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Is torque as fundamental a concept as force?
Shelf always tipping over when pushed, thanks to normal forceUnderstanding Newton's Laws of MotionCalculate force between rotating objectsWhat is force? The basic intuitionTorque/moment of force fundamentallyStatic equilibrium- when do you use forces and when do you use torques?
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I used to think that torque and force were equally “fundamental”. In other words, my understanding was that we usually use Cartesian coordinates in many common problems because it is a convenient system, so as a result instantaneous forces which act in straight lines seem “easier” mathematically but torques require some extra “baggage”. This baggage includes typically teaching that torque is defined in terms of force.
But if say we happened to choose polar coordinates for the problem the situation would appear the other way around. So it would be arbitrary if we chose to define forces in terms of torques instead.
But later on I learned that angular momentum is conserved independently of regular linear momentum (IIRC). This makes it seem much less certain that one should define either torque in terms of force or vice versa — it gives the impression they are more distinct than it first seemed.
That said, as far as I know a lot of physics is about defining & describing “fundamental forces” — not “fundamental torques”.
So is choosing to use either force or torque as the basis of laws & problems arbitrary? Or is there an actual fundamental rationale to when one or the other should be used?
newtonian-mechanics forces torque
$endgroup$
add a comment |
$begingroup$
I used to think that torque and force were equally “fundamental”. In other words, my understanding was that we usually use Cartesian coordinates in many common problems because it is a convenient system, so as a result instantaneous forces which act in straight lines seem “easier” mathematically but torques require some extra “baggage”. This baggage includes typically teaching that torque is defined in terms of force.
But if say we happened to choose polar coordinates for the problem the situation would appear the other way around. So it would be arbitrary if we chose to define forces in terms of torques instead.
But later on I learned that angular momentum is conserved independently of regular linear momentum (IIRC). This makes it seem much less certain that one should define either torque in terms of force or vice versa — it gives the impression they are more distinct than it first seemed.
That said, as far as I know a lot of physics is about defining & describing “fundamental forces” — not “fundamental torques”.
So is choosing to use either force or torque as the basis of laws & problems arbitrary? Or is there an actual fundamental rationale to when one or the other should be used?
newtonian-mechanics forces torque
$endgroup$
$begingroup$
Torque isn't something that arises when we move to polar coordinates. They exist no matter how we choose to represent coordinates. Additionally, you can work with forces in polar coordinates without even referring to torque. Why do you think this, exactly?
$endgroup$
– Aaron Stevens
6 hours ago
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@AaronStevens I was only referring to the choice of coordinate system potentially being more convenient depending on whether you chose to express a particular problem in terms of force or torque.
$endgroup$
– DaveInCaz
4 hours ago
add a comment |
$begingroup$
I used to think that torque and force were equally “fundamental”. In other words, my understanding was that we usually use Cartesian coordinates in many common problems because it is a convenient system, so as a result instantaneous forces which act in straight lines seem “easier” mathematically but torques require some extra “baggage”. This baggage includes typically teaching that torque is defined in terms of force.
But if say we happened to choose polar coordinates for the problem the situation would appear the other way around. So it would be arbitrary if we chose to define forces in terms of torques instead.
But later on I learned that angular momentum is conserved independently of regular linear momentum (IIRC). This makes it seem much less certain that one should define either torque in terms of force or vice versa — it gives the impression they are more distinct than it first seemed.
That said, as far as I know a lot of physics is about defining & describing “fundamental forces” — not “fundamental torques”.
So is choosing to use either force or torque as the basis of laws & problems arbitrary? Or is there an actual fundamental rationale to when one or the other should be used?
newtonian-mechanics forces torque
$endgroup$
I used to think that torque and force were equally “fundamental”. In other words, my understanding was that we usually use Cartesian coordinates in many common problems because it is a convenient system, so as a result instantaneous forces which act in straight lines seem “easier” mathematically but torques require some extra “baggage”. This baggage includes typically teaching that torque is defined in terms of force.
But if say we happened to choose polar coordinates for the problem the situation would appear the other way around. So it would be arbitrary if we chose to define forces in terms of torques instead.
But later on I learned that angular momentum is conserved independently of regular linear momentum (IIRC). This makes it seem much less certain that one should define either torque in terms of force or vice versa — it gives the impression they are more distinct than it first seemed.
That said, as far as I know a lot of physics is about defining & describing “fundamental forces” — not “fundamental torques”.
So is choosing to use either force or torque as the basis of laws & problems arbitrary? Or is there an actual fundamental rationale to when one or the other should be used?
newtonian-mechanics forces torque
newtonian-mechanics forces torque
edited 7 hours ago
Qmechanic♦
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asked 8 hours ago
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DaveInCazDaveInCaz
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Torque isn't something that arises when we move to polar coordinates. They exist no matter how we choose to represent coordinates. Additionally, you can work with forces in polar coordinates without even referring to torque. Why do you think this, exactly?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
@AaronStevens I was only referring to the choice of coordinate system potentially being more convenient depending on whether you chose to express a particular problem in terms of force or torque.
