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2

I'm trying to generate:

"["hello" : "world"]"

gen.writeStartObject();
gen.writeArrayStart();
gen.writeStartObject();
gen.writeStringFeild('hello', 'world');
gen.writeEndObject();
gen.writeArrayEnd();
gen.writeEndObject();

Throws the error:
System.JSONException: Can not start an array, expecting field name

But the array in my example does not have a field name?

apex

share|improve this question

asked 8 hours ago

muchaviemuchavie

7633 bronze badges

add a comment | 

2

I'm trying to generate:

"["hello" : "world"]"

gen.writeStartObject();
gen.writeArrayStart();
gen.writeStartObject();
gen.writeStringFeild('hello', 'world');
gen.writeEndObject();
gen.writeArrayEnd();
gen.writeEndObject();

Throws the error:
System.JSONException: Can not start an array, expecting field name

But the array in my example does not have a field name?

apex

share|improve this question

asked 8 hours ago

muchaviemuchavie

7633 bronze badges

add a comment | 

I'm trying to generate:

"["hello" : "world"]"

gen.writeStartObject();
gen.writeArrayStart();
gen.writeStartObject();
gen.writeStringFeild('hello', 'world');
gen.writeEndObject();
gen.writeArrayEnd();
gen.writeEndObject();

Throws the error:
System.JSONException: Can not start an array, expecting field name

But the array in my example does not have a field name?

apex

share|improve this question

asked 8 hours ago

muchaviemuchavie

7633 bronze badges

gen.writeStartObject();
gen.writeArrayStart();
gen.writeStartObject();
gen.writeStringFeild('hello', 'world');
gen.writeEndObject();
gen.writeArrayEnd();
gen.writeEndObject();

share|improve this question

asked 8 hours ago

muchaviemuchavie

7633 bronze badges

share|improve this question

asked 8 hours ago

muchaviemuchavie

7633 bronze badges

asked 8 hours ago

muchaviemuchavie

7633 bronze badges

asked 8 hours ago

muchaviemuchavie

7633 bronze badges

1 Answer
1

active

oldest

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5

Right now, you open an object before opening your array. An object must consist of field value pairs. Here is an annotated version of what you wrote above, with your three typos corrected.

gen.writeStartObject();
// output: 
// remove this line

gen.writeStartArray();
// output: [
// your post had a typo here which I have fixed
// using writeStartArray rather than writeArrayStart

gen.writeStartObject();
// output: 

gen.writeStringField('hello', 'world');
// output: "hello": "world"
// your post had a typo here which I have fixed
// using writeStringField rather than writeStringFeild

gen.writeEndObject();
// output: 

gen.writeEndArray();
// output: ]
// your post had a typo here which I have fixed
// using writeEndArray rather than writeArrayEnd

gen.writeEndObject();
// output: 
// remove this line

Please note that JSONGenerator is almost never the correct choice for the job. It is almost universally simpler, easier to read, and better performance to just use out of the box serialization/deserialization. For example, here you could write just one line:

String payload = JSON.serialize(new List<Object> 
 new Map<String, String> 'hello' => 'world' 
);

share|improve this answer

edited 7 hours ago

answered 8 hours ago

Adrian Larson♦Adrian Larson

115k1919 gold badges133133 silver badges272272 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Also its writeStartArray and writeEndArray
  
  – salesforcesas
  8 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you Adrian!
  
  – muchavie
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @muchavie If this answer addressed your problem, please consider accepting it by clicking on the check mark/tick to the left of the answer, turning it green. This marks the question as resolved to your satisfaction, and awards reputation both to you and the person who answered. If you have >= 15 reputation points, you may also upvote the answer if you wish. There is no obligation to do either.
  
  – Adrian Larson♦
  7 hours ago
  

  
  
  
  

add a comment | 

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5

Right now, you open an object before opening your array. An object must consist of field value pairs. Here is an annotated version of what you wrote above, with your three typos corrected.

gen.writeStartObject();
// output: 
// remove this line

gen.writeStartArray();
// output: [
// your post had a typo here which I have fixed
// using writeStartArray rather than writeArrayStart

gen.writeStartObject();
// output: 

gen.writeStringField('hello', 'world');
// output: "hello": "world"
// your post had a typo here which I have fixed
// using writeStringField rather than writeStringFeild

gen.writeEndObject();
// output: 

gen.writeEndArray();
// output: ]
// your post had a typo here which I have fixed
// using writeEndArray rather than writeArrayEnd

gen.writeEndObject();
// output: 
// remove this line

Please note that JSONGenerator is almost never the correct choice for the job. It is almost universally simpler, easier to read, and better performance to just use out of the box serialization/deserialization. For example, here you could write just one line:

String payload = JSON.serialize(new List<Object> 
 new Map<String, String> 'hello' => 'world' 
);

share|improve this answer

edited 7 hours ago

answered 8 hours ago

Adrian Larson♦Adrian Larson

115k1919 gold badges133133 silver badges272272 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Also its writeStartArray and writeEndArray
  
  – salesforcesas
  8 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you Adrian!
  
