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How to plot multiple functions from a list

How can I create a table of sliders?PlotLegends from a ListUsing Multiple Kernels When Making PlotsPlot the minimum of a list of functionsHow do I set a PlotStyle when plotting a Table of functions?Evaluating and Plotting Multiple Zero-Counting FunctionsHow to make a table with a jump in range?How to automate plotting of many functions?Plot for a list of parametersBreaking up a list of lists

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;

2

$begingroup$

I'd like to get separate plots for the functions in a list, and I'm trying the following, which doesn't work. What is the correct way to do that?

Table[ContourPlot3D[f, x, -2, 2, y, -2, 2, z, -2, 2], f, x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0]

plotting table

share|improve this question

asked 8 hours ago

FrankFrank

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$endgroup$

add a comment | 

2

$begingroup$

I'd like to get separate plots for the functions in a list, and I'm trying the following, which doesn't work. What is the correct way to do that?

Table[ContourPlot3D[f, x, -2, 2, y, -2, 2, z, -2, 2], f, x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0]

plotting table

share|improve this question

asked 8 hours ago

FrankFrank

23711 silver badge77 bronze badges

$endgroup$

add a comment | 

$begingroup$

I'd like to get separate plots for the functions in a list, and I'm trying the following, which doesn't work. What is the correct way to do that?

Table[ContourPlot3D[f, x, -2, 2, y, -2, 2, z, -2, 2], f, x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0]

plotting table

share|improve this question

asked 8 hours ago

FrankFrank

23711 silver badge77 bronze badges

$endgroup$

Table[ContourPlot3D[f, x, -2, 2, y, -2, 2, z, -2, 2], f, x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0]

share|improve this question

asked 8 hours ago

FrankFrank

23711 silver badge77 bronze badges

share|improve this question

asked 8 hours ago

FrankFrank

23711 silver badge77 bronze badges

asked 8 hours ago

FrankFrank

23711 silver badge77 bronze badges

asked 8 hours ago

FrankFrank

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3 Answers
3

active

oldest

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4

$begingroup$

Table[ContourPlot3D[
 Evaluate[f], x, -2, 2, y, -2, 2, z, -2, 
 2], f, x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, 
 x + y^2 + z + x y^2 z == 0]

Just add Evaluate

share|improve this answer

answered 8 hours ago

yarchikyarchik

4,4261010 silver badges3434 bronze badges

$endgroup$

add a comment | 

1

$begingroup$

Instead of Table you could use Map

ContourPlot3D[#, x, -2, 2, y, -2, 2, z, -2, 2] & /@ x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0

share|improve this answer

answered 8 hours ago

That Gravity GuyThat Gravity Guy

2,27611 gold badge66 silver badges1515 bronze badges

$endgroup$

add a comment | 

1

$begingroup$

Using Table

Table[ContourPlot3D[
 Evaluate@f, x, -2, 2, y, -2, 2, z, -2, 2], f, x + y + z + x y z == 0,
 x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0]

share|improve this answer

answered 8 hours ago

Rohit NamjoshiRohit Namjoshi

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$endgroup$

add a comment | 

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4

$begingroup$

Table[ContourPlot3D[
 Evaluate[f], x, -2, 2, y, -2, 2, z, -2, 
 2], f, x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, 
 x + y^2 + z + x y^2 z == 0]

Just add Evaluate

share|improve this answer

answered 8 hours ago

yarchikyarchik

4,4261010 silver badges3434 bronze badges

$endgroup$

add a comment | 

4

$begingroup$

Table[ContourPlot3D[
 Evaluate[f], x, -2, 2, y, -2, 2, z, -2, 
 2], f, x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, 
 x + y^2 + z + x y^2 z == 0]

Just add Evaluate

share|improve this answer

answered 8 hours ago

yarchikyarchik

4,4261010 silver badges3434 bronze badges

$endgroup$

add a comment | 

$begingroup$

Table[ContourPlot3D[
 Evaluate[f], x, -2, 2, y, -2, 2, z, -2, 
 2], f, x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, 
 x + y^2 + z + x y^2 z == 0]