$endgroup$
– DaveInCaz
4 hours ago
add a comment |
$begingroup$
Torque isn't something that arises when we move to polar coordinates. They exist no matter how we choose to represent coordinates. Additionally, you can work with forces in polar coordinates without even referring to torque. Why do you think this, exactly?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
@AaronStevens I was only referring to the choice of coordinate system potentially being more convenient depending on whether you chose to express a particular problem in terms of force or torque.
$endgroup$
– DaveInCaz
4 hours ago
$begingroup$
Torque isn't something that arises when we move to polar coordinates. They exist no matter how we choose to represent coordinates. Additionally, you can work with forces in polar coordinates without even referring to torque. Why do you think this, exactly?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
Torque isn't something that arises when we move to polar coordinates. They exist no matter how we choose to represent coordinates. Additionally, you can work with forces in polar coordinates without even referring to torque. Why do you think this, exactly?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
@AaronStevens I was only referring to the choice of coordinate system potentially being more convenient depending on whether you chose to express a particular problem in terms of force or torque.
$endgroup$
– DaveInCaz
4 hours ago
$begingroup$
@AaronStevens I was only referring to the choice of coordinate system potentially being more convenient depending on whether you chose to express a particular problem in terms of force or torque.
$endgroup$
– DaveInCaz
4 hours ago
add a comment |
4 Answers
4
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No, torque is not a fundamental quantity. it's only job is to describe where in space a force is acting through (the line of action). Torque just describes a force at a distance. Given a force $boldsymbolF$ and a torque $boldsymboltau$ you can tell that the force acts along a line in space with direction defined by $boldsymbolF$, but location defined by $boldsymboltau$ as follows $$ boldsymbolr = frac boldsymbolF times boldsymboltau boldsymbolF $$
It might be easier to discuss angular momentum first, since torque is the time derivative of angular momentum, just as force is the time derivative of linear momentum.
For a single particle with linear momentum $boldsymbolp = mboldsymbolv$ located at some instant at a point $boldsymbolr$ the angular momentum is $$ boldsymbolL = boldsymbolr times boldsymbolp$$
So where is the momentum line in space? The momentum line is called the axis of percussion. It is located at
$$ boldsymbolr = frac boldsymbolp times boldsymbolL boldsymbolp = fracboldsymbolp times ( boldsymbolr times boldsymbolp) = frac boldsymbolr (boldsymbolp cdot boldsymbolp) - boldsymbolp ( boldsymbolp cdot boldsymbolr) = boldsymbolr frac^2 = r ; checkmark $$
provided that the point $boldsymbolr$ is perpendicular to the momentum $boldsymbolp$. Such a point can always be found, and it is the point on the line closest to the origin.
The conservation law for angular momentum (coupled with the conservation law for linear momentum) just states that not only the magnitude and direction of momentum is conserved but also the line in space where moment acts through is also conserved.
In summary, the common quantities in mechanics are interpreted as follows
$$ beginarrayl
textconcept & textvalue & textmoment\
hline textrotation axis & textrot. velocity, boldsymbolomega & textvelocity, boldsymbolv = boldsymbolrtimes boldsymbolomega \
textline of action & textforce, boldsymbolF & texttorque, boldsymboltau = boldsymbolr times boldsymbolF \
textaxis of percussion & textmomentum, boldsymbolp & textang. momentum, boldsymbolL = boldsymbolr times boldsymbolp
endarray $$
The stuff under the value column are fundamental quantities that give us the magnitude of something (as well as the direction). The stuff under the moment column are secondary quantities that depend on where they are measured and give use the relative location of the fundamental quantities. Hence the terms torque = moment of force, velocity = moment of rotation and angular momentum = moment of momentum. All that means is that these quantities are $boldsymbolr times text(something fundamental)$ and they describe the moment arm to this something.
In statics, for example, we learn to balance forces and moments, which should be interpreted as balancing the force magnitude and the line of action of the force.
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Your first equation suggests that $mathbf F$ is always perpendicular to $mathbf r$. But this certainly is not always true. Am I missing something?
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– Aaron Stevens
2 hours ago
add a comment |
$begingroup$
I would argue that force is more fundamental concept than torque. This is mainly because torques is, for lack of a better term, a property of forces. Also, the torque produced by a force depends on your subjective choice of which point you are calculating the torque about. This is all captured in the definition of torque
$$boldsymboltau=mathbf rtimesmathbf F$$
where $mathbf F$ is the force vector and $mathbf r$ is the vector pointing from the point about which you are calculating the torque to the point where the force is applied.
Note that this defines torque in terms of a force, but you cannot determine a force from a torque. For a given $boldsymboltau$ and a given $mathbf r$ there is not a unique force $mathbf F$. Therefore, this also gives the impression that force is a more fundamental concept.
Also note that the definition of torque does not depend on if we are using polar coordinates or not. You can discuss forces in polar coordinates without referring to torque, and you can talk about torques in Cartesian coordinates.
So torque is not fundamental, however that doesn't mean it's not useful. It is useful in looking at how forces cause extended bodies to move (or not move), and it is useful when motion has rotational symmetry about some point (i.e. when angular momentum is conserved).
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add a comment |
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Just what is fundamental? Torque is certainly more than just force with additional “baggage”. And it’s more than just about coordinate systems. Torque and force are not a matter of either or. Both are needed for the analysis of motion and equilibrium.
