $endgroup$














            • $begingroup$
              Thanks Erik for being amongst the first to answer this question. Jelly certainly is a very popular language on this site. I think I should take the liberty to implement this language. Good to learn from a robust golf-scripting language.
              $endgroup$
              – T. Salim
              6 hours ago













            4












            4








            4





            $begingroup$


            Jelly, 11 bytes



            ḊµŒḊ€IỊ;߀Ạ


            Try it online!



            The empty tree is represented by [].






            share|improve this answer









            $endgroup$




            Jelly, 11 bytes



            ḊµŒḊ€IỊ;߀Ạ


            Try it online!



            The empty tree is represented by [].







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 8 hours ago









            Erik the OutgolferErik the Outgolfer

            35.2k4 gold badges30 silver badges110 bronze badges




            35.2k4 gold badges30 silver badges110 bronze badges














            • $begingroup$
              Thanks Erik for being amongst the first to answer this question. Jelly certainly is a very popular language on this site. I think I should take the liberty to implement this language. Good to learn from a robust golf-scripting language.
              $endgroup$
              – T. Salim
              6 hours ago
















            • $begingroup$
              Thanks Erik for being amongst the first to answer this question. Jelly certainly is a very popular language on this site. I think I should take the liberty to implement this language. Good to learn from a robust golf-scripting language.
              $endgroup$
              – T. Salim
              6 hours ago















            $begingroup$
            Thanks Erik for being amongst the first to answer this question. Jelly certainly is a very popular language on this site. I think I should take the liberty to implement this language. Good to learn from a robust golf-scripting language.
            $endgroup$
            – T. Salim
            6 hours ago




            $begingroup$
            Thanks Erik for being amongst the first to answer this question. Jelly certainly is a very popular language on this site. I think I should take the liberty to implement this language. Good to learn from a robust golf-scripting language.
            $endgroup$
            – T. Salim
            6 hours ago













            1












            $begingroup$


            Prolog (SWI), 49 bytes



            N+_/B/C:-X+B,Y+C,abs(X-Y)<2,N is max(X,Y)+1.
            0+e.


            Try it online!



            Represents trees as Value/Left_Child/Right_Child, with the empty tree being the atom e. Defines +/2, which outputs through success or failure, with an unbound variable (or one already equal to the tree's height) on the left and the tree on the right--if the height argument is unacceptable, add 9 bytes to define -T:-_+T..



            N + _/B/C :- % If the second argument is a tree of the form _Value/B/C,
            X+B, % X is the height of its left child which is balanced,
            Y+C, % Y is the height of its right child which is balanced,
            abs(X-Y) < 2, % the absolute difference between X and Y is strictly less than 2,
            N is max(X,Y)+1. % and N is the height of the full tree.
            0 + e. % If, on the other hand, the second argument is e, the first is 0.





            share|improve this answer









            $endgroup$



















              1












              $begingroup$


              Prolog (SWI), 49 bytes



              N+_/B/C:-X+B,Y+C,abs(X-Y)<2,N is max(X,Y)+1.
              0+e.


              Try it online!



              Represents trees as Value/Left_Child/Right_Child, with the empty tree being the atom e. Defines +/2, which outputs through success or failure, with an unbound variable (or one already equal to the tree's height) on the left and the tree on the right--if the height argument is unacceptable, add 9 bytes to define -T:-_+T..



              N + _/B/C :- % If the second argument is a tree of the form _Value/B/C,
              X+B, % X is the height of its left child which is balanced,
              Y+C, % Y is the height of its right child which is balanced,
              abs(X-Y) < 2, % the absolute difference between X and Y is strictly less than 2,
              N is max(X,Y)+1. % and N is the height of the full tree.
              0 + e. % If, on the other hand, the second argument is e, the first is 0.





              share|improve this answer









              $endgroup$

















                1












                1








                1





                $begingroup$


                Prolog (SWI), 49 bytes



                N+_/B/C:-X+B,Y+C,abs(X-Y)<2,N is max(X,Y)+1.
                0+e.


                Try it online!



                Represents trees as Value/Left_Child/Right_Child, with the empty tree being the atom e. Defines +/2, which outputs through success or failure, with an unbound variable (or one already equal to the tree's height) on the left and the tree on the right--if the height argument is unacceptable, add 9 bytes to define -T:-_+T..



                N + _/B/C :- % If the second argument is a tree of the form _Value/B/C,
                X+B, % X is the height of its left child which is balanced,
                Y+C, % Y is the height of its right child which is balanced,
                abs(X-Y) < 2, % the absolute difference between X and Y is strictly less than 2,
                N is max(X,Y)+1. % and N is the height of the full tree.
                0 + e. % If, on the other hand, the second argument is e, the first is 0.





                share|improve this answer









                $endgroup$




                Prolog (SWI), 49 bytes



                N+_/B/C:-X+B,Y+C,abs(X-Y)<2,N is max(X,Y)+1.
                0+e.


