Negative Resistance Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?How does current flow through a voltage source?Does electric potential influence the direction of current?Reversed Current in Passive Loads?how does negative differential resistance in a PCT work?How to test if a, in circuit, complementary darling transistor is still functioning properly?How can a grounded gate MOSFET conduct current?Visualizing Electrical PotentialDoes voltage limit current?How can an electron have 0 electric potential after exiting a resistor but have current?Why (physically) does a current divider circuit show that both resistors have an effect on individual current?

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Negative Resistance



Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?How does current flow through a voltage source?Does electric potential influence the direction of current?Reversed Current in Passive Loads?how does negative differential resistance in a PCT work?How to test if a, in circuit, complementary darling transistor is still functioning properly?How can a grounded gate MOSFET conduct current?Visualizing Electrical PotentialDoes voltage limit current?How can an electron have 0 electric potential after exiting a resistor but have current?Why (physically) does a current divider circuit show that both resistors have an effect on individual current?



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








5












$begingroup$


I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.










share|improve this question











$endgroup$











  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    1 hour ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    1 hour ago

















5












$begingroup$


I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.










share|improve this question











$endgroup$











  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    1 hour ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    1 hour ago













5












5








5





$begingroup$


I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.










share|improve this question











$endgroup$




I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.







voltage current resistors resistance voltage-source






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 1 hour ago









Marcus Müller

35.5k363101




35.5k363101










asked 2 hours ago









Kinka-ByoKinka-Byo

862




862











  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    1 hour ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    1 hour ago
















  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    1 hour ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    1 hour ago















$begingroup$
Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
$endgroup$
– Michel Keijzers
1 hour ago




$begingroup$
Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
$endgroup$
– Michel Keijzers
1 hour ago




1




1




$begingroup$
Minus R will provide power, not dissipate power.
$endgroup$
– analogsystemsrf
1 hour ago




$begingroup$
Minus R will provide power, not dissipate power.
$endgroup$
– analogsystemsrf
1 hour ago










8 Answers
8






active

oldest

votes


















5












$begingroup$

There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



enter image description here



A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.




If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





schematic





simulate this circuit – Schematic created using CircuitLab



The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






share|improve this answer











$endgroup$








  • 1




    $begingroup$
    That is really a fine choice of an example device you picked.
    $endgroup$
    – The Photon
    1 hour ago










  • $begingroup$
    @ThePhoton LOL, great minds and all that.
    $endgroup$
    – Spehro Pefhany
    1 hour ago











  • $begingroup$
    Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
    $endgroup$
    – J...
    46 mins ago


















2












$begingroup$

Anything that drops in voltage with a rise in current has a negative resistance.



Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



https://en.wikipedia.org/wiki/Negative_resistance






share|improve this answer









$endgroup$




















    2












    $begingroup$

    In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



    Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



    Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






    share|improve this answer









    $endgroup$




















      1












      $begingroup$


      But how is this physically possible?




      Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



      enter image description here



      (image source)



      In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



      It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




      Somewhere I have read that an example of component with negative resistance is a voltage source.




      Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



      This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






      share|improve this answer









      $endgroup$




















        1












        $begingroup$

        In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



        Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



        Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).





        schematic





        simulate this circuit – Schematic created using CircuitLab



        Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



        A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






        share|improve this answer











        $endgroup$












        • $begingroup$
          Why did you answer twice?
          $endgroup$
          – pipe
          8 mins ago


















        1












        $begingroup$


        Somewhere I have read that an example of component with negative
        resistance is a voltage source. But I do not understand this
        statement, since a voltage source is a component which at most shows a
        (positive) internal resistance.




        Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



        For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





        schematic





        simulate this circuit – Schematic created using CircuitLab
        Using the built-in circuit simulator, $ R_load $ was swept from 5 ohms up to 15 ohms:



        • at 5 ohms, voltage drop across Rload is 4.322V


        • at 15 ohms, voltage drop across Rload is 3.993V


        The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






        share|improve this answer









        $endgroup$




















          0












          $begingroup$

          A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



          The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



          enter image description here






          share|improve this answer









          $endgroup$




















            0












            $begingroup$

            DC-DC Converter inputs are a good example of a negative resistance.
            As voltage goes down, current increases to provide the same power output.
            Also a negative resistance can be created by an op amp circuit.






            share|improve this answer









            $endgroup$













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              8 Answers
              8






              active

              oldest

              votes








              8 Answers
              8






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              5












              $begingroup$

              There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



              enter image description here



              A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



              A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.