Just add Evaluate

share|improve this answer

answered 8 hours ago

yarchikyarchik

4,4261010 silver badges3434 bronze badges

$endgroup$

Table[ContourPlot3D[
 Evaluate[f], x, -2, 2, y, -2, 2, z, -2, 
 2], f, x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, 
 x + y^2 + z + x y^2 z == 0]

share|improve this answer

answered 8 hours ago

yarchikyarchik

4,4261010 silver badges3434 bronze badges

answered 8 hours ago

yarchikyarchik

4,4261010 silver badges3434 bronze badges

answered 8 hours ago

yarchikyarchik

4,4261010 silver badges3434 bronze badges

1

$begingroup$

Instead of Table you could use Map

ContourPlot3D[#, x, -2, 2, y, -2, 2, z, -2, 2] & /@ x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0

share|improve this answer

answered 8 hours ago

That Gravity GuyThat Gravity Guy

2,27611 gold badge66 silver badges1515 bronze badges

$endgroup$

add a comment | 

1

$begingroup$

Instead of Table you could use Map

ContourPlot3D[#, x, -2, 2, y, -2, 2, z, -2, 2] & /@ x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0

share|improve this answer

answered 8 hours ago

That Gravity GuyThat Gravity Guy

2,27611 gold badge66 silver badges1515 bronze badges

$endgroup$

add a comment | 

$begingroup$

Instead of Table you could use Map

ContourPlot3D[#, x, -2, 2, y, -2, 2, z, -2, 2] & /@ x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0

share|improve this answer

answered 8 hours ago

That Gravity GuyThat Gravity Guy

2,27611 gold badge66 silver badges1515 bronze badges

$endgroup$

ContourPlot3D[#, x, -2, 2, y, -2, 2, z, -2, 2] & /@ x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0

share|improve this answer

answered 8 hours ago

That Gravity GuyThat Gravity Guy

2,27611 gold badge66 silver badges1515 bronze badges

answered 8 hours ago

That Gravity GuyThat Gravity Guy

2,27611 gold badge66 silver badges1515 bronze badges

answered 8 hours ago

That Gravity GuyThat Gravity Guy

2,27611 gold badge66 silver badges1515 bronze badges

1

$begingroup$

Using Table

Table[ContourPlot3D[
 Evaluate@f, x, -2, 2, y, -2, 2, z, -2, 2], f, x + y + z + x y z == 0,
 x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0]

share|improve this answer

answered 8 hours ago

Rohit NamjoshiRohit Namjoshi

2,05711 gold badge44 silver badges1616 bronze badges

$endgroup$

add a comment | 

1

$begingroup$

Using Table

Table[ContourPlot3D[
 Evaluate@f, x, -2, 2, y, -2, 2, z, -2, 2], f, x + y + z + x y z == 0,
 x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0]

share|improve this answer

answered 8 hours ago

Rohit NamjoshiRohit Namjoshi

2,05711 gold badge44 silver badges1616 bronze badges

$endgroup$

add a comment | 

$begingroup$

Using Table

Table[ContourPlot3D[
 Evaluate@f, x, -2, 2, y, -2, 2, z, -2, 2], f, x + y + z + x y z == 0,
 x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0]

share|improve this answer

answered 8 hours ago

Rohit NamjoshiRohit Namjoshi

2,05711 gold badge44 silver badges1616 bronze badges

$endgroup$

Table[ContourPlot3D[
 Evaluate@f, x, -2, 2, y, -2, 2, z, -2, 2], f, x + y + z + x y z == 0,
 x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0]

share|improve this answer

answered 8 hours ago

Rohit NamjoshiRohit Namjoshi

2,05711 gold badge44 silver badges1616 bronze badges

answered 8 hours ago

Rohit NamjoshiRohit Namjoshi

2,05711 gold badge44 silver badges1616 bronze badges

answered 8 hours ago

Rohit NamjoshiRohit Namjoshi

2,05711 gold badge44 silver badges1616 bronze badges