Shift lens vs move body?Can this cheap tilt-shift compact camera produce good results?What lenses can I use to build a DIY tilt/shift lens for a Nikon DX body?Metering with a Tilt-Shift LensHow to Maximize the Miniaturization Effect With a Tilt-Shift Lens?Why not separate a tilt shift lens into two separate lenses?Are the perspective control advantages of a tilt shift lens less important on higher resolution cameras?What are the techniques for taking portraits using a tilt shift lens?Can Focus Stacking produce the same effect as Tilt-Shift?Framing when adjusting tilt on a tilt-shift lens
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Shift lens vs move body?
Can this cheap tilt-shift compact camera produce good results?What lenses can I use to build a DIY tilt/shift lens for a Nikon DX body?Metering with a Tilt-Shift LensHow to Maximize the Miniaturization Effect With a Tilt-Shift Lens?Why not separate a tilt shift lens into two separate lenses?Are the perspective control advantages of a tilt shift lens less important on higher resolution cameras?What are the techniques for taking portraits using a tilt shift lens?Can Focus Stacking produce the same effect as Tilt-Shift?Framing when adjusting tilt on a tilt-shift lens
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This is a question that sounds basic, but I have yet to find an answer. When using a tilt-shift lens, if you shift the lens up 5 mm, or if you move the camera body up 5 mm, does the camera capture the same image?
tilt-shift
New contributor
add a comment |
This is a question that sounds basic, but I have yet to find an answer. When using a tilt-shift lens, if you shift the lens up 5 mm, or if you move the camera body up 5 mm, does the camera capture the same image?
tilt-shift
New contributor
add a comment |
This is a question that sounds basic, but I have yet to find an answer. When using a tilt-shift lens, if you shift the lens up 5 mm, or if you move the camera body up 5 mm, does the camera capture the same image?
tilt-shift
New contributor
This is a question that sounds basic, but I have yet to find an answer. When using a tilt-shift lens, if you shift the lens up 5 mm, or if you move the camera body up 5 mm, does the camera capture the same image?
tilt-shift
tilt-shift
New contributor
New contributor
New contributor
asked 9 hours ago
Dirk101Dirk101
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4 Answers
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No.
When moving camera body, the change significance is in relation to subject. For example, when taking photo of a person, 5 mm is quite unnoticeable. When shifting lens, the shift significance is in relation to imaging area size. In case of full frame, a 5 mm shift up moves the whole image by 21 percent of the image height.
In principle, shifting a lens allows you to select which part of its image circle will land on sensor. Therefore shift lenses have wider image circles than would be minimally needed for the sensor size from a non-shifting lens. So you can compare it to cropping from an image of a lens with a shorter focal length; the advantage of shift lens is that you can use the sensor area and frame on spot.
add a comment |
The other answers by xenoid and Imre are perfectly correct, but for visual reference, I've created a graphic to display the difference. The blue cone is the camera in the original position, the red demonstrates raising the camera, and the green is a camera in the original position with only the lens raised to the same position.
Usually imaging circles of tilt-shift lenses is larger than normal for the sensor size. That doesn't appear to be represented in your diagram. The green lines also look like the lens has been tilted.
– xiota
8 hours ago
@xiota The imaging circles are not represented at all in this diagram, we are just assuming that the circle is large enough to cover the entire area. This is a map of the extreme edges of the area visible to the sensor using only those rays that pass through the center of the lens. I admit it has been many years since I've worked with a rail camera, but I don't recall a tremendous difference in field of view based on tilt. Either way, this diagram is accurate when all planes are parallel.
– LightBender
7 hours ago
The green lines appear to be shifted and tilted. If the imaging circle is just big enough for the sensor, you would see the edge when it's shifted.
– xiota
1 hour ago
add a comment |
No.
If you shift the camera up 5mm, you shift the captured image by 5 "absoluet" millimeters. For instance, on a building, that would make the picture include or not the thickness of roof tiles.