Moment, which is another term for torque, is a fundamental concept in statics. For example in statics both forces and moments are needed to determine static equilibrium . Forces cause straight line motion. Moments cause rotational motion. The requirements for equilibrium are that the sum of both the moments and forces have to be zero. And it goes beyond statics. Bending moments and shear forces are fundamental to the study of mechanics of materials.
You will learn to appreciate the difference if and when you study statics , dynamics, and mechanics of materials.
Hope this helps
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I would argue that when we're talking about fundamental point particles, torque is just a matter of coordinate systems, and only becomes necessary when we consider composite systems.
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– Danny
6 hours ago
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@Danny what do you mean by saying that torque is just a matter of coordinate systems?
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– Aaron Stevens
6 hours ago
2
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@BobD Certainly torques make life a whole lot simpler for extended bodies, but I would argue that the concept of force is more fundamental than torque, as torque is defined in terms of force, but not the other way around. Couldn't one argue that a zero net torque is just a simpler way of saying that the net force acting on every part of the body must be $0$?
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– Aaron Stevens
6 hours ago
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@AaronStevens I wasn't arguing that torque isn't derived from force or that torque is equally "fundamental" as force. For that matter I'm not sure we can say forces in general are "fundamental" in the same manner as the strong nuclear, weak nuclear, electromagnetic and gravitational forces. Instead my focus was on the OP statement "So is choosing to use either force or torque as the basis of laws & problems arbitrary? Or is there an actual fundamental rationale to when one or the other should be used?" It's the ideal of either or use of force and torque to solve problem I addressed.
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– Bob D
6 hours ago
1
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@AaronStevens You never know.I've given up trying to figure out why
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– Bob D
2 hours ago
|
show 3 more comments
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Transfer of angular momentum is fundamental, and does not reduce to a force being applied.
For example: "...by utilizing transfer of photon spin angular momentum, it is also possible to set objects into rotational motion simply by targeting them with a beam of circularly polarized light"
Source: https://pubs.acs.org/doi/abs/10.1021/nl4010817
New contributor
Gene Ruso is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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4 Answers
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4 Answers
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$begingroup$
No, torque is not a fundamental quantity. it's only job is to describe where in space a force is acting through (the line of action). Torque just describes a force at a distance. Given a force $boldsymbolF$ and a torque $boldsymboltau$ you can tell that the force acts along a line in space with direction defined by $boldsymbolF$, but location defined by $boldsymboltau$ as follows $$ boldsymbolr = frac boldsymbolF times boldsymboltau boldsymbolF $$
It might be easier to discuss angular momentum first, since torque is the time derivative of angular momentum, just as force is the time derivative of linear momentum.
For a single particle with linear momentum $boldsymbolp = mboldsymbolv$ located at some instant at a point $boldsymbolr$ the angular momentum is $$ boldsymbolL = boldsymbolr times boldsymbolp$$
So where is the momentum line in space? The momentum line is called the axis of percussion. It is located at
$$ boldsymbolr = frac boldsymbolp times boldsymbolL boldsymbolp = fracboldsymbolp times ( boldsymbolr times boldsymbolp) = frac boldsymbolr (boldsymbolp cdot boldsymbolp) - boldsymbolp ( boldsymbolp cdot boldsymbolr) = boldsymbolr frac^2 = r ; checkmark $$
provided that the point $boldsymbolr$ is perpendicular to the momentum $boldsymbolp$. Such a point can always be found, and it is the point on the line closest to the origin.
The conservation law for angular momentum (coupled with the conservation law for linear momentum) just states that not only the magnitude and direction of momentum is conserved but also the line in space where moment acts through is also conserved.
In summary, the common quantities in mechanics are interpreted as follows
$$ beginarrayl
textconcept & textvalue & textmoment\
hline textrotation axis & textrot. velocity, boldsymbolomega & textvelocity, boldsymbolv = boldsymbolrtimes boldsymbolomega \
textline of action & textforce, boldsymbolF & texttorque, boldsymboltau = boldsymbolr times boldsymbolF \
textaxis of percussion & textmomentum, boldsymbolp & textang. momentum, boldsymbolL = boldsymbolr times boldsymbolp
endarray $$
The stuff under the value column are fundamental quantities that give us the magnitude of something (as well as the direction). The stuff under the moment column are secondary quantities that depend on where they are measured and give use the relative location of the fundamental quantities. Hence the terms torque = moment of force, velocity = moment of rotation and angular momentum = moment of momentum. All that means is that these quantities are $boldsymbolr times text(something fundamental)$ and they describe the moment arm to this something.
In statics, for example, we learn to balance forces and moments, which should be interpreted as balancing the force magnitude and the line of action of the force.
$endgroup$
$begingroup$
Your first equation suggests that $mathbf F$ is always perpendicular to $mathbf r$. But this certainly is not always true. Am I missing something?
$endgroup$
– Aaron Stevens
2 hours ago
add a comment |
$begingroup$
No, torque is not a fundamental quantity. it's only job is to describe where in space a force is acting through (the line of action). Torque just describes a force at a distance. Given a force $boldsymbolF$ and a torque $boldsymboltau$ you can tell that the force acts along a line in space with direction defined by $boldsymbolF$, but location defined by $boldsymboltau$ as follows $$ boldsymbolr = frac boldsymbolF times boldsymboltau boldsymbolF $$
It might be easier to discuss angular momentum first, since torque is the time derivative of angular momentum, just as force is the time derivative of linear momentum.
