Fibonacci sequence calculator seems correct but can't find similar code online. Is there something wrong?What is Sum of Even Terms In Fibonacci (<4million)? [Large Value Datatype Confusion]Python: Odd behavior with modulo operatorWhat's wrong with my Fibonacci sequence generator?What is wrong with my Fibonacci sequence calculation in Python?Quitting a loopAdding together the values of the elements in a vector in RWriting a method which returns the specified Fibonacci number?Fibonacci sequence calculator pythonFor below code, after certain period i am getting -ve values as output for +ve integer input. can anyone please explain the reason behind this?How to print the Fibonacci sequence, skipping every fourth number, replaces the skips with X and starts from 0
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Fibonacci sequence calculator seems correct but can't find similar code online. Is there something wrong?
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Fibonacci sequence calculator seems correct but can't find similar code online. Is there something wrong?
What is Sum of Even Terms In Fibonacci (<4million)? [Large Value Datatype Confusion]Python: Odd behavior with modulo operatorWhat's wrong with my Fibonacci sequence generator?What is wrong with my Fibonacci sequence calculation in Python?Quitting a loopAdding together the values of the elements in a vector in RWriting a method which returns the specified Fibonacci number?Fibonacci sequence calculator pythonFor below code, after certain period i am getting -ve values as output for +ve integer input. can anyone please explain the reason behind this?How to print the Fibonacci sequence, skipping every fourth number, replaces the skips with X and starts from 0
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I made a simple Fibonacci sequence calculator for the first 22 terms:
i=1
n=0
while i<=20000:
i = i + n
n = i - n
print(i)
Looks like the result is correct
1
2
3
5
8
13
21
34
55
89
144
233
377
610
987
1597
2584
4181
6765
10946
17711
28657
but I can't seem to find similar code anywhere online. I think that's a big red flag. Can someone tell me what is wrong here? Is this inefficient code?
python fibonacci
asked 5 hours ago
fibonaccipistaccifibonaccipistacci
311
New contributor
fibonaccipistacci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I made a simple Fibonacci sequence calculator for the first 22 terms:
i=1
n=0
while i<=20000:
i = i + n
n = i - n
print(i)
Looks like the result is correct
1
2
3
5
8
13
21
34
55
89
144
233
377
610
987
1597
2584
4181
6765
10946
17711
28657
but I can't seem to find similar code anywhere online. I think that's a big red flag. Can someone tell me what is wrong here? Is this inefficient code?
python fibonacci
asked 5 hours ago
fibonaccipistaccifibonaccipistacci
311
New contributor
fibonaccipistacci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I made a simple Fibonacci sequence calculator for the first 22 terms:
i=1
n=0
while i<=20000:
i = i + n
n = i - n
print(i)
Looks like the result is correct
1
2
3
5
8
13
21
34
55
89
144
233
377
610
987
1597
2584
4181
6765
10946
17711
28657
but I can't seem to find similar code anywhere online. I think that's a big red flag. Can someone tell me what is wrong here? Is this inefficient code?
python fibonacci
asked 5 hours ago
fibonaccipistaccifibonaccipistacci
311
New contributor
fibonaccipistacci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I made a simple Fibonacci sequence calculator for the first 22 terms:
i=1
n=0
while i<=20000:
i = i + n
n = i - n
print(i)
Looks like the result is correct
1
2
3
5
8
13
21
34
55
89
144
233
377
610
987
1597
2584
4181
6765
10946
17711
28657
but I can't seem to find similar code anywhere online. I think that's a big red flag. Can someone tell me what is wrong here? Is this inefficient code?
python fibonacci
python fibonacci
asked 5 hours ago
fibonaccipistaccifibonaccipistacci
311
New contributor
fibonaccipistacci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
fibonaccipistaccifibonaccipistacci
311
New contributor
fibonaccipistacci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
fibonaccipistaccifibonaccipistacci
311
New contributor
fibonaccipistacci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
fibonaccipistaccifibonaccipistacci
311
asked 5 hours ago
fibonaccipistaccifibonaccipistacci
311
311
New contributor
fibonaccipistacci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
fibonaccipistacci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
2 Answers
2
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oldest
votes
No, that code is fine. The probable reason you can't find similar code online is that it's unusual to use the subtraction operator in Fibonacci, which is a purely additive function, tn = tn-2 + tn-1.
It works, of course, since addition/subtraction is both commutative and associative, meaning that order and grouping of terms is unimportant:
i = i + n # iNew = iOld + nOld
n = i - n # nNew = (iNew) - nOld
# = (iOld + nOld) - nOld
# = iOld + (nOld - nOld)
# = iOld + (0)
# = iOld
Use of subtraction allows you to bypass needing a third variable, which would be something like this in a lesser language than Python:
nextN = i + n
i = n
n = nextN
In Python, you don't actually need that since you can use tuple assignment such as:
(n, i) = (i, n + i)
With that, everything on the right of the = is evaluated before any assignments to the left.
answered 5 hours ago
paxdiablopaxdiablo
648k17912691695
add a comment |
It's an unusual way to do it, but it's correct. Your lines:
i = i + n
n = i - n
are the same as doing:
new_i = i + n
n = i
i = new_i
or,
i, n = i + n, i
which would be the usual way in Python.
edited 3 mins ago
cs95
145k25177257
answered 5 hours ago
Ned BatchelderNed Batchelder
265k53450572
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
No, that code is fine. The probable reason you can't find similar code online is that it's unusual to use the subtraction operator in Fibonacci, which is a purely additive function, tn = tn-2 + tn-1.
