Untrusted - level 13 - what's wrong with my solution? ( “stick to left side” implementation attempt)Level 10 with droidsHelp with Level 16's lazers
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Untrusted - level 13 - what's wrong with my solution? ( “stick to left side” implementation attempt)
Level 10 with droidsHelp with Level 16's lazers
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
So I'm struggling with this game as a (super fun!) homework. I got stuck at level 13, after 2 hours I glanced at the other topic about it and tried to implement "stick to the left side" method, but it doesn't seem to work.
Could you guys tell me what's wrong? There might be some pretty fundamental mistakes as my first encounter with JavaScript was on Tuesday.
var direction;
if ( me.getX() == 1 & me.getY() == 1 )
if ( me.canMove('right') )
direction = 0;
else
direction = 1;
moveRobot( direction );
direction = getDirection();
function moveRobot( direction )
if ( me.canMove( getDirectionName( direction ) ) )
me.move( getDirectionName( direction ) ) ;
else if ( !me.canMove( getDirectionName( direction ) )
& me.canMove( getDirectionName( (direction + 1) % 4) ) )
me.move( getDirectionName( (direction + 1) % 4) );
direction = (direction + 1) % 4;
else
me.move( getDirectionName( (direction + 2) % 4) );
direction = (direction + 2) % 4;
function getDirection( )
if ( me.canMove( getDirectionName( direction ) ) )
return direction;
else if ( !me.canMove( getDirectionName( direction ) )
& me.canMove( getDirectionName( (direction + 1) % 4) ) )
return (direction + 1) % 4;
else
return (direction + 2) % 4;
function getDirectionName( direction )
if ( direction == 0 )
return 'right';
else if ( direction == 1 )
return 'down';
else if ( direction == 2 )
return 'left';
else
return 'up';
untrusted
asked Nov 12 '15 at 0:08
ltwltw
112 bronze badges
bumped to the homepage by Community♦ 1 hour ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
So I'm struggling with this game as a (super fun!) homework. I got stuck at level 13, after 2 hours I glanced at the other topic about it and tried to implement "stick to the left side" method, but it doesn't seem to work.
Could you guys tell me what's wrong? There might be some pretty fundamental mistakes as my first encounter with JavaScript was on Tuesday.
var direction;
if ( me.getX() == 1 & me.getY() == 1 )
if ( me.canMove('right') )
direction = 0;
else
direction = 1;
moveRobot( direction );
direction = getDirection();
function moveRobot( direction )
if ( me.canMove( getDirectionName( direction ) ) )
me.move( getDirectionName( direction ) ) ;
else if ( !me.canMove( getDirectionName( direction ) )
& me.canMove( getDirectionName( (direction + 1) % 4) ) )
me.move( getDirectionName( (direction + 1) % 4) );
direction = (direction + 1) % 4;
else
me.move( getDirectionName( (direction + 2) % 4) );
direction = (direction + 2) % 4;
function getDirection( )
if ( me.canMove( getDirectionName( direction ) ) )
return direction;
else if ( !me.canMove( getDirectionName( direction ) )
& me.canMove( getDirectionName( (direction + 1) % 4) ) )
return (direction + 1) % 4;
else
return (direction + 2) % 4;
function getDirectionName( direction )
if ( direction == 0 )
return 'right';
else if ( direction == 1 )
return 'down';
else if ( direction == 2 )
return 'left';
else
return 'up';
untrusted
asked Nov 12 '15 at 0:08
ltwltw
112 bronze badges
bumped to the homepage by Community♦ 1 hour ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
This is on-topic on Stack Overflow.
– Anthony Pham
Nov 12 '15 at 0:15
1
@PythonMaster, just to clarify, this is still on topic, here. While StackOverflow can help you with just about any programming-related issue, we still consider it on topic when the problem is also game-related. If you need to solve the programming issue to progress in the game, it is most certainly game-related. vim-adventures is another example of a code-based game
– user106385
Nov 12 '15 at 0:31
@PythonMaster I thought that this question is difficult to be stated on Stack Overflow properly. After all you need to play this game to be able to see what's inside level 13.
– ltw
Nov 12 '15 at 0:38
Oh, it's a game... Wish I could retract my downvote...
– Anthony Pham
Nov 12 '15 at 0:39
1
The game is tagged in the question, @PythonMaster. The question still looks like it could do with a tidy edit, once edited you can change your vote
– user106385
Nov 12 '15 at 0:54
add a comment |
So I'm struggling with this game as a (super fun!) homework. I got stuck at level 13, after 2 hours I glanced at the other topic about it and tried to implement "stick to the left side" method, but it doesn't seem to work.