For a single particle with linear momentum $boldsymbolp = mboldsymbolv$ located at some instant at a point $boldsymbolr$ the angular momentum is $$ boldsymbolL = boldsymbolr times boldsymbolp$$
So where is the momentum line in space? The momentum line is called the axis of percussion. It is located at
$$ boldsymbolr = frac boldsymbolp times boldsymbolL boldsymbolp = fracboldsymbolp times ( boldsymbolr times boldsymbolp) = frac boldsymbolr (boldsymbolp cdot boldsymbolp) - boldsymbolp ( boldsymbolp cdot boldsymbolr) = boldsymbolr frac^2 = r ; checkmark $$
provided that the point $boldsymbolr$ is perpendicular to the momentum $boldsymbolp$. Such a point can always be found, and it is the point on the line closest to the origin.
The conservation law for angular momentum (coupled with the conservation law for linear momentum) just states that not only the magnitude and direction of momentum is conserved but also the line in space where moment acts through is also conserved.
In summary, the common quantities in mechanics are interpreted as follows
$$ beginarrayl
textconcept & textvalue & textmoment\
hline textrotation axis & textrot. velocity, boldsymbolomega & textvelocity, boldsymbolv = boldsymbolrtimes boldsymbolomega \
textline of action & textforce, boldsymbolF & texttorque, boldsymboltau = boldsymbolr times boldsymbolF \
textaxis of percussion & textmomentum, boldsymbolp & textang. momentum, boldsymbolL = boldsymbolr times boldsymbolp
endarray $$
The stuff under the value column are fundamental quantities that give us the magnitude of something (as well as the direction). The stuff under the moment column are secondary quantities that depend on where they are measured and give use the relative location of the fundamental quantities. Hence the terms torque = moment of force, velocity = moment of rotation and angular momentum = moment of momentum. All that means is that these quantities are $boldsymbolr times text(something fundamental)$ and they describe the moment arm to this something.
In statics, for example, we learn to balance forces and moments, which should be interpreted as balancing the force magnitude and the line of action of the force.
$endgroup$
$begingroup$
Your first equation suggests that $mathbf F$ is always perpendicular to $mathbf r$. But this certainly is not always true. Am I missing something?
$endgroup$
– Aaron Stevens
2 hours ago
add a comment |
$begingroup$
No, torque is not a fundamental quantity. it's only job is to describe where in space a force is acting through (the line of action). Torque just describes a force at a distance. Given a force $boldsymbolF$ and a torque $boldsymboltau$ you can tell that the force acts along a line in space with direction defined by $boldsymbolF$, but location defined by $boldsymboltau$ as follows $$ boldsymbolr = frac boldsymbolF times boldsymboltau boldsymbolF $$
It might be easier to discuss angular momentum first, since torque is the time derivative of angular momentum, just as force is the time derivative of linear momentum.
For a single particle with linear momentum $boldsymbolp = mboldsymbolv$ located at some instant at a point $boldsymbolr$ the angular momentum is $$ boldsymbolL = boldsymbolr times boldsymbolp$$
So where is the momentum line in space? The momentum line is called the axis of percussion. It is located at
$$ boldsymbolr = frac boldsymbolp times boldsymbolL boldsymbolp = fracboldsymbolp times ( boldsymbolr times boldsymbolp) = frac boldsymbolr (boldsymbolp cdot boldsymbolp) - boldsymbolp ( boldsymbolp cdot boldsymbolr) = boldsymbolr frac^2 = r ; checkmark $$
provided that the point $boldsymbolr$ is perpendicular to the momentum $boldsymbolp$. Such a point can always be found, and it is the point on the line closest to the origin.
The conservation law for angular momentum (coupled with the conservation law for linear momentum) just states that not only the magnitude and direction of momentum is conserved but also the line in space where moment acts through is also conserved.
In summary, the common quantities in mechanics are interpreted as follows
$$ beginarrayl
textconcept & textvalue & textmoment\
hline textrotation axis & textrot. velocity, boldsymbolomega & textvelocity, boldsymbolv = boldsymbolrtimes boldsymbolomega \
textline of action & textforce, boldsymbolF & texttorque, boldsymboltau = boldsymbolr times boldsymbolF \
textaxis of percussion & textmomentum, boldsymbolp & textang. momentum, boldsymbolL = boldsymbolr times boldsymbolp
endarray $$
The stuff under the value column are fundamental quantities that give us the magnitude of something (as well as the direction). The stuff under the moment column are secondary quantities that depend on where they are measured and give use the relative location of the fundamental quantities. Hence the terms torque = moment of force, velocity = moment of rotation and angular momentum = moment of momentum. All that means is that these quantities are $boldsymbolr times text(something fundamental)$ and they describe the moment arm to this something.
In statics, for example, we learn to balance forces and moments, which should be interpreted as balancing the force magnitude and the line of action of the force.
