Why is the Lucas test not recommended to differentiate higher alcohols?Why are tertiary alkyl halides obtained in higher yield than secondary or primary during free radical halogenation of alkanes?Identification of types of alcoholsLucas test for alcoholsWhy doesn't a halide anion react with primary or secondary alcohols using SN2?Nucleophilicity of alcoxy groupsUnknown alcohol sample. Chromic acid negative but iodoform positive?Is it correct to say that ethenol is an alcohol?Doubts Regarding Ceric Ammonium Nitrate Test for Alcohols

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Why is the Lucas test not recommended to differentiate higher alcohols?


Why are tertiary alkyl halides obtained in higher yield than secondary or primary during free radical halogenation of alkanes?Identification of types of alcoholsLucas test for alcoholsWhy doesn't a halide anion react with primary or secondary alcohols using SN2?Nucleophilicity of alcoxy groupsUnknown alcohol sample. Chromic acid negative but iodoform positive?Is it correct to say that ethenol is an alcohol?Doubts Regarding Ceric Ammonium Nitrate Test for Alcohols






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4












$begingroup$


I read about the Lucas test for alcohols in which a cloudy precipitate is produced with a tertiary or secondary alcohol. However, on a side note it was mentioned that this test is useful only for compounds having less than six carbon atoms. Why is this so?










share|improve this question











$endgroup$













  • $begingroup$
    Post-WWII chemists call them tertiary, secondary and primary alcohols ... ;-)
    $endgroup$
    – Karl
    6 hours ago










  • $begingroup$
    @Karl I didn't get the reference if you mean to indicate something
    $endgroup$
    – StackUpPhysics
    1 hour ago

















4












$begingroup$


I read about the Lucas test for alcohols in which a cloudy precipitate is produced with a tertiary or secondary alcohol. However, on a side note it was mentioned that this test is useful only for compounds having less than six carbon atoms. Why is this so?










share|improve this question











$endgroup$













  • $begingroup$
    Post-WWII chemists call them tertiary, secondary and primary alcohols ... ;-)
    $endgroup$
    – Karl
    6 hours ago










  • $begingroup$
    @Karl I didn't get the reference if you mean to indicate something
    $endgroup$
    – StackUpPhysics
    1 hour ago













4












4








4





$begingroup$


I read about the Lucas test for alcohols in which a cloudy precipitate is produced with a tertiary or secondary alcohol. However, on a side note it was mentioned that this test is useful only for compounds having less than six carbon atoms. Why is this so?










share|improve this question











$endgroup$




I read about the Lucas test for alcohols in which a cloudy precipitate is produced with a tertiary or secondary alcohol. However, on a side note it was mentioned that this test is useful only for compounds having less than six carbon atoms. Why is this so?







organic-chemistry alcohols






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 6 hours ago









William R. Ebenezer

1,7001 gold badge5 silver badges23 bronze badges




1,7001 gold badge5 silver badges23 bronze badges










asked 11 hours ago









StackUpPhysicsStackUpPhysics

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1276 bronze badges














  • $begingroup$
    Post-WWII chemists call them tertiary, secondary and primary alcohols ... ;-)
    $endgroup$
    – Karl
    6 hours ago










  • $begingroup$
    @Karl I didn't get the reference if you mean to indicate something
    $endgroup$
    – StackUpPhysics
    1 hour ago
















  • $begingroup$
    Post-WWII chemists call them tertiary, secondary and primary alcohols ... ;-)
    $endgroup$
    – Karl
    6 hours ago










  • $begingroup$
    @Karl I didn't get the reference if you mean to indicate something
    $endgroup$
    – StackUpPhysics
    1 hour ago















$begingroup$
Post-WWII chemists call them tertiary, secondary and primary alcohols ... ;-)
$endgroup$
– Karl
6 hours ago




$begingroup$
Post-WWII chemists call them tertiary, secondary and primary alcohols ... ;-)
$endgroup$
– Karl
6 hours ago












$begingroup$
@Karl I didn't get the reference if you mean to indicate something
$endgroup$
– StackUpPhysics
1 hour ago




$begingroup$
@Karl I didn't get the reference if you mean to indicate something
$endgroup$
– StackUpPhysics
1 hour ago










2 Answers
2






active

oldest

votes


















4












$begingroup$

The problem is that the alcohols themselves might be insoluble. Ethanol is soluble, yes, but as the alkyl chain length increases, the hydrophobic nature due to the chain starts dominating over whatever hydrophilicity the $ce-OH$ group had been providing for lower homologues.



