Can White Castle? #3Can White Castle? #2Can white's rook and knight without moving white king force stalemate?Chess position such that with perfect play, mirrors itselfForced selfmate in n-movesOne-sided chess: Can you stalemate yourself?There is only s̶i̶x̶t̶y one place he can beFantastic Foxhole FailuresFind Those Chess Notations! #4That Ain’t Rght… 1# (Definitely!)Can White Castle?Can White Castle? #2
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Can White Castle? #3
Can White Castle? #2Can white's rook and knight without moving white king force stalemate?Chess position such that with perfect play, mirrors itselfForced selfmate in n-movesOne-sided chess: Can you stalemate yourself?There is only s̶i̶x̶t̶y one place he can beFantastic Foxhole FailuresFind Those Chess Notations! #4That Ain’t Rght… 1# (Definitely!)Can White Castle?Can White Castle? #2
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
Since it seems at least some people are enjoying these I'm continuing the series.
This one is not quite as elegant, but still interesting.
Can White Castle?
chess retrograde-analysis
$endgroup$
add a comment |
$begingroup$
Since it seems at least some people are enjoying these I'm continuing the series.
This one is not quite as elegant, but still interesting.
Can White Castle?
chess retrograde-analysis
$endgroup$
1
$begingroup$
I got this! Gimme a try!
$endgroup$
– Rewan Demontay
7 hours ago
add a comment |
$begingroup$
Since it seems at least some people are enjoying these I'm continuing the series.
This one is not quite as elegant, but still interesting.
Can White Castle?
chess retrograde-analysis
$endgroup$
Since it seems at least some people are enjoying these I'm continuing the series.
This one is not quite as elegant, but still interesting.
Can White Castle?
chess retrograde-analysis
chess retrograde-analysis
asked 8 hours ago


shoopishoopi
8595 silver badges12 bronze badges
8595 silver badges12 bronze badges
1
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I got this! Gimme a try!
$endgroup$
– Rewan Demontay
7 hours ago
add a comment |
1
$begingroup$
I got this! Gimme a try!
$endgroup$
– Rewan Demontay
7 hours ago
1
1
$begingroup$
I got this! Gimme a try!
$endgroup$
– Rewan Demontay
7 hours ago
$begingroup$
I got this! Gimme a try!
$endgroup$
– Rewan Demontay
7 hours ago
add a comment |
2 Answers
2
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oldest
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$begingroup$
I present to you, pure inefficiency:
1. Nf3 f6 2. Nh4 Kf7 3. Nf5 Ke6 4. Nd6 Ke5
5. Nc4+ Kf4 6. Nb6 Nh6 7. Nxc8 Ng4 8. Nb6 Nc6
9. Nxa8 Nd4 10. Nb6 Nf3+ 11. exf3 Ne5 12. Bd3 Nc4
13. Bg6 hxg6 14. Na4 Rh5 15. Nac3 Rh6 16. Qe2 Rh3
17. Qe4+ Kg5 18. Qf5+ gxf5 19. Na3 Ne3 20. Ncb5 Kf4
21. Nd4 Nc4 22. Nab5 Ne5 23. Na3 Nd3+ 24. cxd3 Ke5
25. Nc6+ Kd5 26. Nb4+ Kd4 27. Nd5 Kc5 28. Nc3 Kb4
29. Ne4 fxe4 30. Nc2+ Kc5 31. Na3 exd3 32. Nb5 Rh4
33. Nc3 Rc4 34. Nd1 Rxc1 35. Rb1 Rc4 36. Rc1 Kb4
37. Rc2 Rh4 38. Ne3 Rh3 39. Nd1 dxc2 40. Nc3 Kc4
41. Nd1 Kd3 42. Nc3 Rg3 43. Nd5 Rg4 44. Ne3 Rg5
45. Nd1 Rg3 46. Ne3 c1=R+ 47. Nd1 Kc2 48. h3 Ra1
49. h4 Kc1 50. Nc3 Rh3 51. Ne4 Rh2 52. Nc3 Kc2+
53. Nb1 Kd3 54. h5 Kd4 55. h6 Ke5 56. h7 Ke6
57. h8=B Kf7 58. d3 Ke8 59. O-O
It can definitely be done faster, but this works.
New contributor
RShields is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Ooo, nice! If correct, that means the answer to the original question is "we can't tell", which is ... disappointing.