$endgroup$
No, torque is not a fundamental quantity. it's only job is to describe where in space a force is acting through (the line of action). Torque just describes a force at a distance. Given a force $boldsymbolF$ and a torque $boldsymboltau$ you can tell that the force acts along a line in space with direction defined by $boldsymbolF$, but location defined by $boldsymboltau$ as follows $$ boldsymbolr = frac boldsymbolF times boldsymboltau boldsymbolF $$
It might be easier to discuss angular momentum first, since torque is the time derivative of angular momentum, just as force is the time derivative of linear momentum.
For a single particle with linear momentum $boldsymbolp = mboldsymbolv$ located at some instant at a point $boldsymbolr$ the angular momentum is $$ boldsymbolL = boldsymbolr times boldsymbolp$$
So where is the momentum line in space? The momentum line is called the axis of percussion. It is located at
$$ boldsymbolr = frac boldsymbolp times boldsymbolL boldsymbolp = fracboldsymbolp times ( boldsymbolr times boldsymbolp) = frac boldsymbolr (boldsymbolp cdot boldsymbolp) - boldsymbolp ( boldsymbolp cdot boldsymbolr) = boldsymbolr frac^2 = r ; checkmark $$
provided that the point $boldsymbolr$ is perpendicular to the momentum $boldsymbolp$. Such a point can always be found, and it is the point on the line closest to the origin.
The conservation law for angular momentum (coupled with the conservation law for linear momentum) just states that not only the magnitude and direction of momentum is conserved but also the line in space where moment acts through is also conserved.
In summary, the common quantities in mechanics are interpreted as follows
$$ beginarrayl
textconcept & textvalue & textmoment\
hline textrotation axis & textrot. velocity, boldsymbolomega & textvelocity, boldsymbolv = boldsymbolrtimes boldsymbolomega \
textline of action & textforce, boldsymbolF & texttorque, boldsymboltau = boldsymbolr times boldsymbolF \
textaxis of percussion & textmomentum, boldsymbolp & textang. momentum, boldsymbolL = boldsymbolr times boldsymbolp
endarray $$
The stuff under the value column are fundamental quantities that give us the magnitude of something (as well as the direction). The stuff under the moment column are secondary quantities that depend on where they are measured and give use the relative location of the fundamental quantities. Hence the terms torque = moment of force, velocity = moment of rotation and angular momentum = moment of momentum. All that means is that these quantities are $boldsymbolr times text(something fundamental)$ and they describe the moment arm to this something.
In statics, for example, we learn to balance forces and moments, which should be interpreted as balancing the force magnitude and the line of action of the force.
answered 3 hours ago
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ja72ja72
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$begingroup$
Your first equation suggests that $mathbf F$ is always perpendicular to $mathbf r$. But this certainly is not always true. Am I missing something?
$endgroup$
– Aaron Stevens
2 hours ago
add a comment |
$begingroup$
Your first equation suggests that $mathbf F$ is always perpendicular to $mathbf r$. But this certainly is not always true. Am I missing something?
$endgroup$
– Aaron Stevens
2 hours ago
$begingroup$
Your first equation suggests that $mathbf F$ is always perpendicular to $mathbf r$. But this certainly is not always true. Am I missing something?
$endgroup$
– Aaron Stevens
2 hours ago
$begingroup$
Your first equation suggests that $mathbf F$ is always perpendicular to $mathbf r$. But this certainly is not always true. Am I missing something?
$endgroup$
– Aaron Stevens
2 hours ago
add a comment |
$begingroup$
I would argue that force is more fundamental concept than torque. This is mainly because torques is, for lack of a better term, a property of forces. Also, the torque produced by a force depends on your subjective choice of which point you are calculating the torque about. This is all captured in the definition of torque
$$boldsymboltau=mathbf rtimesmathbf F$$
where $mathbf F$ is the force vector and $mathbf r$ is the vector pointing from the point about which you are calculating the torque to the point where the force is applied.
Note that this defines torque in terms of a force, but you cannot determine a force from a torque. For a given $boldsymboltau$ and a given $mathbf r$ there is not a unique force $mathbf F$. Therefore, this also gives the impression that force is a more fundamental concept.
Also note that the definition of torque does not depend on if we are using polar coordinates or not. You can discuss forces in polar coordinates without referring to torque, and you can talk about torques in Cartesian coordinates.
So torque is not fundamental, however that doesn't mean it's not useful. It is useful in looking at how forces cause extended bodies to move (or not move), and it is useful when motion has rotational symmetry about some point (i.e. when angular momentum is conserved).
$endgroup$
add a comment |
$begingroup$
I would argue that force is more fundamental concept than torque. This is mainly because torques is, for lack of a better term, a property of forces. Also, the torque produced by a force depends on your subjective choice of which point you are calculating the torque about. This is all captured in the definition of torque
$$boldsymboltau=mathbf rtimesmathbf F$$
where $mathbf F$ is the force vector and $mathbf r$ is the vector pointing from the point about which you are calculating the torque to the point where the force is applied.
Note that this defines torque in terms of a force, but you cannot determine a force from a torque. For a given $boldsymboltau$ and a given $mathbf r$ there is not a unique force $mathbf F$. Therefore, this also gives the impression that force is a more fundamental concept.
