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How to protect bash function from being overridden?
Bash Function DecoratorInclude a bash function into the parent scriptBash Scripting echo locally in a functionDefining bash function dynamically using evalBash function call from script file fails, while call from terminal succeedsHow to export all Bash functions in a file in one line?How to make my bash function known to external programWhy is Bash automatically inserting `--color=auto` in `ls` command used in function
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In the bash shell, we can define a function f with
f() echo Hello;
and then redeclare/override it, without any error or warning messages, with
f() echo Buy;
I believe there is a way to protect functions from being overridden in this way.
bash bash-functions
edited 50 mins ago
Kusalananda♦
166k20 gold badges323 silver badges516 bronze badges
asked 10 hours ago
kybkyb
1661 silver badge11 bronze badges
add a comment
|
In the bash shell, we can define a function f with
f() echo Hello;
and then redeclare/override it, without any error or warning messages, with
f() echo Buy;
I believe there is a way to protect functions from being overridden in this way.
bash bash-functions
edited 50 mins ago
Kusalananda♦
166k20 gold badges323 silver badges516 bronze badges
asked 10 hours ago
kybkyb
1661 silver badge11 bronze badges
1
the same as with variables, withtypeset -r:typeset -rf f.
– mosvy
10 hours ago
2
orreadonly -f f
– mosvy
10 hours ago
add a comment
|
In the bash shell, we can define a function f with
f() echo Hello;
and then redeclare/override it, without any error or warning messages, with
f() echo Buy;
I believe there is a way to protect functions from being overridden in this way.
bash bash-functions
edited 50 mins ago
Kusalananda♦
166k20 gold badges323 silver badges516 bronze badges
asked 10 hours ago
kybkyb
1661 silver badge11 bronze badges
In the bash shell, we can define a function f with
f() echo Hello;
and then redeclare/override it, without any error or warning messages, with
f() echo Buy;
I believe there is a way to protect functions from being overridden in this way.
bash bash-functions
bash bash-functions
edited 50 mins ago
Kusalananda♦
166k20 gold badges323 silver badges516 bronze badges
asked 10 hours ago
kybkyb
1661 silver badge11 bronze badges
edited 50 mins ago
Kusalananda♦
166k20 gold badges323 silver badges516 bronze badges
asked 10 hours ago
kybkyb
1661 silver badge11 bronze badges
edited 50 mins ago
Kusalananda♦
166k20 gold badges323 silver badges516 bronze badges
edited 50 mins ago
Kusalananda♦
166k20 gold badges323 silver badges516 bronze badges
edited 50 mins ago
Kusalananda♦
166k20 gold badges323 silver badges516 bronze badges
166k20 gold badges323 silver badges516 bronze badges
asked 10 hours ago
kybkyb
1661 silver badge11 bronze badges
asked 10 hours ago
kybkyb
1661 silver badge11 bronze badges
asked 10 hours ago
kybkyb
1661 silver badge11 bronze badges
1661 silver badge11 bronze badges
1
the same as with variables, withtypeset -r:typeset -rf f.
– mosvy
10 hours ago
2
orreadonly -f f
– mosvy
10 hours ago
add a comment
|
1
the same as with variables, withtypeset -r:typeset -rf f.
– mosvy
10 hours ago
2
orreadonly -f f
– mosvy
10 hours ago
1
1
the same as with variables, with
typeset -r: typeset -rf f.– mosvy
10 hours ago
the same as with variables, with
typeset -r: typeset -rf f.– mosvy
10 hours ago
2
2
or
readonly -f f– mosvy
10 hours ago
or
readonly -f f– mosvy
10 hours ago
add a comment
|
1 Answer
1
active
oldest
votes
You may declare f as a read-only function using readonly -f f or declare -r -f f (readonly is equivalent to declare -r). It's the -f option to these built-in utilities that makes them act on f as the name of a function, rather than on the variable f.
$ f() echo Hello;
$ readonly -f f
$ f() echo Buy;
bash: f: readonly function
$ unset -f f
bash: unset: f: cannot unset: readonly function
$ f
Hello
As you can see, making the function read-only not only protects it from getting overridden, but also protects it from being unset (removed completely).
answered 10 hours ago
Kusalananda♦Kusalananda
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1 Answer
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1 Answer
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active
oldest
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oldest
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oldest
votes
You may declare f as a read-only function using readonly -f f or declare -r -f f (readonly is equivalent to declare -r). It's the -f option to these built-in utilities that makes them act on f as the name of a function, rather than on the variable f.
$ f() echo Hello;
$ readonly -f f
$ f() echo Buy;
bash: f: readonly function
$ unset -f f
bash: unset: f: cannot unset: readonly function
$ f
Hello
As you can see, making the function read-only not only protects it from getting overridden, but also protects it from being unset (removed completely).
answered 10 hours ago
Kusalananda♦Kusalananda
166k20 gold badges323 silver badges516 bronze badges
add a comment
|
You may declare f as a read-only function using readonly -f f or declare -r -f f (readonly is equivalent to declare -r). It's the -f option to these built-in utilities that makes them act on f as the name of a function, rather than on the variable f.
$ f() echo Hello;
$ readonly -f f
$ f() echo Buy;
bash: f: readonly function
$ unset -f f
bash: unset: f: cannot unset: readonly function
$ f
Hello
As you can see, making the function read-only not only protects it from getting overridden, but also protects it from being unset (removed completely).
answered 10 hours ago
Kusalananda♦Kusalananda
166k20 gold badges323 silver badges516 bronze badges
add a comment
|
You may declare f as a read-only function using readonly -f f or declare -r -f f (readonly is equivalent to declare -r). It's the -f option to these built-in utilities that makes them act on f as the name of a function, rather than on the variable f.
$ f() echo Hello;
$ readonly -f f
$ f() echo Buy;
bash: f: readonly function
$ unset -f f
bash: unset: f: cannot unset: readonly function
$ f
Hello
As you can see, making the function read-only not only protects it from getting overridden, but also protects it from being unset (removed completely).
answered 10 hours ago
Kusalananda♦Kusalananda
166k20 gold badges323 silver badges516 bronze badges
You may declare f as a read-only function using readonly -f f or declare -r -f f (readonly is equivalent to declare -r). It's the -f option to these built-in utilities that makes them act on f as the name of a function, rather than on the variable f.
$ f() echo Hello;
$ readonly -f f
$ f() echo Buy;
bash: f: readonly function
$ unset -f f
bash: unset: f: cannot unset: readonly function
$ f
Hello
As you can see, making the function read-only not only protects it from getting overridden, but also protects it from being unset (removed completely).
answered 10 hours ago
Kusalananda♦Kusalananda
166k20 gold badges323 silver badges516 bronze badges
edited 46 mins ago
answered 10 hours ago
Kusalananda♦Kusalananda
166k20 gold badges323 silver badges516 bronze badges
answered 10 hours ago
Kusalananda♦Kusalananda
166k20 gold badges323 silver badges516 bronze badges
answered 10 hours ago
Kusalananda♦Kusalananda
166k20 gold badges323 silver badges516 bronze badges
166k20 gold badges323 silver badges516 bronze badges
add a comment
|
add a comment
|
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1
the same as with variables, with
typeset -r:typeset -rf f.– mosvy
10 hours ago
2
or
readonly -f f– mosvy
10 hours ago