If you shift the lens by 5mm on a 15mm-high sensor, you shift the capture image by one third of its relative size. If you shoot a building horizontally (to keep parallel verticals) the bottom half of your picture is the ground in front of the building. By shifting lens, you get one third of ground, and two thirds of building so you have more chances to include the full building.
See the diagram here
add a comment |
In the following diagram, the crossed lines represent the light rays. The green square represents the sensor. The shapes represent the physical object and image you wish to capture. In the normal position, the circle is captured on the sensor. A 40mm lens was used to take the photo.
Suppose you wish to capture the square. You could shift the lens up (or shift the sensor down). The sensor captures a different portion of the imaging circle, which contains the square. To take the photo, the 40mm lens was shifted upwards 1-2 cm.
If the imaging circle is too small, you will see its edge when you shift the lens. A 35mm lens was used to take this photo.
Suppose you want to move the camera up, with the sensor and lens in their normal alignment. The distance you'd have to move the camera is about the same as the distance between the circle and the square, which is much greater than the distance the sensor had to be shifted. This is why you can get the framing you want with a tiny shift lens, but might have to lift the camera in a crane. The photo was taken after raising the camera about a foot. The 40mm lens was used.
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
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votes
active
oldest
votes
No.
When moving camera body, the change significance is in relation to subject. For example, when taking photo of a person, 5 mm is quite unnoticeable. When shifting lens, the shift significance is in relation to imaging area size. In case of full frame, a 5 mm shift up moves the whole image by 21 percent of the image height.
In principle, shifting a lens allows you to select which part of its image circle will land on sensor. Therefore shift lenses have wider image circles than would be minimally needed for the sensor size from a non-shifting lens. So you can compare it to cropping from an image of a lens with a shorter focal length; the advantage of shift lens is that you can use the sensor area and frame on spot.
add a comment |
No.
When moving camera body, the change significance is in relation to subject. For example, when taking photo of a person, 5 mm is quite unnoticeable. When shifting lens, the shift significance is in relation to imaging area size. In case of full frame, a 5 mm shift up moves the whole image by 21 percent of the image height.
In principle, shifting a lens allows you to select which part of its image circle will land on sensor. Therefore shift lenses have wider image circles than would be minimally needed for the sensor size from a non-shifting lens. So you can compare it to cropping from an image of a lens with a shorter focal length; the advantage of shift lens is that you can use the sensor area and frame on spot.
add a comment |
No.
When moving camera body, the change significance is in relation to subject. For example, when taking photo of a person, 5 mm is quite unnoticeable. When shifting lens, the shift significance is in relation to imaging area size. In case of full frame, a 5 mm shift up moves the whole image by 21 percent of the image height.
In principle, shifting a lens allows you to select which part of its image circle will land on sensor. Therefore shift lenses have wider image circles than would be minimally needed for the sensor size from a non-shifting lens. So you can compare it to cropping from an image of a lens with a shorter focal length; the advantage of shift lens is that you can use the sensor area and frame on spot.
No.
When moving camera body, the change significance is in relation to subject. For example, when taking photo of a person, 5 mm is quite unnoticeable. When shifting lens, the shift significance is in relation to imaging area size. In case of full frame, a 5 mm shift up moves the whole image by 21 percent of the image height.
In principle, shifting a lens allows you to select which part of its image circle will land on sensor. Therefore shift lenses have wider image circles than would be minimally needed for the sensor size from a non-shifting lens. So you can compare it to cropping from an image of a lens with a shorter focal length; the advantage of shift lens is that you can use the sensor area and frame on spot.
answered 8 hours ago
ImreImre
27.6k9 gold badges96 silver badges169 bronze badges
27.6k9 gold badges96 silver badges169 bronze badges
add a comment |
add a comment |
The other answers by xenoid and Imre are perfectly correct, but for visual reference, I've created a graphic to display the difference. The blue cone is the camera in the original position, the red demonstrates raising the camera, and the green is a camera in the original position with only the lens raised to the same position.