Also note that the definition of torque does not depend on if we are using polar coordinates or not. You can discuss forces in polar coordinates without referring to torque, and you can talk about torques in Cartesian coordinates.
So torque is not fundamental, however that doesn't mean it's not useful. It is useful in looking at how forces cause extended bodies to move (or not move), and it is useful when motion has rotational symmetry about some point (i.e. when angular momentum is conserved).
$endgroup$
add a comment |
$begingroup$
I would argue that force is more fundamental concept than torque. This is mainly because torques is, for lack of a better term, a property of forces. Also, the torque produced by a force depends on your subjective choice of which point you are calculating the torque about. This is all captured in the definition of torque
$$boldsymboltau=mathbf rtimesmathbf F$$
where $mathbf F$ is the force vector and $mathbf r$ is the vector pointing from the point about which you are calculating the torque to the point where the force is applied.
Note that this defines torque in terms of a force, but you cannot determine a force from a torque. For a given $boldsymboltau$ and a given $mathbf r$ there is not a unique force $mathbf F$. Therefore, this also gives the impression that force is a more fundamental concept.
Also note that the definition of torque does not depend on if we are using polar coordinates or not. You can discuss forces in polar coordinates without referring to torque, and you can talk about torques in Cartesian coordinates.
So torque is not fundamental, however that doesn't mean it's not useful. It is useful in looking at how forces cause extended bodies to move (or not move), and it is useful when motion has rotational symmetry about some point (i.e. when angular momentum is conserved).
$endgroup$
I would argue that force is more fundamental concept than torque. This is mainly because torques is, for lack of a better term, a property of forces. Also, the torque produced by a force depends on your subjective choice of which point you are calculating the torque about. This is all captured in the definition of torque
$$boldsymboltau=mathbf rtimesmathbf F$$
where $mathbf F$ is the force vector and $mathbf r$ is the vector pointing from the point about which you are calculating the torque to the point where the force is applied.
Note that this defines torque in terms of a force, but you cannot determine a force from a torque. For a given $boldsymboltau$ and a given $mathbf r$ there is not a unique force $mathbf F$. Therefore, this also gives the impression that force is a more fundamental concept.
Also note that the definition of torque does not depend on if we are using polar coordinates or not. You can discuss forces in polar coordinates without referring to torque, and you can talk about torques in Cartesian coordinates.
So torque is not fundamental, however that doesn't mean it's not useful. It is useful in looking at how forces cause extended bodies to move (or not move), and it is useful when motion has rotational symmetry about some point (i.e. when angular momentum is conserved).
answered 3 hours ago
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Aaron StevensAaron Stevens
22.1k4 gold badges41 silver badges78 bronze badges
22.1k4 gold badges41 silver badges78 bronze badges
add a comment |
add a comment |
$begingroup$
Just what is fundamental? Torque is certainly more than just force with additional “baggage”. And it’s more than just about coordinate systems. Torque and force are not a matter of either or. Both are needed for the analysis of motion and equilibrium.
Moment, which is another term for torque, is a fundamental concept in statics. For example in statics both forces and moments are needed to determine static equilibrium . Forces cause straight line motion. Moments cause rotational motion. The requirements for equilibrium are that the sum of both the moments and forces have to be zero. And it goes beyond statics. Bending moments and shear forces are fundamental to the study of mechanics of materials.
You will learn to appreciate the difference if and when you study statics , dynamics, and mechanics of materials.
Hope this helps
$endgroup$
$begingroup$
I would argue that when we're talking about fundamental point particles, torque is just a matter of coordinate systems, and only becomes necessary when we consider composite systems.
$endgroup$
– Danny
6 hours ago
$begingroup$
@Danny what do you mean by saying that torque is just a matter of coordinate systems?
$endgroup$
– Aaron Stevens
6 hours ago
2
$begingroup$
@BobD Certainly torques make life a whole lot simpler for extended bodies, but I would argue that the concept of force is more fundamental than torque, as torque is defined in terms of force, but not the other way around. Couldn't one argue that a zero net torque is just a simpler way of saying that the net force acting on every part of the body must be $0$?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
@AaronStevens I wasn't arguing that torque isn't derived from force or that torque is equally "fundamental" as force. For that matter I'm not sure we can say forces in general are "fundamental" in the same manner as the strong nuclear, weak nuclear, electromagnetic and gravitational forces. Instead my focus was on the OP statement "So is choosing to use either force or torque as the basis of laws & problems arbitrary? Or is there an actual fundamental rationale to when one or the other should be used?" It's the ideal of either or use of force and torque to solve problem I addressed.
$endgroup$
– Bob D
6 hours ago
1
$begingroup$
@AaronStevens You never know.I've given up trying to figure out why
$endgroup$
– Bob D
2 hours ago
|
show 3 more comments
$begingroup$
Just what is fundamental? Torque is certainly more than just force with additional “baggage”. And it’s more than just about coordinate systems. Torque and force are not a matter of either or. Both are needed for the analysis of motion and equilibrium.
Moment, which is another term for torque, is a fundamental concept in statics. For example in statics both forces and moments are needed to determine static equilibrium . Forces cause straight line motion. Moments cause rotational motion. The requirements for equilibrium are that the sum of both the moments and forces have to be zero. And it goes beyond statics. Bending moments and shear forces are fundamental to the study of mechanics of materials.