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I fried my one brain cell figuring out the trick you see in the answer. What's the "original question"?
$endgroup$
– RShields
4 hours ago
$begingroup$
"Can white castle?".
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I understood the question to be, is there a way to reach this position such that white can castle, which this answers
$endgroup$
– RShields
4 hours ago
3
$begingroup$
None -- because there's no way to rule out starting the game with Nf3 Nf6; Rg1 Rg8; Rh1 Rh8; Ng1 Ng8 and the same on the Q-side.
$endgroup$
– Gareth McCaughan♦
4 hours ago
|
show 3 more comments
$begingroup$
Wrong answer (I made a boneheaded mistake, kindly pointed out in comments by @RShields, to which I have drawn attention below.)
The WBh8 obviously got there by promotion.
The only WP able to reach h8, given the existing WP structure, is the h-pawn.
There is no way the BQR can possibly have escaped from behind the pawns.
Therefore at least one of the BRs currently on the board is promoted.
If it promoted on f1, g1, or h1 then the WK or WR must have moved and W can't castle.
If it ever reached d2 then the WK must have moved and W can't castle.
If it promoted on d1 then the WK must have moved and W can't castle.
So if W can castle, some BP went from c2 to either b1 or c1 and promoted to a R, still on the board.
The only available BP is the h-pawn. To get to c2 it must have made 5 captures.
W is only missing 6 pieces, so all of them must have been taken by that pawn. <-- This is the boneheaded mistake; between writing the previous line and writing this one the number 5 metamorphosed in my brain into the number 6. D'oh!
Those captures all have to have been on white squares.
But one of W's missing pieces is the WQB (which, note, is not the thing now on h8)
which can't possibly have been captured on a white square.
Hence W cannot castle.
$endgroup$
$begingroup$
5 captures is a little short of 6 pieces :P. Note that W has 6 pawns visible, so one of the missing ones can maybe close the gap.
$endgroup$
– RShields
6 hours ago
1
$begingroup$
We always seem to start out with "no" but then the answer is yes...
$endgroup$
– greenturtle3141
6 hours ago
$begingroup$
Oh, I miscounted. Oops!
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I mean, when I wrote "6 pieces", I was literally thinking "that matches the 6 captures".
$endgroup$
– Gareth McCaughan♦
4 hours ago
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I present to you, pure inefficiency:
1. Nf3 f6 2. Nh4 Kf7 3. Nf5 Ke6 4. Nd6 Ke5
5. Nc4+ Kf4 6. Nb6 Nh6 7. Nxc8 Ng4 8. Nb6 Nc6
9. Nxa8 Nd4 10. Nb6 Nf3+ 11. exf3 Ne5 12. Bd3 Nc4
13. Bg6 hxg6 14. Na4 Rh5 15. Nac3 Rh6 16. Qe2 Rh3
17. Qe4+ Kg5 18. Qf5+ gxf5 19. Na3 Ne3 20. Ncb5 Kf4
21. Nd4 Nc4 22. Nab5 Ne5 23. Na3 Nd3+ 24. cxd3 Ke5
25. Nc6+ Kd5 26. Nb4+ Kd4 27. Nd5 Kc5 28. Nc3 Kb4
29. Ne4 fxe4 30. Nc2+ Kc5 31. Na3 exd3 32. Nb5 Rh4
33. Nc3 Rc4 34. Nd1 Rxc1 35. Rb1 Rc4 36. Rc1 Kb4
37. Rc2 Rh4 38. Ne3 Rh3 39. Nd1 dxc2 40. Nc3 Kc4
41. Nd1 Kd3 42. Nc3 Rg3 43. Nd5 Rg4 44. Ne3 Rg5
45. Nd1 Rg3 46. Ne3 c1=R+ 47. Nd1 Kc2 48. h3 Ra1
49. h4 Kc1 50. Nc3 Rh3 51. Ne4 Rh2 52. Nc3 Kc2+
53. Nb1 Kd3 54. h5 Kd4 55. h6 Ke5 56. h7 Ke6
57. h8=B Kf7 58. d3 Ke8 59. O-O
It can definitely be done faster, but this works.
New contributor
RShields is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Ooo, nice! If correct, that means the answer to the original question is "we can't tell", which is ... disappointing.
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I fried my one brain cell figuring out the trick you see in the answer. What's the "original question"?
$endgroup$
– RShields
4 hours ago
$begingroup$
"Can white castle?".
