What is the missing number, can anyone solve this? My original puzzleFind the missing number: A Pentagonal pattern puzzleMissing number in this sequence?Draw the item after decoding the instructionsPredict the missing number in this sequenceFind the missing piece to complete the patternWhat letters should be here?Reasoning - Find Missing NumberFill the grid (pattern)Can you find the next number in the following series?
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What is the missing number, can anyone solve this? My original puzzle
Find the missing number: A Pentagonal pattern puzzleMissing number in this sequence?Draw the item after decoding the instructionsPredict the missing number in this sequenceFind the missing piece to complete the patternWhat letters should be here?Reasoning - Find Missing NumberFill the grid (pattern)Can you find the next number in the following series?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
What is the missing number that should be put in place of the question mark?
3,3=17
2,5=28
3,4=24
4,5=40
5,8=88
6,11=156
6,9=?
pattern
$endgroup$
add a comment
|
$begingroup$
What is the missing number that should be put in place of the question mark?
3,3=17
2,5=28
3,4=24
4,5=40
5,8=88
6,11=156
6,9=?
pattern
$endgroup$
add a comment
|
$begingroup$
What is the missing number that should be put in place of the question mark?
3,3=17
2,5=28
3,4=24
4,5=40
5,8=88
6,11=156
6,9=?
pattern
$endgroup$
What is the missing number that should be put in place of the question mark?
3,3=17
2,5=28
3,4=24
4,5=40
5,8=88
6,11=156
6,9=?
pattern
pattern
edited 4 hours ago
Deepthinker101
asked 8 hours ago
Deepthinker101Deepthinker101
566 bronze badges
566 bronze badges
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2 Answers
2
active
oldest
votes
$begingroup$
If the three numbers in each "equation" are $a$, $b$, $c$ then one possible solution is
$Min(a, 5)^2 + b^2 - 1 = c$, giving the answer $c = 105$ for the last.
$endgroup$
$begingroup$
It doesnt work for 6,11 but fits all others. Maybe there was a typo?
$endgroup$
– Belhenix
6 hours ago
2
$begingroup$
It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
$endgroup$
– JS1
6 hours ago
$begingroup$
yes you were right there was an error in the puzzle
$endgroup$
– Deepthinker101
4 hours ago
add a comment
|
$begingroup$
Is this the answer?
116
The pattern/reasoning is
(a^2 + b^2) -1 = answer
New contributor
$endgroup$
add a comment
|
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
If the three numbers in each "equation" are $a$, $b$, $c$ then one possible solution is
$Min(a, 5)^2 + b^2 - 1 = c$, giving the answer $c = 105$ for the last.
$endgroup$
$begingroup$
It doesnt work for 6,11 but fits all others. Maybe there was a typo?
$endgroup$
– Belhenix
6 hours ago
2
$begingroup$
It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
$endgroup$
– JS1
6 hours ago
$begingroup$
yes you were right there was an error in the puzzle
$endgroup$
– Deepthinker101
4 hours ago
add a comment
|
$begingroup$
If the three numbers in each "equation" are $a$, $b$, $c$ then one possible solution is
$Min(a, 5)^2 + b^2 - 1 = c$, giving the answer $c = 105$ for the last.
$endgroup$
$begingroup$
It doesnt work for 6,11 but fits all others. Maybe there was a typo?
$endgroup$
– Belhenix
6 hours ago
2
$begingroup$
It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
$endgroup$
– JS1
6 hours ago
$begingroup$
yes you were right there was an error in the puzzle
$endgroup$
– Deepthinker101
4 hours ago
add a comment
|
$begingroup$
If the three numbers in each "equation" are $a$, $b$, $c$ then one possible solution is
$Min(a, 5)^2 + b^2 - 1 = c$, giving the answer $c = 105$ for the last.
$endgroup$
If the three numbers in each "equation" are $a$, $b$, $c$ then one possible solution is
$Min(a, 5)^2 + b^2 - 1 = c$, giving the answer $c = 105$ for the last.
edited 6 hours ago
answered 7 hours ago
JensJens
2613 bronze badges
2613 bronze badges
$begingroup$
It doesnt work for 6,11 but fits all others. Maybe there was a typo?
$endgroup$
– Belhenix
6 hours ago
2
$begingroup$
It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
$endgroup$
– JS1
6 hours ago
$begingroup$
yes you were right there was an error in the puzzle
$endgroup$
– Deepthinker101
4 hours ago
add a comment
|
$begingroup$
It doesnt work for 6,11 but fits all others. Maybe there was a typo?
$endgroup$
– Belhenix
6 hours ago
2
$begingroup$
It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
$endgroup$
– JS1
6 hours ago
$begingroup$
yes you were right there was an error in the puzzle
$endgroup$
– Deepthinker101
4 hours ago
$begingroup$
It doesnt work for 6,11 but fits all others. Maybe there was a typo?
$endgroup$
– Belhenix
6 hours ago
$begingroup$
It doesnt work for 6,11 but fits all others. Maybe there was a typo?
$endgroup$
– Belhenix
6 hours ago
2
2
$begingroup$
It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
$endgroup$
– JS1
6 hours ago
$begingroup$
It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
$endgroup$
– JS1
6 hours ago
$begingroup$
yes you were right there was an error in the puzzle
$endgroup$
– Deepthinker101
4 hours ago
$begingroup$
yes you were right there was an error in the puzzle
$endgroup$
– Deepthinker101
4 hours ago
add a comment
|
$begingroup$
Is this the answer?
116
The pattern/reasoning is
(a^2 + b^2) -1 = answer
New contributor
$endgroup$
add a comment
|
$begingroup$
Is this the answer?
116
The pattern/reasoning is
(a^2 + b^2) -1 = answer
New contributor
$endgroup$
add a comment
|
$begingroup$
Is this the answer?
116
The pattern/reasoning is
(a^2 + b^2) -1 = answer
New contributor
$endgroup$
Is this the answer?
116
The pattern/reasoning is
(a^2 + b^2) -1 = answer
New contributor
New contributor
answered 43 mins ago
MobileGlickMobileGlick
111 bronze badge
111 bronze badge
New contributor
New contributor
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