Could you guys tell me what's wrong? There might be some pretty fundamental mistakes as my first encounter with JavaScript was on Tuesday.
var direction;
if ( me.getX() == 1 & me.getY() == 1 )
if ( me.canMove('right') )
direction = 0;
else
direction = 1;
moveRobot( direction );
direction = getDirection();
function moveRobot( direction )
if ( me.canMove( getDirectionName( direction ) ) )
me.move( getDirectionName( direction ) ) ;
else if ( !me.canMove( getDirectionName( direction ) )
& me.canMove( getDirectionName( (direction + 1) % 4) ) )
me.move( getDirectionName( (direction + 1) % 4) );
direction = (direction + 1) % 4;
else
me.move( getDirectionName( (direction + 2) % 4) );
direction = (direction + 2) % 4;
function getDirection( )
if ( me.canMove( getDirectionName( direction ) ) )
return direction;
else if ( !me.canMove( getDirectionName( direction ) )
& me.canMove( getDirectionName( (direction + 1) % 4) ) )
return (direction + 1) % 4;
else
return (direction + 2) % 4;
function getDirectionName( direction )
if ( direction == 0 )
return 'right';
else if ( direction == 1 )
return 'down';
else if ( direction == 2 )
return 'left';
else
return 'up';
untrusted
asked Nov 12 '15 at 0:08
ltwltw
112 bronze badges
So I'm struggling with this game as a (super fun!) homework. I got stuck at level 13, after 2 hours I glanced at the other topic about it and tried to implement "stick to the left side" method, but it doesn't seem to work.
Could you guys tell me what's wrong? There might be some pretty fundamental mistakes as my first encounter with JavaScript was on Tuesday.
var direction;
if ( me.getX() == 1 & me.getY() == 1 )
if ( me.canMove('right') )
direction = 0;
else
direction = 1;
moveRobot( direction );
direction = getDirection();
function moveRobot( direction )
if ( me.canMove( getDirectionName( direction ) ) )
me.move( getDirectionName( direction ) ) ;
else if ( !me.canMove( getDirectionName( direction ) )
& me.canMove( getDirectionName( (direction + 1) % 4) ) )
me.move( getDirectionName( (direction + 1) % 4) );
direction = (direction + 1) % 4;
else
me.move( getDirectionName( (direction + 2) % 4) );
direction = (direction + 2) % 4;
function getDirection( )
if ( me.canMove( getDirectionName( direction ) ) )
return direction;
else if ( !me.canMove( getDirectionName( direction ) )
& me.canMove( getDirectionName( (direction + 1) % 4) ) )
return (direction + 1) % 4;
else
return (direction + 2) % 4;
function getDirectionName( direction )
if ( direction == 0 )
return 'right';
else if ( direction == 1 )
return 'down';
else if ( direction == 2 )
return 'left';
else
return 'up';
untrusted
untrusted
asked Nov 12 '15 at 0:08
ltwltw
112 bronze badges
asked Nov 12 '15 at 0:08
ltwltw
112 bronze badges
edited Nov 12 '15 at 0:49
ltw
asked Nov 12 '15 at 0:08
ltwltw
112 bronze badges
asked Nov 12 '15 at 0:08
ltwltw
112 bronze badges
asked Nov 12 '15 at 0:08
ltwltw
112 bronze badges
112 bronze badges
bumped to the homepage by Community♦ 1 hour ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 1 hour ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 1 hour ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
This is on-topic on Stack Overflow.
– Anthony Pham
Nov 12 '15 at 0:15
1
@PythonMaster, just to clarify, this is still on topic, here. While StackOverflow can help you with just about any programming-related issue, we still consider it on topic when the problem is also game-related. If you need to solve the programming issue to progress in the game, it is most certainly game-related. vim-adventures is another example of a code-based game
– user106385
Nov 12 '15 at 0:31
@PythonMaster I thought that this question is difficult to be stated on Stack Overflow properly. After all you need to play this game to be able to see what's inside level 13.
– ltw
Nov 12 '15 at 0:38
Oh, it's a game... Wish I could retract my downvote...
– Anthony Pham
Nov 12 '15 at 0:39
1
The game is tagged in the question, @PythonMaster. The question still looks like it could do with a tidy edit, once edited you can change your vote
– user106385
Nov 12 '15 at 0:54
add a comment |
This is on-topic on Stack Overflow.
– Anthony Pham
Nov 12 '15 at 0:15
1
@PythonMaster, just to clarify, this is still on topic, here. While StackOverflow can help you with just about any programming-related issue, we still consider it on topic when the problem is also game-related. If you need to solve the programming issue to progress in the game, it is most certainly game-related. vim-adventures is another example of a code-based game
– user106385
Nov 12 '15 at 0:31
@PythonMaster I thought that this question is difficult to be stated on Stack Overflow properly. After all you need to play this game to be able to see what's inside level 13.
