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How to actually concatenate two Strings?


Concatenate string constantsGet strings from Serial.read()error loading an array of stringsIs possible to concatenate integers?Declaring literal stringsHow to multiply strings?Error handling strings and charsHow to combine strings and text together?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















I'm using the SPISlave library, and I have the following code snippet:



String arg;

SPISlave.onData([arg](uint8_t *data, size_t len)
data[len] = 0;
arg += String((char *)data);
// ...



The compiler doesn't like my string concatenation, though:



/home/lars/sketch_apr01a/sketch_apr01a.ino: In lambda function:
sketch_apr01a:65:12: error: passing 'const String' as 'this' argument of 'String& String::operator+=(const String&)' discards qualifiers [-fpermissive]
arg += String((char *)data);



I've tried other versions as well, with similar results:



  • arg.concat((char *)data)

  • arg = arg + String((char *)data)

  • arg += String((const char *)data)

So how exactly do I write this unusual operation?









share







New contributor



larsb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • Funny, on avr-g++ it's fine (with warnings about store duration). Anyway, you are capturing the arg variable by value, so it won't affect variable outside lambda function.

    – KIIV
    9 hours ago


















1















I'm using the SPISlave library, and I have the following code snippet:



String arg;

SPISlave.onData([arg](uint8_t *data, size_t len)
data[len] = 0;
arg += String((char *)data);
// ...



The compiler doesn't like my string concatenation, though:



/home/lars/sketch_apr01a/sketch_apr01a.ino: In lambda function:
sketch_apr01a:65:12: error: passing 'const String' as 'this' argument of 'String& String::operator+=(const String&)' discards qualifiers [-fpermissive]
arg += String((char *)data);



I've tried other versions as well, with similar results:



  • arg.concat((char *)data)

  • arg = arg + String((char *)data)

  • arg += String((const char *)data)

So how exactly do I write this unusual operation?









share







New contributor



larsb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • Funny, on avr-g++ it's fine (with warnings about store duration). Anyway, you are capturing the arg variable by value, so it won't affect variable outside lambda function.

    – KIIV
    9 hours ago














1












1








1








I'm using the SPISlave library, and I have the following code snippet:



String arg;

SPISlave.onData([arg](uint8_t *data, size_t len)
data[len] = 0;
arg += String((char *)data);
// ...



The compiler doesn't like my string concatenation, though:



/home/lars/sketch_apr01a/sketch_apr01a.ino: In lambda function:
sketch_apr01a:65:12: error: passing 'const String' as 'this' argument of 'String& String::operator+=(const String&)' discards qualifiers [-fpermissive]
arg += String((char *)data);



I've tried other versions as well, with similar results:



  • arg.concat((char *)data)

  • arg = arg + String((char *)data)

  • arg += String((const char *)data)

So how exactly do I write this unusual operation?









share







New contributor



larsb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I'm using the SPISlave library, and I have the following code snippet:



String arg;

SPISlave.onData([arg](uint8_t *data, size_t len)
data[len] = 0;
arg += String((char *)data);
// ...



The compiler doesn't like my string concatenation, though:



/home/lars/sketch_apr01a/sketch_apr01a.ino: In lambda function:
sketch_apr01a:65:12: error: passing 'const String' as 'this' argument of 'String& String::operator+=(const String&)' discards qualifiers [-fpermissive]
arg += String((char *)data);



I've tried other versions as well, with similar results:



  • arg.concat((char *)data)

  • arg = arg + String((char *)data)

  • arg += String((const char *)data)

So how exactly do I write this unusual operation?







string





share







New contributor



larsb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share







New contributor



larsb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







share



share






New contributor



larsb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 9 hours ago









larsblarsb

82 bronze badges




82 bronze badges




New contributor



larsb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




larsb is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

















  • Funny, on avr-g++ it's fine (with warnings about store duration). Anyway, you are capturing the arg variable by value, so it won't affect variable outside lambda function.

    – KIIV
    9 hours ago


















  • Funny, on avr-g++ it's fine (with warnings about store duration). Anyway, you are capturing the arg variable by value, so it won't affect variable outside lambda function.

    – KIIV
    9 hours ago

















Funny, on avr-g++ it's fine (with warnings about store duration). Anyway, you are capturing the arg variable by value, so it won't affect variable outside lambda function.

– KIIV
9 hours ago






Funny, on avr-g++ it's fine (with warnings about store duration). Anyway, you are capturing the arg variable by value, so it won't affect variable outside lambda function.