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I understood the question to be, is there a way to reach this position such that white can castle, which this answers
$endgroup$
– RShields
4 hours ago
3
$begingroup$
None -- because there's no way to rule out starting the game with Nf3 Nf6; Rg1 Rg8; Rh1 Rh8; Ng1 Ng8 and the same on the Q-side.
$endgroup$
– Gareth McCaughan♦
4 hours ago
|
show 3 more comments
$begingroup$
I present to you, pure inefficiency:
1. Nf3 f6 2. Nh4 Kf7 3. Nf5 Ke6 4. Nd6 Ke5
5. Nc4+ Kf4 6. Nb6 Nh6 7. Nxc8 Ng4 8. Nb6 Nc6
9. Nxa8 Nd4 10. Nb6 Nf3+ 11. exf3 Ne5 12. Bd3 Nc4
13. Bg6 hxg6 14. Na4 Rh5 15. Nac3 Rh6 16. Qe2 Rh3
17. Qe4+ Kg5 18. Qf5+ gxf5 19. Na3 Ne3 20. Ncb5 Kf4
21. Nd4 Nc4 22. Nab5 Ne5 23. Na3 Nd3+ 24. cxd3 Ke5
25. Nc6+ Kd5 26. Nb4+ Kd4 27. Nd5 Kc5 28. Nc3 Kb4
29. Ne4 fxe4 30. Nc2+ Kc5 31. Na3 exd3 32. Nb5 Rh4
33. Nc3 Rc4 34. Nd1 Rxc1 35. Rb1 Rc4 36. Rc1 Kb4
37. Rc2 Rh4 38. Ne3 Rh3 39. Nd1 dxc2 40. Nc3 Kc4
41. Nd1 Kd3 42. Nc3 Rg3 43. Nd5 Rg4 44. Ne3 Rg5
45. Nd1 Rg3 46. Ne3 c1=R+ 47. Nd1 Kc2 48. h3 Ra1
49. h4 Kc1 50. Nc3 Rh3 51. Ne4 Rh2 52. Nc3 Kc2+
53. Nb1 Kd3 54. h5 Kd4 55. h6 Ke5 56. h7 Ke6
57. h8=B Kf7 58. d3 Ke8 59. O-O
It can definitely be done faster, but this works.
New contributor
RShields is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Ooo, nice! If correct, that means the answer to the original question is "we can't tell", which is ... disappointing.
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I fried my one brain cell figuring out the trick you see in the answer. What's the "original question"?
$endgroup$
– RShields
4 hours ago
$begingroup$
"Can white castle?".
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I understood the question to be, is there a way to reach this position such that white can castle, which this answers
$endgroup$
– RShields
4 hours ago
3
$begingroup$
None -- because there's no way to rule out starting the game with Nf3 Nf6; Rg1 Rg8; Rh1 Rh8; Ng1 Ng8 and the same on the Q-side.
$endgroup$
– Gareth McCaughan♦
4 hours ago
|
show 3 more comments
$begingroup$
I present to you, pure inefficiency:
1. Nf3 f6 2. Nh4 Kf7 3. Nf5 Ke6 4. Nd6 Ke5
5. Nc4+ Kf4 6. Nb6 Nh6 7. Nxc8 Ng4 8. Nb6 Nc6
9. Nxa8 Nd4 10. Nb6 Nf3+ 11. exf3 Ne5 12. Bd3 Nc4
13. Bg6 hxg6 14. Na4 Rh5 15. Nac3 Rh6 16. Qe2 Rh3
17. Qe4+ Kg5 18. Qf5+ gxf5 19. Na3 Ne3 20. Ncb5 Kf4
21. Nd4 Nc4 22. Nab5 Ne5 23. Na3 Nd3+ 24. cxd3 Ke5
25. Nc6+ Kd5 26. Nb4+ Kd4 27. Nd5 Kc5 28. Nc3 Kb4
29. Ne4 fxe4 30. Nc2+ Kc5 31. Na3 exd3 32. Nb5 Rh4
33. Nc3 Rc4 34. Nd1 Rxc1 35. Rb1 Rc4 36. Rc1 Kb4
37. Rc2 Rh4 38. Ne3 Rh3 39. Nd1 dxc2 40. Nc3 Kc4
41. Nd1 Kd3 42. Nc3 Rg3 43. Nd5 Rg4 44. Ne3 Rg5
45. Nd1 Rg3 46. Ne3 c1=R+ 47. Nd1 Kc2 48. h3 Ra1
49. h4 Kc1 50. Nc3 Rh3 51. Ne4 Rh2 52. Nc3 Kc2+
53. Nb1 Kd3 54. h5 Kd4 55. h6 Ke5 56. h7 Ke6
57. h8=B Kf7 58. d3 Ke8 59. O-O
It can definitely be done faster, but this works.