– ltw
Nov 12 '15 at 0:38
Oh, it's a game... Wish I could retract my downvote...
– Anthony Pham
Nov 12 '15 at 0:39
1
The game is tagged in the question, @PythonMaster. The question still looks like it could do with a tidy edit, once edited you can change your vote
– user106385
Nov 12 '15 at 0:54
This is on-topic on Stack Overflow.
– Anthony Pham
Nov 12 '15 at 0:15
This is on-topic on Stack Overflow.
– Anthony Pham
Nov 12 '15 at 0:15
1
1
@PythonMaster, just to clarify, this is still on topic, here. While StackOverflow can help you with just about any programming-related issue, we still consider it on topic when the problem is also game-related. If you need to solve the programming issue to progress in the game, it is most certainly game-related. vim-adventures is another example of a code-based game
– user106385
Nov 12 '15 at 0:31
@PythonMaster, just to clarify, this is still on topic, here. While StackOverflow can help you with just about any programming-related issue, we still consider it on topic when the problem is also game-related. If you need to solve the programming issue to progress in the game, it is most certainly game-related. vim-adventures is another example of a code-based game
– user106385
Nov 12 '15 at 0:31
@PythonMaster I thought that this question is difficult to be stated on Stack Overflow properly. After all you need to play this game to be able to see what's inside level 13.
– ltw
Nov 12 '15 at 0:38
@PythonMaster I thought that this question is difficult to be stated on Stack Overflow properly. After all you need to play this game to be able to see what's inside level 13.
– ltw
Nov 12 '15 at 0:38
Oh, it's a game... Wish I could retract my downvote...
– Anthony Pham
Nov 12 '15 at 0:39
Oh, it's a game... Wish I could retract my downvote...
– Anthony Pham
Nov 12 '15 at 0:39
1
1
The game is tagged in the question, @PythonMaster. The question still looks like it could do with a tidy edit, once edited you can change your vote
– user106385
Nov 12 '15 at 0:54
The game is tagged in the question, @PythonMaster. The question still looks like it could do with a tidy edit, once edited you can change your vote
– user106385
Nov 12 '15 at 0:54
add a comment |
1 Answer
1
active
oldest
votes
1. I think a stick to left side implementation of this problim is not possible. If you want to stick to the left side you have to know where the left side is. So yout have to know what the direction of your last move was. Since the variables of the function
'behavior': function (me) ...
"reset" every time the function gets called, this is not easy to implement.
2. You are only setting the value of direction when x = 1 and y = 1 so it only deos something if those coords are right. Since the robot moves the coords change.
if ( me.getX() == 1 & me.getY() == 1 )
if ( me.canMove('right') )
direction = 0;
else
direction = 1;
Else direction is unset and nothing will work.
You would change it to the following:
moveRobot( direction );
direction = getDirection();
Note:
If you cannot solve a level, don't search for the answers of others, because you will lose the fun of that game. If necessary cheat through and solve the level later:
- Open console (
F12) - Enter: "localStorage.levelReached =
LEVEL_NUMBER - Reload page
Hope it helped :)
answered May 4 '16 at 19:28
Simon MeuselSimon Meusel
1,0275 silver badges16 bronze badges
This isn't true; thebehaviorfunction gets called with the same object every time, so you can use that object to store data.
– pppery
1 hour ago
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
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oldest
votes
active
oldest
votes
1. I think a stick to left side implementation of this problim is not possible. If you want to stick to the left side you have to know where the left side is. So yout have to know what the direction of your last move was. Since the variables of the function
'behavior': function (me) ...
"reset" every time the function gets called, this is not easy to implement.
2. You are only setting the value of direction when x = 1 and y = 1 so it only deos something if those coords are right. Since the robot moves the coords change.
if ( me.getX() == 1 & me.getY() == 1 )
if ( me.canMove('right') )
direction = 0;
else
direction = 1;
Else direction is unset and nothing will work.
You would change it to the following:
moveRobot( direction );
direction = getDirection();
Note:
If you cannot solve a level, don't search for the answers of others, because you will lose the fun of that game. If necessary cheat through and solve the level later:
- Open console (
F12) - Enter: "localStorage.levelReached =
LEVEL_NUMBER - Reload page
Hope it helped :)
answered May 4 '16 at 19:28
Simon MeuselSimon Meusel
1,0275 silver badges16 bronze badges
This isn't true; thebehaviorfunction gets called with the same object every time, so you can use that object to store data.
– pppery
1 hour ago
add a comment |
1. I think a stick to left side implementation of this problim is not possible. If you want to stick to the left side you have to know where the left side is. So yout have to know what the direction of your last move was. Since the variables of the function
'behavior': function (me) ...