  – muchavie
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @muchavie If this answer addressed your problem, please consider accepting it by clicking on the check mark/tick to the left of the answer, turning it green. This marks the question as resolved to your satisfaction, and awards reputation both to you and the person who answered. If you have >= 15 reputation points, you may also upvote the answer if you wish. There is no obligation to do either.
  
  – Adrian Larson♦
  7 hours ago
  

  
  
  
  

add a comment | 

5

Right now, you open an object before opening your array. An object must consist of field value pairs. Here is an annotated version of what you wrote above, with your three typos corrected.

gen.writeStartObject();
// output: 
// remove this line

gen.writeStartArray();
// output: [
// your post had a typo here which I have fixed
// using writeStartArray rather than writeArrayStart

gen.writeStartObject();
// output: 

gen.writeStringField('hello', 'world');
// output: "hello": "world"
// your post had a typo here which I have fixed
// using writeStringField rather than writeStringFeild

gen.writeEndObject();
// output: 

gen.writeEndArray();
// output: ]
// your post had a typo here which I have fixed
// using writeEndArray rather than writeArrayEnd

gen.writeEndObject();
// output: 
// remove this line

Please note that JSONGenerator is almost never the correct choice for the job. It is almost universally simpler, easier to read, and better performance to just use out of the box serialization/deserialization. For example, here you could write just one line:

String payload = JSON.serialize(new List<Object> 
 new Map<String, String> 'hello' => 'world' 
);

share|improve this answer

edited 7 hours ago

answered 8 hours ago

Adrian Larson♦Adrian Larson

115k1919 gold badges133133 silver badges272272 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Also its writeStartArray and writeEndArray
  
  – salesforcesas
  8 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you Adrian!
  
  – muchavie
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @muchavie If this answer addressed your problem, please consider accepting it by clicking on the check mark/tick to the left of the answer, turning it green. This marks the question as resolved to your satisfaction, and awards reputation both to you and the person who answered. If you have >= 15 reputation points, you may also upvote the answer if you wish. There is no obligation to do either.
  
  – Adrian Larson♦
  7 hours ago
  

  
  
  
  

add a comment | 

Right now, you open an object before opening your array. An object must consist of field value pairs. Here is an annotated version of what you wrote above, with your three typos corrected.

gen.writeStartObject();
// output: 
// remove this line

gen.writeStartArray();
// output: [
// your post had a typo here which I have fixed
// using writeStartArray rather than writeArrayStart

gen.writeStartObject();
// output: 

gen.writeStringField('hello', 'world');
// output: "hello": "world"
// your post had a typo here which I have fixed
// using writeStringField rather than writeStringFeild

gen.writeEndObject();
// output: 

gen.writeEndArray();
// output: ]
// your post had a typo here which I have fixed
// using writeEndArray rather than writeArrayEnd

gen.writeEndObject();
// output: 
// remove this line

Please note that JSONGenerator is almost never the correct choice for the job. It is almost universally simpler, easier to read, and better performance to just use out of the box serialization/deserialization. For example, here you could write just one line:

String payload = JSON.serialize(new List<Object> 
 new Map<String, String> 'hello' => 'world' 
);

share|improve this answer

edited 7 hours ago

answered 8 hours ago

Adrian Larson♦Adrian Larson

115k1919 gold badges133133 silver badges272272 bronze badges

gen.writeStartObject();
// output: 
// remove this line

gen.writeStartArray();
// output: [
// your post had a typo here which I have fixed
// using writeStartArray rather than writeArrayStart

gen.writeStartObject();
// output: 

gen.writeStringField('hello', 'world');
// output: "hello": "world"
// your post had a typo here which I have fixed
// using writeStringField rather than writeStringFeild

gen.writeEndObject();
// output: 

gen.writeEndArray();
// output: ]
// your post had a typo here which I have fixed
// using writeEndArray rather than writeArrayEnd

gen.writeEndObject();
// output: 
// remove this line

String payload = JSON.serialize(new List<Object> 
 new Map<String, String> 'hello' => 'world' 
);

share|improve this answer

edited 7 hours ago

answered 8 hours ago

Adrian Larson♦Adrian Larson

115k1919 gold badges133133 silver badges272272 bronze badges

answered 8 hours ago

Adrian Larson♦Adrian Larson

115k1919 gold badges133133 silver badges272272 bronze badges

answered 8 hours ago

Adrian Larson♦Adrian Larson

115k1919 gold badges133133 silver badges272272 bronze badges