From source [1]:




.. any alcohol that is insoluble in the reagent might appear to be giving a positive 3° test.




The paper goes on to properly quantify several things:




Based on the results of this study, using 1 drop of alcohol added to 10 drops of reagent, it can be said that, at the very least, all saturated acyclic monofunctional alcohols having six or fewer carbons are soluble in the Lucas reagent.




It is clear that the relative amounts of the sample and the reagent become important in such borderline cases (~6 carbon long chains). If too much alcohol is added, it may cause an illusion of positive lucas test.



From source [1]: (emphasis mine)




That statement may not be true when 3 or 4 drops are used
per 10 drops of reagent. In fact, sometimes when 10 drops of
reagent are added to 3 or 4 drops of some of the alcohols, an
interesting event occurs after a delay of a couple of minutes
or so. Apparently, some undissolved alcohol that has been
clinging to the bottom of the test tube suddenly breaks loose
and, by streaming to the surface of the very dense Lucas
reagent, gives a momentary illusion of a positive test. The
real cloudiness, alkyl chloride formation, appears later—all
the more reason to use a high reagent/alcohol ratio.




References:



[1] "A study of the Lucas test"
R. A. Kjonaas and B. A. Riedford
J. Chem. Ed. 1991 68 (8), 704
DOI: 10.1021/ed068p704






share|improve this answer









$endgroup$






















    2












    $begingroup$

    To get a cloudy "precipitate", you need to dissolve the alcohol in the acid solution. Alcohols get less soluble in water as their chain length increases. By the time you pass 6 carbons, the alcohol itself is more or less insoluble. If it reacts along the interface, the chloride product would just mix into the alcohol layer, with no visible change.






    share|improve this answer









    $endgroup$










    • 1




      $begingroup$
      Please share the reference you've used
      $endgroup$
      – StackUpPhysics
      9 hours ago










    • $begingroup$
      I had no specific reference in mind, just general knowledge. The other answer is more complete than anything I had in mind.
      $endgroup$
      – jeffB
      6 hours ago










    • $begingroup$
      no problem still I appreciate your efforts
      $endgroup$
      – StackUpPhysics
      1 hour ago













    Your Answer








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    2 Answers
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    active

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    2 Answers
    2






    active

    oldest

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    active

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    active

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    4












    $begingroup$

    The problem is that the alcohols themselves might be insoluble. Ethanol is soluble, yes, but as the alkyl chain length increases, the hydrophobic nature due to the chain starts dominating over whatever hydrophilicity the $ce-OH$ group had been providing for lower homologues.



    From source [1]:




    .. any alcohol that is insoluble in the reagent might appear to be giving a positive 3° test.




    The paper goes on to properly quantify several things:




    Based on the results of this study, using 1 drop of alcohol added to 10 drops of reagent, it can be said that, at the very least, all saturated acyclic monofunctional alcohols having six or fewer carbons are soluble in the Lucas reagent.




    It is clear that the relative amounts of the sample and the reagent become important in such borderline cases (~6 carbon long chains). If too much alcohol is added, it may cause an illusion of positive lucas test.



    From source [1]: (emphasis mine)




    That statement may not be true when 3 or 4 drops are used
    per 10 drops of reagent. In fact, sometimes when 10 drops of
    reagent are added to 3 or 4 drops of some of the alcohols, an
    interesting event occurs after a delay of a couple of minutes
    or so. Apparently, some undissolved alcohol that has been
    clinging to the bottom of the test tube suddenly breaks loose
    and, by streaming to the surface of the very dense Lucas
    reagent, gives a momentary illusion of a positive test. The
    real cloudiness, alkyl chloride formation, appears later—all
    the more reason to use a high reagent/alcohol ratio.




    References:



    [1] "A study of the Lucas test"
    R. A. Kjonaas and B. A. Riedford
    J. Chem. Ed. 1991 68 (8), 704
    DOI: 10.1021/ed068p704






    share|improve this answer









    $endgroup$



















      4












      $begingroup$

      The problem is that the alcohols themselves might be insoluble. Ethanol is soluble, yes, but as the alkyl chain length increases, the hydrophobic nature due to the chain starts dominating over whatever hydrophilicity the $ce-OH$ group had been providing for lower homologues.



      From source [1]:




      .. any alcohol that is insoluble in the reagent might appear to be giving a positive 3° test.