It works, of course, since addition/subtraction is both commutative and associative, meaning that order and grouping of terms is unimportant:
i = i + n # iNew = iOld + nOld
n = i - n # nNew = (iNew) - nOld
# = (iOld + nOld) - nOld
# = iOld + (nOld - nOld)
# = iOld + (0)
# = iOld
Use of subtraction allows you to bypass needing a third variable, which would be something like this in a lesser language than Python:
nextN = i + n
i = n
n = nextN
In Python, you don't actually need that since you can use tuple assignment such as:
(n, i) = (i, n + i)
With that, everything on the right of the = is evaluated before any assignments to the left.
answered 5 hours ago
paxdiablopaxdiablo
648k17912691695
add a comment |
No, that code is fine. The probable reason you can't find similar code online is that it's unusual to use the subtraction operator in Fibonacci, which is a purely additive function, tn = tn-2 + tn-1.
It works, of course, since addition/subtraction is both commutative and associative, meaning that order and grouping of terms is unimportant:
i = i + n # iNew = iOld + nOld
n = i - n # nNew = (iNew) - nOld
# = (iOld + nOld) - nOld
# = iOld + (nOld - nOld)
# = iOld + (0)
# = iOld
Use of subtraction allows you to bypass needing a third variable, which would be something like this in a lesser language than Python:
nextN = i + n
i = n
n = nextN
In Python, you don't actually need that since you can use tuple assignment such as:
(n, i) = (i, n + i)
With that, everything on the right of the = is evaluated before any assignments to the left.
answered 5 hours ago
paxdiablopaxdiablo
648k17912691695
add a comment |
No, that code is fine. The probable reason you can't find similar code online is that it's unusual to use the subtraction operator in Fibonacci, which is a purely additive function, tn = tn-2 + tn-1.
It works, of course, since addition/subtraction is both commutative and associative, meaning that order and grouping of terms is unimportant:
i = i + n # iNew = iOld + nOld
n = i - n # nNew = (iNew) - nOld
# = (iOld + nOld) - nOld
# = iOld + (nOld - nOld)
# = iOld + (0)
# = iOld
Use of subtraction allows you to bypass needing a third variable, which would be something like this in a lesser language than Python:
nextN = i + n
i = n
n = nextN
In Python, you don't actually need that since you can use tuple assignment such as:
(n, i) = (i, n + i)
With that, everything on the right of the = is evaluated before any assignments to the left.
answered 5 hours ago
paxdiablopaxdiablo
648k17912691695
No, that code is fine. The probable reason you can't find similar code online is that it's unusual to use the subtraction operator in Fibonacci, which is a purely additive function, tn = tn-2 + tn-1.
It works, of course, since addition/subtraction is both commutative and associative, meaning that order and grouping of terms is unimportant:
i = i + n # iNew = iOld + nOld
n = i - n # nNew = (iNew) - nOld
# = (iOld + nOld) - nOld
# = iOld + (nOld - nOld)
# = iOld + (0)
# = iOld
Use of subtraction allows you to bypass needing a third variable, which would be something like this in a lesser language than Python:
nextN = i + n
i = n
n = nextN
In Python, you don't actually need that since you can use tuple assignment such as:
(n, i) = (i, n + i)
With that, everything on the right of the = is evaluated before any assignments to the left.
answered 5 hours ago
paxdiablopaxdiablo
648k17912691695
edited 39 mins ago
answered 5 hours ago
paxdiablopaxdiablo
648k17912691695
answered 5 hours ago
paxdiablopaxdiablo
648k17912691695
answered 5 hours ago
paxdiablopaxdiablo
648k17912691695
648k17912691695
add a comment |
add a comment |
It's an unusual way to do it, but it's correct. Your lines:
i = i + n
n = i - n
are the same as doing:
new_i = i + n
n = i
i = new_i
or,
i, n = i + n, i
which would be the usual way in Python.
edited 3 mins ago
cs95
145k25177257
answered 5 hours ago
Ned BatchelderNed Batchelder
265k53450572
add a comment |
It's an unusual way to do it, but it's correct. Your lines:
i = i + n
n = i - n
are the same as doing:
new_i = i + n
n = i
i = new_i
or,
i, n = i + n, i
which would be the usual way in Python.
edited 3 mins ago
cs95
145k25177257
answered 5 hours ago
Ned BatchelderNed Batchelder
265k53450572
add a comment |
It's an unusual way to do it, but it's correct. Your lines:
i = i + n
n = i - n
are the same as doing:
new_i = i + n
n = i
i = new_i
or,
i, n = i + n, i
which would be the usual way in Python.
edited 3 mins ago
cs95
145k25177257
answered 5 hours ago
Ned BatchelderNed Batchelder
265k53450572
It's an unusual way to do it, but it's correct. Your lines:
i = i + n
n = i - n
are the same as doing:
new_i = i + n
n = i
i = new_i
or,
i, n = i + n, i
which would be the usual way in Python.
edited 3 mins ago
cs95
145k25177257
answered 5 hours ago
Ned BatchelderNed Batchelder
265k53450572
edited 3 mins ago
cs95
145k25177257
edited 3 mins ago
cs95
145k25177257
edited 3 mins ago
cs95
145k25177257
145k25177257
answered 5 hours ago
Ned BatchelderNed Batchelder
265k53450572
answered 5 hours ago
Ned BatchelderNed Batchelder
265k53450572
answered 5 hours ago
Ned BatchelderNed Batchelder
265k53450572
265k53450572
add a comment |
add a comment |
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fibonaccipistacci is a new contributor. Be nice, and check out our Code of Conduct.
fibonaccipistacci is a new contributor. Be nice, and check out our Code of Conduct.
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