              If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





              schematic





              simulate this circuit – Schematic created using CircuitLab



              The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






              share|improve this answer











              $endgroup$








              • 1




                $begingroup$
                That is really a fine choice of an example device you picked.
                $endgroup$
                – The Photon
                1 hour ago










              • $begingroup$
                @ThePhoton LOL, great minds and all that.
                $endgroup$
                – Spehro Pefhany
                1 hour ago











              • $begingroup$
                Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
                $endgroup$
                – J...
                46 mins ago















              5












              $begingroup$

              There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



              enter image description here



              A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



              A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.




              If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





              schematic





              simulate this circuit – Schematic created using CircuitLab



              The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






              share|improve this answer











              $endgroup$








              • 1




                $begingroup$
                That is really a fine choice of an example device you picked.
                $endgroup$
                – The Photon
                1 hour ago










              • $begingroup$
                @ThePhoton LOL, great minds and all that.
                $endgroup$
                – Spehro Pefhany
                1 hour ago











              • $begingroup$
                Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
                $endgroup$
                – J...
                46 mins ago













              5












              5








              5





              $begingroup$

              There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



              enter image description here



              A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



              A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.




              If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





              schematic





              simulate this circuit – Schematic created using CircuitLab



              The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






              share|improve this answer











              $endgroup$



              There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



              enter image description here



              A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



              A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.




              If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





              schematic





              simulate this circuit – Schematic created using CircuitLab



              The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 1 hour ago

























              answered 1 hour ago









              Spehro PefhanySpehro Pefhany

              215k5164438




              215k5164438







              • 1




                $begingroup$
                That is really a fine choice of an example device you picked.
                $endgroup$
                – The Photon
                1 hour ago










              • $begingroup$
                @ThePhoton LOL, great minds and all that.
                $endgroup$
                – Spehro Pefhany
                1 hour ago











              • $begingroup$
                Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
                $endgroup$
                – J...
                46 mins ago












              • 1




                $begingroup$
                That is really a fine choice of an example device you picked.
                $endgroup$
                – The Photon
                1 hour ago










              • $begingroup$
                @ThePhoton LOL, great minds and all that.
                $endgroup$
                – Spehro Pefhany
                1 hour ago











              • $begingroup$
                Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
                $endgroup$
                – J...
                46 mins ago







              1




              1




              $begingroup$
              That is really a fine choice of an example device you picked.
              $endgroup$
              – The Photon
              1 hour ago




              $begingroup$
              That is really a fine choice of an example device you picked.
              $endgroup$
              – The Photon
              1 hour ago












              $begingroup$
              @ThePhoton LOL, great minds and all that.
              $endgroup$
              – Spehro Pefhany
              1 hour ago





              $begingroup$
              @ThePhoton LOL, great minds and all that.
              $endgroup$
              – Spehro Pefhany
              1 hour ago













              $begingroup$
              Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
              $endgroup$
              – J...
              46 mins ago




              $begingroup$
              Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
              $endgroup$
              – J...
              46 mins ago













              2












              $begingroup$

              Anything that drops in voltage with a rise in current has a negative resistance.



              Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



              https://en.wikipedia.org/wiki/Negative_resistance






              share|improve this answer









              $endgroup$

















                2












                $begingroup$

                Anything that drops in voltage with a rise in current has a negative resistance.



                Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



                https://en.wikipedia.org/wiki/Negative_resistance






                share|improve this answer









                $endgroup$















                  2












                  2








                  2





                  $begingroup$

                  Anything that drops in voltage with a rise in current has a negative resistance.



                  Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



                  https://en.wikipedia.org/wiki/Negative_resistance






                  share|improve this answer









                  $endgroup$



                  Anything that drops in voltage with a rise in current has a negative resistance.



                  Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



                  https://en.wikipedia.org/wiki/Negative_resistance







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 1 hour ago









                  Sunnyskyguy EE75Sunnyskyguy EE75

                  72.2k227103




                  72.2k227103





















                      2












                      $begingroup$

                      In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                      Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                      Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






                      share|improve this answer









                      $endgroup$

















                        2












                        $begingroup$

                        In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                        Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                        Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






                        share|improve this answer









                        $endgroup$















                          2












                          2








                          2





                          $begingroup$

                          In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                          Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                          Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






                          share|improve this answer









                          $endgroup$



                          In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                          Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                          Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered 1 hour ago









                          LvWLvW

                          14.9k21330




                          14.9k21330





















                              1












                              $begingroup$


                              But how is this physically possible?