Usually imaging circles of tilt-shift lenses is larger than normal for the sensor size. That doesn't appear to be represented in your diagram. The green lines also look like the lens has been tilted.
– xiota
8 hours ago
@xiota The imaging circles are not represented at all in this diagram, we are just assuming that the circle is large enough to cover the entire area. This is a map of the extreme edges of the area visible to the sensor using only those rays that pass through the center of the lens. I admit it has been many years since I've worked with a rail camera, but I don't recall a tremendous difference in field of view based on tilt. Either way, this diagram is accurate when all planes are parallel.
– LightBender
7 hours ago
The green lines appear to be shifted and tilted. If the imaging circle is just big enough for the sensor, you would see the edge when it's shifted.
– xiota
1 hour ago
add a comment |
The other answers by xenoid and Imre are perfectly correct, but for visual reference, I've created a graphic to display the difference. The blue cone is the camera in the original position, the red demonstrates raising the camera, and the green is a camera in the original position with only the lens raised to the same position.
Usually imaging circles of tilt-shift lenses is larger than normal for the sensor size. That doesn't appear to be represented in your diagram. The green lines also look like the lens has been tilted.
– xiota
8 hours ago
@xiota The imaging circles are not represented at all in this diagram, we are just assuming that the circle is large enough to cover the entire area. This is a map of the extreme edges of the area visible to the sensor using only those rays that pass through the center of the lens. I admit it has been many years since I've worked with a rail camera, but I don't recall a tremendous difference in field of view based on tilt. Either way, this diagram is accurate when all planes are parallel.
– LightBender
7 hours ago
The green lines appear to be shifted and tilted. If the imaging circle is just big enough for the sensor, you would see the edge when it's shifted.
– xiota
1 hour ago
add a comment |
The other answers by xenoid and Imre are perfectly correct, but for visual reference, I've created a graphic to display the difference. The blue cone is the camera in the original position, the red demonstrates raising the camera, and the green is a camera in the original position with only the lens raised to the same position.
The other answers by xenoid and Imre are perfectly correct, but for visual reference, I've created a graphic to display the difference. The blue cone is the camera in the original position, the red demonstrates raising the camera, and the green is a camera in the original position with only the lens raised to the same position.
answered 8 hours ago
LightBenderLightBender
7094 silver badges15 bronze badges
7094 silver badges15 bronze badges
Usually imaging circles of tilt-shift lenses is larger than normal for the sensor size. That doesn't appear to be represented in your diagram. The green lines also look like the lens has been tilted.
– xiota
8 hours ago
@xiota The imaging circles are not represented at all in this diagram, we are just assuming that the circle is large enough to cover the entire area. This is a map of the extreme edges of the area visible to the sensor using only those rays that pass through the center of the lens. I admit it has been many years since I've worked with a rail camera, but I don't recall a tremendous difference in field of view based on tilt. Either way, this diagram is accurate when all planes are parallel.
– LightBender
7 hours ago
The green lines appear to be shifted and tilted. If the imaging circle is just big enough for the sensor, you would see the edge when it's shifted.
– xiota
1 hour ago
add a comment |
Usually imaging circles of tilt-shift lenses is larger than normal for the sensor size. That doesn't appear to be represented in your diagram. The green lines also look like the lens has been tilted.
– xiota
8 hours ago
@xiota The imaging circles are not represented at all in this diagram, we are just assuming that the circle is large enough to cover the entire area. This is a map of the extreme edges of the area visible to the sensor using only those rays that pass through the center of the lens. I admit it has been many years since I've worked with a rail camera, but I don't recall a tremendous difference in field of view based on tilt. Either way, this diagram is accurate when all planes are parallel.
– LightBender
7 hours ago
The green lines appear to be shifted and tilted. If the imaging circle is just big enough for the sensor, you would see the edge when it's shifted.