"reset" every time the function gets called, this is not easy to implement.
2. You are only setting the value of direction when x = 1 and y = 1 so it only deos something if those coords are right. Since the robot moves the coords change.
if ( me.getX() == 1 & me.getY() == 1 )
if ( me.canMove('right') )
direction = 0;
else
direction = 1;
Else direction is unset and nothing will work.
You would change it to the following:
moveRobot( direction );
direction = getDirection();
Note:
If you cannot solve a level, don't search for the answers of others, because you will lose the fun of that game. If necessary cheat through and solve the level later:
- Open console (
F12) - Enter: "localStorage.levelReached =
LEVEL_NUMBER - Reload page
Hope it helped :)
answered May 4 '16 at 19:28
Simon MeuselSimon Meusel
1,0275 silver badges16 bronze badges
This isn't true; thebehaviorfunction gets called with the same object every time, so you can use that object to store data.
– pppery
1 hour ago
add a comment |
1. I think a stick to left side implementation of this problim is not possible. If you want to stick to the left side you have to know where the left side is. So yout have to know what the direction of your last move was. Since the variables of the function
'behavior': function (me) ...
"reset" every time the function gets called, this is not easy to implement.
2. You are only setting the value of direction when x = 1 and y = 1 so it only deos something if those coords are right. Since the robot moves the coords change.
if ( me.getX() == 1 & me.getY() == 1 )
if ( me.canMove('right') )
direction = 0;
else
direction = 1;
Else direction is unset and nothing will work.
You would change it to the following:
moveRobot( direction );
direction = getDirection();
Note:
If you cannot solve a level, don't search for the answers of others, because you will lose the fun of that game. If necessary cheat through and solve the level later:
- Open console (
F12) - Enter: "localStorage.levelReached =
LEVEL_NUMBER - Reload page
Hope it helped :)
answered May 4 '16 at 19:28
Simon MeuselSimon Meusel
1,0275 silver badges16 bronze badges
1. I think a stick to left side implementation of this problim is not possible. If you want to stick to the left side you have to know where the left side is. So yout have to know what the direction of your last move was. Since the variables of the function
'behavior': function (me) ...
"reset" every time the function gets called, this is not easy to implement.
2. You are only setting the value of direction when x = 1 and y = 1 so it only deos something if those coords are right. Since the robot moves the coords change.
if ( me.getX() == 1 & me.getY() == 1 )
if ( me.canMove('right') )
direction = 0;
else
direction = 1;
Else direction is unset and nothing will work.
You would change it to the following:
moveRobot( direction );
direction = getDirection();
Note:
If you cannot solve a level, don't search for the answers of others, because you will lose the fun of that game. If necessary cheat through and solve the level later:
- Open console (
F12) - Enter: "localStorage.levelReached =
LEVEL_NUMBER - Reload page
Hope it helped :)
answered May 4 '16 at 19:28
Simon MeuselSimon Meusel
1,0275 silver badges16 bronze badges
answered May 4 '16 at 19:28
Simon MeuselSimon Meusel
1,0275 silver badges16 bronze badges
answered May 4 '16 at 19:28
Simon MeuselSimon Meusel
1,0275 silver badges16 bronze badges
answered May 4 '16 at 19:28
Simon MeuselSimon Meusel
1,0275 silver badges16 bronze badges
1,0275 silver badges16 bronze badges
This isn't true; thebehaviorfunction gets called with the same object every time, so you can use that object to store data.
– pppery
1 hour ago
add a comment |
This isn't true; thebehaviorfunction gets called with the same object every time, so you can use that object to store data.
– pppery
1 hour ago
This isn't true; the
behavior function gets called with the same object every time, so you can use that object to store data.– pppery
1 hour ago
This isn't true; the
behavior function gets called with the same object every time, so you can use that object to store data.– pppery
1 hour ago
add a comment |
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This is on-topic on Stack Overflow.
– Anthony Pham
Nov 12 '15 at 0:15
1
@PythonMaster, just to clarify, this is still on topic, here. While StackOverflow can help you with just about any programming-related issue, we still consider it on topic when the problem is also game-related. If you need to solve the programming issue to progress in the game, it is most certainly game-related. vim-adventures is another example of a code-based game
– user106385
Nov 12 '15 at 0:31
@PythonMaster I thought that this question is difficult to be stated on Stack Overflow properly. After all you need to play this game to be able to see what's inside level 13.
– ltw
Nov 12 '15 at 0:38
Oh, it's a game... Wish I could retract my downvote...
– Anthony Pham
Nov 12 '15 at 0:39
1
The game is tagged in the question, @PythonMaster. The question still looks like it could do with a tidy edit, once edited you can change your vote
– user106385
Nov 12 '15 at 0:54