– KIIV
9 hours ago











2 Answers
2






active

oldest

votes


















2















Your lambda is capturing arg by copy, which is most certainly not what
you want. And since it doesn't have the mutable qualifier, the
captured parameters are not modifiable. Hence the compiler error.



You could get rid of the error by qualifying the capture as mutable,
but you would then be modifying the captured copy of arg, not the
original one. The correct solution would be to capture the String by
reference instead of capturing by copy. See Lambda
expressions.



But then, I concur with Michel Keijzers that avoiding Strings altogether
is a better option.






share|improve this answer

























  • Makes perfect sense, thanks!

    – larsb
    8 hours ago











  • Thanks for the insight and correct answer too (upvoted)

    – Michel Keijzers
    6 hours ago


















1















Actually for such string concatenation (which is in a function that may be called a lot), this could result in memory fragmentation, an on most Arduinos the memory will be soon too scattered that no useful memory is left.



Instead, it's better to create beforehand a buffer with the maximum size of the string you want to handle, like:



static const int MAX_BUFFER_LENGTH = 256;

char buffer[MAX_BUFFER_LENGTH];


And use the function strcat or strncat for concatenating two strings; there are generic C functions.






share|improve this answer

























  • Fair enough, and good advice in general. But I'd still like to know the answer to my question. :-)

    – larsb
    9 hours ago











  • I wonder what error you get when using concat (cannot be a String passing operation error). Maybe some casting to const.

    – Michel Keijzers
    9 hours ago













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









2















Your lambda is capturing arg by copy, which is most certainly not what
you want. And since it doesn't have the mutable qualifier, the
captured parameters are not modifiable. Hence the compiler error.



You could get rid of the error by qualifying the capture as mutable,
but you would then be modifying the captured copy of arg, not the
original one. The correct solution would be to capture the String by
reference instead of capturing by copy. See Lambda
expressions.



But then, I concur with Michel Keijzers that avoiding Strings altogether
is a better option.






share|improve this answer

























  • Makes perfect sense, thanks!

    – larsb
    8 hours ago











  • Thanks for the insight and correct answer too (upvoted)

    – Michel Keijzers
    6 hours ago















2















Your lambda is capturing arg by copy, which is most certainly not what
you want. And since it doesn't have the mutable qualifier, the
captured parameters are not modifiable. Hence the compiler error.



You could get rid of the error by qualifying the capture as mutable,
but you would then be modifying the captured copy of arg, not the
original one. The correct solution would be to capture the String by
reference instead of capturing by copy. See Lambda
expressions.



But then, I concur with Michel Keijzers that avoiding Strings altogether
is a better option.






share|improve this answer

























  • Makes perfect sense, thanks!

    – larsb
    8 hours ago











  • Thanks for the insight and correct answer too (upvoted)

    – Michel Keijzers
    6 hours ago













2














2










2









Your lambda is capturing arg by copy, which is most certainly not what
you want. And since it doesn't have the mutable qualifier, the
captured parameters are not modifiable. Hence the compiler error.



You could get rid of the error by qualifying the capture as mutable,
but you would then be modifying the captured copy of arg, not the
original one. The correct solution would be to capture the String by
reference instead of capturing by copy. See Lambda
expressions.



But then, I concur with Michel Keijzers that avoiding Strings altogether
is a better option.






share|improve this answer













Your lambda is capturing arg by copy, which is most certainly not what
you want. And since it doesn't have the mutable qualifier, the
captured parameters are not modifiable. Hence the compiler error.



You could get rid of the error by qualifying the capture as mutable,
but you would then be modifying the captured copy of arg, not the
original one. The correct solution would be to capture the String by
reference instead of capturing by copy. See Lambda
expressions.



But then, I concur with Michel Keijzers that avoiding Strings altogether
is a better option.







share|improve this answer












share|improve this answer



share|improve this answer










answered 9 hours ago









Edgar BonetEdgar Bonet

26.9k2 gold badges25 silver badges47 bronze badges




26.9k2 gold badges25 silver badges47 bronze badges















  • Makes perfect sense, thanks!

    – larsb
    8 hours ago











  • Thanks for the insight and correct answer too (upvoted)

    – Michel Keijzers
    6 hours ago

















  • Makes perfect sense, thanks!

    – larsb
    8 hours ago











  • Thanks for the insight and correct answer too (upvoted)

    – Michel Keijzers
    6 hours ago
















Makes perfect sense, thanks!

– larsb
8 hours ago





Makes perfect sense, thanks!