– xiota
1 hour ago
Usually imaging circles of tilt-shift lenses is larger than normal for the sensor size. That doesn't appear to be represented in your diagram. The green lines also look like the lens has been tilted.
– xiota
8 hours ago
Usually imaging circles of tilt-shift lenses is larger than normal for the sensor size. That doesn't appear to be represented in your diagram. The green lines also look like the lens has been tilted.
– xiota
8 hours ago
@xiota The imaging circles are not represented at all in this diagram, we are just assuming that the circle is large enough to cover the entire area. This is a map of the extreme edges of the area visible to the sensor using only those rays that pass through the center of the lens. I admit it has been many years since I've worked with a rail camera, but I don't recall a tremendous difference in field of view based on tilt. Either way, this diagram is accurate when all planes are parallel.
– LightBender
7 hours ago
@xiota The imaging circles are not represented at all in this diagram, we are just assuming that the circle is large enough to cover the entire area. This is a map of the extreme edges of the area visible to the sensor using only those rays that pass through the center of the lens. I admit it has been many years since I've worked with a rail camera, but I don't recall a tremendous difference in field of view based on tilt. Either way, this diagram is accurate when all planes are parallel.
– LightBender
7 hours ago
The green lines appear to be shifted and tilted. If the imaging circle is just big enough for the sensor, you would see the edge when it's shifted.
– xiota
1 hour ago
The green lines appear to be shifted and tilted. If the imaging circle is just big enough for the sensor, you would see the edge when it's shifted.
– xiota
1 hour ago
add a comment |
No.
If you shift the camera up 5mm, you shift the captured image by 5 "absoluet" millimeters. For instance, on a building, that would make the picture include or not the thickness of roof tiles.
If you shift the lens by 5mm on a 15mm-high sensor, you shift the capture image by one third of its relative size. If you shoot a building horizontally (to keep parallel verticals) the bottom half of your picture is the ground in front of the building. By shifting lens, you get one third of ground, and two thirds of building so you have more chances to include the full building.
See the diagram here
add a comment |
No.
If you shift the camera up 5mm, you shift the captured image by 5 "absoluet" millimeters. For instance, on a building, that would make the picture include or not the thickness of roof tiles.
If you shift the lens by 5mm on a 15mm-high sensor, you shift the capture image by one third of its relative size. If you shoot a building horizontally (to keep parallel verticals) the bottom half of your picture is the ground in front of the building. By shifting lens, you get one third of ground, and two thirds of building so you have more chances to include the full building.
See the diagram here
add a comment |
No.
If you shift the camera up 5mm, you shift the captured image by 5 "absoluet" millimeters. For instance, on a building, that would make the picture include or not the thickness of roof tiles.
If you shift the lens by 5mm on a 15mm-high sensor, you shift the capture image by one third of its relative size. If you shoot a building horizontally (to keep parallel verticals) the bottom half of your picture is the ground in front of the building. By shifting lens, you get one third of ground, and two thirds of building so you have more chances to include the full building.
See the diagram here
No.
If you shift the camera up 5mm, you shift the captured image by 5 "absoluet" millimeters. For instance, on a building, that would make the picture include or not the thickness of roof tiles.
If you shift the lens by 5mm on a 15mm-high sensor, you shift the capture image by one third of its relative size. If you shoot a building horizontally (to keep parallel verticals) the bottom half of your picture is the ground in front of the building. By shifting lens, you get one third of ground, and two thirds of building so you have more chances to include the full building.
See the diagram here
answered 9 hours ago
xenoidxenoid
6,0931 gold badge10 silver badges25 bronze badges
6,0931 gold badge10 silver badges25 bronze badges
add a comment |
add a comment |
In the following diagram, the crossed lines represent the light rays. The green square represents the sensor. The shapes represent the physical object and image you wish to capture. In the normal position, the circle is captured on the sensor. A 40mm lens was used to take the photo.