You will learn to appreciate the difference if and when you study statics , dynamics, and mechanics of materials.
Hope this helps
$endgroup$
$begingroup$
I would argue that when we're talking about fundamental point particles, torque is just a matter of coordinate systems, and only becomes necessary when we consider composite systems.
$endgroup$
– Danny
6 hours ago
$begingroup$
@Danny what do you mean by saying that torque is just a matter of coordinate systems?
$endgroup$
– Aaron Stevens
6 hours ago
2
$begingroup$
@BobD Certainly torques make life a whole lot simpler for extended bodies, but I would argue that the concept of force is more fundamental than torque, as torque is defined in terms of force, but not the other way around. Couldn't one argue that a zero net torque is just a simpler way of saying that the net force acting on every part of the body must be $0$?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
@AaronStevens I wasn't arguing that torque isn't derived from force or that torque is equally "fundamental" as force. For that matter I'm not sure we can say forces in general are "fundamental" in the same manner as the strong nuclear, weak nuclear, electromagnetic and gravitational forces. Instead my focus was on the OP statement "So is choosing to use either force or torque as the basis of laws & problems arbitrary? Or is there an actual fundamental rationale to when one or the other should be used?" It's the ideal of either or use of force and torque to solve problem I addressed.
$endgroup$
– Bob D
6 hours ago
1
$begingroup$
@AaronStevens You never know.I've given up trying to figure out why
$endgroup$
– Bob D
2 hours ago
|
show 3 more comments
$begingroup$
Just what is fundamental? Torque is certainly more than just force with additional “baggage”. And it’s more than just about coordinate systems. Torque and force are not a matter of either or. Both are needed for the analysis of motion and equilibrium.
Moment, which is another term for torque, is a fundamental concept in statics. For example in statics both forces and moments are needed to determine static equilibrium . Forces cause straight line motion. Moments cause rotational motion. The requirements for equilibrium are that the sum of both the moments and forces have to be zero. And it goes beyond statics. Bending moments and shear forces are fundamental to the study of mechanics of materials.
You will learn to appreciate the difference if and when you study statics , dynamics, and mechanics of materials.
Hope this helps
$endgroup$
Just what is fundamental? Torque is certainly more than just force with additional “baggage”. And it’s more than just about coordinate systems. Torque and force are not a matter of either or. Both are needed for the analysis of motion and equilibrium.
Moment, which is another term for torque, is a fundamental concept in statics. For example in statics both forces and moments are needed to determine static equilibrium . Forces cause straight line motion. Moments cause rotational motion. The requirements for equilibrium are that the sum of both the moments and forces have to be zero. And it goes beyond statics. Bending moments and shear forces are fundamental to the study of mechanics of materials.
You will learn to appreciate the difference if and when you study statics , dynamics, and mechanics of materials.
Hope this helps
edited 8 hours ago
answered 8 hours ago
Bob DBob D
12.4k3 gold badges10 silver badges37 bronze badges
12.4k3 gold badges10 silver badges37 bronze badges
$begingroup$
I would argue that when we're talking about fundamental point particles, torque is just a matter of coordinate systems, and only becomes necessary when we consider composite systems.
$endgroup$
– Danny
6 hours ago
$begingroup$
@Danny what do you mean by saying that torque is just a matter of coordinate systems?
$endgroup$
– Aaron Stevens
6 hours ago
2
$begingroup$
@BobD Certainly torques make life a whole lot simpler for extended bodies, but I would argue that the concept of force is more fundamental than torque, as torque is defined in terms of force, but not the other way around. Couldn't one argue that a zero net torque is just a simpler way of saying that the net force acting on every part of the body must be $0$?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
@AaronStevens I wasn't arguing that torque isn't derived from force or that torque is equally "fundamental" as force. For that matter I'm not sure we can say forces in general are "fundamental" in the same manner as the strong nuclear, weak nuclear, electromagnetic and gravitational forces. Instead my focus was on the OP statement "So is choosing to use either force or torque as the basis of laws & problems arbitrary? Or is there an actual fundamental rationale to when one or the other should be used?" It's the ideal of either or use of force and torque to solve problem I addressed.
$endgroup$
– Bob D
6 hours ago
1
$begingroup$
@AaronStevens You never know.I've given up trying to figure out why
$endgroup$
– Bob D
2 hours ago
|
show 3 more comments
$begingroup$
I would argue that when we're talking about fundamental point particles, torque is just a matter of coordinate systems, and only becomes necessary when we consider composite systems.
$endgroup$
– Danny
6 hours ago
$begingroup$
@Danny what do you mean by saying that torque is just a matter of coordinate systems?
$endgroup$
– Aaron Stevens
6 hours ago
2
$begingroup$
@BobD Certainly torques make life a whole lot simpler for extended bodies, but I would argue that the concept of force is more fundamental than torque, as torque is defined in terms of force, but not the other way around. Couldn't one argue that a zero net torque is just a simpler way of saying that the net force acting on every part of the body must be $0$?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
@AaronStevens I wasn't arguing that torque isn't derived from force or that torque is equally "fundamental" as force. For that matter I'm not sure we can say forces in general are "fundamental" in the same manner as the strong nuclear, weak nuclear, electromagnetic and gravitational forces. Instead my focus was on the OP statement "So is choosing to use either force or torque as the basis of laws & problems arbitrary? Or is there an actual fundamental rationale to when one or the other should be used?" It's the ideal of either or use of force and torque to solve problem I addressed.