                              Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                              enter image description here



                              (image source)



                              In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                              It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                              Somewhere I have read that an example of component with negative resistance is a voltage source.




                              Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                              This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






                              share|improve this answer









                              $endgroup$

















                                1












                                $begingroup$


                                But how is this physically possible?




                                Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                                enter image description here



                                (image source)



                                In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                                It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                                Somewhere I have read that an example of component with negative resistance is a voltage source.




                                Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                                This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






                                share|improve this answer









                                $endgroup$















                                  1












                                  1








                                  1





                                  $begingroup$


                                  But how is this physically possible?




                                  Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                                  enter image description here



                                  (image source)



                                  In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                                  It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                                  Somewhere I have read that an example of component with negative resistance is a voltage source.




                                  Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                                  This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






                                  share|improve this answer









                                  $endgroup$




                                  But how is this physically possible?




                                  Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                                  enter image description here



                                  (image source)



                                  In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                                  It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                                  Somewhere I have read that an example of component with negative resistance is a voltage source.




                                  Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                                  This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.







                                  share|improve this answer












                                  share|improve this answer



                                  share|improve this answer










                                  answered 1 hour ago









                                  The PhotonThe Photon

                                  87.9k399205




                                  87.9k399205





















                                      1












                                      $begingroup$

                                      In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                                      Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                                      Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).





                                      schematic





                                      simulate this circuit – Schematic created using CircuitLab



                                      Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                      A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






                                      share|improve this answer











                                      $endgroup$












                                      • $begingroup$
                                        Why did you answer twice?
                                        $endgroup$
                                        – pipe
                                        8 mins ago















                                      1












                                      $begingroup$

                                      In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                                      Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                                      Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).





                                      schematic





                                      simulate this circuit – Schematic created using CircuitLab



                                      Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                      A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






                                      share|improve this answer











                                      $endgroup$












                                      • $begingroup$
                                        Why did you answer twice?
                                        $endgroup$
                                        – pipe
                                        8 mins ago













                                      1












                                      1








                                      1





                                      $begingroup$

                                      In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                                      Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                                      Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).





                                      schematic





                                      simulate this circuit – Schematic created using CircuitLab



                                      Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                      A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






                                      share|improve this answer











                                      $endgroup$



                                      In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                                      Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                                      Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).





                                      schematic





                                      simulate this circuit – Schematic created using CircuitLab



                                      Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                      A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.







                                      share|improve this answer














                                      share|improve this answer



                                      share|improve this answer








                                      edited 1 hour ago

























                                      answered 1 hour ago









                                      LvWLvW

                                      14.9k21330




                                      14.9k21330











                                      • $begingroup$
                                        Why did you answer twice?
                                        $endgroup$
                                        – pipe
                                        8 mins ago
















                                      • $begingroup$
                                        Why did you answer twice?
                                        $endgroup$
                                        – pipe
                                        8 mins ago















                                      $begingroup$
                                      Why did you answer twice?
                                      $endgroup$
                                      – pipe
                                      8 mins ago




                                      $begingroup$
                                      Why did you answer twice?
                                      $endgroup$
                                      – pipe
                                      8 mins ago











                                      1












                                      $begingroup$


                                      Somewhere I have read that an example of component with negative
                                      resistance is a voltage source. But I do not understand this
                                      statement, since a voltage source is a component which at most shows a
                                      (positive) internal resistance.




                                      Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                                      For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                                      schematic





                                      simulate this circuit – Schematic created using CircuitLab
                                      Using the built-in circuit simulator, $ R_load $ was swept from 5 ohms up to 15 ohms:



                                      • at 5 ohms, voltage drop across Rload is 4.322V


                                      • at 15 ohms, voltage drop across Rload is 3.993V


                                      The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






                                      share|improve this answer









                                      $endgroup$

















                                        1












                                        $begingroup$


                                        Somewhere I have read that an example of component with negative
                                        resistance is a voltage source. But I do not understand this
                                        statement, since a voltage source is a component which at most shows a
                                        (positive) internal resistance.