New contributor
RShields is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I present to you, pure inefficiency:
1. Nf3 f6 2. Nh4 Kf7 3. Nf5 Ke6 4. Nd6 Ke5
5. Nc4+ Kf4 6. Nb6 Nh6 7. Nxc8 Ng4 8. Nb6 Nc6
9. Nxa8 Nd4 10. Nb6 Nf3+ 11. exf3 Ne5 12. Bd3 Nc4
13. Bg6 hxg6 14. Na4 Rh5 15. Nac3 Rh6 16. Qe2 Rh3
17. Qe4+ Kg5 18. Qf5+ gxf5 19. Na3 Ne3 20. Ncb5 Kf4
21. Nd4 Nc4 22. Nab5 Ne5 23. Na3 Nd3+ 24. cxd3 Ke5
25. Nc6+ Kd5 26. Nb4+ Kd4 27. Nd5 Kc5 28. Nc3 Kb4
29. Ne4 fxe4 30. Nc2+ Kc5 31. Na3 exd3 32. Nb5 Rh4
33. Nc3 Rc4 34. Nd1 Rxc1 35. Rb1 Rc4 36. Rc1 Kb4
37. Rc2 Rh4 38. Ne3 Rh3 39. Nd1 dxc2 40. Nc3 Kc4
41. Nd1 Kd3 42. Nc3 Rg3 43. Nd5 Rg4 44. Ne3 Rg5
45. Nd1 Rg3 46. Ne3 c1=R+ 47. Nd1 Kc2 48. h3 Ra1
49. h4 Kc1 50. Nc3 Rh3 51. Ne4 Rh2 52. Nc3 Kc2+
53. Nb1 Kd3 54. h5 Kd4 55. h6 Ke5 56. h7 Ke6
57. h8=B Kf7 58. d3 Ke8 59. O-O
It can definitely be done faster, but this works.
New contributor
RShields is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
RShields is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 4 hours ago
RShieldsRShields
6011 silver badge9 bronze badges
6011 silver badge9 bronze badges
New contributor
RShields is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
RShields is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
Ooo, nice! If correct, that means the answer to the original question is "we can't tell", which is ... disappointing.
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I fried my one brain cell figuring out the trick you see in the answer. What's the "original question"?
$endgroup$
– RShields
4 hours ago
$begingroup$
"Can white castle?".
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I understood the question to be, is there a way to reach this position such that white can castle, which this answers
$endgroup$
– RShields
4 hours ago
3
$begingroup$
None -- because there's no way to rule out starting the game with Nf3 Nf6; Rg1 Rg8; Rh1 Rh8; Ng1 Ng8 and the same on the Q-side.
$endgroup$
– Gareth McCaughan♦
4 hours ago
|
show 3 more comments
$begingroup$
Ooo, nice! If correct, that means the answer to the original question is "we can't tell", which is ... disappointing.
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I fried my one brain cell figuring out the trick you see in the answer. What's the "original question"?
$endgroup$
– RShields
4 hours ago
$begingroup$
"Can white castle?".
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I understood the question to be, is there a way to reach this position such that white can castle, which this answers
$endgroup$
– RShields
4 hours ago
3
$begingroup$
None -- because there's no way to rule out starting the game with Nf3 Nf6; Rg1 Rg8; Rh1 Rh8; Ng1 Ng8 and the same on the Q-side.
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
Ooo, nice! If correct, that means the answer to the original question is "we can't tell", which is ... disappointing.
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
Ooo, nice! If correct, that means the answer to the original question is "we can't tell", which is ... disappointing.
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I fried my one brain cell figuring out the trick you see in the answer. What's the "original question"?
$endgroup$
– RShields
4 hours ago
$begingroup$
I fried my one brain cell figuring out the trick you see in the answer. What's the "original question"?
$endgroup$
– RShields
4 hours ago
$begingroup$
"Can white castle?".
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
"Can white castle?".