      The paper goes on to properly quantify several things:




      Based on the results of this study, using 1 drop of alcohol added to 10 drops of reagent, it can be said that, at the very least, all saturated acyclic monofunctional alcohols having six or fewer carbons are soluble in the Lucas reagent.




      It is clear that the relative amounts of the sample and the reagent become important in such borderline cases (~6 carbon long chains). If too much alcohol is added, it may cause an illusion of positive lucas test.



      From source [1]: (emphasis mine)




      That statement may not be true when 3 or 4 drops are used
      per 10 drops of reagent. In fact, sometimes when 10 drops of
      reagent are added to 3 or 4 drops of some of the alcohols, an
      interesting event occurs after a delay of a couple of minutes
      or so. Apparently, some undissolved alcohol that has been
      clinging to the bottom of the test tube suddenly breaks loose
      and, by streaming to the surface of the very dense Lucas
      reagent, gives a momentary illusion of a positive test. The
      real cloudiness, alkyl chloride formation, appears later—all
      the more reason to use a high reagent/alcohol ratio.




      References:



      [1] "A study of the Lucas test"
      R. A. Kjonaas and B. A. Riedford
      J. Chem. Ed. 1991 68 (8), 704
      DOI: 10.1021/ed068p704






      share|improve this answer









      $endgroup$

















        4












        4








        4





        $begingroup$

        The problem is that the alcohols themselves might be insoluble. Ethanol is soluble, yes, but as the alkyl chain length increases, the hydrophobic nature due to the chain starts dominating over whatever hydrophilicity the $ce-OH$ group had been providing for lower homologues.



        From source [1]:




        .. any alcohol that is insoluble in the reagent might appear to be giving a positive 3° test.




        The paper goes on to properly quantify several things:




        Based on the results of this study, using 1 drop of alcohol added to 10 drops of reagent, it can be said that, at the very least, all saturated acyclic monofunctional alcohols having six or fewer carbons are soluble in the Lucas reagent.




        It is clear that the relative amounts of the sample and the reagent become important in such borderline cases (~6 carbon long chains). If too much alcohol is added, it may cause an illusion of positive lucas test.



        From source [1]: (emphasis mine)




        That statement may not be true when 3 or 4 drops are used
        per 10 drops of reagent. In fact, sometimes when 10 drops of
        reagent are added to 3 or 4 drops of some of the alcohols, an
        interesting event occurs after a delay of a couple of minutes
        or so. Apparently, some undissolved alcohol that has been
        clinging to the bottom of the test tube suddenly breaks loose
        and, by streaming to the surface of the very dense Lucas
        reagent, gives a momentary illusion of a positive test. The
        real cloudiness, alkyl chloride formation, appears later—all
        the more reason to use a high reagent/alcohol ratio.




        References:



        [1] "A study of the Lucas test"
        R. A. Kjonaas and B. A. Riedford
        J. Chem. Ed. 1991 68 (8), 704
        DOI: 10.1021/ed068p704






        share|improve this answer









        $endgroup$



        The problem is that the alcohols themselves might be insoluble. Ethanol is soluble, yes, but as the alkyl chain length increases, the hydrophobic nature due to the chain starts dominating over whatever hydrophilicity the $ce-OH$ group had been providing for lower homologues.



        From source [1]:




        .. any alcohol that is insoluble in the reagent might appear to be giving a positive 3° test.




        The paper goes on to properly quantify several things:




        Based on the results of this study, using 1 drop of alcohol added to 10 drops of reagent, it can be said that, at the very least, all saturated acyclic monofunctional alcohols having six or fewer carbons are soluble in the Lucas reagent.




        It is clear that the relative amounts of the sample and the reagent become important in such borderline cases (~6 carbon long chains). If too much alcohol is added, it may cause an illusion of positive lucas test.



        From source [1]: (emphasis mine)




        That statement may not be true when 3 or 4 drops are used
        per 10 drops of reagent. In fact, sometimes when 10 drops of
        reagent are added to 3 or 4 drops of some of the alcohols, an
        interesting event occurs after a delay of a couple of minutes
        or so. Apparently, some undissolved alcohol that has been
        clinging to the bottom of the test tube suddenly breaks loose
        and, by streaming to the surface of the very dense Lucas
        reagent, gives a momentary illusion of a positive test. The
        real cloudiness, alkyl chloride formation, appears later—all
        the more reason to use a high reagent/alcohol ratio.




