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How do I make a logic gate that takes 4 input and gives and output if only one is powered?


Powered rail not powering downHow do I create a redstone circuit whose output depends on it's previous input?How can I toggle an output using the same input pulse?Gate to allow only one player to pass throughMinecraft redstone logic - comparing 6 inputsRedstone NOR gate with one of two inputs adjacent to outputHow do I make a command block output a Redstone signal when it is successful?A Redstone circuit that will only fire if a specific input is turned on?How to make a implication gate using command blocks?How do you make a redstone clock that has four outputs and doesn't break when leaving/returning to the chunk?






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How can I make a red_stone logic gate/gates that takes in 4 inputs but only gives an output when 1 of them is powered.










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    How can I make a red_stone logic gate/gates that takes in 4 inputs but only gives an output when 1 of them is powered.










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      How can I make a red_stone logic gate/gates that takes in 4 inputs but only gives an output when 1 of them is powered.










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      How can I make a red_stone logic gate/gates that takes in 4 inputs but only gives an output when 1 of them is powered.







      minecraft minecraft-redstone






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      edited 27 mins ago









      aytimothy

      12.3k13 gold badges62 silver badges115 bronze badges




      12.3k13 gold badges62 silver badges115 bronze badges










      asked 1 hour ago









      tannertanner

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      315 bronze badges























          1 Answer
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          Being X is your output, and A, B, C and D are your inputs,



          X = ((A && !B && !C && !D) || (!A && B && !C && !D) || (!A && !B && C && !D) || (!A && !B && !C && D))


          There are better methods, but this is one of the simplest to derive. && is an AND gate, and || is an OR gate.

          The brackets group simultaneous lines/operations.






          share|improve this answer

























          • Thank you so much!

            – tanner
            42 mins ago











          • Don't forget to mark the question as correct if it is correct.

            – aytimothy
            29 mins ago














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          1 Answer
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          active

          oldest

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          active

          oldest

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          0
















          Being X is your output, and A, B, C and D are your inputs,



          X = ((A && !B && !C && !D) || (!A && B && !C && !D) || (!A && !B && C && !D) || (!A && !B && !C && D))


          There are better methods, but this is one of the simplest to derive. && is an AND gate, and || is an OR gate.

          The brackets group simultaneous lines/operations.






          share|improve this answer

























          • Thank you so much!

            – tanner
            42 mins ago











          • Don't forget to mark the question as correct if it is correct.

            – aytimothy
            29 mins ago
















          0
















          Being X is your output, and A, B, C and D are your inputs,



          X = ((A && !B && !C && !D) || (!A && B && !C && !D) || (!A && !B && C && !D) || (!A && !B && !C && D))


          There are better methods, but this is one of the simplest to derive. && is an AND gate, and || is an OR gate.

          The brackets group simultaneous lines/operations.






          share|improve this answer

























          • Thank you so much!

            – tanner
            42 mins ago











          • Don't forget to mark the question as correct if it is correct.

            – aytimothy
            29 mins ago














          0














          0










          0









          Being X is your output, and A, B, C and D are your inputs,



          X = ((A && !B && !C && !D) || (!A && B && !C && !D) || (!A && !B && C && !D) || (!A && !B && !C && D))


          There are better methods, but this is one of the simplest to derive. && is an AND gate, and || is an OR gate.

          The brackets group simultaneous lines/operations.






          share|improve this answer













          Being X is your output, and A, B, C and D are your inputs,



          X = ((A && !B && !C && !D) || (!A && B && !C && !D) || (!A && !B && C && !D) || (!A && !B && !C && D))


          There are better methods, but this is one of the simplest to derive. && is an AND gate, and || is an OR gate.

          The brackets group simultaneous lines/operations.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 1 hour ago









          aytimothyaytimothy

          12.3k13 gold badges62 silver badges115 bronze badges




          12.3k13 gold badges62 silver badges115 bronze badges















          • Thank you so much!

            – tanner
            42 mins ago











          • Don't forget to mark the question as correct if it is correct.

            – aytimothy
            29 mins ago


















          • Thank you so much!

            – tanner
            42 mins ago











          • Don't forget to mark the question as correct if it is correct.

            – aytimothy
            29 mins ago

















          Thank you so much!

          – tanner
          42 mins ago





          Thank you so much!

          – tanner
          42 mins ago













          Don't forget to mark the question as correct if it is correct.

          – aytimothy
          29 mins ago






          Don't forget to mark the question as correct if it is correct.

          – aytimothy
          29 mins ago



















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