                Try it online!



                Represents trees as Value/Left_Child/Right_Child, with the empty tree being the atom e. Defines +/2, which outputs through success or failure, with an unbound variable (or one already equal to the tree's height) on the left and the tree on the right--if the height argument is unacceptable, add 9 bytes to define -T:-_+T..



                N + _/B/C :- % If the second argument is a tree of the form _Value/B/C,
                X+B, % X is the height of its left child which is balanced,
                Y+C, % Y is the height of its right child which is balanced,
                abs(X-Y) < 2, % the absolute difference between X and Y is strictly less than 2,
                N is max(X,Y)+1. % and N is the height of the full tree.
                0 + e. % If, on the other hand, the second argument is e, the first is 0.






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 7 hours ago









                Unrelated StringUnrelated String

                3,1252 gold badges3 silver badges16 bronze badges




                3,1252 gold badges3 silver badges16 bronze badges
























                    1












                    $begingroup$

                    JavaScript, 162 bytes





                    f=x=>for(f=0,s=[[x,1]];s[0];)if(!((d=(t=s.pop())[0]).a&&d.breturn 1


                    Try it online!



                    The format of the input is an object



                    root=a:node,b:node,c:value


                    Explanation



                    for(f=0,s=[[x,1]];s[0];)


                    Continuing the breadth first search, return zero if any element is two deeper than the depth of the first node missing branches.



                    return 1}


                    If no such node is found, return 1






                    share|improve this answer











                    $endgroup$










                    • 1




                      $begingroup$
                      There is probably some way to do the breadth first search better but I couldn't think of it.
                      $endgroup$
                      – fəˈnɛtɪk
                      5 hours ago















                    1












                    $begingroup$

                    JavaScript, 162 bytes





                    f=x=>for(f=0,s=[[x,1]];s[0];)if(!((d=(t=s.pop())[0]).a&&d.breturn 1


                    Try it online!



                    The format of the input is an object



                    root=a:node,b:node,c:value


                    Explanation



                    for(f=0,s=[[x,1]];s[0];)


                    Continuing the breadth first search, return zero if any element is two deeper than the depth of the first node missing branches.



                    return 1}


                    If no such node is found, return 1






                    share|improve this answer











                    $endgroup$










                    • 1




                      $begingroup$
                      There is probably some way to do the breadth first search better but I couldn't think of it.
                      $endgroup$
                      – fəˈnɛtɪk
                      5 hours ago













                    1












                    1








                    1





                    $begingroup$

                    JavaScript, 162 bytes





                    f=x=>for(f=0,s=[[x,1]];s[0];)if(!((d=(t=s.pop())[0]).a&&d.breturn 1


                    Try it online!



                    The format of the input is an object



                    root=a:node,b:node,c:value


                    Explanation



                    for(f=0,s=[[x,1]];s[0];)


                    Continuing the breadth first search, return zero if any element is two deeper than the depth of the first node missing branches.



                    return 1}


                    If no such node is found, return 1






                    share|improve this answer











                    $endgroup$



                    JavaScript, 162 bytes





                    f=x=>for(f=0,s=[[x,1]];s[0];)if(!((d=(t=s.pop())[0]).a&&d.breturn 1


                    Try it online!



                    The format of the input is an object



                    root=a:node,b:node,c:value


                    Explanation



                    for(f=0,s=[[x,1]];s[0];)


                    Continuing the breadth first search, return zero if any element is two deeper than the depth of the first node missing branches.



                    return 1}


                    If no such node is found, return 1







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 5 hours ago

























                    answered 6 hours ago









                    fəˈnɛtɪkfəˈnɛtɪk

                    3,7362 gold badges6 silver badges37 bronze badges




                    3,7362 gold badges6 silver badges37 bronze badges










                    • 1




                      $begingroup$
                      There is probably some way to do the breadth first search better but I couldn't think of it.
                      $endgroup$
                      – fəˈnɛtɪk
                      5 hours ago












                    • 1




                      $begingroup$
                      There is probably some way to do the breadth first search better but I couldn't think of it.
                      $endgroup$
                      – fəˈnɛtɪk
                      5 hours ago







                    1




                    1




                    $begingroup$
                    There is probably some way to do the breadth first search better but I couldn't think of it.
                    $endgroup$
                    – fəˈnɛtɪk
                    5 hours ago




                    $begingroup$
                    There is probably some way to do the breadth first search better but I couldn't think of it.
                    $endgroup$
                    – fəˈnɛtɪk
                    5 hours ago










                    T. Salim is a new contributor. Be nice, and check out our Code of Conduct.









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                    T. Salim is a new contributor. Be nice, and check out our Code of Conduct.












                    T. Salim is a new contributor. Be nice, and check out our Code of Conduct.











                    T. Salim is a new contributor. Be nice, and check out our Code of Conduct.














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