– larsb
8 hours ago













Thanks for the insight and correct answer too (upvoted)

– Michel Keijzers
6 hours ago





Thanks for the insight and correct answer too (upvoted)

– Michel Keijzers
6 hours ago













1















Actually for such string concatenation (which is in a function that may be called a lot), this could result in memory fragmentation, an on most Arduinos the memory will be soon too scattered that no useful memory is left.



Instead, it's better to create beforehand a buffer with the maximum size of the string you want to handle, like:



static const int MAX_BUFFER_LENGTH = 256;

char buffer[MAX_BUFFER_LENGTH];


And use the function strcat or strncat for concatenating two strings; there are generic C functions.






share|improve this answer

























  • Fair enough, and good advice in general. But I'd still like to know the answer to my question. :-)

    – larsb
    9 hours ago











  • I wonder what error you get when using concat (cannot be a String passing operation error). Maybe some casting to const.

    – Michel Keijzers
    9 hours ago















1















Actually for such string concatenation (which is in a function that may be called a lot), this could result in memory fragmentation, an on most Arduinos the memory will be soon too scattered that no useful memory is left.



Instead, it's better to create beforehand a buffer with the maximum size of the string you want to handle, like:



static const int MAX_BUFFER_LENGTH = 256;

char buffer[MAX_BUFFER_LENGTH];


And use the function strcat or strncat for concatenating two strings; there are generic C functions.






share|improve this answer

























  • Fair enough, and good advice in general. But I'd still like to know the answer to my question. :-)

    – larsb
    9 hours ago











  • I wonder what error you get when using concat (cannot be a String passing operation error). Maybe some casting to const.

    – Michel Keijzers
    9 hours ago













1














1










1









Actually for such string concatenation (which is in a function that may be called a lot), this could result in memory fragmentation, an on most Arduinos the memory will be soon too scattered that no useful memory is left.



Instead, it's better to create beforehand a buffer with the maximum size of the string you want to handle, like:



static const int MAX_BUFFER_LENGTH = 256;

char buffer[MAX_BUFFER_LENGTH];


And use the function strcat or strncat for concatenating two strings; there are generic C functions.






share|improve this answer













Actually for such string concatenation (which is in a function that may be called a lot), this could result in memory fragmentation, an on most Arduinos the memory will be soon too scattered that no useful memory is left.



Instead, it's better to create beforehand a buffer with the maximum size of the string you want to handle, like:



static const int MAX_BUFFER_LENGTH = 256;

char buffer[MAX_BUFFER_LENGTH];


And use the function strcat or strncat for concatenating two strings; there are generic C functions.







share|improve this answer












share|improve this answer



share|improve this answer










answered 9 hours ago









Michel KeijzersMichel Keijzers

8,2576 gold badges21 silver badges41 bronze badges




8,2576 gold badges21 silver badges41 bronze badges















  • Fair enough, and good advice in general. But I'd still like to know the answer to my question. :-)

    – larsb
    9 hours ago











  • I wonder what error you get when using concat (cannot be a String passing operation error). Maybe some casting to const.

    – Michel Keijzers
    9 hours ago

















  • Fair enough, and good advice in general. But I'd still like to know the answer to my question. :-)

    – larsb
    9 hours ago











  • I wonder what error you get when using concat (cannot be a String passing operation error). Maybe some casting to const.

    – Michel Keijzers
    9 hours ago
















Fair enough, and good advice in general. But I'd still like to know the answer to my question. :-)

– larsb
9 hours ago





Fair enough, and good advice in general. But I'd still like to know the answer to my question. :-)

– larsb
9 hours ago













I wonder what error you get when using concat (cannot be a String passing operation error). Maybe some casting to const.

– Michel Keijzers
9 hours ago





I wonder what error you get when using concat (cannot be a String passing operation error). Maybe some casting to const.

– Michel Keijzers
9 hours ago










larsb is a new contributor. Be nice, and check out our Code of Conduct.









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Кастелфранко ди Сопра Становништво Референце Спољашње везе Мени за навигацију43°37′18″ СГШ; 11°33′32″ ИГД / 43.62156° СГШ; 11.55885° ИГД / 43.62156; 11.5588543°37′18″ СГШ; 11°33′32″ ИГД / 43.62156° СГШ; 11.55885° ИГД / 43.62156; 11.558853179688„The GeoNames geographical database”„Istituto Nazionale di Statistica”проширитиууWorldCat156923403n850174324558639-1cb14643287r(подаци)