        References:



        [1] "A study of the Lucas test"
        R. A. Kjonaas and B. A. Riedford
        J. Chem. Ed. 1991 68 (8), 704
        DOI: 10.1021/ed068p704







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 9 hours ago









        William R. EbenezerWilliam R. Ebenezer

        1,7001 gold badge5 silver badges23 bronze badges




        1,7001 gold badge5 silver badges23 bronze badges


























            2












            $begingroup$

            To get a cloudy "precipitate", you need to dissolve the alcohol in the acid solution. Alcohols get less soluble in water as their chain length increases. By the time you pass 6 carbons, the alcohol itself is more or less insoluble. If it reacts along the interface, the chloride product would just mix into the alcohol layer, with no visible change.






            share|improve this answer









            $endgroup$










            • 1




              $begingroup$
              Please share the reference you've used
              $endgroup$
              – StackUpPhysics
              9 hours ago










            • $begingroup$
              I had no specific reference in mind, just general knowledge. The other answer is more complete than anything I had in mind.
              $endgroup$
              – jeffB
              6 hours ago










            • $begingroup$
              no problem still I appreciate your efforts
              $endgroup$
              – StackUpPhysics
              1 hour ago















            2












            $begingroup$

            To get a cloudy "precipitate", you need to dissolve the alcohol in the acid solution. Alcohols get less soluble in water as their chain length increases. By the time you pass 6 carbons, the alcohol itself is more or less insoluble. If it reacts along the interface, the chloride product would just mix into the alcohol layer, with no visible change.






            share|improve this answer









            $endgroup$










            • 1




              $begingroup$
              Please share the reference you've used
              $endgroup$
              – StackUpPhysics
              9 hours ago










            • $begingroup$
              I had no specific reference in mind, just general knowledge. The other answer is more complete than anything I had in mind.
              $endgroup$
              – jeffB
              6 hours ago










            • $begingroup$
              no problem still I appreciate your efforts
              $endgroup$
              – StackUpPhysics
              1 hour ago













            2












            2








            2





            $begingroup$

            To get a cloudy "precipitate", you need to dissolve the alcohol in the acid solution. Alcohols get less soluble in water as their chain length increases. By the time you pass 6 carbons, the alcohol itself is more or less insoluble. If it reacts along the interface, the chloride product would just mix into the alcohol layer, with no visible change.






            share|improve this answer









            $endgroup$



            To get a cloudy "precipitate", you need to dissolve the alcohol in the acid solution. Alcohols get less soluble in water as their chain length increases. By the time you pass 6 carbons, the alcohol itself is more or less insoluble. If it reacts along the interface, the chloride product would just mix into the alcohol layer, with no visible change.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 9 hours ago









            jeffBjeffB

            1,2013 silver badges10 bronze badges




            1,2013 silver badges10 bronze badges










            • 1




              $begingroup$
              Please share the reference you've used
              $endgroup$
              – StackUpPhysics
              9 hours ago










            • $begingroup$
              I had no specific reference in mind, just general knowledge. The other answer is more complete than anything I had in mind.
              $endgroup$
              – jeffB
              6 hours ago










            • $begingroup$
              no problem still I appreciate your efforts
              $endgroup$
              – StackUpPhysics
              1 hour ago












            • 1




              $begingroup$
              Please share the reference you've used
              $endgroup$
              – StackUpPhysics
              9 hours ago










            • $begingroup$
              I had no specific reference in mind, just general knowledge. The other answer is more complete than anything I had in mind.
              $endgroup$
              – jeffB
              6 hours ago










            • $begingroup$
              no problem still I appreciate your efforts
              $endgroup$
              – StackUpPhysics
              1 hour ago







            1




            1




            $begingroup$
            Please share the reference you've used
            $endgroup$
            – StackUpPhysics
            9 hours ago




            $begingroup$
            Please share the reference you've used
            $endgroup$
            – StackUpPhysics
            9 hours ago












            $begingroup$
            I had no specific reference in mind, just general knowledge. The other answer is more complete than anything I had in mind.
            $endgroup$
            – jeffB
            6 hours ago




            $begingroup$
            I had no specific reference in mind, just general knowledge. The other answer is more complete than anything I had in mind.
            $endgroup$
            – jeffB
            6 hours ago












            $begingroup$
            no problem still I appreciate your efforts
            $endgroup$
            – StackUpPhysics
            1 hour ago




            $begingroup$
            no problem still I appreciate your efforts
            $endgroup$
            – StackUpPhysics
            1 hour ago

















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