$endgroup$
– Bob D
6 hours ago
1
$begingroup$
@AaronStevens You never know.I've given up trying to figure out why
$endgroup$
– Bob D
2 hours ago
$begingroup$
I would argue that when we're talking about fundamental point particles, torque is just a matter of coordinate systems, and only becomes necessary when we consider composite systems.
$endgroup$
– Danny
6 hours ago
$begingroup$
I would argue that when we're talking about fundamental point particles, torque is just a matter of coordinate systems, and only becomes necessary when we consider composite systems.
$endgroup$
– Danny
6 hours ago
$begingroup$
@Danny what do you mean by saying that torque is just a matter of coordinate systems?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
@Danny what do you mean by saying that torque is just a matter of coordinate systems?
$endgroup$
– Aaron Stevens
6 hours ago
2
2
$begingroup$
@BobD Certainly torques make life a whole lot simpler for extended bodies, but I would argue that the concept of force is more fundamental than torque, as torque is defined in terms of force, but not the other way around. Couldn't one argue that a zero net torque is just a simpler way of saying that the net force acting on every part of the body must be $0$?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
@BobD Certainly torques make life a whole lot simpler for extended bodies, but I would argue that the concept of force is more fundamental than torque, as torque is defined in terms of force, but not the other way around. Couldn't one argue that a zero net torque is just a simpler way of saying that the net force acting on every part of the body must be $0$?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
@AaronStevens I wasn't arguing that torque isn't derived from force or that torque is equally "fundamental" as force. For that matter I'm not sure we can say forces in general are "fundamental" in the same manner as the strong nuclear, weak nuclear, electromagnetic and gravitational forces. Instead my focus was on the OP statement "So is choosing to use either force or torque as the basis of laws & problems arbitrary? Or is there an actual fundamental rationale to when one or the other should be used?" It's the ideal of either or use of force and torque to solve problem I addressed.
$endgroup$
– Bob D
6 hours ago
$begingroup$
@AaronStevens I wasn't arguing that torque isn't derived from force or that torque is equally "fundamental" as force. For that matter I'm not sure we can say forces in general are "fundamental" in the same manner as the strong nuclear, weak nuclear, electromagnetic and gravitational forces. Instead my focus was on the OP statement "So is choosing to use either force or torque as the basis of laws & problems arbitrary? Or is there an actual fundamental rationale to when one or the other should be used?" It's the ideal of either or use of force and torque to solve problem I addressed.
$endgroup$
– Bob D
6 hours ago
1
1
$begingroup$
@AaronStevens You never know.I've given up trying to figure out why
$endgroup$
– Bob D
2 hours ago
$begingroup$
@AaronStevens You never know.I've given up trying to figure out why
$endgroup$
– Bob D
2 hours ago
|
show 3 more comments
$begingroup$
Transfer of angular momentum is fundamental, and does not reduce to a force being applied.
For example: "...by utilizing transfer of photon spin angular momentum, it is also possible to set objects into rotational motion simply by targeting them with a beam of circularly polarized light"
Source: https://pubs.acs.org/doi/abs/10.1021/nl4010817
New contributor
Gene Ruso is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Transfer of angular momentum is fundamental, and does not reduce to a force being applied.
For example: "...by utilizing transfer of photon spin angular momentum, it is also possible to set objects into rotational motion simply by targeting them with a beam of circularly polarized light"
Source: https://pubs.acs.org/doi/abs/10.1021/nl4010817
New contributor
Gene Ruso is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Transfer of angular momentum is fundamental, and does not reduce to a force being applied.
For example: "...by utilizing transfer of photon spin angular momentum, it is also possible to set objects into rotational motion simply by targeting them with a beam of circularly polarized light"
Source: https://pubs.acs.org/doi/abs/10.1021/nl4010817
New contributor
Gene Ruso is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Transfer of angular momentum is fundamental, and does not reduce to a force being applied.
For example: "...by utilizing transfer of photon spin angular momentum, it is also possible to set objects into rotational motion simply by targeting them with a beam of circularly polarized light"
Source: https://pubs.acs.org/doi/abs/10.1021/nl4010817
New contributor
Gene Ruso is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Gene Ruso is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 mins ago
Gene RusoGene Ruso
11 bronze badge
11 bronze badge
New contributor
Gene Ruso is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Gene Ruso is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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$begingroup$
Torque isn't something that arises when we move to polar coordinates. They exist no matter how we choose to represent coordinates. Additionally, you can work with forces in polar coordinates without even referring to torque. Why do you think this, exactly?
$endgroup$
– Aaron Stevens
6 hours ago
$begingroup$
@AaronStevens I was only referring to the choice of coordinate system potentially being more convenient depending on whether you chose to express a particular problem in terms of force or torque.
$endgroup$
– DaveInCaz
4 hours ago