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I understood the question to be, is there a way to reach this position such that white can castle, which this answers
$endgroup$
– RShields
4 hours ago
$begingroup$
I understood the question to be, is there a way to reach this position such that white can castle, which this answers
$endgroup$
– RShields
4 hours ago
3
3
$begingroup$
None -- because there's no way to rule out starting the game with Nf3 Nf6; Rg1 Rg8; Rh1 Rh8; Ng1 Ng8 and the same on the Q-side.
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
None -- because there's no way to rule out starting the game with Nf3 Nf6; Rg1 Rg8; Rh1 Rh8; Ng1 Ng8 and the same on the Q-side.
$endgroup$
– Gareth McCaughan♦
4 hours ago
|
show 3 more comments
$begingroup$
Wrong answer (I made a boneheaded mistake, kindly pointed out in comments by @RShields, to which I have drawn attention below.)
The WBh8 obviously got there by promotion.
The only WP able to reach h8, given the existing WP structure, is the h-pawn.
There is no way the BQR can possibly have escaped from behind the pawns.
Therefore at least one of the BRs currently on the board is promoted.
If it promoted on f1, g1, or h1 then the WK or WR must have moved and W can't castle.
If it ever reached d2 then the WK must have moved and W can't castle.
If it promoted on d1 then the WK must have moved and W can't castle.
So if W can castle, some BP went from c2 to either b1 or c1 and promoted to a R, still on the board.
The only available BP is the h-pawn. To get to c2 it must have made 5 captures.
W is only missing 6 pieces, so all of them must have been taken by that pawn. <-- This is the boneheaded mistake; between writing the previous line and writing this one the number 5 metamorphosed in my brain into the number 6. D'oh!
Those captures all have to have been on white squares.
But one of W's missing pieces is the WQB (which, note, is not the thing now on h8)
which can't possibly have been captured on a white square.
Hence W cannot castle.
$endgroup$
$begingroup$
5 captures is a little short of 6 pieces :P. Note that W has 6 pawns visible, so one of the missing ones can maybe close the gap.
$endgroup$
– RShields
6 hours ago
1
$begingroup$
We always seem to start out with "no" but then the answer is yes...
$endgroup$
– greenturtle3141
6 hours ago
$begingroup$
Oh, I miscounted. Oops!
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I mean, when I wrote "6 pieces", I was literally thinking "that matches the 6 captures".
$endgroup$
– Gareth McCaughan♦
4 hours ago
add a comment |
$begingroup$
Wrong answer (I made a boneheaded mistake, kindly pointed out in comments by @RShields, to which I have drawn attention below.)
The WBh8 obviously got there by promotion.
The only WP able to reach h8, given the existing WP structure, is the h-pawn.
There is no way the BQR can possibly have escaped from behind the pawns.
Therefore at least one of the BRs currently on the board is promoted.
If it promoted on f1, g1, or h1 then the WK or WR must have moved and W can't castle.
If it ever reached d2 then the WK must have moved and W can't castle.
If it promoted on d1 then the WK must have moved and W can't castle.
So if W can castle, some BP went from c2 to either b1 or c1 and promoted to a R, still on the board.
The only available BP is the h-pawn. To get to c2 it must have made 5 captures.
W is only missing 6 pieces, so all of them must have been taken by that pawn. <-- This is the boneheaded mistake; between writing the previous line and writing this one the number 5 metamorphosed in my brain into the number 6. D'oh!
Those captures all have to have been on white squares.
But one of W's missing pieces is the WQB (which, note, is not the thing now on h8)
which can't possibly have been captured on a white square.
Hence W cannot castle.
$endgroup$
$begingroup$
5 captures is a little short of 6 pieces :P. Note that W has 6 pawns visible, so one of the missing ones can maybe close the gap.
$endgroup$
– RShields
6 hours ago
1
$begingroup$
We always seem to start out with "no" but then the answer is yes...
$endgroup$
– greenturtle3141
6 hours ago
$begingroup$
Oh, I miscounted. Oops!
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I mean, when I wrote "6 pieces", I was literally thinking "that matches the 6 captures".
$endgroup$
– Gareth McCaughan♦
4 hours ago
add a comment |
$begingroup$
Wrong answer (I made a boneheaded mistake, kindly pointed out in comments by @RShields, to which I have drawn attention below.)
The WBh8 obviously got there by promotion.
The only WP able to reach h8, given the existing WP structure, is the h-pawn.