                                        Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                                        For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                                        schematic





                                        simulate this circuit – Schematic created using CircuitLab
                                        Using the built-in circuit simulator, $ R_load $ was swept from 5 ohms up to 15 ohms:



                                        • at 5 ohms, voltage drop across Rload is 4.322V


                                        • at 15 ohms, voltage drop across Rload is 3.993V


                                        The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






                                        share|improve this answer









                                        $endgroup$















                                          1












                                          1








                                          1





                                          $begingroup$


                                          Somewhere I have read that an example of component with negative
                                          resistance is a voltage source. But I do not understand this
                                          statement, since a voltage source is a component which at most shows a
                                          (positive) internal resistance.




                                          Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                                          For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                                          schematic





                                          simulate this circuit – Schematic created using CircuitLab
                                          Using the built-in circuit simulator, $ R_load $ was swept from 5 ohms up to 15 ohms:



                                          • at 5 ohms, voltage drop across Rload is 4.322V


                                          • at 15 ohms, voltage drop across Rload is 3.993V


                                          The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






                                          share|improve this answer









                                          $endgroup$




                                          Somewhere I have read that an example of component with negative
                                          resistance is a voltage source. But I do not understand this
                                          statement, since a voltage source is a component which at most shows a
                                          (positive) internal resistance.




                                          Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                                          For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                                          schematic





                                          simulate this circuit – Schematic created using CircuitLab
                                          Using the built-in circuit simulator, $ R_load $ was swept from 5 ohms up to 15 ohms:



                                          • at 5 ohms, voltage drop across Rload is 4.322V


                                          • at 15 ohms, voltage drop across Rload is 3.993V


                                          The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.







                                          share|improve this answer












                                          share|improve this answer



                                          share|improve this answer










                                          answered 59 mins ago









                                          glen_geekglen_geek

                                          9,78611016




                                          9,78611016





















                                              0












                                              $begingroup$

                                              A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                              The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                              enter image description here






                                              share|improve this answer









                                              $endgroup$

















                                                0












                                                $begingroup$

                                                A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                                The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                                enter image description here






                                                share|improve this answer









                                                $endgroup$















                                                  0












                                                  0








                                                  0





                                                  $begingroup$

                                                  A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                                  The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                                  enter image description here






                                                  share|improve this answer









                                                  $endgroup$



                                                  A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                                  The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                                  enter image description here







                                                  share|improve this answer












                                                  share|improve this answer



                                                  share|improve this answer










                                                  answered 1 hour ago









                                                  Mattman944Mattman944

                                                  3015




                                                  3015





















                                                      0












                                                      $begingroup$

                                                      DC-DC Converter inputs are a good example of a negative resistance.
                                                      As voltage goes down, current increases to provide the same power output.
                                                      Also a negative resistance can be created by an op amp circuit.






                                                      share|improve this answer









                                                      $endgroup$

















                                                        0












                                                        $begingroup$

                                                        DC-DC Converter inputs are a good example of a negative resistance.
                                                        As voltage goes down, current increases to provide the same power output.
                                                        Also a negative resistance can be created by an op amp circuit.






                                                        share|improve this answer









                                                        $endgroup$















                                                          0












                                                          0








                                                          0





                                                          $begingroup$

                                                          DC-DC Converter inputs are a good example of a negative resistance.
                                                          As voltage goes down, current increases to provide the same power output.
                                                          Also a negative resistance can be created by an op amp circuit.






                                                          share|improve this answer









                                                          $endgroup$



                                                          DC-DC Converter inputs are a good example of a negative resistance.
                                                          As voltage goes down, current increases to provide the same power output.
                                                          Also a negative resistance can be created by an op amp circuit.







                                                          share|improve this answer












                                                          share|improve this answer



                                                          share|improve this answer










                                                          answered 11 mins ago









                                                          EE_socalEE_socal

                                                          1,10016




                                                          1,10016



























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                                                              Кастелфранко ди Сопра Становништво Референце Спољашње везе Мени за навигацију43°37′18″ СГШ; 11°33′32″ ИГД / 43.62156° СГШ; 11.55885° ИГД / 43.62156; 11.5588543°37′18″ СГШ; 11°33′32″ ИГД / 43.62156° СГШ; 11.55885° ИГД / 43.62156; 11.558853179688„The GeoNames geographical database”„Istituto Nazionale di Statistica”проширитиууWorldCat156923403n850174324558639-1cb14643287r(подаци)