Suppose you wish to capture the square. You could shift the lens up (or shift the sensor down). The sensor captures a different portion of the imaging circle, which contains the square. To take the photo, the 40mm lens was shifted upwards 1-2 cm.
If the imaging circle is too small, you will see its edge when you shift the lens. A 35mm lens was used to take this photo.
Suppose you want to move the camera up, with the sensor and lens in their normal alignment. The distance you'd have to move the camera is about the same as the distance between the circle and the square, which is much greater than the distance the sensor had to be shifted. This is why you can get the framing you want with a tiny shift lens, but might have to lift the camera in a crane. The photo was taken after raising the camera about a foot. The 40mm lens was used.
add a comment |
In the following diagram, the crossed lines represent the light rays. The green square represents the sensor. The shapes represent the physical object and image you wish to capture. In the normal position, the circle is captured on the sensor. A 40mm lens was used to take the photo.
Suppose you wish to capture the square. You could shift the lens up (or shift the sensor down). The sensor captures a different portion of the imaging circle, which contains the square. To take the photo, the 40mm lens was shifted upwards 1-2 cm.
If the imaging circle is too small, you will see its edge when you shift the lens. A 35mm lens was used to take this photo.
Suppose you want to move the camera up, with the sensor and lens in their normal alignment. The distance you'd have to move the camera is about the same as the distance between the circle and the square, which is much greater than the distance the sensor had to be shifted. This is why you can get the framing you want with a tiny shift lens, but might have to lift the camera in a crane. The photo was taken after raising the camera about a foot. The 40mm lens was used.
add a comment |
In the following diagram, the crossed lines represent the light rays. The green square represents the sensor. The shapes represent the physical object and image you wish to capture. In the normal position, the circle is captured on the sensor. A 40mm lens was used to take the photo.
Suppose you wish to capture the square. You could shift the lens up (or shift the sensor down). The sensor captures a different portion of the imaging circle, which contains the square. To take the photo, the 40mm lens was shifted upwards 1-2 cm.
If the imaging circle is too small, you will see its edge when you shift the lens. A 35mm lens was used to take this photo.
Suppose you want to move the camera up, with the sensor and lens in their normal alignment. The distance you'd have to move the camera is about the same as the distance between the circle and the square, which is much greater than the distance the sensor had to be shifted. This is why you can get the framing you want with a tiny shift lens, but might have to lift the camera in a crane. The photo was taken after raising the camera about a foot. The 40mm lens was used.
In the following diagram, the crossed lines represent the light rays. The green square represents the sensor. The shapes represent the physical object and image you wish to capture. In the normal position, the circle is captured on the sensor. A 40mm lens was used to take the photo.
Suppose you wish to capture the square. You could shift the lens up (or shift the sensor down). The sensor captures a different portion of the imaging circle, which contains the square. To take the photo, the 40mm lens was shifted upwards 1-2 cm.
If the imaging circle is too small, you will see its edge when you shift the lens. A 35mm lens was used to take this photo.
Suppose you want to move the camera up, with the sensor and lens in their normal alignment. The distance you'd have to move the camera is about the same as the distance between the circle and the square, which is much greater than the distance the sensor had to be shifted. This is why you can get the framing you want with a tiny shift lens, but might have to lift the camera in a crane. The photo was taken after raising the camera about a foot. The 40mm lens was used.
edited 44 mins ago
answered 8 hours ago
xiotaxiota
16.6k4 gold badges22 silver badges79 bronze badges
16.6k4 gold badges22 silver badges79 bronze badges
add a comment |
add a comment |
Dirk101 is a new contributor. Be nice, and check out our Code of Conduct.
Dirk101 is a new contributor. Be nice, and check out our Code of Conduct.
Dirk101 is a new contributor. Be nice, and check out our Code of Conduct.
Dirk101 is a new contributor. Be nice, and check out our Code of Conduct.
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