There is no way the BQR can possibly have escaped from behind the pawns.
Therefore at least one of the BRs currently on the board is promoted.
If it promoted on f1, g1, or h1 then the WK or WR must have moved and W can't castle.
If it ever reached d2 then the WK must have moved and W can't castle.
If it promoted on d1 then the WK must have moved and W can't castle.
So if W can castle, some BP went from c2 to either b1 or c1 and promoted to a R, still on the board.
The only available BP is the h-pawn. To get to c2 it must have made 5 captures.
W is only missing 6 pieces, so all of them must have been taken by that pawn. <-- This is the boneheaded mistake; between writing the previous line and writing this one the number 5 metamorphosed in my brain into the number 6. D'oh!
Those captures all have to have been on white squares.
But one of W's missing pieces is the WQB (which, note, is not the thing now on h8)
which can't possibly have been captured on a white square.
Hence W cannot castle.
$endgroup$
Wrong answer (I made a boneheaded mistake, kindly pointed out in comments by @RShields, to which I have drawn attention below.)
The WBh8 obviously got there by promotion.
The only WP able to reach h8, given the existing WP structure, is the h-pawn.
There is no way the BQR can possibly have escaped from behind the pawns.
Therefore at least one of the BRs currently on the board is promoted.
If it promoted on f1, g1, or h1 then the WK or WR must have moved and W can't castle.
If it ever reached d2 then the WK must have moved and W can't castle.
If it promoted on d1 then the WK must have moved and W can't castle.
So if W can castle, some BP went from c2 to either b1 or c1 and promoted to a R, still on the board.
The only available BP is the h-pawn. To get to c2 it must have made 5 captures.
W is only missing 6 pieces, so all of them must have been taken by that pawn. <-- This is the boneheaded mistake; between writing the previous line and writing this one the number 5 metamorphosed in my brain into the number 6. D'oh!
Those captures all have to have been on white squares.
But one of W's missing pieces is the WQB (which, note, is not the thing now on h8)
which can't possibly have been captured on a white square.
Hence W cannot castle.
edited 4 hours ago
answered 7 hours ago
Gareth McCaughan♦Gareth McCaughan
75k3 gold badges189 silver badges289 bronze badges
75k3 gold badges189 silver badges289 bronze badges
$begingroup$
5 captures is a little short of 6 pieces :P. Note that W has 6 pawns visible, so one of the missing ones can maybe close the gap.
$endgroup$
– RShields
6 hours ago
1
$begingroup$
We always seem to start out with "no" but then the answer is yes...
$endgroup$
– greenturtle3141
6 hours ago
$begingroup$
Oh, I miscounted. Oops!
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I mean, when I wrote "6 pieces", I was literally thinking "that matches the 6 captures".
$endgroup$
– Gareth McCaughan♦
4 hours ago
add a comment |
$begingroup$
5 captures is a little short of 6 pieces :P. Note that W has 6 pawns visible, so one of the missing ones can maybe close the gap.
$endgroup$
– RShields
6 hours ago
1
$begingroup$
We always seem to start out with "no" but then the answer is yes...
$endgroup$
– greenturtle3141
6 hours ago
$begingroup$
Oh, I miscounted. Oops!
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I mean, when I wrote "6 pieces", I was literally thinking "that matches the 6 captures".
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
5 captures is a little short of 6 pieces :P. Note that W has 6 pawns visible, so one of the missing ones can maybe close the gap.
$endgroup$
– RShields
6 hours ago
$begingroup$
5 captures is a little short of 6 pieces :P. Note that W has 6 pawns visible, so one of the missing ones can maybe close the gap.
$endgroup$
– RShields
6 hours ago
1
1
$begingroup$
We always seem to start out with "no" but then the answer is yes...
$endgroup$
– greenturtle3141
6 hours ago
$begingroup$
We always seem to start out with "no" but then the answer is yes...
$endgroup$
– greenturtle3141
6 hours ago
$begingroup$
Oh, I miscounted. Oops!
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
Oh, I miscounted. Oops!
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I mean, when I wrote "6 pieces", I was literally thinking "that matches the 6 captures".
$endgroup$
– Gareth McCaughan♦
4 hours ago
$begingroup$
I mean, when I wrote "6 pieces", I was literally thinking "that matches the 6 captures".
$endgroup$
– Gareth McCaughan♦
4 hours ago
add a comment |
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